I need help please if you can aid me in my quest to write this code

Question

I am trying really hard to accomplish this and my head hurts from trying mulitple ideas on the right code.A lottery requires that you select six different numbers from the integers 1 to 49. Write a Java program that will do this for you and generate five sets of six numbers as a result.
Details:
For generating random numbers you can use the random() static method of class Math. It returns a double so you will need to cast it as an integer. If you set the range to 49, you can generate a random number between 1 and 49 through:
number = (int) ( range * Math.random() ) + 1;
Note that you need 5 sets of numbers and in each set you have should have six different numbers. There should not be duplicate numbers within each set. Of course the same number can occur in multiple sets, but within the same set of 6 numbers it should only occur once, if at all.
Here is an example of a valid set of numbers: 5, 41, 3, 9, 22, 30
Here is an example of an invalid set of numbers: 15, 8, 19, 33, 8, 21
It is invalid because the number 8 appears twice.
This is the dilema the code I have so far (I know it is not much) is import java.util.Scanner;
import java.util.Random;
public class Lottery
public static void main(String[] args)
          int[] numbers = new int[6];
number = (int) (range 49 Math.random() ) + 1;
am I on the right track totally wrong or???? Please help me and god bless

Answer 1

Tinkerbell... wrote:
Navy_Coder wrote:
Tinkerbell... wrote:
Navy_Coder wrote:
Yeahhhhh, don't do that...Why not?because you butchered an otherwise simple process by the whole generic list with 50 numbers and sorting mess.
java.util.Random. <-- learn how to use it.Well, please explain how you would better do it using java.util.Random then?
Random r = new Random();
int[] vals = new int[6];
for(int i = 0; i < vals.length; i++ )
    vals[i] = (r.nextInt(49) + 1);