Leap year without date objects

I need to check to see how many leap years are between two user-inputted years and I can't use date objects. I figure I need to start with a for loop, but I get lost when to by the mod 4, mod 100, or mod 400. Any help?
for(int l=cYear; l <= eYear; l++){
 if(l%4 == 0){
 if(l%100 == 0){
 }also, if anyone is bored and really wants to give of themselves, I could use some more help with a pretty challenging-for-my-level program. Let me know.
Message was edited by:
kaluga

yeah, he said like 20 times "one big main method, no
other methods"He's a moron and should not be teaching CS or Java.
Problems: 1. I am having trouble wrapping my mind
around the logic,Meaning what? You described it--or was that just copy/paste of what's in the asisgnent? I gave you some pseudocode that's practically Java already.
Just try it. Take your best shot and write some test cases and see how close you are.
2. I don't know if this (below)
syntax works.Try it. If the syntax is wrong, it won't compile.
Once you get it to compile, then test it. Here's one reason why you'd want a separate method--you could test just that method by itself. As it stands, the easiest way to test it is to always give it just one year and see if you end up with the proper count--zero or one. If you give it many, you could end up with the right number by having the same number of false positives and false negatives.
Once you know it works for one year, feed it a few lists of 5 or 10.
btw jverd, I appreciate your helpYou're quite welcome. It looks like you're on the right track. Just don't be afraid to try stuff and see what happens, and then come back with specific questions about the specific problems you observed. :-)
---- Edit ----Or do like DrClap suggested and print each one. This way you can still test many at once.
Note to self: Duh, Jeff.
---- ---- ----Message was edited by:
jverd

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Here are some helpfull hints for you:
1. Your code is really hard to read, there are two main reasons for this. First, your indentation sucks. Second, you seem to be fascinated with saving two (ok four if you count the shift key) keypresses to avoid using { and }.
2. Not using the brackets (you know { and } which you like to avoid) also is causing your code to do some stuff you don't realize or want to happen, or at least it would be if your code compiled.
3. If statements require arguements, "year == 1" is an arguement, "3" is not an arguement. Each operator like the or operator ("||") is essentially a new if and requires a complete arguement. So the following code peice:
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)Literally translates to if year equals 1 or if 3 or if 5 or if 7 or if 8 or if 10 or if 12. Doesn't make much sense in english, and it doesn't make much sense in Java either.
4. I am pretty sure "year" is not the variable you want in the code snippet above (the one used in hint 3), especially considering years 1, 3, 5, 7, 8, 10, and 12 are not between 1000 and 1999. You need to be really carefull not make these kind of mistakes when coding, because they are by far the hardest to track down and fix later since they don't really throw up any flags or anything at compile or run time. Take your time and think thuroughly about each line of code while coding it, it will save you tons of time in the long run.
5. What exactly do you expect statements like "month = month;" to do? That translates as make month equal to month. Do you go to the bank and say " I have exactly $3.56 in my pocket, so I would like to deposite all $3.56 and then withdraw $3.56 and put it back in my pocket"? How do you think the teller would look at you? Teller would probably do it, but the teller would feel like he/she wasted time with you and that you are not really right in the head. Java feels the same way when you make it do the same thing, and you love to do it.
6. Code like the following is all wrong, and for more reasons than pointed out in hint 5.
if (month >= 1)
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else;Let's say someone put 13 in as the month. It passes the first check because 13 is greater than or equal to 1. so month which is 13, now gets set to 13 (gee that was effective). Now we hit the else and things get confusing because you didn't use brackets or proper indentation (hint 1) so we don't know what your real intent was. Did you mean else do nothing, and the next if statement is then executed, or did you mean to just run the next if statement if the else condition was met? Fortunatly it doesn't matter here because the next if statement is failed anyways since 13 is not less than or equal to 12.
So, we leave this code with month ebing 13, wait when did we add a 13th month to the calendar? Are you using the Jewish calendar? Could be, except even if I put 1234567 as the month your code would except it as valid, and I know no calendar with that many months. Try writing this in english first and translating it to jave, like i would probably say "if the month is greater than or equal to 1 and less than or equal to 12 then the month is valid." Course now what do you do if it is invalid? Hmm, maybe I would actually say "while the month is less than 1 or greater than 12 ask the user for the month" until they get it right.
There are a few other problems, but most of them are probably things you haven't learned yet, and they are not show stoppers so we will let them fly. You already have a lot of work to do to make this better. But I do have one more really really big usefull hint for you:
Never, ever, under any circumstances, should you ever ask in any way or even hint at asking for someone else to provide code solutions to your problems. So "so if you do hint me with some code then I'd appreciate it if it was stuff that's not too advanced " was a very bad thing to do, but fortunatly for you you followed it with proof you were trying to write the code yourself. Had the code you provided not been so full of problems it was obvious a beginner wrote it, you would probably have gotten much less cordial responses. I would seriously consider avoiding any implication of wanting code, at least until you become a regular poster here and people know you are not just looking to get your homework done for you.
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JSG

