ImportXML: file vs. string ?

Hello!
I am working on some XML import solutions for work and have learned quite a bit!  I already have the basic XML import and XML rules written and it works great.  However, I have come to a point where I would like to parse a string into XMLElements.
I know importXML() will import an xml file and propagate the xml structure within the InDesign document.  However, I would like to know if you can do this on a string.
For example, say I have a string: "This big sly fox jumps over the dog."
This string was taken from untagged text sitting in my InDesign document somewhere.  I would then like to parse that string somehow and replace that text in the document with the actual XML structure/elements extracted from the string.
Any ideas on how to do this?
Thanks a ton!!
- Dimitri

Hi Dmitri,
Really, the easiest thing to do in this case is to write the XML out to a file and then import it into the structure. You could use the JavaScript XML object like this:
var myString = "This big sly fox jumps over the dog";
var myXMLElement = new XML(myString);
...and then parse the XML, creating XML elements in the InDesign XML structure as you find each element in the JavaScript XML object, but it's still easier (and much faster) to use a temporary file.
Thanks,
Ole

Similar Messages

  • How to retrieve IndividualStrings from a txt file using String Tokenizer.

    hello can any one help me to retrieve the individual strings from a txt file using string tokenizer or some thing like that.
    the data in my txt file looks like this way.
    Data1;
    abc; cder; efu; frg;
    abc1; cder2; efu3; frg4;
    Data2
    sdfabc; sdfcder; hvhefu; fgfrg;
    uhfhabc; gffjcder; yugefu; hhfufrg;
    Data3
    val1; val2; val3; val4; val5; val6;
    val1; val2; val3; val4; val5; val6;
    val1; val2; val3; val4; val5; val6;
    val1; val2; val3; val4; val5; val6;
    i need to read the data as an individual strings and i need to pass those values to diffarent labels,the dat in Data3 i have to read those values and add to an table datamodel as 6 columns and rows depends on the data.
    i try to retrieve data using buffered reader and inputstream reader,but only the way i am retrieving data as an big string of entire line ,i tried with stringtokenizer but some how i was failed to retrive the data in a way i want,any help would be appreciated.
    Regards,

    Hmmm... looks like the file format isn't even very consistent... why the semicolon after Data1 but not after Data2 or Data3??
    Your algorithm is reading character-by-character, and most of the time it's easier to let a StringTokenizer or StreamTokenizer do the work of lexical analysis and let you focus on the parsing.
    I am also going to assume your format is very rigid. E.g. section Data1 will ALWAYS come before section Data2, which will come before section Data3, etc... and you might even make the assumption there can never be a Data4, 5, 6, etc... (this is why its nice to have some exact specification, like a grammar, so you know exactly what is and is not allowed.) I will also assume that the section names will always be the same, namely "DataX" where X is a decimal digit.
    I tend to like to use StreamTokenizer for this sort of thing, but the additional power and flexibility it gives comes at the price of a steeper learning curve (and it's a little buggy too). So I will ignore this class and focus on StringTokenizer.
    I would suggest something like this general framework:
    //make a BufferedReader up here...
    do
      String line = myBufferedReader.readLine();
      if (line!=null && line.trim().length()>0)
        line = line.trim();
        //do some processing on the line
    while (line!=null);So what processing to do inside the if statement?
    Well, you can recognize the DataX lines easily enough - just do something like a line.startsWith("Data") and check that the last char is a digit... you can even ignore the digit if you know the sections come in a certain order (simplifying assumptions can simplify the code).
    Once you figure out which section you're in, you can parse the succeeding lines appropriately. You might instantiate a StringTokenizer, i.e. StringTokenizer strtok = new StringTokenizer(line, ";, "); and then read out the tokens into some Collection, based on the section #. E.g.
    strtok = new StringTokenizer(line, ";, ");
    if (sectionNo==0)
      //read the tokens into the Labels1 collection
    else if (sectionNo==1)
      //read the tokens into the Labels2 collection
    else //sectionNo must be 2
      //create a new line in your table model and populate it with the token values...
    }I don't think the delimiters are necessary if you are using end-of-line's as delimiters (which is implicit in the fact that you are reading the text out line-by-line). So the original file format you listed looks fine (except you might want to get rid of that rogue semicolon).
    Good luck.

