Is it possible to store a field name in a variable, then assign it a value?

Question

Good day, everyone!
I am working on a program in which there are many different amount fields in which an amount may be assigned.  For reusability purposes, I was wondering if it would be possible to write a routine that identifies the target amount field, stores it in a variable that is passed back to the calling program, and then assigns a value to it.  There may be different structures having the same field name; what I'm trying to do is avoid having to code a huge IF or CASE statement for each structure.  For example:
Structures S1, S2, and S3 have some fields identically named.  Call one of them F1.
What I'd like to do is call a routine that identifies "F1" as my target field to populate.  Then, upon return, I can assign it to the desired structure.  Kinda like this:
S1-fieldname = 24.17.  (but fieldname isn't a true field in the structure -- it would hold the value of the true field, "F1").
I realize this might not even be possible, but given how talented the folks are on this forum, I thought I should at least pose the question.
As always, points given for all helpful answers, and thank you!!
Dave

Answer 1

Ok.  I gave that a shot, but what happens is that my ASSIGN COMPONENT statement doesn't work.  It gets a sy-subrc of 4, and <column> remains unassigned.  The program then abends on the line to assign <a1>-trbtr's value to the field because of <column> being unassigned.
  DATA:
    w_setname         TYPE setleaf-setname,
    w_column_name(20) TYPE c.
    ASSIGN COMPONENT w_column_name OF STRUCTURE wa_expense_ng_report
                  TO <column>.
    <column> = <a1>-trbtr.
Any thoughts on what I might be doing wrong?