Incompatable types:java.lang.String and phone number[]

Question

i am trying to run a search of an array but i can not get the Class to compile.
The code is below:
public class People
private int numberSize;
private PhoneNumber[] number;
public People(int maxNumberSize)
number = new PhoneNumber[maxNumberSize];
numberSize = 0;
public void addAPerson(String personName, String Number)
PhoneNumber thePerson = new PhoneNumber (personName, Number);
number[numberSize] = thePerson;
numberSize++;
private String findPhoneNumber(String person)
int location = -1;
for (int i=0; i<numberSize; i++)
if (number.getNumber() == number)
location = i ;

Answer 1

Hi.
you're using
private String findPhoneNumber(String person)
int location = -1;
for (int i=0; i<numberSize; i++)
if (number.getNumber() == number)
location = i ;
}Now - your method gets a name of a person, right?
And you want to find that person's object in the array, and retrieve the phone number.
Your first problem lies in -
if (number.getNumber()==number)Can you see the problem? number is an array. You want to check the data of the object in the array's location i, but you're not doing it. So, first, you would change it to read
if (number.getNumber()==number)
Now - what are we doing here? You are getting the number of the person in place i in the array, by using the getNumber() method. Then you check if it equals to number.
It won't be, because number is the array itself. And anyway - you are doing it the other way around, because you want to check if the object in place i in the array has the name that you got previously.
So, you're looking at something like
if (number.getName()==person)
(person is the argument you got on calling the method, remember?)
ok.
Now you can go on with the rest.
Nimo.