Int value of unicode character

if i do this:
char c = (char) 100023;
c should be a unicode value, but when i then do:
long l = (long)c;
i dont get 100023, i get 51447
How can i get that original number?
BTW, am i even doing any of this correct?

It should also
be able to work if it is already less than 65536....I
dont think there is such a thing but i thought i would
ask anyways.if (l < 65536) {
//it's less than 65536
} else {
//it isn't
}Now go back to the [url http://forum.java.sun.com/forum.jsp?forum=54]New to Java forum

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How to get the hex. value of unicode character

Hi all
I would like to get the hex. value of unicode and vice versa. I tried
String name1 = new String(request.getParameter("textfield").getBytes("ISO8859_1"), "UTF-8");
but it just get the unicode character, not the "hex value"
pls help
thx.
Regards,
Kin

String str = "asdf";
char c = str.charAt(0);
System.out.println(Integer.toString((int)c, 16));
Is that what you want? Or are you thinking "hex value" is something it's not, which is just a way of writing numbers in base-16.

Req. help on converting int value to a character(ASCII?)

I have an array, letter[x]...where x is an int from 0 to 26. Each element is storing the freq of a particular letter in a piece of text.
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here's the problem code...
if (letter[x]>currentMostCommon)
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Yes, it was meant to be 0-25...silly error.
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Numeric value of a Character

What is the difference between numerical value and unicode value of a character.
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Character.getNumericalValue('A'); --> returns 10
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[url http://java.sun.com/j2se/1.4.1/docs/api/java/lang/Character.html#getNumericValue(char)]the api is your friend :)

Additional CR when printing unicode character

Hello,
the following code prints two lines on a printer. The second line contains an escaped unicode character. When running the example code I can't even see the unicode character on the paper; but in my original application it is visible. So this is not the problem. But always an additional carriage return is inserted after the unicode character, thus overprinting the beginning of the line with the remaining text. This did not occur in java 6 if I remember correctly. Is there any workaround for this?
Regards
J.
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import java.awt.event.*;
import java.awt.print.*;
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Hello Sabre,
thank you for testing. Of course it's good news that you don't see any overprinting, but unfortunately that doesn't help me on my site (Win7 64-Bit, java 1.7.0_09).
Since I can see the character in my original application as I wrote, I made up the following test case and met a strange behaviour. I can make my desired unicode character appear without any overprinting as long as I don't use any other character in the string below 2000(16).
Kindly run the following code. It prints a line of unicode characters starting with my desired one.
Then change iConstant in makeTextLine() to any value below 0x2000. At my site this results in overprinting.
Does it also happen at yours?
import java.awt.*;
import java.awt.event.*;
import java.awt.print.*;
import javax.swing.*;
public class UnicodeTest extends JFrame implements Printable {
String text= "Test line with unicode \u2259 character.";
public UnicodeTest() {
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Unicode character not displaying correctly

when i am stroring Unicode Character in Oracle 8 DB .The Stored Character are not displayed correctly . Through sql client seen as '�' .Altough through JSp it displays correct value 集 (in japanese)
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Using code as below before inserting in DB
String temp =product.getDescription();
String newResult = new String(temp.getBytes("UTF-8"), "UTF-8");

TryString newResult = new String(temp.getBytes(default),>
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Sorry there was a slip. Try the following.
String newResult = new String(temp.getBytes(default));

How to input unicode character set from oralce form 9i

Hi,
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Thank you !

Thank Duncan R Mills !
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NLS_TIME_FORMAT HH.MI.SSXFF AM
PARAMETER VALUE
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Unicode character

what is the unicode character for space? Is there one?
if (letter == ' ') {
//do something
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Hello experts,
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Regards,
girig.

Basically, i am using eclipse Ide, and seeing the
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Can't read int value

import java.io.*;
class binary
     public static void main(String args[])
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plz reply

thanks it worked
i read my number using the readLine() method as a
String and then converted it back to an int value
ut is there no method by which i could read values as
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Need help to convert this format of string in a int value?

public static int isNumber( String number, int defaultValue ) {
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*(space)�23,000(space).*
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Is there any way I can convert this format into a simple int value?
Thanks for any guidance.
Zub

Hi, I tried the following code but it don't seem to work
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Hi,
I have a database column that stores unicode characters as : "ï"
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I am using an af:outputFormatted UI element to display this.
The encoding for the VO which reads from the database is "UTF-8" and the PageDefinition file for the Page is also "UTF-8"
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I also tried replacing it as \u00E9 and it disn;t work either too.
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<af:outputFormatted id="uni" value="#{'ï'}"/>
The above code works for me so assuming your string have the proper value it should also work for you.

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I am trying to study Java by books, but sometimes it is quite difficult to find answers even to simple questions...
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Strings are just concatenations of zero or more chars. the charAt(i)
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char b= 'B';
String t= ""+a+b;
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sb.append(a);
sb.append(b);
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kind regards,
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I am trying to test the new Unicode character by using J2SE1.5.
For example, If I wanted to test the music symbol "1D15F", how do we test that or how do we write code?
The following is my code.
import java.text.*;
import java.util.*;
import java.lang.Character.*;
public class NewUnicodeCharacterTest {
public static void main (String[] args) {
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my output was
What is wrong?

Looking at the Java 1.5 API, I figured out that you should be able to create a string with UTF-32 code points by specifying an int[]:
String s = new String(new int[] { 0x1D15F }, 0, 1);
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Int value of unicode character

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