Information on the flow of a backing map put() call?

Hi,
I've been trying to find information on the flow of a backing map put() call. Can you explain how/when/if the put() is backed up in a distributed cache? e.g. is the backup copy updated during the put call as in the case of a normal put through the distributed service?
Thanks,
Andy

BigAndy wrote:
Hi,
I've been trying to find information on the flow of a backing map put() call. Can you explain how/when/if the put() is backed up in a distributed cache? If you do a direct backing map put(), the put() call does not wait for the backup to happen.
When exactly that backup happens depends on which Coherence version you use.
For certain later Coherence version (I believe starting with 3.6.0p4) if you did that backing map put from within a MapTrigger.process() or EntryProcessor.process/processAll method (in which case, I believe, it is backed up together with changes done within the EntryProcessor/MapTrigger), or not.
For earlier versions, a backing map put from an EntryProcessor or MapTrigger is going to be backed up in a backup message which is sent earlier than the backup message for the entry-processor change or whatever change triggered the map-trigger.
For a backing map put not done from an entry-processor or map trigger, first of all don't do such a thing, as it can not be guaranteed that the partition is local when the backing map put is carried out. Second of all, it is going to be backed up asynchronously and there is no other operation to compare to so nothing more needs to be said about this case...
e.g. is the backup copy updated during the put call as in the case of a normal put through the distributed service? No, it is going to happen asynchronously, and very probably later than the backing map put() returns. See above
Best regards,
Robert

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