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 days = days + daysInMonth[cntr];
 millisAfterYear = days * MILLIS_IN_DAY + 1;
 setTimeInMillis(getTimeInMillis() + millisAfterYear);
 *Returns the month stored in this object. With this object 0 represents January and 11 represents December.
 public int getMonth()
 long theseMillis = millisAfterYear;
 int cntr = 0;
 while (theseMillis > (MILLIS_IN_DAY * daysInMonth[cntr]))
 theseMillis = theseMillis - MILLIS_IN_DAY * daysInMonth[cntr];
 cntr++;
 return cntr;
 *Set the day of month to the one passed.
 public void setDayOfMonth(int day)
 if (day < 1 || day > daysInMonth[getMonth()])
 throw new ArrayIndexOutOfBoundsException(day);
 setMonth(getMonth());
 //Internally, this actually works starting at zero, however to anyone using this class it appears to start at 1. Therefore
 //i must subtract one here.
 long addMillis = MILLIS_IN_DAY * (day - 1);
 millisAfterYear = millisAfterYear + addMillis;
 setTimeInMillis(getTimeInMillis() + addMillis + 1);
 *Returns the day of month.
 public int getDayOfMonth()
 int days = (int)(millisAfterYear / MILLIS_IN_DAY);
 int cntr = 0;
 while (days >= daysInMonth[cntr])
 days = days - daysInMonth[cntr];
 cntr++;
 //Internally this class stores dates starting at zero, but i want it to look like it starts at 1.
 return days + 1;
 *Sets the time to the currently selected day at the passed hour on the hour. uses 24 hour clock.
 public void setHour(int hour)
 if (hour < 0 || hour > 23)
 throw new ArrayIndexOutOfBoundsException(hour);
 setDayOfMonth(getDayOfMonth());
 long addMillis = MILLIS_IN_HOUR * hour;
 millisAfterYear = millisAfterYear + addMillis;
 setTimeInMillis(getTimeInMillis() + addMillis);
 *Returns the hour (but not how many minutes past the hour).
 public int getHour()
 long millisAfterDay = millisAfterYear % MILLIS_IN_DAY;
 return (int)(millisAfterDay / MILLIS_IN_HOUR);
 *Set the minutes past the hour. Works 0-59.
 public void setMinute(int minute)
 if (minute < 0 || minute > 59)
 throw new ArrayIndexOutOfBoundsException(minute);
 setHour(getHour());
 long addMillis = MILLIS_IN_MINUTE * minute;
 millisAfterYear = millisAfterYear + addMillis;
 setTimeInMillis(getTimeInMillis() + addMillis);
 *Returns the minutes past the hour, 0-59.
 public int getMinute()
 long millisAfterHour = millisAfterYear % MILLIS_IN_HOUR;
 return (int)(millisAfterHour / MILLIS_IN_MINUTE);
 *Sets the seconds past the minute, 0-59.
 public void setSecond(int second)
 if (second < 0 || second > 59)
 throw new ArrayIndexOutOfBoundsException(second);
 setMinute(getMinute());
 long addMillis = MILLIS_IN_SECOND * second;
 millisAfterYear = millisAfterYear + addMillis;
 setTimeInMillis(getTimeInMillis() + addMillis);
 *Returns the seconds past the minute, 0-59.
 public int getSecond()
 long millisAfterMinute = millisAfterYear % MILLIS_IN_MINUTE;
 return (int)(millisAfterMinute / MILLIS_IN_SECOND);
 *The more commonly seen set method of other date objects. Sets the date/time to 00:00 of the year/month/day passed. Convenience method
 *for setDate(int year, int month, int day, int hour, int minute, int second).
 public void setDate(int year, int month, int day)
 setDate(year, month, day, 0 , 0 , 0);
 *Sets every date/time field.
 public void setDate(int year, int month, int day, int hour, int minute, int second)
 setYear(year);
 setMonth(month);
 setDayOfMonth(day);
 setHour(hour);
 setMinute(minute);
 setSecond(second);
 *Returns yes if the stored date is a leap year. A leap year is every year that is divisible by four unless it is divisible by 100
 *unless it is also divisible by 400.
 public boolean isLeapYear()
 return isLeapYear(this.year);
 *For internal use. Returns if the passed year meets the criteria for a leap year.
 private boolean isLeapYear(int year)
 boolean leapYear = false;
 if (year % 4 == 0)
 if (year % 100 != 0)
 leapYear = true;
 else if (year % 400 == 0)
 leapYear = true;
 return leapYear;
