HT5077 Decryption of Encrypted hfs+ using Lion OS X

How to Decrypt coreStorage (Encrypted hfs+ using Lion OS X) file system. because i forgot my encrypted drive(hfs+ encrypted) password or how to change password of this drive. please help me regarding this file system as soon as possible.

I'm afraid you're out of luck. The whole purpose of encryption is so it can be accessed only by someone with the password.
Is this your OSX drive? If so, did you record the Recovery Key? And/or register it with Apple? If you did, follow the procedures in OS X Lion: About FileVault 2.
Note this in the Additional Information section:
"Please take note that the encryption used in FileVault 2 will make accessing data on your encrypted drive impossible without the permitted user accounts' passwords or the recovery key. When you choose to turn on FileVault, you will no longer be able to auto-login. Take great care in choosing an account password that you feel is both secure and easy for you to remember. When enabling FileVault, carefully write it down or be certain to make a copy of exactly what is shown and store it outside of your encrypted disk. If choosing to store your recovery key with Apple, take great care in choosing your questions and providing answers you can, if needed, clearly convey to an AppleCare phone support advisor." (emphasis added)

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Unable to unlock encrypted disk images created with Snow Leopard using Lion

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Decrypt the encrypted password

Hi there,
I have been scratching my head for some time to fix one issue. We are planning to change the plateform/technology and we need to bring over existing login to new system. In order to have the same password I need to decrypt the password before I send it to new system. When we stored the password, it encrypts them and stores it in database. I am using following code to decrypt it. it's not worlking . This is error I am getting.
Given final block not properly padded
Here is some more information:
Key is :javax.crypto.spec.SecretKeySpec@18f3a
Format is :RAW
getAlgorithm() is :DES
String encrypted = abcdefgh
Provider is: com.sun.crypto.provider.SunJCE()
This is my code to decrypt which throws error " Given final block not properly padded" :
public String decrypt(String encrypted){
          Cipher ci = null;
          byte [] result = null;
          try {
               ci = Cipher.getInstance("DES");
               ci.init(Cipher.DECRYPT_MODE, key);
               System.out.println("CryptoUtil()" +"before hexToByteArray. Byte Data: "+encrypted);
               byte [] encryptedData = hexToByteArray(encrypted, false);
               //Log.out("CryptoUtil()" +"after hexToByteArray. lenth: "+ encryptedData.length);
               result = ci.doFinal(encryptedData);
          catch (Exception e) {
               System.out.println("CryptoUtil()" +"ERROR: "+ e.getMessage());
               return encrypted;
          String strResult = new String(result);
          return strResult;
Please help.
Thank you.

These are the two values I am getting for encrypted password:
97654de7857cd9aab331995cba044fc6
a125a6b2a71e23adc002ac7fbe1a1042
Is this a hex code?
I think the key is: abcdefgh
This is my code to encrypt and decrypt:
      * empty constructor
      * @param keydata
     public CryptoUtil(String keydata){
          if (keydata.trim().equals("")){
               logDebug("CryptoUtil()" +" Constructor didn't get a valid key!");
               usage();
               System.exit(0);
          }else{
               keyBytes = keydata.getBytes();
               key = new SecretKeySpec(keyBytes, 0, keyBytes.length, "DES");
          try {
               Provider sp = new com.sun.crypto.provider.SunJCE();
               //logDebug("CryptoUtil() " + sp.getInfo());
                Security.addProvider(sp);
              }catch (Exception ex) {
                     logDebug("CryptoUtil() " +"Problem loading crypto provider \n error:"+ex.getMessage());
               usage();
                System.exit(0);
      * Encrypt
      * @param s
     public String encrypt(String s){
          Cipher ci = null;
              byte [] result = null;
              try {
               ci = Cipher.getInstance("DES");
               ci.init(Cipher.ENCRYPT_MODE, key);
               result = ci.doFinal(s.getBytes());
              }catch (Exception e) {
                    logDebug("CryptoUtil()" +"ERROR: "+ e.getMessage());
          String strResult = byteArrayToHex(result);
              return strResult;
      * decrypt a card number
      * @param encrypted
     public String decrypt(String encrypted){
          Cipher ci = null;
              byte [] result = null;
              try {
               ci = Cipher.getInstance("DES");
               ci.init(Cipher.DECRYPT_MODE, key);
               //Log.out("CryptoUtil()" +"before hexToByteArray. Byte Data: "+encrypted);
               byte [] encryptedData = hexToByteArray(encrypted, false);
               //Log.out("CryptoUtil()" +"after hexToByteArray. lenth: "+ encryptedData.length);
               result = ci.doFinal(encryptedData);
              catch (Exception e) {
               logError("CryptoUtil()" +"ERROR: "+ e.getMessage());
               return encrypted;
          String strResult = new String(result);
          return strResult;
     static final String hexDigitChars = "0123456789abcdef";
      * @param a
     public static final String byteArrayToHex(byte [] a) {
          int hn, ln, cx;
          StringBuffer buf = new StringBuffer(a.length * 2);
          for(cx = 0; cx < a.length; cx++) {
                hn = ((int)(a[cx]) & 0x00ff) / 16;
                ln = ((int)(a[cx]) & 0x000f);
                buf.append(hexDigitChars.charAt(hn));
                buf.append(hexDigitChars.charAt(ln));
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      * @param rev
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          StringBuffer acc = new StringBuffer(str.length() + 1);
          int cx, rp, ff, val;
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          str.toLowerCase().getChars(0, str.length(), s, 0);
          for(cx = str.length() - 1, ff = 0; cx >= 0; cx--) {
          if (hexDigitChars.indexOf(s[cx]) >= 0) {
               acc.append(s[cx]);
               ff++;
           }else {
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          for(cx = 0, rp = ret.length - 1; cx < acc.length(); cx++, rp--) {
                val = hexDigitChars.indexOf(acc.charAt(cx));
                cx++;
                val += 16 * hexDigitChars.indexOf(acc.charAt(cx));
                ret[rp] = (byte)val;
          if (rev) {
                byte tmp;
                int fx, bx;
                for(fx = 0, bx = ret.length - 1; fx < (ret.length / 2); fx++, bx--) {
                    tmp = ret[bx];
                    ret[bx] = ret[fx];
                    ret[fx] = tmp;
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Will that give you any more information to help me?

