List-range partition

Hi Oracle Gurus,
I have a table with list partition, as the partitions are growing large I need to create subpartitions.
Is it possible to create a range subpartition under list partition. If yes I need that subpartition to be built on time not on date.
Is it possible.

While range-list partitioning exists in 10g, list-range partitioning to the best of my knowledge does not exist. There are some new options in 11g but I can't remember what they are off the top of my head. You can check the on-line documentation to see what your partitioning options are
Your partitioning options will depend on what version of Oracle you are using. Also remember that you need the licence to use the partitioning feature

Similar Messages

Create list-range partition table

Database version: Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
I am trying to create a partition table with LIST-Range, and I am getting this following error, is oracle 10.2.0.4 database supports to create list-range partition(composite)
SQL> CREATE TABLE tbp_list_range
REPORT_DATE DATE,
member_id_01 varchar2(2),
DATE_SERVICE date,
member_id varchar2(15)
PARTITION BY LIST(member_id_01)
SUBPARTITION BY RANGE (DATE_SERVICE)
PARTITION SPTYR04M01_C VALUES('AA','aa')
NOLOGGING
COMPRESS (
SUBPARTITION PTYR12M011 VALUES LESS THAN (TO_DATE(' 2012-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')),
SUBPARTITION PTYR12M021 VALUES LESS THAN (TO_DATE(' 2012-02-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')),
SUBPARTITION recent1 VALUES LESS THAN (MAXVALUE)
PARTITION SPTYR04M01_Yo VALUES('BJ','bj')
NOLOGGING
COMPRESS (
SUBPARTITION PTYR12M01 VALUES LESS THAN (TO_DATE(' 2012-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')),
SUBPARTITION PTYR12M02 VALUES LESS THAN (TO_DATE(' 2012-02-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')),
SUBPARTITION recent2 VALUES LESS THAN (MAXVALUE)
SUBPARTITION BY RANGE (DATE_SERVICE)
ERROR at line 9:
ORA-00922: missing or invalid option
SQL> select * from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for Linux: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
Any help would be greatly appreciated.
Thanks,

any possible work around for this scenario on 10.2.0.4
--thanks

Oracle 11g List - Range Partition - Help Needed

Hi All,
I want to create a composite partition (LIST-RANGE) but RANGE partition should using interval partition
This is my query .
CREATE TABLE "DMSDB"."DEVICE_UTILS"
(     "ULID" VARCHAR2(100 CHAR),
     "IP_ADDRESS" VARCHAR2(24 CHAR),
     "PORT" VARCHAR2(8 CHAR),
     "SHUTDOWN" NUMBER(10,0),
     "LINE_TYPE" NUMBER(10,0) DEFAULT '0',
     "OCCUPIED" NUMBER(10,0),
     "UTILIZATION" NUMBER(10,0),
     "IDLE_TIME" VARCHAR2(32 CHAR),
     "ACTIVATION_TIME" VARCHAR2(32 CHAR),
     "PULLED_DATE" TIMESTAMP (6) DEFAULT SYSDATE,
     "ACCESS_TIME" TIMESTAMP (6) DEFAULT SYSDATE
PARTITION BY LIST(ULID)
          PARTITION PART_DEVUTILS_ULID VALUES (DEFAULT)
     SUBPARTITION BY RANGE( PULLED_DATE)
     PARTITION PART_DEVUTILS_WEEK INTERVAL (NUMTOYMINTERVAL(1,'WEEK'))
Somehow its not working. can you please suggest where i am making mistake?

Interval partitioning is not supported at the subpartition level.
http://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_7002.htm#BABCDDIA
Regards
Girish Sharma

List-range partition and subpartition

Does anyone know that Oracle 10g support partition by list and subpartition by range? Thanks.

check the documentation link [http://download.oracle.com/docs/cd/B19306_01/appdev.102/b31695/dialogs.htm#sthref441]
hope you will find your answer on link page.

NULL partition key in RANGE partition

All,
This is regarding partitioning a table using RANGE partition method. But the partition key contains null. How do I handle this situation? This is because there is no DEFAULT partition in RANGE partition though its present in LIST partition. Will rows with NULL partition key fall in MAXVALUE partition? Seeking your guidence.
Thanks,
...

