I need to send a group of files in a zip file. How do I do that?

I have Microsoft Office for MAC and send to send a group of files. I would like to compress them into a zip file. Is there a way to do that with my MAC?

Select all the files, control-click any one of them, and compress them.
(64471)

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Ok, I don't know why I am here, but!
I have built a slideshow in iPhoto -- I need/want the file in .mp4 format. How do I do that?
The question may have been answered somewhere but I was sent here -- so her I am.
Still I think I need my slideshow in .MP4 format to play on windows/smartTVs and the .m4v file that export offers seems to be the only option and it fails.
I am using iPhoto v9.5.1 on a Macbook Air.
help.

Try changing the extension to .m4v and see if that will do the trick. It did for me on another occasion where it wouldn't play as .MP4. If it works it's a simple solution.
I compared an .m4v and an .MP4 file in Qujicktime Player via the Winde ➙ Show Movie Inspector menu and both were the same codec:
H.264, 1280 × 720, Millions
AAC, Stereo (L R), 44.100 kHz
Check to see what codec the Movie Inspector window shows.
OT

Adding a file into existing zip file

I need a add a file into existing zip file. and write into printwriter.
How to do it?
Waiting for the reply.
Thanks and Regards,
Narayanan. G

Narayanan.G wrote:
I need a add a file into existing zip file.API: [ZipOutputStream#putNextEntry()|http://java.sun.com/javase/6/docs/api/java/util/zip/ZipOutputStream.html#putNextEntry%28java.util.zip.ZipEntry%29]
Tutorial: [http://java.sun.com/developer/technicalArticles/Programming/compression/].
and write into printwriter.Writing a zip file into printwriter? Huh? Please elaborate.

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I've got code that successfully processes a file within a zip file.
But now the zip file can also contain other zip files. How can I
process a zip nested within a zip without actually extracting the
files? It looks like I need a ZipFile object to be able to take
advantage of the zip classes for reading zip entries. But the
ZipFile methods want as an argument an actual file, as opposed
to some object in memory. I can read the 'inner' zip file into a
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I have successfully done it.
You cannot have the code - it is proprietary.
However here are a few pointers:
o Use ZipStreams rather than ZipFile.
o ZipStream is just a filter on a stream, so you can have a zipstream open, read a ZipEntry, then ask for a substream for the stuff up to the next ZipEntry. Put a second ZipStream on that substream.
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Hope this helps.

How to find if the uloaded file is a zip file

Hello everyone,
I am currently implementing a filter in my code where I put a restriction that allows only a certain type of files to be accepted. One of them is the zip file type.
However, when I tried to read the mimetype of this zip file using the folloing API :
IWDResource.getResourceType().getHtmlMime(),
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Hi Dhruwat
there is a java-api called [truezip|https://truezip.dev.java.net]
in which you will find the following class ZipDetector, and the method "isZipFile".
[https://truezip.dev.java.net/javadoc-5/de/schlichtherle/io/ZipDetector.html#isZipFile(java.lang.String)]
Or something other but i don't know if you can find out that.
Every (regular) zip has the encoding "CP437". Maybe you can
check the outputstreams-encoding..?
Regards

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Dear Experts ,
I finded out the way to extrcat pdf files in presentation server. But now my problem is that I am not able to add multiple pdf files in a zip file. When I am adding new pdf file then older one is not coming in read data set. So please kindly tell me how can I add multiple pdf file in my zip file and again I can get all the pdf files from here.

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http://remotepsadmins.com/2013/03/04/peoplesoft-unified-navigation-with-peoplesoft-applicatations-portal-interaction-hub/

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Reading a Compressed File from a ZIP File, which is an entry of ZIP File

Hello, Experts,
Would it be possible somebody to help me with code example for the following problem?
I want to read a compressed file from a ZIP file, which is an entry of ZIP File, without extacting/writing files on file system. Is this possible?
Lets say we have a ZipFile1. There is ZipFile2 inside ZipFile1. And inside ZipFile2 is FileA. The scenario is reading FileA without extracting on file system.
Thank you in advance for your help.
Cheers
RADY

The classes you want to be using are java.util.zip.ZipInputStream and and ZipEntry from the same package. Construct the ZipInputStream with the input you have for the outer zip. Loop with ZipInputStream.getNextEntry until you find the inner zip you're looking for - that method returns a ZipEntry, and you get the name of the zip entry with ZipEntry.getName. Read the ZipInputStream from that point into some buffer, and read that buffer into a new ZipInputStream - rinse and repeat until you have the contents of the file in the zip in the zip...