  • How to read from a xml file(in String format) using a java program

    hi friends
    i have a string , which is xml format. i want read the values and display it.can any one suggest how to read a xml file of string format using a javaprogram
    thanks

            final DocumentBuilder db =  DocumentBuilderFactory.newInstance().newDocumentBuilder();      
            final InputStream documentStream = new ByteArrayInputStream(documentXMLSourceString.getBytes("utf-8"));
            final Document document = db.parse(documentStream);

  • How to create a xls file from String [ ][ ]

    Hi, I have a java class where I can read the content of files xls and store this information in a String [][].
    But now, I have to do the opposite.
    I have a String[][] where the information is. And I have to guard this information in a file xls.
    My code when I read xls to String[][] is:
    import java.io.*;
    import java.io.File;
    import jxl.Workbook;
    import jxl.Sheet;
    import jxl.Cell;
    import jxl.*;
    public class ReadfichExcel
        private static int numCols;
        private static int numRows;
    public static String[] dimensionFile(String pathFolder, String file){
        String [] dimension = new String[2];
        try{
            Workbook libro = Workbook.getWorkbook(new File(pathFolder+"/"+file));
            Sheet hoja = libro.getSheet(0);
            numRows = hoja.getRows();
            numCols = hoja.getColumns();
        catch (Exception e)
            e.printStackTrace();
            return null;
        dimension[0] = String.valueOf(numRows);
        dimension[1] = String.valueOf(numCols);
        return dimension;
    }How can I do to create a file xls with the information of a String [] []?
    Thanks very much

    I have solved the problem:
    http://www.andykhan.com/jexcelapi/tutorial.html#writing
    What do you want to do then? Do you want to read the contents of the Excel file into the array?I only wanted to create a xls file with the information I have in a String[][]. The code I posted before is the code I ussually use to read a xls file.
    Next to create and write a xls file I'd do:
    public static int CreateTemp (File folderUser, String file, String [][] table)
        int exito = 0;
        int rows = table.length;
        int cols = table[0].length;          
        if (!folderUser.exists())
            folderUser.mkdir();
        try
            WritableWorkbook libro = Workbook.createWorkbook(new File(folderUser+"/"+file));
            WritableSheet hoja = libro.createSheet("First Sheet",0);
            // BEGIN TO WRITE
            for (int i=0;i<rows;i++)
                for (int j=0; j<cols;j++)
                    Label label = new Label(j, i, table[i][j]);
                    hoja.addCell(label);
            }// FOR
            // All sheets and cells added. Now write out the workbook
            libro.write();
            libro.close();
            exito = 1;
        } catch (Exception e)
                e.printStackTrace();
                return 0;
        return exito;
    }Another question. As I want to copy into the xls file the information in the String[][], Is right to do this using as follow:
    Label label = new Label(j, i, table[i][j]);
    hoja.addCell(label); (there will be characters and numbers in the cells)
    Thanks for your response.

