Importing XML with html style tags

I have an xml with an element <description> that contains some styling like, <em> or <b>. What do I need to do in order for me to import the xml into ID and see the italicized words?
I appreciate any help.

Similar Messages

XML with HTML Tags... (easy points) 11g question

Dear Programming Gods,
I have been researching this for about 2 weeks now, and I have hit the final road block.
Using BI Publisher 11.1.1
In APEX 4.0 I have a Rich Text Field. The data from the Rich Text Field is store in CLOB. The data has HTML formatting tags. I have a data model that selects the data. I create an xml which has the html tags. I export the xml and import it into MS Word using the BI Publisher add-in. I import my subtemplate which handles almost all of the formatting tags. I apply the template to the CLOB field so that the HTML formatting tags will be rendered when printed.
The problem is this. The subtemplate is looking for this < and / > however BI publisher convters the tags stored in the CLOB from raw html tags to this &.lt; and &.gt; so the subtemplate can not match to it.
Here is what I need to figure out and please explain it in very novice terms.
When I generate and export the XML from BI Publisher how do I prevent it from converting my raw tags?
Here is some further assistance when prepairing your answer.
My subtemplate is based on the htmlmarkup.xsl from the following blog but has been modified heavily to include support for simple tables, more formatting such as subscripts and superscripts, ect...
http://blogs.oracle.com/xmlpublisher/2007/01/formatting_html_with_templates.html
I am also familliar with this blog but I do not understand how to implement it using BI 11g.
http://blogs.oracle.com/xmlpublisher/2009/08/raw_data.html
I have tried adding this to my layout but it doesnt seem to work.
<xsl: element name="R_CLOB" dataType="xdo:xml" value="R_CLOB" / >
Please, help me. I have to have this working in 4 days.
Richard

This did not work either. Here's more infor on what I have so far.
My data template looks like this:
<dataTemplate name="Data" description="Template">
     <parameters>
          <parameter name="p_person_id" dataType="character" defaultValue="1"/>
     </parameters>
     <dataQuery>
          <sqlStatement name="Q1">
                              select TEMPORARY_TEMPLATE_DATA.line_id as LABEL_line_ID,
TEMPORARY_TEMPLATE_DATA.column_id as LABEL_column_ID,
TEMPORARY_TEMPLATE_DATA.person_id as LABEL_PERSON_ID,
TEMPORARY_TEMPLATE_DATA.label as LABEL_DATA
from MY_BIO.clm_TEMPORARY_TEMPLATE_DATA TEMPORARY_TEMPLATE_DATA
Where person_id = :p_person_id
and style = 'L'
                         </sqlStatement>
          <sqlStatement name="Q2" parentQuery="Q1" parentColumn="LABEL_DATA">
                              select TEMPORARY_TEMPLATE_DATA.LINE_ID as LINE_ID,
TEMPORARY_TEMPLATE_DATA.COLUMN_ID as COLUMN_ID,
TEMPORARY_TEMPLATE_DATA.label as COLUMN_LABEL,
to_nclob(TEMPORARY_TEMPLATE_DATA.COLUMN_DATA) as COLUMN_DATA,
TEMPORARY_TEMPLATE_DATA.STYLE as STYLE,
TEMPORARY_TEMPLATE_DATA.ATTRIBUTE as ATTRIBUTE,
NVL(TEMPORARY_TEMPLATE_DATA.JUSTIFY,'L') as JUSTIFY
from MY_BIO.clm_TEMPORARY_TEMPLATE_DATA TEMPORARY_TEMPLATE_DATA
Where person_id =:p_person_id
and label = :LABEL_DATA
and style != 'L'
Order by line_id, column_id
                         </sqlStatement>
     </dataQuery>
     <dataStructure>
          <group name="G_LABEL" source="Q1">
               <element name="LColumnData" value="label_data"/>
               <group name="G_DATA" parentGroup="G_Label" source="Q2">
                    <element name="LineID" value="line_id"/>
                    <element name="ColumnID" value="column_id"/>
                    <element name="ColumnData" value="column_data"/>
                    <element name="Style" value="style"/>
                    <element name="Attribute" value="attribute"/>
                    <element name="Justify" value="justify"/>
               </group>
          </group>
     </dataStructure>
</dataTemplate>
After running this data_template there was no change in the xml file generated see partial : Note:
my test actually has the B with the html tags
</G_DATA>
- <G_DATA>
<LINEID>20</LINEID>
<COLUMNID>1</COLUMNID>
<COLUMNDATA>test test <B>my test</B></COLUMNDATA>
<STYLE>R</STYLE>
<ATTRIBUTE />
<JUSTIFY>C</JUSTIFY>
</G_DATA>
- <G_DATA>
<LINEID>21</LINEID>
I loaded in to MS Word but there was no change documnet still look the same. I left the commands import file command and xsl:apply-templates command in the word document template.
I really appreciate you helpiing me.
cheryl