NULLS would fit into the MAXVAL partition yes.
http://download.oracle.com/docs/cd/B19306_01/server.102/b14220/partconc.htm#sthref2590
Thanks
Paul

Is there any plan of allowing non-range partitioning of spatial indexes

our application is really lacking the ability of spatial index being partitioned by list. We are binning information in our data warehouse by spatial locations, and when we query it (actually, MapViewer is generating a tile), entire geometry set is searched because table is list-partitioned and we cannot have local spatial index.

Hi,
I'm not in a position to answer the question about list partitioning, but would a pseudo-list partition implemented as a range partition work? For example, something like this:
CREATE TABLE customers (
first_name    VARCHAR2(20),
last_name     VARCHAR2(20),
address_1     VARCHAR2(20),
address_2     VARCHAR2(20),
city          VARCHAR2(20),
state_abrv    VARCHAR2(3),
postal_code   VARCHAR2(10),
customer_id   NUMBER NOT NULL UNIQUE)
PARTITION BY RANGE (state_abrv)
   PARTITION ALASKA         VALUES LESS THAN ('AKz'),
   PARTITION ALABAMA        VALUES LESS THAN ('ALz'),
   PARTITION ARKANSAS       VALUES LESS THAN ('ARz'),
   PARTITION AMERICANSAMOA VALUES LESS THAN ('ASz'),
   PARTITION ARIZONA        VALUES LESS THAN ('AZz'),
   PARTITION CALIFORNIA     VALUES LESS THAN ('CAz'),
   PARTITION WYOMING        VALUES LESS THAN ('WYz')
   );I've used this method in the past, although I agree a list partitioning solution is much preferred.
Dan

Subpartition existing range partition in Oracle

I have table xyz with following structure
xyz ( vld_dte date,
prd_typ varchar2(100),
sales number
table XYZ is partitioned by range on field vld_dte and partitions are monthly partitions like JAN-2009 , FEB-2009....DEC-2009 and so on.table is currently loaded with data.
How can I modify existing range partition into composite range-list partition so that every partiton is subpartitioned on prd_typ , basically three sub-partitions for every partition 1- Grocery , 2-Home decoration,3-OTHERS

ORA-14759: SET INTERVAL is not legal on this table.
Cause: ALTER TABLE SET INTERVAL is only legal on a range partitioned table with a single partitioning column. Additionally this table cannot have a maxvalue partition.
Action: Use SET INTERVAL only on a valid table
mark answered post as helpful / correct*

Problem with a 2 columns Range Partitioning for a indexed organized table

have an indexed organized table with a 2 column PK. the first field (datum) is a date field the second field (installatieid) is a number(2) field.
Every minute a 7 records are inserted (installatieid 0-6).
I like to partition this table with one partition per year per installatieid.
I tried to do it with:
partition by range(datum,installatieid)
(partition P_2004_0 values less than (to_date('2004-01,'yyyy-mm'),1)
,partition P_2004_6 values less than (to_date('2004-01','yyyy-mm'),7)
partition P_2005_0 values less than (to_date('2005-01','yyyy-mm'),1)
,partition P_2005_6 values less than (to_date('2005-01','yyyy-mm'),7)
but now only the P_2004_0 and P_2005_0 are filled.
I thought about to combine a range partition on datum with a list subpartition on installatieid, but I read this is not allowed with an index organized table.
How can I solve this problem.

partition by range(datum,installatieid)
(partition P_2004_0 values less than
(to_date('2004-01,'yyyy-mm'))
,partition P_2004_6 values less than
(to_date('2004-07','yyyy-mm'))
partition P_2005_0 values less than
(to_date('2005-01','yyyy-mm'))
,partition P_2005_6 values less than
(to_date('2005-07','yyyy-mm'))
? Sorry haven't got time to test it this morning ;0)

