Java messgae mapping help pls

Question

hi forum, in message mapping, when i see the XML of the target or source structure i can see the prefix of the qualifiedNameas as ns1 or ns0,
eg., <ns0:MT_sdptest_JMapTest2>
what does that signify....
coz when i made a java mapping programm and tried to test it as an independant program outside XI, taking one XML file as input and one XML file as output, in the code for creating the output structure, i hade created the root element(for the output structure) as
Element rootNode = documentOut.createElementNS("http://zpoc.com.test/sdptest","ns0:MT_sdptest_JMapTest2");
the XML produced gives error as:
"Reference to undeclared namespace prefix: 'ns0'. Error processing resource "
pls help me.....coz i want to intergrate it in a Interface mapping in a scenario

Answer 1

You can remove the namespace prefixes using an XSLT mapping if they are causing problems with applications outside of XI.
Try the following code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.arconw.com/XI/XSLT_Library/XmlNamespacePrefixRemoval"
version="1.0">
<xsl:output method = "xml" />
<xsl:template match="/">
<xsl:apply-templates select="*" mode="remprefix"/>
</xsl:template>
<xsl:template match="*" mode="remprefix">
<xsl:variable name="newname" select="local-name(.)"/>
<xsl:element name="{$newname}" namespace ="{namespace-uri()}">
<xsl:apply-templates mode="copyall" select="@*|comment()|processing-instruction()|text()"/>
<xsl:apply-templates select="*" mode="remprefix"/>
</xsl:element>
</xsl:template>
<xsl:template mode="copyall" match="@*|comment()|processing-instruction()|text()">
<xsl:copy>
<xsl:apply-templates mode="copyall" select="@*|comment()|processing-instruction()|text()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
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Thanks,
Paul D.
Message was edited by:
        Paul Digance