Issue with Gregorian Calendar and setting Day of the week

Question

Hi
This may have a simple solution, but its currently got me stumped. Basically, after some calculation I determine the date that a particular event should occur on. These events are listed in a JTable where the column headers are the dates of the beginning of the weeks. In order to place my calculated event in the correct column I create a Gregorian Calendar, set it to the date of the event and then set the day of the week to the beginning of the week. Normally this works fine but for a few instances, rather than getting the date at the beginning of the week, I get the date thats the beginning of the next week.
As a quick example, to kind of illustrate my problem:
I determine that the date of the event is 27/06/2006 which is a Tuesday.
I want this event to appear in the column headed 25/06/2006, the date of the beginning of the week.
In fact it appears in the column headed the 02/07/2006 which is the beginning date of the following week.
Is there anyway to get it so when I set the day to the first day of the week it goes to the beginning of the current week rather than the beginning of the next week?
Any suggestions would be gratefully recieved as I'm currently struggling to think of any.
Thanks

Answer 1

Hi, I dont say Monday is the begining of the week. At least I dont think I do.
As for code I'll post the conversion bit which is:
for (int i = 0; i < areaNameSelectionTable.getRowCount(); i++) {
GregorianCalendar conversionCalendar = new GregorianCalendar();
conversionCalendar.setTime((java.util.Date) prioritiesTable.getValueAt(i, 10));
conversionCalendar.set(GregorianCalendar.DAY_OF_WEEK, GregorianCalendar.SUNDAY);
}//end for loopI then create a string from the GregorianCalendar in the format DD/MM/YYYY and compare that with the headers of my table columns (Also dates in the format DD/MM/YYYY) When they match thats the column this particular event should appear in. I can post this code if necessary, but I dont know if its relevant.
Thanks