Using range partition

my table has partition and subpartition like -----
PARTITION BY RANGE (SEGMENT_)
SUBPARTITION BY LIST (DATE_FOR_PURGE)
PARTITION S_1 VALUES LESS THAN (2)
NOLOGGING
NOCOMPRESS
TABLESPACE TAO_TBL
( SUBPARTITION S_1_D_99999999 VALUES (99999999) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20100520 VALUES (20100520) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20100628 VALUES (20100628) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20100629 VALUES (20100629) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20100705 VALUES (20100705) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20100708 VALUES (20100708) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20100930 VALUES (20100930) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20101001 VALUES (20101001) TABLESPACE TAO_TBL,
SUBPARTITION S_1_D_20101002 VALUES (20101002) TABLESPACE TAO_TBL )
i want to use partition in the select clause
what will be the query?

You mean that you want to explicitly set the partition in the select statement?
SELECT <column list>
FROM <table name>
PARTITION (<partition name>)
WHERE<predicates>

Unique key on range-partitioned table

Hi,
We are using a composite range-hash interval partitioned table
Uses index - trying to make this have same tablespace as the partitions i.e. local but not liking it
alter table RETAILER_TRANSACTION_COMP_POR
add constraint RETAILER_TRANSACTION_COMP_PK primary key (DWH_NUM)
using index
LOCAL
ora-14039: partitioning columns must form a subset of key columns of a unique index
Without local then fine but doesn't have same tablespace as the partitions and don't want to make this part of partition key.
Tbale range partitioned - this is just a UK to prevent duplicates

[oracle@localhost ~]$ oerr ora 14039
14039, 00000, "partitioning columns must form a subset of key columns of a UNIQUE index"
// *Cause: User attempted to create a UNIQUE partitioned index whose
//          partitioning columns do not form a subset of its key columns
//          which is illegal
// *Action: If the user, indeed, desired to create an index whose
//          partitioning columns do not form a subset of its key columns,
//          it must be created as non-UNIQUE; otherwise, correct the
//          list of key and/or partitioning columns to ensure that the index'
//          partitioning columns form a subset of its key columns

Existing Range partition to Interval Partition

I have an Range and list partition tables on Oracle 11g with some records and have to move the
range and List partition tables to interval partitions. I tried for the range partition
table with following query,
SQL> alter table F_PTP_PAYMENTS set interval (numtoyminterval(3,'MONTH'));
alter table F_PTP_PAYMENTS set interval (numtoyminterval(3,'MONTH'))
ERROR at line 1:
ORA-14759: SET INTERVAL is not legal on this table.
it doesnt worked out.
Can you please help me to create the interval partitions.

ORA-14759: SET INTERVAL is not legal on this table.
Cause: ALTER TABLE SET INTERVAL is only legal on a range partitioned table with a single partitioning column. Additionally this table cannot have a maxvalue partition.
Action: Use SET INTERVAL only on a valid table
mark answered post as helpful / correct*

About range partition

Dear Friends ,
I am using Oracle10g . I have to create a range partition like below :
CREATE TABLE EMP
EMPNO NUMBER(4),
ENAME VARCHAR2(10 BYTE),
JOB VARCHAR2(9 BYTE),
MGR NUMBER(4),
HIREDATE DATE,
SAL NUMBER(7,2),
COMM NUMBER(7,2),
DEPTNO NUMBER(2)
PARTITION BY RANGE(hiredate)
PARTITION emp_1980 VALUES LESS THAN(TO_DATE('31/12/1980','DD/MM/YYYY')) TABLESPACE USERS,
PARTITION emp_1981 VALUES LESS THAN(TO_DATE('31/12/1981','DD/MM/YYYY')) TABLESPACE USERS,
PARTITION emp_1982 VALUES LESS THAN(TO_DATE('31/12/1982','DD/MM/YYYY')) TABLESPACE USERS,
PARTITION emp_1987 VALUES LESS THAN(TO_DATE('31/12/1987','DD/MM/YYYY')) TABLESPACE USERS
But the problem is :
1) if any input data is not match with the above criteria then where it goes ? i mean , the data which dont follow the above rule which partition it goes ? is there any way to set DEFAULT partition option in the range partition ?
I only find the DEFAULT option in LIST partition
2) Barring this , when I add a new partition with the above then it shows the below error :
alter table emp add partition emp.emp_1988 VALUES LESS THAN(TO_DATE('31/12/1988','DD/MM/YYYY')) TABLESPACE USERS
Error :
"ORA-14020: this physical attribute may not be specified for a table partition" ,
Would anybody plz help me , How can I solve the above problems ?

