Image from a URL database record

Question

Hi
I am building an online catalog usual stuff product name, link, price, image etc
the product link and image are on another server url's are datatbade cells
no problem with the product link using <td><p><a href="<?php echo $row_Recordset1['productUrl']; ?>" target="_new"> click for more</a></p></td>
But I am having problem with the image have tried
<td><img src="<a href="<?php echo $row_Recordset1['imageUrl']; ?>" ></td>
   <?php echo $row_Recordset1['description']; ?></td>
but just get an image placeholder box even when uploaded to server and previewed in browser
the whole details are
<table border="1">
  <tr>
    <td>name</td>
    <td>productUrl</td>
    <td>imageUrl</td>
    <td>description</td>
  </tr>
  <?php do { ?>
    <tr>
      <td><?php echo $row_Recordset1['name']; ?></td>
      <td><p><a href="<?php echo $row_Recordset1['productUrl']; ?>" target="_new"> click for more</a></p></td>
      <td><img src="<a href="<?php echo $row_Recordset1['imageUrl']; ?>" ></td>
   <?php echo $row_Recordset1['description']; ?></td>
    </tr>
    <?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?>
</table>
Thank you

Answer 1

You have a href in your image src... I've never seen that before, so I wouldn't know if it's correct syntax.
Change:
<td><img src="<a href="<?php echo $row_Recordset1['imageUrl']; ?>" ></td>
to:
<td><img src="<?php echo $row_Recordset1['imageUrl']; ?>" ></td>
and if you want the image to be clickable:
<td><a href="url-here" border="0"><img src="<?php echo $row_Recordset1['imageUrl']; ?>" ></a></td>