Integer to string
Hi , I declare a variable int i = 001, i++ etc... than i want to use "i" in a string like "..." + i + " ...." , but the problem that I am loosing the zeros
( i become 1 instead of 001 ), any help ? tks
I think, If u declare it as integer it would not be possible.
But if you want some thing what you have told you can implement your own number class and operations on dat.
Put 001 in an array a= [0,0,1] and manpulate the array to have desired operations
Note: There is no overloading operator in java. So you cannot do i++ and all.so u can replace them like postincrement(i)
Thanks
D. L. Kumar
Similar Messages
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How to convert from integer to string
import javax.swing.*;
import java.awt.*;
public class Hw extends JFrame{
JButton[] buttons = new JButton[26];
public Hw(){
getContentPane().setLayout(new GridLayout(2,13));
JButton []buttons=new JButton[26];
for(int i=65; i<90;i++)
buttons=new JButton(i+" ");
getContentPane().add(buttons[i]);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
pack();
public static void main(String[] args) {
Hw win = new Hw();
win.setVisible(true);
win.setLocation(50, 100);
I have 26 buttons and each buttons will contain a character like A,B,C,D,...
but i dont know how to convert it from integer to stringimport javax.swing.*;
import java.awt.*;
public class Hw extends JFrame{
JButton[] buttons = new JButton[26];
public Hw(){
getContentPane().setLayout(new GridLayout(2,13));
JButton []buttons=new JButton[26];
for(int i=0; i<buttons.length;i++)
buttons=new JButton(""+('A'+i));
getContentPane().add(buttons[i]);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
pack();
public static void main(String[] args) {
Hw win = new Hw();
win.setVisible(true);
win.setTitle("Hangman Game");
tjacobs01 , thnx for urgent reply, but i didnt apply your algorithm inside of the my program, if its possible can u compile the program with your codes..
its a little complex for me i didnt understand anythind :S -
Why Integer.valueOf(String) does not recognize plus sign
The Integer.valueOf(String) works fine with strings like "-1", but does not work with "+1". The following code throws NumberFormatException:
int i = Integer.valueOf( "+1" );
Does anybody know what's the reason for this?
Thanks,
-- LKWelcome to the forum!
>
The Integer.valueOf(String) works fine with strings like "-1", but does not work with "+1". The following code throws NumberFormatException:
int i = Integer.valueOf( "+1" );
Does anybody know what's the reason for this?
>
The short answer is because it is defined that way.
The place to start for questions like this is the Javadoc.
You don't state what Java version you are using but for 1.6 the 'valueOf' method says this
http://127.0.0.1:8082/resource/jar%3Afile%3A/C%3A/Software/Java/jdk1.6.0_02/jdk-6-doc.zip%21/docs/api/java/lang/Integer.html#valueOf(java.lang.String)
>
valueOf
public static Integer valueOf(String s)
throws NumberFormatExceptionReturns an Integer object holding the value of the specified String. The argument is interpreted as representing a signed decimal integer, exactly as if the argument were given to the parseInt(java.lang.String) method. The result is an Integer object that represents the integer value specified by the string.
>
As you can see the description further refers you to the 'parseInt' method where you will find the answer.
>
parseInt
public static int parseInt(String s)
throws NumberFormatExceptionParses the string argument as a signed decimal integer. The characters in the string must all be decimal digits, except that the first character may be an ASCII minus sign '-' ('\u002D') to indicate a negative value. The resulting integer value is returned, exactly as if the argument and the radix 10 were given as arguments to the parseInt(java.lang.String, int) method.
>
You may have to do a little digging but when you have a question like this you should read the relevant Javadoc sections, search the forum for similar questions, search on the net and then if you still can't figure it out post a thread. -
NetBeans 6.5 - Integer.parseInt(String)
Hello,
I'm beginner with NetBeans 6.5.
I created a simple hello-java application and a simple hello java-web JSF application.
I have no error with hello-java application for these 2 lines:
String name = "12345";
int aInt = Interger.parseInt(name) ;
but I get exception handler from java-web JSF application as below.
Hope you help me to solve this, Thanks !
Exception Handler
Description: An unhandled exception occurred during the execution of the web application. Please review the following stack trace for more information regarding the error.