Problem with compressing unicode file names in zip file

Hi Everyone,
I have a problem while compressing the unicode file name in a zip file. I used the below code for compressing the unicode files.
String[] source = null;
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source = new String[] {"C:\\TestData\\temp_properties.xml","C:\\TestData\\unicode_filename.txt" };
byte[] buf = new byte[1024];
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ZipOutputStream out = new ZipOutputStream(new FileOutputStream(target));
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for (int i = 0; i < source.length; i++)
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     File tempFile;
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zipEntry = new ZipEntry(fileName);
zipEntry.setMethod(ZipEntry.DEFLATED);
getUTF8Bytes(source[i]);
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out.putNextEntry(zipEntry);
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int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
// Complete the entry
out.closeEntry();
in.close();
// Complete the ZIP file
out.close();Please help me how to fix this issue.
Thanks

Hi,
Thanks for your time for looking into my query.
Please check the below code for debugging the issue and throw your comments/suggestions for fixing the issue.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipTest
public static void main(String[] args) {
          String[] source = new String[] {"C:\\TestData\\APP_Properties.xml","C:\\TestData\\??.txt" };
          byte[] buf = new byte[1024];
          try {
               // Create the ZIP file
               String target = "C:\\TestData\\target.zip";
               ZipOutputStream out = new ZipOutputStream(new FileOutputStream(target));
               // Compress the files
               for (int i = 0; i < source.length; i++) {
                    FileInputStream in = new FileInputStream(source);
                    // Add ZIP entry to output stream.
                    String fileName;
                    File tempFile;
                    ZipEntry zipEntry = new ZipEntry(source[i]);
                    fileName = zipEntry.getName();
                    zipEntry = new ZipEntry(fileName);
                    zipEntry.setMethod(ZipEntry.DEFLATED);
                    getUTF8Bytes(source[i]);
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                    int len;
                    while ((len = in.read(buf)) > 0) {
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                    out.closeEntry();
                    in.close();
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               out.close();
          } catch (IOException e) {
               e.printStackTrace();
     private static byte[] getUTF8Bytes(String s) {
          char[] c = s.toCharArray();
          FileOutputStream file;
          try {
               file = new FileOutputStream("C:\\TestData\\output.txt", true);
               int len = c.length;
               // Count the number of encoded bytes...
               int count = 0;
               for (int i = 0; i < len; i++) {
                    int ch = c[i];
                    if (ch <= 0x7f) {
                         count++;
                    } else if (ch <= 0x7ff) {
                         count += 2;
                    } else {
                         count += 3;
               // Now return the encoded bytes...
               byte[] b = new byte[count];
               int off = 0;
               for (int i = 0; i < len; i++) {
                    int ch = c[i];
                    if (ch <= 0x7f) {
                         b[off++] = (byte) ch;
                         file.write((byte) ch);
                    } else if (ch <= 0x7ff) {
                         b[off++] = (byte) ((ch >> 6) | 0xc0);
                         file.write((byte) ((ch >> 6) | 0xc0));
                         b[off++] = (byte) ((ch & 0x3f) | 0x80);
                         file.write((byte) ((ch & 0x3f) | 0x80));
                    } else {
                         b[off++] = (byte) ((ch >> 12) | 0xe0);
                         file.write((byte) ((ch >> 12) | 0xe0));
                         b[off++] = (byte) (((ch >> 6) & 0x3f) | 0x80);
                         file.write((byte) (((ch >> 6) & 0x3f) | 0x80));
                         b[off++] = (byte) ((ch & 0x3f) | 0x80);
                         file.write((byte) ((ch & 0x3f) | 0x80));
               file.write((byte) '\n');
               file.write((byte) '\r');
               file.flush();
               file.close();
               return b;
          } catch (FileNotFoundException e1) {
               e1.printStackTrace();
          } catch (IOException e1) {
               e1.printStackTrace();
          return null;
}Thanks
Aravind

How to zip multi files into one zip file in ABAP

hi all:
As you know, ABAP has CL_ABAP_GZIP class to support zip file function. But it only support one file zip. If I want to zip two files into one zip file, how to do it?
thanks.

Hi,
<li>If you know how to zip one file, to zip two files , you can follow the below steps.
DATA:g_zipper     TYPE REF TO cl_abap_zip.
"create our zipper object
CREATE OBJECT g_zipper.
"add 1st file to zip
CALL METHOD g_zipper->add
   EXPORTING
     name    = file_name
     content = content_x.
"add 2nd file to zip
CALL METHOD g_zipper->add
   EXPORTING
     name    = file_name
     content = content_y.
"save zip
CALL METHOD g_zipper->save
   RECEIVING
     zip = zip.
Thanks
Venkat.O

How to read/unzip a specific file within a zip file

Hi,
I have a file within a zip file that contains a timestamp - I want to read this timestamp and then create a destination directory for the remaining zip files to be unzipped into. Since I know the name of the file with the timestamp in it I thought I could create a zipfile and use getEntry to get the entry but then other than getting the size and name of the file I can't do much more with it like read it unless I use a stream (zipinputstream) instead of a file (zipfile) - do I have this right?
Does this mean to get the content I would have to loop through possibly all the files using the stream until I come across the one I want - then get the timestamp and loop through them all again to write them to the destination directory? Or am I reading this wrong - seems a bit round about.
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Thanks

this works though - and you don't have to loop through all the files - just use the ZipFile:
ZipEntry ze = zipfile.getEntry("path/to/file");
BufferedReader br = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
line = br.readLine;Thanks!

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Install Lightroom the same way you did the first time. Then follow these instructions on how to move your collection of images and your catalog.
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