Invoking a supersuperclass method

Question

I'd like to invoke the gradparent's version of a method
from a method. For example, the following
public class Test {
public static void main(String[] args) throws Exception {
C c = new C();
c.test();
class A {
void f() {System.out.println("A.f");}
class B extends A {
void f() {System.out.println("B.f");}
class C extends B {
void f() {System.out.println("C.f");}
void test() { ((A)this).f(); }
prints C.f(). I'd like it to display A.f()
Without creating a new A object of course.
super.f() calls B's version, I know, but I'm stumped
as to how to skip over B.
Thanks

Answer 1

You can't do that, and if you want to do that there is
a good chance you have a problem with your design.No kidding. I'm trying to workaround a "design problem" in existing
code where the skip is the best way to bury the problem.
I probably should have made that point in the original post,
as it didn't take long for someone to notice. Reflection doesn't
even help, and I know the JLS points out method invocation is
always sensitive to the runtime type of the object. Still, I was
hoping there is some clever mechanism.