Location of XMl file of a Concurrent Request

Hi All,
I have developed a report in XML Publisher. The report runs successfully in DEV. Now this has been migrated to higher instances. The data is not correctly appearing in the report. I want to debug this .
I understand that when we click on Diagnostics and View XML on the concurrent request ,we see the ..XML file with all the tags generated. Up until this point its working fine.
My problem comes, while viewing the XML. The XML file with tags stops after few records saying that there is an Invalid character.
My question here is , "DOES ANY ONE KNOW WHERE DOES THIS XML FILE WITH THE RUNTIME TAGS STORE IN THE APPLICATION"?. Please help me
Thanks for taking time to read and help me
Thanks
Sandeep

Similar Messages

The output file for your concurrent request is not initialized

Application: Application Object Library(FND)
Component Type: SERVICE_INSTANCE
Component Name: Standard Manager(STANDARD)
/*The output file for your concurrent request is not initialized.
Cause: Your concurrent program execution was not preceded by calls to standard
Application Object Library routines to initialize concurrent processing. FDPFOP
received a return code of failure.
Action: Change your concurrent program to initialize files by calling standard
Application Object Library routines. */
I got the mail with the above message from System ( Oracle Applicaitons Release 12.1.1)
I have checked the following metalink document
The Output File For Your Concurrent Request is Not Initialized: FDPFOP received a return code of failure [ID 296830.1]
I can not undestand, why the alert sends mail?
Could you please let me know..what happened to standard manager? how to resolve the above issue? why the above alert happened?
The above meatlink note did not help much....

Hi;
>
/*The output file for your concurrent request is not initialized.
Cause: Your concurrent program execution was not preceded by calls to standard
Application Object Library routines to initialize concurrent processing. FDPFOP
received a return code of failure.
Action: Change your concurrent program to initialize files by calling standard
Application Object Library routines. */
The Output File For Your Concurrent Request is Not Initialized: FDPFOP received a return code of failure [ID 296830.1]
I can not undestand, why the alert sends mail? Could you please let me know..what happened to standard manager? how to resolve the above issue? why the above alert happened?I checked related note and it mention its internal bug which mean we cant say too many thing about issue.
The above meatlink note did not help much....It helped or not? Issue still appear or not?
Please run adadmin utulity >> from Maintain Applications Files>> Relink Applications programs
Be sure it wont through any error message than retest issue
Regard
Helios

Concurrent request output files removed - now concurrent requests failing

Hi.
I recently removed all *.out files from the concurrent request out directory that were older than 5 days.
I didnt think these were needed, only recorded output from earlier concurrent requests. But now we have a request complaining that
The Applications File Server could not open the file /apps/prod/prodcomn/admin/out/PROD/o16499119.out for read.
Any ideas?
Thanks.
Oracle 10.2.0.4
EBS 11.5.0.2
DA

Dan,
It is expected to get this error as the concurrent request output file is missing. The only way to fix this error is to restore the out files from a recent backup you have taken. Or, ask the user to submit the same concurrent program again and a new out file will be created then.
Thanks,
Hussein

Problems by getting info out of XML file with a HTTP request

Hi,
I have a litte question. I'm working on an application that works together with google maps. In my java code, I get general information about address out of one database table, and I want to add some geographic information like coordinates that I want to retrieve from Google Maps through HTTP:
Right now my code is like:
while (resultSet.next())
                         title = resultSet.getString("title").replaceAll("'","''").toUpperCase();
                         author = resultSet.getString("author").replaceAll("'","''").toUpperCase();
                         location = resultSet.getString("location").replaceAll("'","''").toUpperCase();
                         straatnaam = resultSet.getString("straatnaam").replaceAll("'","''").toUpperCase();
                         nummer = resultSet.getString("nummer");
                         landcode = resultSet.getString("landcode").replaceAll("'","''").toUpperCase();
                         address = straatnaam + " " + nummer + " , " + location + " " + landcode;
                         url = "http://maps.google.com/maps/geo?q=" + address + "&output=xml&key=+key+";
                         String query = "INSERT INTO data2 VALUES ('" + i + "','" + title + "','" + author + "','" + resultSet.getString("date1") + "','" + resultSet.getString("date2") + "','" + location + "','" + resultSet.getString("postcode") + "','" + straatnaam + "','" + resultSet.getString("nummer") + "','" + landcode + "','+something like url.getCoordX+','something like url.getCoordY')";
                         success = sql2.executeUpdate(query);
                         i++;
Now I don't know how I can handle that. Is it possible to do an HTTP request in Java without using Java Script of servlets? I just want to get the X and Y coordinates out of the XML file.
The XML file will be something like:
<kml xmlns="http://earth.google.com/kml/2.0">
<Response>
<name>1600 amphitheatre mountain view ca</name>
<Status>
<code>200</code>
<request>geocode</request>
</Status>
<Placemark>
<address>
1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA
</address>
<AddressDetails Accuracy="8">
<Country>
<CountryNameCode>US</CountryNameCode>
<AdministrativeArea>
<AdministrativeAreaName>CA</AdministrativeAreaName>
<SubAdministrativeArea>
<SubAdministrativeAreaName>Santa Clara</SubAdministrativeAreaName>
<Locality>
<LocalityName>Mountain View</LocalityName>
<Thoroughfare>
<ThoroughfareName>1600 Amphitheatre Pkwy</ThoroughfareName>
</Thoroughfare>
<PostalCode>
<PostalCodeNumber>94043</PostalCodeNumber>
</PostalCode>
</Locality>
</SubAdministrativeArea>
</AdministrativeArea>
</Country>
</AddressDetails>
<Point>
<coordinates>-122.083739,37.423021,0</coordinates>
</Point>
</Placemark>
</Response>
</kml>
many greetings and thanks in advance
Mathias