Exception Details: java.lang.NumberFormatException
null
Possible Source of Error:
Class Name: java.lang.Integer
File Name: Integer.java
Method Name: parseInt
Line Number: 415
Source not available. Information regarding the location of the exception can be identified using the exception stack trace below.
......they're different, i was trying to convert the string entered in a TextField to a number, and thought that I already hard coded '12345' in the code to see whether the parseInt works therefore i didn't enter anything in the TextField.
thanks raychen ! -
Cannot convert integer to string in ARM project?
Hi all,
I'm getting started with an ARM project in LabVIEW and I'm having trouble with a simple example: I'm reading integer values from an accelerometer and printing them to the front panel. I cannot, however, convert any of the integers to a string and display the converted value in a string indicator on the front panel. I can't find this problem listed as a limitation of the string methods in the ARM module: http://zone.ni.com/reference/en-XX/help/372459C-01/lvarmhelp/arm_bd_strings/ Any ideas? A simple example demonstrating the problem is attached (although I suppose you can only run it without modifications if you have an accelerometer...)
Thanks!
Mike
Attachments:
problem_example.vi 18 KBDid you try the format into string function?
Just a thougt
Tim
Johnson Controls
Holland Michigan -
let say i have string like string s = "Page (34).jpg"
now i want to take the 34 as integer..
i do loop form char 1 to s.length(), i get the string substring
substring will always return string, but how to know whether the substring is string or integer
is there any method in java, like isInteger and return boolean?
ThanksMatcher matcher = Pattern.compile("\\d+").matcher(s);
if (matcher.find())
int value = Integer.parseInt(matcher.group());
} -
How convert integer into string
Hi,
I need to convert answer3 from double into String
answer3 = Double.parseDouble(dij3)/(1 + Math.pow(( Double.parseDouble(tesside_luas_i) / Double.parseDouble(tesside_luas_j) ),0.5847));Now the integer value is string but why i cannot get valur from my servlet to my web page
package net.mybizaid.isodms.servlet;
import java.io.*;
import java.util.*;
import java.sql.*;
import javax.servlet.*;
import javax.servlet.http.*;
import net.mybizaid.isodms.*;
public class SPLDataInputServlet extends HttpServlet {
public void doPost (HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
System.out.println( "******************** Calculation Servlet ******************" );
String dij ;
String population_i ;
String population_j ;
String project_name = "";
String project_status = "";
double answer;
String handler = "";
String url = "";
double answer3;
String dij3 ="";
String tesside_luas_i ="";
String tesside_luas_j ="";
double answer2;
String dij2 ="";
String luas_i ="";
String luas_j ="";
String counter = "";
String i = "";
handler = request.getParameter( "handler" );
dij = request.getParameter("dij");
population_i = request.getParameter("population_i");
population_j = request.getParameter( "population_j");
project_name = request.getParameter( "project_name");
project_status = request.getParameter( "project_status");
dij2 = request.getParameter("dij2");
luas_i = request.getParameter("luas_i");
luas_j = request.getParameter( "luas_j");
dij3 = request.getParameter("dij3");
tesside_luas_i = request.getParameter("tesside_luas_i");
tesside_luas_j = request.getParameter( "tesside_luas_j");
HttpSession session = null;
session = request.getSession(true);
int cnt = counter != null && !counter.equals("") ? Integer.parseInt(counter) : 0;
int ii = i != null && !i.equals("") ? Integer.parseInt(i) : 0;
//Tesside
if (handler != null && !handler.equals( "" ) && handler.equals( "cal3" ))
try
System.out.println("The DIJ3 value is :"+dij3);
System.out.println("The tesside_luas_i value is :"+tesside_luas_i);
System.out.println("The tesside_luas_j value is :"+tesside_luas_j);
answer3 = Double.parseDouble(dij3)/(1 + Math.pow(( Double.parseDouble(tesside_luas_i) / Double.parseDouble(tesside_luas_j) ),0.5847));
String str = String.valueOf( answer3 );