  • How to convert xslt file into string

    i'm writting a java program to use xslt to transform the xml file. i'm encountering the problem when i try to convert the xslt file into string. i've defined my utility class called 'XmlUtil' to carry out the operation of transform xml file through xslt. but in my main java program i need to convert both xml and xslt file into a string in order to input them in my function argument. my function argument is as follows:
    String htmlString = XmlUtil.applyXsltString(xmlContent, xsltString);
    i've already converted xmlcontent into string by using:
    xmlContent = xmlContentBuffer.toString();
    but i don't know how to convert 'xsltString' now ? i've searched the google for an hour but i cannot find the solution. anyone can help ?
    detail of my souce code is as follow:
    import java.io.*;
    import java.net.*;
    import java.lang.*;
    import java.io.StringReader;
    import java.lang.reflect.Array;
    import java.util.Properties;
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.transform.TransformerFactory;
    import javax.xml.transform.sax.SAXResult;
    import javax.xml.transform.sax.SAXSource;
    import javax.xml.transform.sax.SAXTransformerFactory;
    import javax.xml.transform.sax.TransformerHandler;
    import javax.xml.transform.stream.StreamSource;
    import org.apache.xml.serializer.OutputPropertiesFactory;
    import org.apache.xml.serializer.Serializer;
    import org.apache.xml.serializer.SerializerFactory;
    import org.w3c.dom.Document;
    import org.w3c.dom.Node;
    import org.w3c.dom.NodeList;
    import org.xml.sax.InputSource;
    import org.xml.sax.XMLReader;
    import org.xml.sax.helpers.XMLReaderFactory;
    import XmlUtil;
    public class FileDownload {
    public static void download(String address, String localFileName){
    OutputStream out = null;
    URLConnection conn = null;
    InputStream in = null;
    StringBuffer xmlContentBuffer = new StringBuffer();
    String temp = new String();
    String xmlContent;
    try {
    URL url = new URL(address);
    out = new BufferedOutputStream(
    new FileOutputStream(localFileName));
    conn = url.openConnection();
    in = conn.getInputStream();
    byte[] buffer = new byte[1024];
    int numRead;
    long numWritten = 0;
    System.out.println (in.toString ());
    while ((numRead = in.read(buffer)) != -1) {
    out.write(buffer, 0, numRead);
    numWritten += numRead;
    temp = new String(buffer);
    xmlContentBuffer.append(temp);
    System.out.println(localFileName + "\t" + numWritten);
    xmlContent = xmlContentBuffer.toString();
    String htmlString = XmlUtil.applyXsltString(xmlContent, xsltString);
    } catch (Exception exception) {
    exception.printStackTrace();
    } finally {
    try {
    if (in != null) {
    in.close();
    if (out != null) {
    out.close();
    } catch (IOException ioe) {
    public static void download(String address) {
    int lastSlashIndex = address.lastIndexOf('/');
    if (lastSlashIndex >= 0 &&
    lastSlashIndex < address.length() - 1) {
    download(address, address.substring(lastSlashIndex + 1));
    } else {
    System.err.println("Could not figure out local file name for " + address);
    public static void main(String[] args) {
    for (int i = 0; i < args.length; i++) {
    download(args);
    }

    I don't understand why you need load the XML and XLS files into a String. A Transformer can be constructed from a Source and there is a StreamSouce which can be constructed from an InputStream. The transform() method can take a Source as input and can produce a Result. There is no need to go near a String representation of either the input.

  • Reading text file, Replace string, Write to new file....

    I'm kind a lost of on this problem. Using the BufferedReader class and BufferedWriter class, develop an application that reads lines of text from a file. Replace any occurrence of the word *?the?* with *?JAVAJAVA?* and change all characters to upper case before writing each line to a different text file named outfile.txt. Finally, have your application use the appropriate method on the File class to return the absolute path of the outfile.txt file and output the path to the screen.
    * Created December 10, 2008
    * @author Fausto Rivera
    * Colorado Technical University - Online Campus
    * IT271-0804B-02 Intermediate Object Oriented Programming II
    * Phase 2 IP
    * Instructor: Cheryl B Frederick
    import java.io.File;
    import java.io.BufferedReader;
    import java.io.BufferedWriter;
    import java.io.FileNotFoundException;
    import java.io.FileReader;
    import java.io.FileWriter;
    import java.io.IOException;
    public class FRiveraReader {
          public static void main(String[] args) {
          // instantiated a new application object to initialize the application
          FRiveraReader application = new FRiveraReader();}
    //      application.getReadfr();  // call to openFile method
    //      application.doWritefr(); // call to readRecords method
    //      application.closeFile();  // call to closeFile method
    public FRiveraReader(){}
      public void getReadfr (String friveraInfile, String fr []){
       int i;
       File fileName = makeAbsoluteFilename(friveraInfile);
       try{
        BufferedReader reader = new BufferedReader(new FileReader(fileName));
        String line = reader.readLine();
         i=0;
          while (line != null) {
           fr[i] =line;
           line = reader.readLine();
        i++;
      reader.close();
    catch(IOException e) {
    System.out.println("Error with reading file:" + friveraInfile);
    }//end of getOrder method
    public void doWritefr(String friveraOutfile, String fw[]){//String name of file, String array to be written
    int i;
    File fileNameout = makeAbsoluteFilename(friveraOutfile);
    try {
    BufferedWriter writer = new BufferedWriter(new FileWriter (fileNameout));
      i=0;
      while (fw[i] != null) {
       writer.write(fw[i] + "%n"); //need delimiters between data in file;also, reader reads a line
       i++;
      writer.close();
    catch(FileNotFoundException e) {
    System.out.println("File not found");
    catch(IOException e) {
    System.out.println("Error with reading file:" + friveraOutfile);
    }//end of getOrder method
    private File makeAbsoluteFilename(String friveraOutfile)//these 2 classes used to resolve file name
            File file = new File(friveraOutfile);
            if(!file.isAbsolute()) {
                file = new File(friveraOutfile);
            return file;