 *Returns the difference in milliseconds between the time stored in this object and the millis passed to this method.
 public long getDifferenceInMillis(long millis)
 return getTimeInMillis() - millis;
 *Returns the difference in milliseconds between this date and the date passed to this method.
 public long getDifferenceInMillis(AwesomeDate otherDate)
 return getDifferenceInMillis(otherDate.getTimeInMillis());
 *Designed to be a wrapper method for the getDifferenceInMillis method. This method changes millis into years/days/whatever. Pass
 *the number of milliseconds you have to convert in the first parameter. The second parameter should be the type of denomination you
 *want (year, day, whatever). Use the MILLIS_IN_* fields associated with this object. Also bear in mind when workin with years that
 *some years are leap years, so in extreme cases of differences of 365+ years you may gain/lose a year.
 public static int toGreaterDenom(long millis, long denom)
 return (int)(millis / denom);
 * The first argument is how many of whatever (days, months, years, etc.) to add (use negative numbers to subtract). For the second
 * argument pass one of the MILLIS_IN_* fields. Thus, to add two hours would be
 * <code>
 * AwesomeDate.adjustDate(2, AwesomeDate.MILLIS_IN_HOUR);
 * </code>
 public void adjustDate(int amount, long typeMillis)
 setTimeInMillis(this.millis + amount * typeMillis);
 *Returns an object of type java.util.Date set to the date/time stored here.
 public java.util.Date toUtilDate()
 long offset = TimeZone.getDefault().getRawOffset();
 return new java.util.Date(getTimeInMillis() + -1 * offset);
// return new java.util.Date(getTimeInMillis());
 *Returns an object of type GregorianCalendar set to the date/time stored here.
 public GregorianCalendar toGregorianCalendar()
 long offset = TimeZone.getDefault().getRawOffset();
 GregorianCalendar cal = new GregorianCalendar();
 cal.setTimeInMillis(getTimeInMillis() - offset);
 return cal;
 *Returns an object of type java.sql.Date set to the date/time stored here.
 public java.sql.Date toSQLDate()
 long offset = TimeZone.getDefault().getRawOffset();
 return new java.sql.Date(getTimeInMillis() - offset);
 /** Format the date using the string that you pass. Works just like the SimpleDateFormat object. Infact, it uses one! Heres
 *how it works:
 *Letter Date or Time Component Presentation Examples 
 *G Era designator Text AD 
 *y Year Year 1996; 96 
 *M Month in year Month July; Jul; 07 
 *w Week in year Number 27 
 *W Week in month Number 2 
 *D Day in year Number 189 
 *d Day in month Number 10 
 *F Day of week in month Number 2 
 *E Day in week Text Tuesday; Tue 
 *a Am/pm marker Text PM 
 *H Hour in day (0-23) Number 0 
 *k Hour in day (1-24) Number 24 
 *K Hour in am/pm (0-11) Number 0 
 *h Hour in am/pm (1-12) Number 12 
 *m Minute in hour Number 30 
 *s Second in minute Number 55 
 *S Millisecond Number 978 
 *z Time zone General time zone Pacific Standard Time; PST; GMT-08:00 
 *Z Time zone RFC 822 time zone -0800 
 public String toFormattedString(String format)
 SimpleDateFormat formattage = new SimpleDateFormat(format);
 return formattage.format(toUtilDate());
 *I overrode the toString method. Now it tells everyone how awesome my AwesomeDate is.
 public String toString()
 String output = "John's Awesome Date!";
 output = output + " Millis: " + getTimeInMillis();
 output = output + " Year: " + getYear();
 output = output + " Month: " + getMonth();
 output = output + " Date: " + getDayOfMonth();
 output = output + " Time: ";
 if (getHour() < 10)
 output = output + "0" + getHour();
 else
 output = output + getHour();
 if (getMinute() < 10)
 output = output + "0" + getMinute();
 else
 output = output + getMinute();
 output = output + " Seconds: " + getSecond();
 return output;
 public static void main(String[] psvm)
 AwesomeDate blah = new AwesomeDate();
 GregorianCalendar blah1 = new GregorianCalendar();
 GregorianCalendar blah2 = new GregorianCalendar();
}

