Interface variable value

Question

Hi,
Can some body will help me to understand the below code and explain the output or flow of this -
public class Test implements A, B, C {
    public static void main(String[] args) {
        System.out.println("A = " + A);
interface A extends B {
    public static final int A = 2 * B;
interface B {
    public static final int B = C.C + 1;
interface C extends A {
    public static final int C = A + 2;
}output :
A = 6I am not getting how it has printed the output value.
Thanks

Answer 1

Until initialization completes A has a "value" of zero. A references B, which references C, which references the (uninitialized) A.
We'll call uninitialized value of A a prime = A'
We'll call the initialized value of A a double prime = A''
A' = 0
C = A' + 2 = 2
B = C + 1 = 3
A'' = B * 2 = 6The value that's printed is therefore 6. But to understand this in detail you must read the JLS. But it's a toy problem; you shouldn't have this sort of "loop" initialization in the first place and the first step to "debugging" it would be to eliminate it.