    I have modified my code as far as being able to create a text file, write to string, and change to upper case. Now, how can I connected input to the output stream and then replace all the instances of the string "the" for the string "JAVAJAVA"? When the file is created, it goes into a loop writing the following:
    nJAVA.IO.BUFFEREDWRITER@19821F%nJAVA.IO.BUFFEREDWRITER@19821F%nJAVA.IO.BUFFEREDWRITER@19821F%nJAVA.IO.BUFFEREDWRITER@19821F%nJAVA.IO.BUFFEREDWRITER@19821F%nJAVA.IO.BUFFEREDWRITER@19821F%
    Here is my modified code
    import java.io.File;
    import java.io.BufferedReader;
    import java.io.BufferedWriter;
    import java.io.FileNotFoundException;
    import java.io.FileReader;
    import java.io.FileWriter;
    import java.io.IOException;
    public class FRiveraReader {
    public FRiveraReader() {}
    private static final String inFile = "C:\\Documents and Settings\\Fausto Rivera\\My Documents\\NetBeansProjects\\Rivera_F_IT271_0804B_02_PH2_IP\\friverainfile.txt";//the path name of your file
      public void myReadfr (){
       try {
        BufferedReader reader = new BufferedReader(new FileReader(inFile));
        //String "JAVAJAVA" = String "the";
        System.out.println(inFile);
        String line = reader.readLine();
          while (reader != null) {
           line = reader.readLine();
      reader.close();
    catch(IOException e) {
    System.out.println("Error with reading file:" + inFile);
    }//end of myReadfr method
    public void myWritefr(){//String name of file, String array to be written
    File outFile = new File ("C:\\Documents and Settings\\Fausto Rivera\\My Documents\\NetBeansProjects\\Rivera_F_IT271_0804B_02_PH2_IP\\myoutFile.txt");
    try {
    BufferedWriter writer = new BufferedWriter(new FileWriter (outFile));
    String newline = writer.toString() .toUpperCase();
      while (writer != null) {
       writer.write(newline + "%n"); //need delimiters between data in file;also, reader reads a line
      writer.close();
    catch(FileNotFoundException e) {
    System.out.println("File not found");
    catch(IOException e) {
    System.out.println("Error writing file:" + outFile);
    }//end of getOrder method
    private File makeAbsoluteFilename(String myoutFile)//these 2 classes used to resolve file name
            File file = new File(myoutFile);
            if(!file.isAbsolute()) {
                file = new File(myoutFile);
            return file;
      }Edited by: FRiveraJr on Dec 17, 2008 12:10 PM

  • Convert a line read from text file into string

    how to convert a line from text file into string?
    i know how to convert to numbers,
    private int  parseLine1(String line) {
              StringTokenizer tokenizer = new StringTokenizer(line);
                  value1 = Integer.valueOf(tokenizer.nextToken()).intValue();
                  value2 = Integer.valueOf(tokenizer.nextToken()).intValue();
                 return value1;
                     }but what about charactrs?

    ok, here is my problem, i have a file with a bunch of Xs in it but position function doesn't return a correct value, what's going wrong?
    private int positioni(){
           int i=0;
           int j=0;
           int b=0;
           String line="";
            while(line!= null){
                for(int a=0; a<line.length(); a++){
                    if(line.charAt(a)=='X'){
                        i=a;}
                b++;
                j=b;
                t=line.length();
                line=read(gridFileN);
           return i;
    private String read(String ggridFileN){
             TextStreamReader ggridFile = new TextStreamReader(ggridFileN);
             return ggridFile.readLine();