Importing xml with xslt in InDesign CS4

Hello All,
i need someone's help who's an expert at xml and xslt features of InDesign CS4.
i work in publication, besides our magazines we produce yearbooks with lots of repetative information fields in them. we get the data in xml fromat which we flow in to InDesign. the xml files are very simple, here's an example:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<Root>
<Story>
      <Country> Afganistan </Country>
<Company_ID>
   <Company_Name> Kam Air </Company_Name>
   <Company_Code> 1 </Company_Code>
   <Address_text> 1205 Qalla Fatuha </Address_text>
   <Address_text> P.O.Box 456 </Address_text>
   <Address_text> Kabul </Address_text>
   <Address_text> 22004 </Address_text>
   <Address_text> Afganistan </Address_text>
   <Telephone_text> Telephone: +93 20 2200 108 </Telephone_text>
   <Fax_text> Fax: +93 20 2200 110 </Fax_text>
   <Email_text> E-mail: [email protected] </Email_text>
   <Website_text> Website: www.flykamair.com </Website_text>
   <Personel_text> Abdul Raquib, chief Executive <Personel_text>
   <Personelmail_text> ([email protected]) </Personelmail_text>
   <Job_code> A1 </Job_code>
</Company_ID>
     <Country> Albania </Country>
etc.
</Story>
</Root>
the problem is we don't want <Company_Code> and <Job_code> elements displayed in the InDesign file.
so we created an xslt file that shoud get rid of these two unwanted elements (obviously the xml file above was pointed to this xslt file)
<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
<Root>
<Story>
<Country>
<xsl:for-each select="Company_ID">
   <Company_ID>
      <xsl:value-of select="Company_Name"/>
      <xsl:value-of select="Address"/>
      <xsl:value-of select="Telephone_text"/>
      <xsl:values-of select="Fax_tex"/>
      <xsl:value-of select=Email_text"/>
      <xsl:value-of select="Website_text"/>
      <xsl:value-of select="Personel_text"/>
      <xsl:value-of select="Pesronelmail_text"/>
   </Company_ID>
</xsl:for-each>
</Story>
</Root>
</xsl:template>
</xsl:stylesheet>
but it doesn't work. could someone tell me what's wrong with the xslt file? or what would the correct xslt file look like?
Thanks everyone!

