Is it possible to read DDP formatted files from disc?

I need to check some layers in a master file.
I know I can read from DLT tape but can I read in a similar way from these files?

there are special programs, the name escapes me, that are used to analyze the files for replication. I've never used them. That was always left to the replicator. My guess, and it is a guess, is that if you've rendered the DDP files to your drive then you could read them the same way. DLT is just a storage/transport medium anyway.

Similar Messages

Reading an xml file from a jar file

Short question:
Is it possible to read an xml file from a jar file when the dtd is
placed inside the jar file? I am using jdom (SAXBuilder) and the default
sax parser which comes with it.
Long Question:
I am trying to create an enterprise archive file on Weblogic 6.1. We
have a framework that is similar to the struts framework which uses it's
own configuration files
I could place the dtd files outside the jar ear file and specify the
absolute path in an environment variable in web.xml which is
configurable through the admin console.
But I want to avoid this step and specify a relative path within the jar
file.
I have tried to use a class which implements the entityresolver as well
as try to extend the saxparser and set the entity resolver within this
class explicitly, but I always seem to sun into problems like:
The setEntityresolver method does not get called or there is a
classloader problem. i.e. JDOM complains that it cannot load My custom
parser which is part of the application
Vijay

Please contact the main BEA Support team [email protected]
They will need to check with product support to determine
the interoperatablity of Weblogic Server with these other
products.

1.is it possible to read a .xls file and load it into an oracle table

1.is it possible to read a .xls file and load it into an oracle table, using oracle database or oracle forms i.e. either utl_file, or text_io, or any other oracle tool.
As far as I know we need a csv file or a txt ( tab delimited) file ?
2.Are there any windows tools for the same

Hi,
If you want to use the DDE package to read the XLS file then yes, you will neeed to know the number of rows and columns in the input file.
i.e. How will you know :
1) How many columns are there in the input file.
If I have a XLS file with the following data :
R1C1 R1C2 R1C3 R1C4 R1C5 R1C6 R1C7
xxx xx x
Where R represents row and C represents column, then how will you know the each row has 7 columns. If you know the answer upfront, then it's not a issue.
Using the DDE apprach, you will have to specify the RowNum and the ColumnNo of each idividual cells to read/write data from xls sheet.
Look at the syntax in my ealier post.
using the other approch (i.e. comma delimited text file - CSV file) , you need not know the number of columns as you can loop thru the input record till the last column is read.
All you have to do is to look for the 'n' occurances of the field delimiter say ',', do a substr from the current position to the point where the ',' was found.
This process is to be repeated in a loop till all columns are read.
The TEXT_IO package can trap for EOF (End Of File).
Hope I made myself clear.
-- Shailender Mehta --

How to read KNE format file in SAP

Hi All,
Our requirement is to read KNE format file (contains accouting information generated from DATEV) in SAP. Could you please help me, how to do this?
Thanks in advance.
Sameer

Hi Shinde,
Basically we have to following file conversion types that are supported in SAP.
'BIN' , 'ASC' , ''DAT' , ''DBF' , 'WK1' and 'VSS'.
try to convert 'KNE' format file into sap supported file format.
Thanks

I have iphoto '08 version with an imac osx 10.5.8. It will not read my RAW files from my Nikon D800 - a very new model.How can I get it to read my RAW files?

my somewhat old imac osx 10.5.8 with iphoto '08 will not read my RAW files from my new Nikon D800 camera - a new model on the market( 5 months or so). How can I get iphoto to read my RAW files?

iPhoto 08 would not read RAW files from that new a camera. You need to upgrade so you can get more up-to-date version of OS X and iPhoto. Another possiblity is see if iPhoto 11 will run on 10.5.8, if so you should update. You can also attempt to run Software Update and see if it finds a newer release of iPhoto 08 that supports newer RAW formats.