  • How to read a data file combining strings and data

    Hello,
    I'm having a data file combining strings and datas to read. I'm trying to read the filename, time, constants and comments into four seperate string indicators (the lines for the comments varies for different files). And read the data into a 2-D numeric array. How can I do this? Is there any function that can serch special characters in the spreadsheet file so I can exactly locate where I should start reading the specific data. The following is how the data file appears. Thank you very much.
    Best,
    Richard
    filename.dat
    14:59:00 12/31/2009
    Sample = 2451
    Frequency = 300, Wait time = 2500
    Temperature = 20
    some comments
    some comments
    some comments
    some comments
    some comments
    7.0000E+2    1.5810E-5
    7.0050E+2    1.5400E-5
    7.0100E+2    1.5500E-5
    7.0150E+2    1.5180E-5
    Message Edited by Richard1017 on 10-02-2009 03:10 PM
    Solved!
    Go to Solution.

    Hi,
         I'm fairly new to the NI forums too and I think you just have to wait longer.  Your post was done right.  I do a similiar function as to what you are talking about except I read in numbers from a file.  I create an ini file (just a notepad file of type *.ini) that is is set up with sections inside brackets [] and keys with whatever name followed by an = sign.  You may be able to use a *.dat file too, I just haven't.  Then the vi attached goes to that file and reads the keys from those sections.  You just repeat for the different sections and keys you want to read.  You can use similar provide VI's to write to that same file or create it.  Let me know how that works. 
    Attachments:
    Help1.ini ‏1 KB
    Help1.vi ‏10 KB

  • Reading in text file into strings

    Hi,
    I'm new to the reading in data part of java and I can't work out a good way to read in a .txt file and then store each line of the txt file into strings.
    I think I'm probably just missing something obvious but if anyone can help :D!
    Thanks,
    Bex

    Look up Scanner in Java 1.5, or BufferedReader in Java 1.4.

  • XML file into String

    Hello,
        I want to convert total xml file into string in UDF, i am getting an error. can anybody tell me the solution. what is the wrong in bellow code.
    String str =a+b;
    String strLine;
    StringBuffer sbr=new StringBuffer();
    try{
         FileInputStream fileInputStream = new FileInputStream(str);
             DataInputStream dataInputStream = new DataInputStream(fileInputStream);
             BufferedReader bufferedReader = new BufferedReader(new   InputStreamReader(dataInputStream));
             while ((strLine = bufferedReader.readLine()) != null)   {
             sbr.append(strLine);
         catch (Exception e){      e.printStackTrace();       }
    return sbr.toString();}

    check this link
    How to store big XML string  in ABAB DB
    regards,
    srinivas
    <b>*reward for useful answers*</b>

  • Converting a file to string and then, the string to a file

    I need to send a File (a JPG file) as String (inside a XML document).
    After this, i want to write the String representing the file (reading the XML document) as a File on my disk (making a JPG).
    Can anybody help me ???
    Thanks in advance !!

    I found this in the forum, the author was brianlmartino1
    and it works perfectly.
    Thank you !!
    import java.io.*;
    import org.apache.soap.encoding.soapenc.Base64;
    public class FileUtils {
    static public void main(String args[]) throws Exception {
    System.out.println("-- go !!!!");
    // get input binary source
    File file = new File("c:\\temp\\file.JPG");
    BufferedInputStream bis = new BufferedInputStream(new
    FileInputStream(file));
    int bytes = (int) file.length();
    byte[] buffer = new byte[bytes];
    int readBytes = bis.read(buffer);
    bis.close();
    // encode binary source
    String encodedString = Base64.encode(buffer);
    // decode String source and save the file to the disk
    byte[] buffer2=Base64.decode(encodedString);
    File file2 = new File("c:\\temp\\fileNew.jpg");
    BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(file2));
    bos.write(buffer2);
    bos.close();
    System.out.println("-- ready !!!!");
    }

  • How to run a .bat file with string arguments?