Here's the sort of thing I mean in more detail.
First, the XML file:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<?xml-stylesheet type="text/xsl" href="transform2.xsl"?>
<Root>
<Country>
<Country_name>Afganistan</Country_name>
<Company_ID>
   <Company_Name> Kam Air </Company_Name>
   <Company_Code> 1 </Company_Code>
   <Address_text> 1205 Qalla Fatuha </Address_text>
   <Address_text> P.O.Box 456 </Address_text>
   <Address_text> Kabul </Address_text>
   <Address_text> 22004 </Address_text>
   <Address_text> Afganistan </Address_text>
   <Telephone_text> Telephone: +93 20 2200 108 </Telephone_text>
   <Fax_text> Fax: +93 20 2200 110 </Fax_text>
   <Email_text> E-mail: [email protected] </Email_text>
   <Website_text> Website: www.flykamair.com </Website_text>
   <Personel_text> Abdul Raquib, chief Executive </Personel_text>
   <Personelmail_text> ([email protected]) </Personelmail_text>
   <Job_code> A1 </Job_code>
</Company_ID>
<Company_ID>
   <Company_Name> Another Company </Company_Name>
   <Company_Code> 2 </Company_Code>
   <Address_text> Elswhere</Address_text>
   <Address_text> P.O.Box 123</Address_text>
   <Address_text>Another City</Address_text>
   <Address_text> 22005 </Address_text>
   <Address_text> Afganistan </Address_text>
   <Telephone_text> Telephone: +12345678 </Telephone_text>
   <Fax_text> Fax: +12345678 </Fax_text>
   <Email_text> E-mail: [email protected] </Email_text>
   <Website_text> Website: www.dfhdfh.com </Website_text>
   <Personel_text> dfhdfhdfhdfhdfh</Personel_text>
   <Personelmail_text>dfhdfhdfhdfh</Personelmail_text>
   <Job_code> A2 </Job_code>
</Company_ID>
</Country>
     <Country>
<Country_name>Albania</Country_name>
<Company_ID>
   <Company_Name> Number 3 </Company_Name>
   <Company_Code>3</Company_Code>
   <Address_text>Somewhere in Albania</Address_text>
   <Address_text>Freedonia Avenue</Address_text>
   <Address_text>Whatever the captial of Albania is called</Address_text>
   <Address_text> 88888</Address_text>
   <Address_text> Albania </Address_text>
   <Telephone_text> Telephone: + 666 666 666 666 </Telephone_text>
   <Fax_text> Fax: + 777 777 777 777</Fax_text>
   <Email_text> E-mail: [email protected] </Email_text>
   <Website_text> Website: www.albaniar.com </Website_text>
   <Personel_text>Ludwig Wittgenstein, chief Executive </Personel_text>
   <Personelmail_text> ([email protected]) </Personelmail_text>
   <Job_code> A1 </Job_code>
</Company_ID>
</Country>
</Root>
Note that I have renamed the XSL file "transform2.xsl". I have got rid of the "Story" tag, and I have nested the tags more appropriately, with a new tag "Country_name". Here's the XSL:
<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
<Root>
<xsl:for-each select="/Root/Country">
<Country>
<Country_name><xsl:value-of select="Country_name"/></Country_name>
<xsl:for-each select="Company_ID">
<Company_Name><xsl:value-of select="Company_Name"/></Company_Name>
<Address_text><xsl:value-of select="Address_text"/></Address_text>
<Telephone_text><xsl:value-of select="Telephone_text"/></Telephone_text>
<Fax_text><xsl:value-of select="Fax_text"/></Fax_text>
<Email_text><xsl:value-of select="Email_text"/></Email_text>
<Website_text><xsl:value-of select="Website_text"/></Website_text>
<Personel_text><xsl:value-of select="Personel_text"/></Personel_text>
<Personelmail_text><xsl:value-of select="Personelmail_text"/></Personelmail_text>
</xsl:for-each>
</Country>
</xsl:for-each>
</Root>
</xsl:template>
</xsl:stylesheet>
(That file should be saved as "transform2.xsl" to match the link on line 2 of the XML.)
Hope that works -- Jeremy

Importing XML - white spaces before tags

Hello,
I'm importing XML into an inDesign document. Everything imports fine but I get extra spaces whenever there is a paragraph return. How could I get rid of those extra white spaces? I don't want to go and edit out all those white spaces by hand....
Thanks for your help.

Hello,
Your issue looks like the one described in this page:
http://www.xmlplease.com/normalized
For reference purposes, here is the link for the supported schema and wsdl in PI 7.1
http://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/00a9a425-1769-2a10-9196-bd8eeed72e4c
As a temporary work around, you can try editing the xsd by removing the spaces before importing it into PI.
Hope this helps,
Mark

Parsing XML with html tags for style

I'm using flash to pull in XML data, but I want to use html
tags to be able to style the text. When I add any html, it treats
it as a sub-node and ignores the data. Also, line breaks in the xml
are being converted to double spaced paragraphs? The relevant code
is basically this:
if (element.nodeName.toUpperCase() == "TEXT")
{//add text to text array
ar_text[s]=element.firstChild.nodeValue;
textbox1.text = ar_text[0];

try to use htmlText instead text... like this:
textbox1.htmlText = ar_text[0]
adam

Export/import text with all styles (indesign CS3 (XP SP2))

I'm looking for the best way to export text so authors can edit their text using MS Word, Excel or xml. (they don't want to use Indesign). after they are done editting I want to import the text back into Indesign (with par, char, obj styles).
I know how to import/export to .doc with styles, but this doesn't work for table, object styles, and page breaks.
Xml tags or plugin/software might be a solution.
I've searched the forums, google and read the help file, but still don't know what the best/quickest solution might be. ... ?
thanks in advance

1. Those programs don't support every feaature of InDesign, so you are out of luck.
2. If they don't want to use InDesign, ask them to use InCopy, that is the only one programm which supports the whole InDesgin-functionlity
3. Page breaks should never be done manually, never in Word, neither with InDesign. They should be created via paragraph styles in both program, but with the import options is a checker to get Word's page breaks.