Range Partitioning provides for a range of values. Therefore, any value higher than the maximum value provided in your partition definitions would fail. Thus, for example, 01/01/1988 and above would error. That is why Range Partitioning allows you to specify a "highest" values possible where you say "values less than (MAXVALUE)". Therefore, if you had included an "emp_maxvalue" partition with "values less than (MAXVALUE)" after the "emp_1987" partition, any value for 1988 or higher would go into the emp_maxvalue partition.
{ Since there is no minvalue specified, a value of, say, 01/06/1979 would go into the "emp_1980" partition as it is "less than (01/01/1980)" ! }
Again, as Partitioning is a Range of Dates, you cannot add a partition. You have to SPLIT a partition. For example, if you had an "emp_maxvalue" partition present, in order to create the emp_1988 partition, you would SPLIT "emp_maxvalue" into two partitions : emp_1988 and emp_maxvalue.
Please read the documentation on Partition Maintenance in the Administrator's Guide.
Hemant K Chitale
http://hemantoracledba.blogspot.com

Create range partition

hi ,
Oracle 10.2.0.1.0
I'm getting error while creating a range partition to already existing table (method employed : partition swap method ) .
PF screen shot of error
SQL> ed
Wrote file afiedt.buf
1 create table employee_details_temp partition by range (eid) (
2 partition eid_1r values less than (1000)
3 partition eid_2r values less than (20000)
4 partition eid_3r values less than (40000)
5 partition eid_3r values less than (maxvalue)
6* )
SQL> /
partition eid_2r values less than (20000)
ERROR at line 3:
ORA-14020: this physical attribute may not be specified for a table partitionalso ,
SQL> ed
Wrote file afiedt.buf
1 create table employee_details_temp partition by range (eid) (
2 partition eid_1r values less than (1000)
3 partition eid_2r values less than (20000)
4 partition eid_3r values less than (40000)
5 partition eid_3r values less than (maxvalue)
6 ) as select * from employee_details where 1=1;
7* /
SQL> /
partition eid_2r values less than (20000)
ERROR at line 3:
ORA-14020: this physical attribute may not be specified for a table partition please help .

answered .

How to find out the min & max partition_id in a range partition?

Hi we have a table set up by range partition
In the table creation script. It goes something like:
PARTITION PARTD_CUST_3_1_NEW VALUES LESS THAN ('39500')
so how we can find out this number '39500' from some of the data_dictionary view?
What we want to do is to set up parallel processing (do-it-yourself) based on partition.
So the number of parallel process will be based on this ID-range.
I can find out how many partitions are there by using something like this:
SELECT COUNT(*)
FROM all_tab_partitions WHERE table_owner='OWNER_NAME' AND table_name='TABLE_NAME'
We have 5 partitions now but the table structure can change in the near future even this table has moer than 130Million rows
I do not want to hardcode this "39500" just in case the table structure changes (partition structure changes)
Any idea ??

vxwo0owxv wrote:
Hi we have a table set up by range partition
In the table creation script. It goes something like:
PARTITION PARTD_CUST_3_1_NEW VALUES LESS THAN ('39500')
so how we can find out this number '39500' from some of the data_dictionary view?
What we want to do is to set up parallel processing (do-it-yourself) based on partition.
So the number of parallel process will be based on this ID-range.
I can find out how many partitions are there by using something like this:
SELECT COUNT(*)
FROM all_tab_partitions WHERE table_owner='OWNER_NAME' AND table_name='TABLE_NAME'
We have 5 partitions now but the table structure can change in the near future even this table has moer than 130Million rows
I do not want to hardcode this "39500" just in case the table structure changes (partition structure changes)
Any idea ??query DBA_TAB_PARTITIONS.HIGH_VALUE

Non-Partitioned Global Index on Range-Partitioned Table.