System.out.println("The answer value is :"+str);
url = "/jsp/model/tessideAnswer.jsp";
dispatchErrorMsg( request, response, url, "" );
catch (Exception e)
request.setAttribute("pd.errorMessage", e.getMessage());
dispatchErrorMsg( request, response, "/jsp/Error.jsp", e.getMessage() );
//PotensiPasaran
if (handler != null && !handler.equals( "" ) && handler.equals( "cal2" ))
try
System.out.println("The DIJ2 value is :"+dij2);
System.out.println("The luas_i value is :"+luas_i);
System.out.println("The luas_j value is :"+luas_j);
answer2 = Double.parseDouble(dij2)/(1 + Math.sqrt(( Double.parseDouble(luas_i) / Double.parseDouble(luas_j) )));
System.out.println("The answer value is :"+answer2);
url = "/jsp/model/potensiPasaranAnswer.jsp";
dispatchErrorMsg( request, response, url, "" );
catch (Exception e)
request.setAttribute("pd.errorMessage", e.getMessage());
dispatchErrorMsg( request, response, "/jsp/Error.jsp", e.getMessage() );
//Reilly
if (handler != null && !handler.equals( "" ) && handler.equals( "add" ))
try
System.out.println("The DIJ value is :"+dij);
System.out.println("The population_i value is :"+population_i);
System.out.println("The population_j value is :"+population_j);
answer = Double.parseDouble(dij)/(1 + Math.sqrt(( Double.parseDouble(population_i) / Double.parseDouble(population_j) )));
System.out.println("The answer value is :"+answer);
url = "/jsp/model/reillyAnswer.jsp";
dispatchErrorMsg( request, response, url, "" );
catch (Exception e)
request.setAttribute("pd.errorMessage", e.getMessage());
dispatchErrorMsg( request, response, "/jsp/Error.jsp", e.getMessage() );
public void doGet (HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
doPost(request, response);
}//end doGet
public void dispatchErrorMsg(HttpServletRequest req, HttpServletResponse res,
String target, String message)
try
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(target);
req.setAttribute("eshop.ErrMessage",message);
dispatcher.forward(req, res);
catch (Exception e)
System.err.println( e.getMessage() );
}//end class -
Why Integer. valueOf(String,radix) throws exception
Can any one explains why this method throws exception
Integer a = Integer. valueOf(" 123 ", 2);
System.out.println(a);prady_jo wrote:
Can any one explains why this method throws exception
Integer a = Integer. valueOf(" 123 ", 2);
System.out.println(a);As already mentioned, in binary notation, only 1's and 0's are permitted. Besides that, I see you also have some white spaces in your string: this will throw an exception as well. -
Hi All,
Can anyone help me in finding integers in string?
The scenerio is like I have to shortlist the strings which has numbers in it.
Consider this as a table with following data.
Ashwin
Bala12
Daniel
Mark67
Patty.
i have to get the answer as follows:
Bala12
Mark67
Thanks in advance.Hi,
Hope this code will help :)
create table my_test (some_val varchar2(100));
insert into my_test values ('1Abcd2');
insert into my_test values ('eFgh');
insert into my_test values ('IjklM');
insert into my_test values ('nOpq');
insert into my_test values ('r34st');
insert into my_test values ('uVw0');
insert into my_test values ('xyZ');
insert into my_test values ('!$-#_)(');
insert into my_test values ('1234567890');
commit;
select some_val
from my_test
where instr(some_val, '1') + instr(some_val, '2') + instr(some_val, '3') +
instr(some_val, '4') + instr(some_val, '5') + instr(some_val, '6') +
instr(some_val, '7') + instr(some_val, '8') + instr(some_val, '9') +
instr(some_val, '0') > 0;Good luck!
http://dba-star.blogspot.com -
can we print any number value to its string.
ex: in figures: 123
in words: one two three
like this.is it possible in java?
the same figure should be print in currency i.e
ex: in figures: 123
in words: one hundred twenty three
send solution to [email protected]Sudigali wrote:
i got some knowledge on this.I assume you mean you gained some knowledge.
but am new to java.
am not able to understand ur link.
i searched all the methds which u sent thru lnk.
i need some more clarification.
can u plz help me in this.Your request for clarification is too vague.