Importing RSS with HTML in AS3

I succesfully imported RSS in Flash... now in flash i have
<title>
<link>
and <description>
I want to Display in a List component the Title and the Description, and on click a textfield displays the HTML text grabbed from the Link...
Here's my code
var rssLoader:URLLoader = new URLLoader();
    var rssURL:URLRequest =
         new URLRequest("http://www.parliamocidicalcio.it/rss/xml/RSS2.0/category/34-seriea.html");
    rssLoader.addEventListener(Event.COMPLETE, rssLoaded);
    rssLoader.load(rssURL);
    var rssXML:XML = new XML();
    rssXML.ignoreWhitespace = true;
    function rssLoaded(evt:Event):void {
        rssXML = XML(rssLoader.data);
        for(var item:String in rssXML.channel.item) {
            liLog.addItem(
                      {label: rssXML.channel.item[item].pubDate.substr(0, 16) +
                    ": " + rssXML.channel.item[item].description } );
    function selectLog(evt:Event):void {
        var list:XMLList =
                    rssXML.channel.item[evt.target.selectedIndex ].children();
   var item:XML;
        for(var i = 0; i<list.length(); i++)
            if(list[i].name() == "description")
            { i++; break; }
    item = list[i].children()[0];
    var LinkLoader:String = rssXML.channel.item[evt.target.selectedIndex].link;
    var textLoader:URLLoader = new URLLoader();
    var textReq:URLRequest = new URLRequest(LinkLoader);
    textLoader.load(textReq);
        taLog.htmlText = textLoader.data;
        //taLog.htmlText = item.toString();
    liLog.addEventListener(Event.CHANGE, selectLog);
    liLog.rowHeight = 90;
And there's another problem... the <description> contains an <img src="xxx">... AS doesn't read HTML so it displays the code... is there a solution to remove <img src"xx"> from <description> when importing in flash? And to remove it and display the image?

Yout cannot put an iframe into a Flash file.
Dan Smith > adobe community expert
Flash Helps >
http://www.smithmediafusion.com/blog/?cat=11
twitter:
http://twitter.com/dmode
"tziady" <[email protected]> wrote in
message
news:g58bqj$o0q$[email protected]..
> Hello all; I am looking to embed a google calendar into
a flash file. Has
> anyone attempted this successfully. The embedding code
looks like this:
>
> <iframe
> src="
http://www.google.com/calendar/embed?src=40j2e2qt3efr2rblk8r08fv530%40group
> .calendar.google.com&ctz=America/New_York"
style="border: 0" width="800"
> height="600" frameborder="0"
scrolling="no"></iframe>
>
> Any help with this problem would be greatly appreciated.
>
> Cheers
> Tamer
>

Having problems passing more than one parameter with html:link tag

Hi guys,
for my web application I�m using Struts. I�ve got a database with user details. I would like to get users list and link to the details of each user. I wrote the code and everything is working fine only the users list is repeating as many times as users in the list.
For ex: I have in the database User1, User2 and User3. I would like to have a result like:
User1
User2
User3
Instead of it I have the result like:
User1
User2
User3
User1
User2
User3
User1
User2
User3
What I�m doing wrong? Could somebody help me please?
Thank you in advance
There is a snippet of the code, which I�m using in jsp:
<code>
<logic:iterate id="root" name="user">
               <%
                    java.util.HashMap users = new java.util.HashMap();
                    params.put("user",root);
                    pageContext.setAttribute("usersName", users);
               %>
               <html:link name=" usersName " scope="page" page="/name.do">
                    <logic:iterate id="folder" name="user">
                         <bean:write name="folder" /><br>
                    </logic:iterate>
               </html:link><br>
               </logic:iterate>
</code>