Hi, sorry for being not so clear. My question was actually if it is possible to do a HTTP request in Java without using servlets or being in Java Script. Actually my question was more specific for Google maps, because it didn't seem to work. It was my mistake, and already solved, to forget to make the webservice-call "URL-encoded". Because of that, I always received a HTTP 400 error, and that's why I thought it wouldn't be possible.
But now I have another, perhaps for you guys stupid question. The result I get from the webservice URL is of the form:
<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.0">
<Response>
     <name>nieuwelaan 38, Hamme</name>
     <Status>
          <code>200</code>
          <request>geocode</request>
     </Status>
     <Placemark id="p1">
          <address>Nieuwelaan 38, 9220 Hamme, Hamme, Belgium</address>
          <AddressDetails Accuracy="8" xmlns="urn:oasis:names:tc:ciq:xsdschema:xAL:2.0">
          <Country>
               <CountryNameCode>BE</CountryNameCode>
               <AdministrativeArea>
                    <AdministrativeAreaName>Vlaams Gewest</AdministrativeAreaName>
                    <SubAdministrativeArea>
                         <SubAdministrativeAreaName>Oost-Vlaanderen</SubAdministrativeAreaName>
                         <Locality>
                              <LocalityName>Hamme</LocalityName>
                              <DependentLocality>
                                   <DependentLocalityName>Hamme</DependentLocalityName>
                                   <Thoroughfare>
                                        <ThoroughfareName>Nieuwelaan 38</ThoroughfareName>
                                   </Thoroughfare>
                                   <PostalCode>
                                        <PostalCodeNumber>9220</PostalCodeNumber>
                                  </PostalCode>
                             </DependentLocality>
                        </Locality>
                    </SubAdministrativeArea>
               </AdministrativeArea>
         </Country>
         </AddressDetails>
         <Point>
               <coordinates>4.126295,51.097724,0</coordinates>
         </Point>
     </Placemark>
</Response>
</kml> Now I want to get the value of the coordinates field.
This is my code:
address = URLEncoder.encode(address, "UTF-8");
urlString = "http://maps.google.com/maps/geo?q=" + address + "&output=xml&key=ABQIAAAA9fEXNK-q6vKpPU0JCmPPkxQjbVBpjtblJJYkDfbMo0e51afwehRmujfvBtJqx1Qehg6e6QgCRY8poA";
url = new URL(urlString);
XPath xPath = XPathFactory.newInstance().newXPath();
Document domDoc = processData(url);
path = "/kml/Response/Placemark/Point/coordinates";
coord = xPath.evaluate(path, domDoc);
System.out.println("coord : " + coord);Now, in the last line, by writing out the value of coord to my screen, I get the value "1", instead of "4.126295,51.097724,0" I would expect, anyone knows what I'm doing wrong?
greetings
Mathias

Use parameter to define location of xml-file

Hi,
here is a question about importing data from a xml-file using the xfa.host.importdata
A tool we use generates a copy of a 'template'-pdf an put it into a unique folder. This unique folder will contain:
(1) a Batch-file
(2) a fillable, certified, reader-enabled pdf
(3) a xml-file containing data for the pdf
The batchfile will run a command 'start iexplore.exe file://C:/Doc.pdf?Address="C:/Doc.xml"
So, the Internet Explorer will be started, opens the local PDF and creates a parameter with the location of the xml-file.
So, now is my question how to make it work that in the DocReady-event the command xfa.host.importdata(); will be executed pointing to the xml-file. It should be like xfa.host.importdata("C:/Doc.xml");
If I put the command in the click-event of a button, it works fine, but I need help with setting up that command using the parameter.
Thank in advance!
Erik