Issue with reading a xml file from xsl

Hi,
When I am trying to read a xml file from xsl, I am getting unwanted output.
Following is the XSL:
<?xml version="1.0" encoding="UTF-8" ?>
<?oracle-xsl-mapper

<mapSources>
    <source type="XSD">
      <schema location="../xsd/B2BMarketProperties.xsd"/>
      <rootElement name="ReceipentIDType" namespace="http://www.example.org"/>
    </source>
</mapSources>
<mapTargets>
    <target type="XSD">
      <schema location="../xsd/B2BMarketProperties.xsd"/>
      <rootElement name="ReceipentIDType" namespace="http://www.example.org"/>
    </target>
</mapTargets>

?>
<xsl:stylesheet version="1.0"
                xmlns:bpws="http://schemas.xmlsoap.org/ws/2003/03/business-process/"
                xmlns:xp20="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.Xpath20"
                xmlns:mhdr="http://www.oracle.com/XSL/Transform/java/oracle.tip.mediator.service.common.functions.MediatorExtnFunction"
                xmlns:bpel="http://docs.oasis-open.org/wsbpel/2.0/process/executable"
                xmlns:oraext="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.ExtFunc"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                xmlns:ns0="http://www.example.org"
                xmlns:dvm="http://www.oracle.com/XSL/Transform/java/oracle.tip.dvm.LookupValue"
                xmlns:hwf="http://xmlns.oracle.com/bpel/workflow/xpath"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:med="http://schemas.oracle.com/mediator/xpath"
                xmlns:ids="http://xmlns.oracle.com/bpel/services/IdentityService/xpath"
                xmlns:bpm="http://xmlns.oracle.com/bpmn20/extensions"
                xmlns:xdk="http://schemas.oracle.com/bpel/extension/xpath/function/xdk"
                xmlns:xref="http://www.oracle.com/XSL/Transform/java/oracle.tip.xref.xpath.XRefXPathFunctions"
                xmlns:xsd="http://www.w3.org/2001/XMLSchema"
                xmlns:ora="http://schemas.oracle.com/xpath/extension"
                xmlns:socket="http://www.oracle.com/XSL/Transform/java/oracle.tip.adapter.socket.ProtocolTranslator"
                xmlns:ldap="http://schemas.oracle.com/xpath/extension/ldap"
                exclude-result-prefixes="xsi xsl ns0 xsd bpws xp20 mhdr bpel oraext dvm hwf med ids bpm xdk xref ora socket ldap">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:variable name="ReceipentID" select="document('../xsd/B2BMarketProperties.xml')"/>
<xsl:template match="/">
    <ns0:ReceipentIDType>
    <xsl:for-each select="$ReceipentID">
      <ns0:ReceipentID>
        <xsl:value-of select="$ReceipentID"/>
      </ns0:ReceipentID>
      </xsl:for-each>
    </ns0:ReceipentIDType>
</xsl:template>
</xsl:stylesheet>
Following is the XML ( B2BMarketProperties.xml)
<?xml version="1.0" encoding="UTF-8" ?>
<ReceipentIDType xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                 xsi:schemaLocation="http://www.example.org B2BMarketProperties.xsd"
                 xmlns="http://www.example.org">
<ReceipentID>123</ReceipentID>
<ReceipentID>345</ReceipentID>
</ReceipentIDType>
The output i am getting with this code is
<?xml version="1.0" encoding="UTF-8"?>
<ns0:ReceipentIDType xmlns:ns0="http://www.example.org">
    <ns0:ReceipentID>123345</ns0:ReceipentID>
</ns0:ReceipentIDType>
But, I need output in the following format
<ns0:ReceipentIDType xmlns:ns0="http://www.example.org">
    <ns0:ReceipentID>123</ns0:ReceipentID>
     <ns0:ReceipentID>345</ns0:ReceipentID>
</ns0:ReceipentIDType>
Could you guys let me know what i am doing wrong. Any help would be appreciated.
Thanks,

This worked for me :
<xsl:template match="/">
    <ns0:ReceipentIDType>
      <xsl:for-each select="document('B2BMarketProperties.xml')/*:ReceipentIDType/*:ReceipentID">
        <xsl:variable name="count" select="position()"/>
        <ns0:ReceipentID>
          <xsl:value-of select="document('B2BMarketProperties.xml')/*:ReceipentIDType/*:ReceipentID[$count]"/>
        </ns0:ReceipentID>
      </xsl:for-each>
    </ns0:ReceipentIDType>
</xsl:template>

Is it possible to pickup a specific file from a folder?