Suggestion: next time you post code use the "CODE" button to put code tags around it. It formats much nicer that way :-)
You have a nested loop structure here.
<logic:iterate id="root" name="user">
<%
    java.util.HashMap users = new java.util.HashMap();
    params.put("user",root);
    pageContext.setAttribute("usersName", users);
%>
<html:link name=" usersName " scope="page" page="/name.do">
    <logic:iterate id="folder" name="user">
      <bean:write name="folder" /><br>
    </logic:iterate>
</html:link><br>
</logic:iterate>Both loops iterate over your "user".
Your first loop loops over each user.
Then your second loop also loops over each user - hence you get number of users * number of users = 3 groups of 3.
If you have 4 users, you would have 4 groups of 4.
I only see you setting one parameter: "usersName" What other parameters do you need to pass?
At a guess, the inner loop is unnecessary, and you want to write the users name as the text for the link, and also use it as a link parameter.
<logic:iterate id="root" name="user">
<%
    java.util.HashMap users = new java.util.HashMap();
    params.put("user",root);
    pageContext.setAttribute("usersName", users);
%>
<html:link name="usersName" scope="page" page="/name.do">
      <bean:write name="user" /><br>
</html:link><br>
</logic:iterate>

Automate create xml with HTML blocks

Hi,
I have to base on certain trigger, database query result
create an XML file.
In the XML file I'm passing an HTML page. I have the HTML
page saved on the
local server.. page1.html, page2.html etcs..
Any suggestions on how I can do this would be greatly
appreciated. This will
need to be an automate process... which I can do.. but the
actual creating
the XML file, I'm not sure about.
Thanks in advance!

Thanks for your reply... the XML that i need to create will
be like this?
<emailMessage>
<messagetype>Welcome</MessageTpye>
<Subject>Welcome</Subject>
<MessageContent>
<![CDATA[<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0
Transitional//EN"
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="
http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html;
charset=UTF-8" />
<title>test</title>
</head>
<body>
welcome to our site<br /> you are blah blah<br
/><br />
<p>blah blah</p>
<table><tr><td>whatever</td></tr></table>
</body>
</html>
]]>
</MessageContent>
</emailMessage>
The part thats in the CDATA are now indivual html files so i
want to take
the content of that html file and put it in the CDATA. i'm
not sure if
that's the best way to do it though... might be better to
store the HTML in
the DB and then write it out from there???
SUggestions?
"coffeedrinker56" <[email protected]> wrote
in message
news:[email protected]...
> I'm not certain that I understand what you're asking.
Creating an XML file
from
> a database is pretty easy stuff so I'm undoubtedly
misunderstanding the
> question(?):
> <cfquery name="abc" ...>
> Exec myStoredProcedure #myparam1#, '#myparam2#'
> </cfquery>
> <cfxml var="abc">
> <page>
> <html>
> <head>
> <title>abc example</title>
> <link rel="stylesheet" type="text/css"
href="css/default.css" />
> <script language="javascript" type="text/javascript"
src="abc.js" />
> </head>
> <body>
> <form name="pageForm" method="post"
action="javascript:checkForm();">
> <table ...>
> </table>
> </form>
> </body>
> </html>
> </page>
> </cfxml>
>
> If you choose to do so, you can display the XML like:
> <cfoutput>#abc#</cfoutput>
>
> ... or you can save the XML on your server as a file
using CFFILE.
>
> If your intention is solely to display the XML, you can
also use ...
> <cfcontent type="text/xml"><?xml version="1.0"
encoding="UTF-8" ?><abc>
> </abc>
>
> ... instead of the <cfxml> and </cfxml>
tags.
>
> [I use the latter form when passing data back and forth
between the
server and
> the client.]
>
>

How to import xml with data?

Excel 2013
i got an XML file generated by the GPinventory tool. when i import it into Excel, i only get the headers.
how can i import the data as well?

Hi,
As far as I know, the GPinventory tool Supported Operating System :Windows 2000, Windows Server 2003, Windows XP, I suppose it generated XML file with Excel 2003 schema, but Excel 2013 have a new XML schema. This issue usually caused by the XML scheme.
Please create a Excel 2013 schema XML file
to test with Excel 2013, if the file could be import well. We'd better check the generated XML file.
As a workaround, we'd better save the results as
a tab-delimited text file and then import to Excel 2013.
If this issue still exists, please upload the XML file through OneDrive. I want to test it.
Regards,
George Zhao
Forum Support
Come back and mark the replies as answers if they help and unmark them if they provide no help. If you have any feedback on our support, please click "[email protected]"

Importing xml with TOAD

Hi,
how to import table structure and data from xml file generated with Access 2003 using TOAD?

