JAXB Help

Question

im looking to do following
I have a XSD . I want to manipulate JAva beans representing the XSD complex types in Java, at runtime , set values in the beans, and then easily generate a XML string out of the java bean
The xml string if written to file must be a valid XML document.
1) can i use JAXB for this
2) any code samples, or pointers to tutorials will really help
thanks

Answer 1

We are using JAXB through Top Link.
What you have to do is to generate the java bean class corresponding to your xml schema using the jaxb compilator in Jdeveloper.
We have seen that the element in the xml schema has to be defined as global or reference a simple or complex type to generated correctly as a class we will have to use later as data control.
Create a java bean that reference you main object class and load the document, by example in the getter.
public Classification getClassificationDocument() {
try {
//Create a JAXBContext instance
jaxbContext = JAXBContext.newInstance("classification.toplinkInterface");
// get the xml document file
file = new java.io.File(this.pathXML);
if (file.exists() == true) {
// create the unmarhaller objet to read the document
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
// read the document into the objet that represent the document structure
classificationDocument =
(Classification)unmarshaller.unmarshal(file);
} catch (Exception e) {
e.printStackTrace();
return classificationDocument;
Use that java bean to generate a data control.
Be careful to the interface that are generated with java.array.util.list that are not typped. For them you have typped manually or you declare the corresponding bean class in the data control xml file corresponding the that iterator.
<?xml version="1.0" encoding="UTF-8" ?>
<JavaBean xmlns="http://xmlns.oracle.com/adfm/beanmodel" version="10.1.3.39.84"
id="ClassificationLanguageType"
BeanClass="classification.toplinkInterface.ClassificationLanguageType"
Package="classification.toplinkInterface" isJavaBased="true">
<Attribute Name="classificationLanguageCode" Type="java.lang.String"/>
<Attribute Name="classificationLanguageLabel" Type="java.lang.String"/>
</JavaBean>
Note also that jdeveloper don't create a data control file for the implementation file and will need it at execution time. Be sure to create a data control manually for the implementation class you will use. classification.toplinkInterface.ClassificationLanguageType is the interface, so i will have to create a data control for classification.toplinkInterface.impl.ClassificationLanguageTypeImpl too.
<?xml version="1.0" encoding="UTF-8" ?>
<JavaBean xmlns="http://xmlns.oracle.com/adfm/beanmodel" version="10.1.3.39.84"
id="ClassificationLanguageTypeImpl"
BeanClass="classification.toplinkInterface.impl.ClassificationLanguageTypeImpl"
Package="classification.toplinkInterface.impl" isJavaBased="true">
<Attribute Name="classificationLanguageCode" Type="java.lang.String"/>
<Attribute Name="classificationLanguageLabel" Type="java.lang.String"/>
<ConstructorMethod IsCollection="false" Type="void"
id="ClassificationLanguageTypeImpl"/>
</JavaBean>
Hope this will help you ...
<?xml version="1.0" encoding="UTF-8" ?>
<JavaBean xmlns="http://xmlns.oracle.com/adfm/beanmodel" version="10.1.3.39.84"
id="ClassificationLanguageTypeImpl"
BeanClass="classification.toplinkInterface.impl.ClassificationLanguageTypeImpl"
Package="classification.toplinkInterface.impl" isJavaBased="true">
<Attribute Name="classificationLanguageCode" Type="java.lang.String"/>
<Attribute Name="classificationLanguageLabel" Type="java.lang.String"/>
<ConstructorMethod IsCollection="false" Type="void"
id="ClassificationLanguageTypeImpl"/>
</JavaBean>
Note that we are using jxpath too search node in the xml document with xpath. That is very very very useful.
Here is an example that search for all main-title in french as a pointer, get the title value and get the correponding identification to generate an alphabetic index from a hierarchical structure.
Hope this will help you