    Hi,
    I have a problem in running a .bat file with string arguments
    - the file is XPathOverlap.bat with 2 stringarguments like: "/a" and "//a"
    - the cmd: c:\Downloads>XPathOverlap "//a" "/a" works fine.
    - here is my code:
    public static void test(){
         try{
              String loc1 = "//a";
              String loc2 = "/a";
              String[] cmdarray = {"c:\Downloads\XPathOverlap", loc1, loc2};
              Process p = Runtime.getRuntime().exec(cmdarray);
              p.waitFor();
              System.out.println("Exit Value: "+p.exitValue());
              //code to print command line replies
              InputStream cmdReply = p.getInputStream();
              InputStreamReader isr = new InputStreamReader(cmdReply);
              BufferedReader br = new BufferedReader(isr);
              String line = null;
              while((line=br.readLine())!=null){
                   System.out.println(line);
         }catch(Throwable t){
              t.printStackTrace();
    How can i run this bat file with 2 string arguments?

    Hi,
    thanks thats good and helpfully
    so this code works:
    String loc1 = "\"/a\"";
    String loc2 = "\"//a\"";
    String path = System.getenv("MuSatSolver");
    String[] cmdarray = {"cmd.exe","/C",path+"XPathOverlap.bat", loc1, loc2};
    Process p = Runtime.getRuntime().exec(cmdarray);
    p.waitFor();
    System.out.println("Exit Value: "+p.exitValue());
    InputStream cmdErr = p.getErrorStream();
    InputStreamReader isrErr = new InputStreamReader(cmdErr);
    BufferedReader brErr = new BufferedReader(isrErr);
    String line2 = null;
    while((line2=brErr.readLine())!=null){
         System.out.println("Error: "+line2);
    but now i have another problem, this is the output:
    Exit Value: 0
    Error: java.lang.NoClassDefFoundError: fr/inrialpes/wam/treelogic/_xml/XPathOverlap
    Error: Exception in thread "main" The Exit value is 0, so the process terminates normally.
    I have tested this bat file in cmd and there it works correctly.
    Why do i get this error message?

  • How can i delete a UserName  from a text file using Strings or io.

    hi i m trainee
    i have been assigned to make java program which deletes a UserName and
    his Passwor from a Text File
    i m unable to do it using the code below
    plz help
    do reply
      import javax.swing.*;
    import java.awt.*;
    import java.awt.event.*;
    import java .applet.*;
    import java.io.*;
    class Del extends JFrame  implements ActionListener
         String s2;
         JTextField CWDMUserDText = new JTextField();
         JButton CWDMSecDelButton = new JButton("DELETE");
         JLabel CWDMUserLabel = new JLabel("USER NAME");
         JPasswordField CWDMPassDText = new JPasswordField();
         JLabel CWDMPassLabel = new JLabel("PASSWORD");
         //String user,pass;
         /* CONSTRUCTOR*/
              Del()
                   Container contentPane=getContentPane();
                   contentPane.setLayout(null);
                  setLocation(400,200);
                   contentPane.add(CWDMUserDText);
                   contentPane.add(CWDMSecDelButton);
                   contentPane.add(CWDMUserLabel);
                   contentPane.add(CWDMPassDText);
                   contentPane.add(CWDMPassLabel);
                  CWDMUserLabel.setBounds(20,70,100,25);
                  CWDMPassLabel.setBounds(20,100,100,25);
                   CWDMUserDText.setBounds(150,70,100,25);
                   CWDMPassDText.setBounds(150,100,100,25);
                   CWDMSecDelButton.setBounds(80,135,100,25);
                   CWDMUserDText.addActionListener(this);
                   CWDMPassDText.addActionListener(this);
                   CWDMSecDelButton.addActionListener(this);
                   contentPane.setBackground(Color.CYAN);
                   setVisible(true);
                   setDefaultCloseOperation(EXIT_ON_CLOSE);
         public void actionPerformed(ActionEvent ae)
                  if(ae.getSource()==CWDMSecDelButton)
         //             user = CWDMUserDText.getText();
         //          pass = CWDMPassDText.getText();
         //          showarr();
                   s2 = CWDMUserDText.getText();
                   CWDMUserDText.setText("");
                   CWDMPassDText.setText("");
                   DelUser(s2);
              public static void main(String args[])
                   Del myframe1= new Del();
                   myframe1.setSize(300,200);
                   myframe1.setVisible(true);
              public void DelUser(String s)
                   //int a;
                   try
                        FileReader fr = new FileReader("file.txt");
                        BufferedReader br = new BufferedReader(fr);
                       String s1;
                       int a;
                       int len = s.length();
                       System.out.println(len);
                       //s2 = CWDMUserDText.getText();
                        while ((s1=br.readLine()) !=null)
                             if((a=s1.indexOf(s))>0 && (a=s1.indexOf(s))!=0)
                                  System.out.println(a);
                        fr.close();
                   catch(FileNotFoundException e)
                        System.out.println("exception occured");
                   catch(IOException e)
                        System.out.println("io");
         }