Hi,
how to import table structure and data from xml file generated with Access 2003 using TOAD?

Loading an XML with multiple nested tags

I've got some problems dealing with loading a nested tags XML file.
Let's suppose I have such a very simple myxml.xml file:
<ROWDATA>
<ROW>
<EMPNO>7369</EMPNO>
<ENAME>SMITH</ENAME>
   </ROW>
<ROW>
<EMPNO>7902</EMPNO>
<ENAME>FORD</ENAME>
</ROW>
</ROWDATA>
I can create the following table:
create table EMP
empno NUMBER(4) not null,
ename VARCHAR2(10),
and then inserting the XML file in this way:
insert into EMP
    (empno, ename)
select extractvalue (column_value, '/ROW/EMPNO'),
      extractvalue (column_value, '/ROW/ENAME'),
from   table
           (xmlsequence
          (extract
           (xmltype
             (bfilename ('MY_DIR', 'myxml.xml'),
               nls_charset_id ('AL32UTF8')),
             '/ROWDATA/ROW')))
so as to get inserted two rows into my table:
EMPNO   ENAME
7369         SMITH
7902         FORD
Now, and this is my question, let's suppose I have such a “more difficult” XML:
<ROWDATA>
<ROW>
<COMPANY>
    <EMPNO>7369</EMPNO>
    <ENAME>SMITH</ENAME>
    <EMPNO>1111</EMPNO>
    <ENAME>TAYLOR</ENAME>
</COMPANY>
</ROW>
<ROW>
<COMPANY>
   <EMPNO>7902</EMPNO>
   <ENAME>FORD</ENAME>
</COMPANY>
</ROW>
<ROW>
<COMPANY>
</COMPANY>
</ROW>
</ROWDATA>
In this case it seems to me things look harder 'cause for every row that I should insert into my table, I don't know how many “empno” and “ename” I'll find for each /ROW/COMPANY and so how could I define a table since the number of empno and ename columns are “unknown”?
According to you, in that case should I load the whole XML file in an unique XMLType column and than “managing” its content by using EXTRACT and EXTRACTVALUE built-in funcions? But this looks a very difficult job.
My Oracle version is 10gR2 Express Edition
Thanks in advance!

Here's a possible solution using a single pass through the XML data :
with sample_data as (
select xmltype(
    '<ROWDATA>
    <ROW>
      <COMPANY>
        <EMPNO>7369</EMPNO>
        <ENAME>SMITH</ENAME>
        <EMPNO>1111</EMPNO>
        <ENAME>TAYLOR</ENAME>
      </COMPANY>
    </ROW>
    <ROW>
      <COMPANY>
       <EMPNO>7902</EMPNO>
       <ENAME>FORD</ENAME>
      </COMPANY>
    </ROW>
</ROWDATA>'
) doc
from dual
select min(case when node_name = 'EMPNO' then node_value end) as empno
     , min(case when node_name = 'ENAME' then node_value end) as ename
from (
select trunc((rownum-1)/2) as rn
       , extractvalue(value(x), '.') as node_value
       , value(x).getrootelement() as node_name
from sample_data t
     , table(
         xmlsequence(extract(t.doc, '/ROWDATA/ROW/COMPANY/*'))
       ) x
group by rn ;
I would be cautious with this approach though, as I'm not sure the ROWNUM projection is entirely deterministic.
As Jason said, it's probably safer to first apply a transformation in order to get a more friendly format.
For example :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>
<xsl:template match="COMPANY">
    <xsl:apply-templates select="EMPNO"/>
</xsl:template>
<xsl:template match="EMPNO">
    <EMP>
      <xsl:copy-of select="."/>
      <xsl:copy-of select="following-sibling::ENAME[1]"/>
    </EMP>
</xsl:template>
</xsl:stylesheet>

I am not getting required output after importing xml file having HTML tags, MathML and Latex code