Problem Decrypting a text file using OpenPGP

I am new in java cryptography. We have a file from vendor which needs to be decrypted. I am using the code below which gives me error after the bolded comment line. Below the code are the error messages that I get.
Can anyone give me any assistance in telling me what is the problem.
Thank you,
Ed
package cryptix.openpgp.examples;
import cryptix.message.EncryptedMessage;
import cryptix.message.KeyBundleMessage;
import cryptix.message.LiteralMessage;
import cryptix.message.Message;
import cryptix.message.MessageException;
import cryptix.message.MessageFactory;
import cryptix.message.NotEncryptedToParameterException;
import cryptix.openpgp.PGPSignedMessage;
import cryptix.pki.KeyBundle;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.security.NoSuchAlgorithmException;
import java.security.UnrecoverableKeyException;
import java.util.Collection;
public class Decrypt {
public static void main(String[] args) {
java.security.Security.addProvider(
new cryptix.jce.provider.CryptixCrypto() );
java.security.Security.addProvider(
new cryptix.openpgp.provider.CryptixOpenPGP() );
KeyBundle bundle = null;
MessageFactory mf = null;
try {
FileInputStream in = new FileInputStream("secretkey.asc");
mf = MessageFactory.getInstance("OpenPGP");
Collection msgs = mf.generateMessages(in);
KeyBundleMessage kbm = (KeyBundleMessage)msgs.iterator().next();
bundle = kbm.getKeyBundle();
in.close();
} catch (IOException ioe) {
System.err.println("IOException... You did remember to run the "+
"GenerateAndWriteKey example first, right?");
ioe.printStackTrace();
System.exit(-1);
} catch (NoSuchAlgorithmException nsae) {
System.err.println("Cannot find the OpenPGP MessageFactory. "+
"This usually means that the Cryptix OpenPGP provider is not "+
"installed correctly.");
nsae.printStackTrace();
System.exit(-1);
} catch (MessageException me) {
System.err.println("Reading keybundle failed.");
me.printStackTrace();
System.exit(-1);
EncryptedMessage em = null;
try {
FileInputStream in = new FileInputStream("C:\\Java\\enc_dec\\pgptestin.pgp");
Collection msgs = mf.generateMessages(in);
em = (EncryptedMessage)msgs.iterator().next();
in.close();
} catch (IOException ioe) {
System.err.println("IOException... You did remember to run the "+
"Encrypt example first, right?");
ioe.printStackTrace();
System.exit(-1);
} catch (MessageException me) {
System.err.println("Reading message failed.");
me.printStackTrace();
System.exit(-1);
try {
     // System.out.println(em);
      // if fails after the below statement
Message msg = em.decrypt(bundle,"password".toCharArray());
PGPSignedMessage pmsg = (PGPSignedMessage)msg;
LiteralMessage lmsg = (LiteralMessage)pmsg.getContents();
FileOutputStream out = new FileOutputStream("C:\\Java\\enc_dec\\pgptestout.txt");
out.write(lmsg.getTextData().getBytes());
out.close();
} catch (NotEncryptedToParameterException netpe) {
System.err.println("Not encrypted to this key.");
netpe.printStackTrace();
System.exit(-1);
} catch (UnrecoverableKeyException uke) {
System.err.println("Invalid passphrase.");
uke.printStackTrace();
System.exit(-1);
} catch (MessageException me) {
System.err.println("Decrypting message failed.");
me.printStackTrace();
System.exit(-1);
} catch (IOException ioe) {
          System.err.println("Writing the decrypted message failed.");
          ioe.printStackTrace();
          System.exit(-1);
Here are the error messages:
Exception in thread "main" java.lang.RuntimeException: NYI
     at cryptix.jce.provider.elgamal.ElGamalCipher.engineGetParameters(ElGamalCipher.java:120)
     at javax.crypto.Cipher.a(DashoA12275)
     at javax.crypto.Cipher.init(DashoA12275)
     at javax.crypto.Cipher.init(DashoA12275)
     at cryptix.openpgp.algorithm.PGPElGamal.decrypt(PGPElGamal.java:612)
     at cryptix.openpgp.packet.PGPPublicKeyEncryptedSessionKeyPacket.decrypt(PGPPublicKeyEncryptedSessionKeyPacket.java:189)
     at cryptix.openpgp.provider.PGPEncryptedMessageImpl.decrypt(PGPEncryptedMessageImpl.java:186)
     at cryptix.openpgp.provider.PGPEncryptedMessageImpl.decrypt(PGPEncryptedMessageImpl.java:315)
     at cryptix.openpgp.examples.Decrypt.main(Decrypt.java:118)
Message was edited by:
eidasharif
Message was edited by:
eidasharif
Message was edited by:
eidasharif
Message was edited by:
eidasharif
Message was edited by:
eidasharif
Message was edited by:
eidasharif
Message was edited by:
eidasharif
null

You have to download and install something called "Unlimited strength jurisdiction policy files 5.0", is the solution por the NYI (Not Yet implemented) problem. It worked in my case (you can download the file from Sun, and read the readme to know how to install it)

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regards
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>
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HT5077 Decryption of Encrypted hfs+ using Lion OS X

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