Hi
I am wondering whether it is possible to pick a specific file from a folder. I have a shape where I have got a filename and I need to look for it in a folder.
Is that possible?
And how can I achieve this? The next step is to pick the file up and transfer it to another location. So basically in pseudo code I need to ask my defined folder with a filename as parameter. Get the file and move it to another folder.
Suggestions are most appreciated. Thanks

Assuming you are using orchestration, you could
create an assembly, install it in the GAC, add a reference to it in your BTS
project, and call it from an Expression shape to resolve the receive
location. You would only really need one static method in a class. Be sure
to add a reference to Microsoft.BizTalk.ExplorerOM.dll.
Example:
using Microsoft.BizTalk.ExplorerOM;
namespace Phil
public class OrchestrationHelpers
public static string ResolveReceiveLocationName(string
inboundTransportLocation, string receivePortName)
BtsCatalogExplorer bts = new BtsCatalogExplorer();
bts.ConnectionString =
"SERVER=localhost;DATABASE=BizTalkMgmtDb;Trusted_Connection=True;Network
Library=DBMSSOCN;"
foreach (ReceiveLocation location in
bts.ReceivePorts[receivePortName].ReceiveLocations)
if (location.Address == inboundTransportLocation) return location.Name;
return null;
In your Expression shape within your orchestration, assuming a message
called "MyMessage" and a string variable "receiveLocationName":
receiveLocationName =
Phil.OrchestrationHelpers.ResolveReceiveLocationName(MyMessage(BTS.InboundTransportLocation),
MyMessage(BTS.ReceivePortName));
If this post answers your question, please mark it as such. If this post is helpful, click 'Vote as helpful'.

Read an EXCEL file from application server

Hi all
I have to read an excel file from applicatin sever and update my custom tablels.
The problem is when the file is uploaded into the application server .
the fields it has are
name age gender
xyz 67 m.
when seeing the file using al11 tcode :
its showing the following:
###ࡱ##################>#######################################################################################################################
#################################################################O#b#j#I#n#f#o################################################################
How do i read this and put in my internal table
Pleaes help.
Thanks and Regards,

Hi,
I am using ECC6.0.
I think the EXCEL file is stored in compressed format to save space.
Please let me know how to decompress etc.
I tried using the function moduel
text_convert_xls_to_sap.
How do I pass the parameter to I_filename.
Regards,

Reading a Compressed File from a ZIP File, which is an entry of ZIP File

Hello, Experts,
Would it be possible somebody to help me with code example for the following problem?
I want to read a compressed file from a ZIP file, which is an entry of ZIP File, without extacting/writing files on file system. Is this possible?
Lets say we have a ZipFile1. There is ZipFile2 inside ZipFile1. And inside ZipFile2 is FileA. The scenario is reading FileA without extracting on file system.
Thank you in advance for your help.
Cheers
RADY

The classes you want to be using are java.util.zip.ZipInputStream and and ZipEntry from the same package. Construct the ZipInputStream with the input you have for the outer zip. Loop with ZipInputStream.getNextEntry until you find the inner zip you're looking for - that method returns a ZipEntry, and you get the name of the zip entry with ZipEntry.getName. Read the ZipInputStream from that point into some buffer, and read that buffer into a new ZipInputStream - rinse and repeat until you have the contents of the file in the zip in the zip...

Reading external xml files from a jar

Hi,
I am trying to read an xml file from a jar (which is not present inside the jar ) .
I am passing the file name as a string (like C:/folder/filename) to the SAXBuilder but it throwing
unknown protocol: c error.
i tried using an url , tried using a relative path but to no use.
Need help in this regard urgently.
TIA,
Regards,
Harsha

Hi,
Actually, my application needs to read two xml files , parse it, perform some operation and write
the result to an output file.
The names of the two xml files i mentioned, are specified in a properties file as absolute paths. (I even tried converting them to URIs)
The xml files are in the same directory as the jar ( i dont know if it should matter as i am giving the absolute path).
The main class reads the names of the files and passes the names as strings to the SAXBuilder.
This is where i am getting an exception.
Going by what you said, is it not possible for a java class to read a fie outside of the jar ? Is there no way to do this ? And right now i am not sure of how to go about this or if there's any work around . Any help would be appreciated.
Kindly reply at the earliest
TIA,
Harsha

Do you know if it's possible to generate Word 2003 files from RoboHelp if we're using Office 2007 and RoboHelp 2007?

Do you know if it's possible to generate Word 2003 files from
RoboHelp if we're using Office 2007 and RoboHelp 2007? We are
thinking of upgrading, but have customers that would still require
Word 2003 formats because they won't have 2007 installed.
Thanks!

Hi NewtoRobohelp
Unfortunately I don't have Office 2007 in front of me to test
with. But I'm thinking that as long as Office 2007 still produces
the same formats as 2003, you could do it this way.
From RoboHelp 7 and using Office 2007, generate Printed
ouptut. Open said printed output in Office 2007 and perform a Save
As. Save the document as a RTF (Rich Text Format) document.
RTF is more universal. So I'm thinking this may be a possible
way around it. There is also the possibility that Word 2007 offers
up an ability when saving a file to save in an older format.
Cheers... Rick

How to read an audio file from the disk and play it?