I created well formatted xml having html tags, MathML code and Latex code inside
XML with sample latex
<question>
    <p> 8. In this problem, <Image style="vertical-align: -9pt" title="5a\frac{7b}{3}" alt="5a\frac{7b}{3}" href="http://www.snapwiz.com/cgi-bin/mathtex.cgi?%205a%5Cfrac%7B7b%7D%7B3%7D%0A"></Image> and <Image href="http://www.snapwiz.com/cgi-bin/mathtex.cgi?%207b%5Cfrac%7B5a%7D%7B3%7D" style="vertical-align: -9pt" title="7b\frac{5a}{3}" alt="7b\frac{5a}{3}"> </Image>are both mixed numbers, like <Image src="http://www.snapwiz.com/cgi-bin/mathtex.cgi?%203%20%5Cfrac%7B1%7D%7B2%7D%20=%203.5" style="vertical-align: -9pt" title="3 \frac{1}{2} = 3.5" alt="3 \frac{1}{2} = 3.5"></Image>. The expression <Image style="vertical-align: -9pt" title="5a \frac{7b}{3} \ \times 7b \frac{5a}{3}" alt="5a \frac{7b}{3} \ \times 7b \frac{5a}{3}" href="http://www.snapwiz.com/cgi-bin/mathtex.cgi?%205a%20%5Cfrac%7B7b%7D%7B3%7D%20%5C%20%5Ctimes %207b%20%5Cfrac%7B5a%7D%7B3%7D"> </Image>is equal to which of the following choices? </p>
</question>
XML with sample html tags
<p>4. Examine the expression 3<i>k</i><sup>2</sup> + 6<i>k</i> - 5 + 6<i>k</i><sup>2</sup> + 2.</p><p>When it is simplified, which of the following is the equivalent expression?</p>
XML with sample MathML tags
<p>5. Find the vertex of the parabola associated with the quadratic function <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>y</mi><mo> </mo><mo>=</mo><mo> </mo><mo>-</mo><msup><mi>x</mi><mn>2</mn></msup><mo> </mo><mo>+</mo><mo> </mo><mn>10</mn><mi>x</mi><mo> </mo><mo>+</mo><mo> </mo><mn>4</mn></math></p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mo>-</mo><mn>5</mn><mo>,</mo><mo> </mo><mn>69</mn></mrow></mfenced></math><br>
    <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mn>5</mn><mo>,</mo><mo> </mo><mn>29</mn></mrow></mfenced></math><br>
    <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mn>5</mn><mo>,</mo><mo> </mo><mn>69</mn></mrow></mfenced></math><br>
    <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mo>-</mo><mn>5</mn><mo>,</mo><mo> </mo><mn>29</mn></mrow></mfenced></math>
None of the above works fine after importing xml to Indesign document/templete, it is not renderting equivalent out instead it is showing the same text inside tags in the Indesign document.
I have lot of content in our database, I will export to XML, import to Indesign, Indesign should render required output like what we see in the browser and export the output to printed format.
Import formated XML to indesign --> Export to Quality Print Format
Can any one guide me and let me know whether it is posible to do with Indesign, if so let me know in case if I am missing anything in importing xml and get required output.
Thanks in advance. Waiting for reply ASAP.

Possibly your expectations are too high. ... Scratch that "possibly".
XML, in general, cannot be "rendered". It's just an abstract data format. Compare it to common markup such as *asterisks* to indicate emphasized words -- e-mail clients will show this text in bold, but InDesign, and the vast majority of other software, does not.
To "render" XML, HTML, MathML, or LaTeX -- you seem to freely mix these *very* different markup formats, unaware of the fact that they are vastly different from each other! -- in the format you "expect", you need to apply the appropriate software to each of the original data files. None of these markup languages are supported natively by InDesign.

Unwanted Default Formatting with import XML

I have a problem of unwanted default formatting with import XML. Under InDesign CS6, I import XML with merge mode.
One frame is difficult to apply with the placeholder, I should put the XML element A inside by hand. InDesign automatically applies the character style of the child element B to the following text in element A.
I tried the steps of this article http://indesignsecrets.com/fixing-unwanted-default-formatting.php/comment-page-1#comment-5 62875
But it doesn't work for me.
Dose anyone have an idea? Thanks.

