I subtract two dates and have total seconds. How to convert seconds to.....

days/hours/minutes/seconds.
Does anyone know how to convert a # that equals total seconds to days/hours/minutes/seconds??
Thanks as always
Adam

i guess you can mod the number with 360 first and get the number of days, then get the remainder and mode by 60 get the hour and so forth, maybe a better way is using recursive function to return you a final result. Hopefully this will help, don't complain on me if I am misleading you since this is my first time try to help.

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Hi Friends
I have to subtract two dates and get the difference in months. Here's the sample data:
select DATE '2009-10-01' Date_value, 111 Cust_id, DATE '2009-10-22' Open_date from dual
union all
select DATE '2009-10-01', 112 , DATE '2009-10-15' from dual
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select DATE '2009-11-01', 113 ,DATE '2009-10-22' from dualAnd here’s my query to get the difference in month:
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113     1/10/2009     5/10/2009     0
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113     1/11/2009     22/10/2009     0Ideally, the output should be as per the following:
CUST_ID     DATE_VALUE     OPEN_DATE     DIFF_IN_MONTHS
111     1/10/2009     22/10/2009     0
112     1/10/2009     15/10/2009     0
113     1/10/2009     5/10/2009     0
111     1/11/2009     22/10/2009     1
112     1/11/2009     15/10/2009     1
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Hi Centinul
Found the resolution. When I use the following query, I get the perfect result:
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FROM tAnd here's the output of all three columns:
CUST_ID     DATE_VALUE     OPEN_DATE     MONTHS     DIFF_IN_MONTHS     FINAL_VAL
111     1/10/2009     22/10/2009     1     1     0
112     1/10/2009     15/10/2009     0     0     0
113     1/10/2009     5/10/2009     0     0     0
111     1/11/2009     22/10/2009     0     0     1
112     1/11/2009     15/10/2009     1     1     1
113     1/11/2009     22/10/2009     0     0     1

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I subtract two dates and have total seconds. How to convert seconds to.....

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