    Some tips:
    1) If you are adding or deleting stuff from a text file you need to write a new, modified file and then, optionally, do something like:
    rename the old file to whatever.bak or the like.
    rename the new file to the old.
    2) Don't depend on System.out so much on a GUI application. For example if you get an exception use javax.swing.JOptionPane to display an alert (and show the message from the exception). You can write the stack trace to System.out if you want.
    3) Don't muck about with calculating bounds for screen objects, let a layout manager sort it out. I like BoxLayoutManager for most things like this.
    4) For bonus points do your IO in a separate Thread. Generally you don't want anything happening in an actionPerformed method which significantly delays it's return. The method should launch a new Thread to do the job, and disable the button until the Thread finishes.

  • How to create a xml file from String object in CS4

    Hi All,
    I want to convert a string object into an XML file using Javascript in Indesign CS4.
    I have done the following script. But it does not convert the namespaces for the xml elements with no value in it.
    var xml = new XML(string);
    The value present in string is "<level_1 xsi:nil="true" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>"
    When it is converted to xml, the value becomes "<level_1 xsi:nil="true"/>"
    On processing the above xml object, am getting an error like this "Uncaught JavaScript exception: Unbound namespace prefix."
    Kindly help.
    Thanks,
    Anitha

    Can you post more of the script?
    Are you getting the XML file from disk, or a string?

  • Read from file, compare string and return a part

    Hello, is there a reasonable good way to read text file containing information, and if string comparison is successfull, return a nother part of the string.
    What i have done so far:
    set file_name to (path to desktop as text) & "filename.txt"
    set F to open for access tiedosto with write permission
    set file_information to (read F)
    close access F
    (i will be moving this to Application Support/Appname/ when i figure it out).
    The data in the file is in following format
    12234567890Name1
    98765432123Name2
    92347928347Name3
    What im stuck now is:
    I need to compare each line the 10 numbers with search string, if match is found, the name part should be returned.
    Any idea's?

    You already read in the text file, so you need to put the data thru a repeat loop:
    repeat with name_part in paragraphs of file_information
    -- ((character 1 thru 10 of name_part) as string) is the first 10 digits of name part
    if ((character 1 thru 10 of name_part) as string) is search_string then return name_part
    end

Maybe you are looking for

  • Error while activation the Datastore Object

    Hi folks, I am in SAP BASIS, so not aware of BI very much...can u help me in this, One user is getting error while activation the Datastore Object below is error log, (Green) Activation of Objects with Type DataStore Object (Green) Checking Objects w

  • Hello please can you tell me how to set up AirPlay as I can't seem to get it to work!

    HI I've recently brought a Apple TV tired to set it up yesterday to watch cartonn hd but can't seem to get it to play on my TV am I doing something wrong? aany help gratefully received  

  • SAP Import Letter of Credit

    Hi All, Can anybody guide me whether letter of credit can be mapped in SAP MM. Do i need to make changes in existing pricing procedure for L/C . Pl. guide

  • Fix deleted project from imovie

    i accidentally deleted a project from imovie, however the thumbnail still shows on my hard drive. how can i restore the file? it even shows screenshot preview of project and lists file size but i am unable to open the file in imovie or quicktime. hel

  • Captivate 7 - The Exit Bug and a Solution

    Hey Everyone, I wanted to take a second and share some good information I found in regards to SCORM and the Exit functionality in Captivate 7. Below is the blog post that shows how to make the Adobe Exit functionality "SCORM Compliant" and solved my