Hi All,
Is it possible to create Non-Partitioned Global Index on Range-Partitioned Table?
We have 4 indexes on CS_BILLING range-partitioned table, in which one is CBS_CLIENT_CODE(*local partitioned index*) and others are unknown types of index to me??
Means other 3 indexes are what type indexes ...either non-partitioned global index OR non-partitioned normal index??
Also if we create index as :(create index i_name on t_name(c_name)) By default it will create Global index. Please correct me......
Please help me in identifying other 3 indexes types by referring below ouputs!!!
select INDEX_NAME,TABLE_NAME,PARTITIONING_TYPE,LOCALITY from dba_part_indexes where TABLE_NAME='CS_BILLING';
INDEX_NAME TABLE_NAME PARTITI LOCALI
CSB_CLIENT_CODE CS_BILLING RANGE LOCAL
select index_name,index_type,table_name,table_type,PARTITIONED from dba_indexes where table_name='CS_BILLING';
INDEX_NAME INDEX_TYPE TABLE_NAME TABLE_TYPE PAR
CSB_CREATE_DATE NORMAL CS_BILLING TABLE NO
CSB_SUBMIT_ORDER NORMAL CS_BILLING TABLE NO
CSB_CLIENT_CODE NORMAL CS_BILLING TABLE YES
CSB_ORDER_NBR NORMAL CS_BILLING TABLE NO
select INDEX_OWNER,INDEX_NAME,TABLE_NAME,COLUMN_NAME from dba_ind_columns where TABLE_NAME='CS_BILLING';
INDEX_OWNER INDEX_NAME TABLE_NAME COLUMN_NAME
RPADMIN CSB_CREATE_DATE CS_BILLING CREATE_DATE
RPADMIN CSB_SUBMIT_ORDER CS_BILLING SUBMIT_TO_INVOICE
RPADMIN CSB_SUBMIT_ORDER CS_BILLING ORDER_NBR
RPADMIN CSB_CLIENT_CODE CS_BILLING CLIENT_CODE
RPADMIN CSB_ORDER_NBR CS_BILLING ORDER_NBR
select dip.index_name, dpi.locality, dip.partition_name, dip.status
from dba_part_indexes dpi, dba_ind_partitions dip
where dpi.table_name ='CS_BILLING'
and dpi.index_name = dip.index_name;
INDEX_NAME LOCALI PARTITION_NAME STATUS
CSB_CLIENT_CODE LOCAL CSB_2006_4Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2006_3Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2007_1Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2007_2Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2007_3Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2007_4Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2008_1Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2008_2Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2008_3Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2008_4Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2009_1Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2009_2Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2009_3Q USABLE
CSB_CLIENT_CODE LOCAL CSB_2009_4Q USABLE
select * from dba_part_indexes
where table_name ='CS_BILLING'
and locality = 'GLOBAL';
no rows selected
-Yasser
Edited by: YasserRACDBA on Mar 5, 2009 11:45 PM

Yaseer,
Is it possible to create Non-Partitioned and Global Index on Range-Partitioned Table?
Yes
We have 4 indexes on CS_BILLING range-partitioned table, in which one is CBS_CLIENT_CODE(*local partitioned index*) and others are unknown types of index to me??
Means other 3 indexes are what type indexes ...either non-partitioned global index OR non-partitioned normal index??
You got local index and 3 non-partitioned "NORMAL" b-tree tyep indexes
Also if we create index as :(create index i_name on t_name(c_name)) By default it will create Global index. Please correct me......
Above staement will create non-partitioned index
Here is an example of creating global partitioned indexes
CREATE INDEX month_ix ON sales(sales_month)
   GLOBAL PARTITION BY RANGE(sales_month)
      (PARTITION pm1_ix VALUES LESS THAN (2)
       PARTITION pm2_ix VALUES LESS THAN (3)
       PARTITION pm3_ix VALUES LESS THAN (4)
        PARTITION pm12_ix VALUES LESS THAN (MAXVALUE));Regards

List-range partition

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