You need to be more specific. Exactly what do you not understand?
import java.util.Locale;
import com.ibm.icu.text.RuleBasedNumberFormat;
import com.ibm.icu.util.ULocale;
public final class TestIcu {
static final Locale l_US = new Locale("en","US");
static final RuleBasedNumberFormat fmt_US =
new RuleBasedNumberFormat(l_US, RuleBasedNumberFormat.SPELLOUT);
public static final void main(String[] arg) {
double d = Double.parseDouble(arg[0]);
System.out.println("US: "+fmt_US.format(d,fmt_US.getDefaultRuleSetName()));
C:\...>java -cp .;icu4j_3_4_4.jar TestIcu 1234.45
US: one thousand two hundred and thirty-four point four five -
How to convert integer to string?
for example :
int num = 1;
String num_str;
how to convert the value of num variable to string .have u ever checked the documentation of WTK
one method called valueOf
will help u
alpesh -
How to cast an Object into a specific type (Integer/String) at runtime
Problem:
How to cast an Object into a specific type (Integer/String) at runtime, where type is not known at compile time.
Example:
public class TestCode {
public static Object func1()
Integer i = new Integer(10); //or String str = new String("abc");
Object temp= i; //or Object temp= str;
return temp;
public static void func2(Integer param1)
//Performing some stuff
public static void main(String args[])
Object obj = func1();
//cast obj into Integer at run time
func2(Integer);
Description:
In example, func1() will be called first which will return an object. Returned object refer to an Integer object or an String object. Now at run time, I want to cast this object to the class its referring to (Integer or String).
For e.g., if returned object is referring to Integer then cast that object into Integer and call func2() by passing Integer object.GDS123 wrote:
Problem:
How to cast an Object into a specific type (Integer/String) at runtime, where type is not known at compile time.
There is only one way to have an object of an unknown type at compile time. That is to create the object's class at runtime using a classloader. Typically a URLClassloader.
Look into
Class.ForName(String) -
Conversion of String to big integer
Here we have Converted a Big Integer to String using String.valueOf() in the server side.
Now when the reciever has String convert back to Big Integer.. Pls helpWhy did you feel it necessary to resurrect a six-month-old thread to request information that the thread already contains?
Grant -
Space after Integer, String etc.
Hello,
i have a problem in one of my Webapplications. Is it possible to suppress the Space after an integer or string variable using the print directive? i.e.:
Date counter type i.
counter = 1.
<%=counter%> would result in "1 "
whereas
Date counter type n.
counter = 1.
<%=counter%> would result in "1"
Is it somehow possible to use an Integer variable without the space?
Greetz
DanielIm using the counter as an extension of the name of an input field:
<INPUT type="text" name="field_<%=counter%>">
it should result in:
<INPUT type="text" name="field_1">
but it results in
<INPUT type="text" name="field_1 ">
This makes it difficult for me to get values of the field in OnInputProcessing because of the appended space at the end of the name. Is it somehow possible to supress this behavior? -
How to Convert the Stream of strings into ArrayList Integer
I have a String st = "12 54 456 76ASD 243 646"
what I want to do is print it like this from the ArrayList<Integer>:
12
54
456
243
646
It should catch the "76ASD" exception as it contain String Character.
This is how I am doing, which it seems to work but when it reaches the 76ASD it catches the exception so it is not adding the rest to the Arraylist, therefore I could not print in sequence.
public static void main(String[] args) {
// TODO code application logic here
getDatas(testString);
for (int i = 0; i < at.size(); ++i) {
System.out.println(at.get(i));
private static ArrayList<Integer> getDatas(String aString) {
StringTokenizer st = new StringTokenizer(aString);
try {
while (st.hasMoreTokens()) {
String sts = "";
sts = st.nextToken();
at.add(Integer.parseInt(sts));
} catch (Exception e) {
System.out.println("Error: " + e);
return at;
}Please guide me where I am going
Thankspaulcw wrote:
This is one of the few cases where I'd say catching an exception as part of the design is acceptable. When parsing, either something parses, or it doesn't. Using parseInt, we're parsing the string and using the result of the parse. By using a regular expression, we're parsing it twice, in two different ways, which may get out of sync. Not only that, if you have a more complicated case, like negative numbers and decimals, the regex gets really ugly.
I agree this is exactly the case where it is appropriate to try, catch, handle, move on. I sometimes wish there were an Integer.isValid(String) method, but even if there were, we'd call it, and if it returned true, we'd then call parseInt anyway, which would repeat the same work that isValid did. All it would buy us would be an if test instead of a try/catch.
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