Do you know who to read an audio file from the hard disk and play it. It's for an application and not an applet. I tried with the Applet.newAudioClip(URL url) thing, but I keep getting a MalformedURLException.
And is there a way to get the path of the file you are using? Currently I'm doing this:
File file = new file("randomname");
string = file.getAbsolutePath();
file.delete();
I'm sure there's a better way. And this is not for an applet, just a normal app.

Below is a class that should be of use to you.
package com.sound;
import java.io.File;
import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.Clip;
import javax.sound.sampled.DataLine;
public class SoundPlayer implements Runnable {
     String filename;
     public SoundPlayer(String filename){
          this.filename = filename;
          Thread t = new Thread(this);
          t.start();
     }//SoundPlayer constructor
     public void run(){
          playSound();
     }//run method
     public boolean playSound(){
          try {
               File file = new File(filename);
               AudioInputStream stream = AudioSystem.getAudioInputStream(file);
               AudioFormat     format = stream.getFormat();
               DataLine.Info info = new DataLine.Info(Clip.class, format);
               Clip clip = (Clip)AudioSystem.getLine(info);
               clip.open(stream);
               clip.start();
               while (clip.isRunning()) {
                   Thread.sleep(100);
               clip.close();
          catch (Exception e) {
              System.err.println("Error in run in SoundPlayer");
               return false;
          return true;
     }//playSound() method
}//Class SoundPlayer

How to generate .SQL format file from oracle database?

How to generate .SQL format file from oracle database?
I have a database of Oracle 8.1.6,now want to generate script file (including table structure,index,etc.) from it,What should I do?
Thanks.

Your question pertains to the Database Export/Import. This forum exclusively focusses on the export/import utilities that come along with "Oracle Portal" which is a web-based tool. Could you please post your question under the RDBMS export/import or migration forum.

Help reading a .txt file from the hard drive....

Hi guys,
Ok... I need to know how to read a .txt file from the hard drive... I have an example on how to read from a disk, but I don't have a disk drive. I could be confusing terminology, but I don't think I am. Here is the code I have for reading from a disk.. please let me know how I should change it to read from a hard drive.
Also, when the error pops up, it says that it can't read another .txt file that is not specified in the code... any ideas how that is occuring? Please advise.
import java.io.*;
public class TEST {
public static void main(String args[]) throws Exception{
FileReader fr = new FileReader("customer.txt");
BufferedReader bfr = new BufferedReader (fr);
String s;
while ((s=bfr.readLine())!= null){
System.out.println (s);
fr.close();
}

Ok... I need to know how to read a .txt file from the
hard drive... I have an example on how to read from a
disk, but I don't have a disk drive. I could be
confusing terminology, but I don't think I am. Here
is the code I have for reading from a disk.. please
let me know how I should change it to read from a
hard drive.The code will be the same, regardless of where the file is located. It's just the filename that will be different.
Also, when the error pops up, it says that it can't
read another .txt file that is not specified in the
code... any ideas how that is occuring? Please
advise.Probably becuase the class file (compiled version of the source code) is a different version to the source code, i.e. the source code hasn't been recompiled since the source code was changed.
How does this relate to EJBs?

Read a zip file from Application server.

Hi,
Is there a way to read a zip file from the applicatoin server to internal table in ABAP program? The operation system is running MS windows server. The zip file contains only 1 text file. I tried to use open dataset 'uncompress', and use read dataset, but read dataset gave me sy-subrc = 4. Any feedback is greatly appreciated.
Thanks.

hi,
to convert xstring to text you can use this:
DATA unzipped_data TYPE xstring.
DATA text_data TYPE string.
DATA conv_x2c TYPE REF TO cl_abap_conv_in_ce.
conv_x2c = cl_abap_conv_in_ce=>create( ).
conv_x2c->convert( EXPORTING input = unzipped_data IMPORTING data = text_data ).
moreover, if you want to split your text at "end of line" (CR LF in microsoft windows) into lines:
DATA text_lines TYPE TABLE OF string.
SPLIT text_data AT cl_abap_char_utilities=>cr_lf INTO TABLE text_lines.

Is it possible to read DDP formatted files from disc?

Similar Messages

Maybe you are looking for