Kasyan, I agree with you!
So this is what i did in xslt.
First I added the following namespace to the stylesheet.
xmlns:file="http://www.jclark.com/xt/java/java.io.File"
This is not supported by indesign, you have to do this with a parser. I used saxon to parse the xml.
And this is the part for the existing file lookup.
If the file exists the image is placed as a href, if it doesn't exist i put the name of the image between brackets. In this case we can see in which image doesn't exist.
<xsl:choose>
     <xsl:when test="file:exists(file:new(string($imagefile)))">
          <xsl:element name="Articleimage">
               <xsl:attribute name="href">file://../images/<xsl:value-of select="Properties/Property[@field = 9]"/></xsl:attribute>
          </xsl:element>
      </xsl:when>
      <xsl:otherwise>
          <xsl:text>[</xsl:text><xsl:value-of select="Properties/Property[@field = 9]"/><xsl:text>]</xsl:text>
      </xsl:otherwise>
</xsl:choose>
I hope it helps for others.
Good luck!
Glen

Import XML, apply XSLT and embed images

Hi everyone. I've been looking for days now about a way to export the content of a website as XML and import it then into InDesign, involving some basic text formatting and maybe links, lists and tables. Getting a XML version of a website isn't actually the problem. But including some InDesign readable formatting structure caused me some headache.
First of all, I used InDesign from CS2 and read a lot about INX structure, XML Namespaces and Tagged Text. None of what I did seemed to result in any acceptable or properly working import. So I've read about CS3 having a new feature of applying XSL Stylesheets when importing a XML file and finally downloaded a trial version to test this out. Problem is, I can't find any helpful documentation on how to use this feature right. Neither in the web nor in your forums.
So how does a XSL file have to look like in order to import XML with some basic formatting?
Let's say the XML looks like this, very simple:
] <?xml version="1.0" encoding="UTF-8"?>
] <?xsl-stylesheet type="text/xsl" href="style.xsl"?>
] <root>
] <text>
] <bold>This text is bold</bold> and <italic>this seems to be italic</italic>.
] </text>
] <underline>I'm under the line</underline>
] </root>
How does my XSLT code in "style.xsl" have to look like in order to tell InDesign that the content of <bold> has to be bold, the one of <italic> italic and leaving <underline> underlined?
I tried placing Tagged Tags around the content with XSL but this just resulted in errors or plain text output in InDesign. I also tried to understand the magical code structure of INX, but left it behind until I recognized how complex it is.
Until now, only Tagged Tags do what they shall do for me. Only problem is, the file with this Tagged Tags has to be TXT, but I want XML. Isn't there any way to apply a XSL file over a XML file and replace the XML tags with some Tagged Tags, and finally import everything successful into InDesign? I tried something like that and told the XSL to output the file as Text with
i <xsl:output method="text" />
but InDesign replies with an error as "text" is not valid for DOM structuring.
Moreover, another problem is with importing images without having them saved on the local machine. Meaning, how to send images embed in XML files?
Here I also tried many things like <![CDATA[base64-code-here]]> and so on, but never happened to tell InDesign that it has to do something with this code instead of just displaying it. Using
i <image href="data:image/jpeg;base64,base64-code-here" />
or anything alike didn't work at all.
In the end, I want to allow downloading a XML version of the viewed site on my website which can be imported into InDesign with all basic formatting used on the site itself. Getting the XML file prepared is just a matter of some PHP scripting. Now I only have to know what InDesign can actually read, and of course, if InDesign is even able to do anything of what I've planned.
I hope someone can help me.
Thank you very much in advance, Dan

XSL will re-arrange incoming XML so that you can flow the XML into an InDesign document that may be arranged differently than the incoming XML file. You still need to set up tags and associate those tags with styles in order to achieve what you want. You can use Maivald's "A Designer's Guide to Adobe InDesign and XML: Harness the Power of XML to Automate your Print and Web Workflows" as a starting point, but you will need to play with the pieces to figure it out.<br /><br />For your simple example, you will need to set up tags in text frames for <bold> and <italic>, create paragaph (or object) styles of [bold] and [italic] and then associate those styles with the tags. Only then can you import the XML file and have things work. InDesign has no pre-defined knowledge of what any XML tag means, even when the meaning seems obvious. You are free to define your <bold> XML tag to mean italic text, for example.<br /><br />Though I've read through the Maivald book and converted a Spanish cookbook to English (as a gift for my mom), I am not by any means overly knowledgeable here. It could well be that there are many ways to achieve the goal and I only know one, lol.<br /><br />Hope this helps.

Importing XML with html style tags

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