The reason Callendar is so complicated is that it is trying to solve a very complicated problem.
You don't appear to support leap seconds (of which there can be upto 2 in any time interval)
http://www.timeanddate.com/time/leapseconds.html
Some of your code will not work for large dates very well (seems to iterate over the years). Try using your date class for astronomical or geological calculations. them big numbers will make your code slow at the moment.
You don't seem to support timezones or transitory offsets (BST vs GMT). You most definately don't handle changes to timezone offsets that have occured in the past or historical daylight savings time offsets (they have not always been the same)
The difference between two calendars is a "duration" a duration means nothing unless it is applied to a caledar/date (although you may be able to get away with it if the duration is always stored in millis)

Year to Date using SAP variables

I've run into a sticking point when trying to create a year to date calculation that works without user entry. The infocube is updated by finance each month (for the previous month) after the final adjustments are made. For this reason, when the query pulls YTD information, it should be cumulating from January 20XX to Current Month - 1.
The first way that I tried was to use overlapping restrictions: Fiscal Year/Period < Current Fiscal Year/Period AND Fiscal Year = Current Fiscal Year. This worked very well until we reached January. Now the overlapping restrictions return no results since all previous months are not in the current fiscal year.
I've also attempted using the SAP exit variable 0FYTLFP (Cumulated to Last Fiscal year Period) on Fiscal Year/Period. It is not working, and I assume it is because the last fiscal year period is falling into a different fiscal year. Using it today, the value I get is equal to the value for Jan 2007. The variable seems to first look up the first day of the current fiscal year, saves that as one end of the range, then goes to the previous month to get the other end of the range. I tried offsetting this variable by -1 and the value returned was equal to Dec 2006, but not YTD.
I'm assuming it must be possible to use the standard SAP delivered objects to create a working YTD calculation that does not require manual entry and cumulates correctly through current period - 1. Does anyone have any suggestions?
Thanks!

Dear Adam,
For Year to Date , We have created a Customer Exit , For working , Create a Variable for 0calday and populate that with from and to value ...to value would be Sy-datum and From value is year starting date. Hope it helps..
Thanks,
Krish

Bug or error when handling leap years with WDS/DS

Hi all,
I discovered a difference in outcome with Build and Debug (without screens) and Build and Debug with Web Determinations or Determinations Server when calculating days within leap years.
I use the function DayDifferenceInclusive to calculate the amount of days in an insurance period.
the amount of days of the insurance period = DayDifferenceInclusive(the start date of the insurance, the end date of the insurance)
With the regression tester or Build and Debug (without screens) I get the following outcome for the following input:
*93 = DayDifferenceInclusive(02-29-2008, 05-31-2008)*
When we use Web Determinations or Determinations Server we get the value of *92* for the exact same input data when it should be 93.
Is this a bug in the java code? How can we fix this or is there a work around for it?
We're in the middle of System Integration Testing for a huge project so help is much appreciated!
Best regards,
Niels Roest

Niels,
thanks for that - and it looks like in the Netherlands daylight savings started on the 30th of March 2008, which as far as I know is the trigger for this error.
I have reproduced the issue against 10.1 using the period 01 October 2010 to 30 October 2010, which contains the date that daylight saving started in Australia.
As for ways to work around the issue, I can offer 3:
* wait for 10.2 - it's in beta at the moment (though given your opening comments, this might not be an option for you)
* set your server locale to one that doesn't have DST
* work around the issue in rules:
Firstly, the issue is that the shipping version fails because it doesn't take into account that one of the days is shorter than the standard 24 hours.
The trick is to replace the DayDifference function with the HourDifference function and round to the nearest number of days.
So given a rule that looks like:
the result = DayDifference(date one, date two)
it can be rewritten as:
The result = round(HourDifference(date one at 00:00:00, date two at 00:00:00) / 24, 0)
* the whole "at 00:00:00" is necessary because HourDifference works on datetimes, not dates.
Sorry for the hassle.
Regards
Andrew

Leap year without date objects

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