You will not be able to automate using script the reading of a data file. This is deemed a security risk (as the user is not aware that this iis happening) and as such the user must pick the file.
There is another way though. There is an xml format supported by XFA forms called XML Data Package(XDP). This format keeps the data in teh same way as the xml file but allows a couple of goodies in it. Like the template that was used to create the file. If you open your PDF file and save the data out in that xdp format, then open the file in a text editor you will see a reference to the template that was used to load it. Now if you double click the xdp file then it will open the data file, find the reference to the template and merge the data and template together for you. This is not a security risk because the user casued teh data file to open. Note that this will not work on machines that have Designer on it because the XDP extension is registered with Designer and not Acrobat/Reader. If you change that association in Windows then it will work fine.
So my suggested solution is to make your data files xdp files and add the reference to the template that you want to use and have the user launch the xdp file and you shoudl be able to accomplish what you asked for.
Hope that helps
Paul

Specifying Schema Location in XML file and not in the Java code

I have a repository of schema xsd files. When I receive my xml file, I need to validate it against the specified schema. The xml file would declare the schema location, using the following syntax:
<CERD:CERD xsi:schemaLocation = "..\CERD.xsd" xmlns:CERD = "CERD.xsd" xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance">
Is it really necessary to define the schema location again in the JAVA code? Why set the schemaLocation in the xml file at all then?
Does anybody have any examples where the schema location is not set in the JAVA code? I am using Java 1.6, and at this point in time I only need to validate. Any help would be appreciated.

Thank you very much for your quick reply. I have made some progress but I am still stumped.
In my code I am doing this:
SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = factory.newSchema();
Validator validator = schema.newValidator();
validator.validate(XML_SOURCE);
I find this works if my schema does not have a target namespace. I have downloaded the following simple example from the internet that uses a target namespace and it fails:
library1.xsd:
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://example.org/prod"
xmlns:prod="http://example.org/prod">
<xsd:element name="product" type="prod:ProductType"/>
<xsd:complexType name="ProductType">
<xsd:sequence>
<xsd:element name="number" type="xsd:integer"/>
<xsd:element name="size" type="prod:SizeType"/>
</xsd:sequence>
<xsd:attribute name="effDate" type="xsd:date"/>
</xsd:complexType>
<xsd:simpleType name="SizeType">
<xsd:restriction base="xsd:integer">
<xsd:minInclusive value="2"/>
<xsd:maxInclusive value="18"/>
</xsd:restriction>
</xsd:simpleType>
</xsd:schema>
<prod:product xmlns:prod="http://example.org/prod"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="library1.xsd"
effDate="2001-04-02">
<number>557</number>
<size>10</size>
</prod:product>
I get the following SAXParseException when I validate:
[line 4, col 36|
cvc-elt.1: Cannot find the declaration of element 'prod:product'.
Am I doing something wrong with the namespace declaration?
Edited by: alfredamorrissey on Oct 31, 2007 6:34 AM

Add node at particular location in XML file

I'd like to add an item to a particular location in an XML file. Location of parent node is given by string variable "itemtoaddto" and the XML file is given by "myXML":
function TraverseXMLfile(itemtoaddto,myXML): void {
    var AttributeList:XMLList = myXML.attributes() + myXML.*.attributes() + myXML.*.*.attributes();
     for each (var labelname:XML in AttributeList) {
      if(labelname == itemtoaddto){
        trace (labelname + "match found!!!!!");
        myXML.*.labelname.appendChild(<SON name="Will" bday="01/15" />);
In the above code, the parent item is being found in fact it's printing the "match found!!!!!" message. However, the line
       myXML.*.labelname.appendChild(<SON name="Will" bday="01/15" />);
is giving the following error:
     TypeError: Error #1086: The appendChild method only works on lists containing one item.
Can someone help please? thanks.

var myXML:XML = <product>
                            <subAssembly label="Sub1"> 
                                <part label="Part1_1"/> 
                                <part label="Part1_2"/> 
                                <part label="Part1_3"/> 
                                <part label="Part1_4"/> 
                            </subAssembly> 
                            <subAssembly label="Sub2"> 
                                <part label="Part2_1"> 
                                    <feature label="Feature2_1_1"/> 
                                    <feature label="Feature2_1_2"/> 
                                </part> 
                                <part label="Part2_2"> 
                                    <feature label="Feature2_2_1"/> 
                                    <feature label="Feature2_2_2"/> 
                                </part> 
                            </subAssembly> 
                            <subAssembly label="Sub3">  
                                <part label="Part3_1"> 
                                    <feature label="Feature3_1_1"/> 
                                    <feature label="Feature3_1_2"/> 
                                </part> 
                            </subAssembly> 
                        </product>;
myXML.subAssembly.(@label == "Sub1")[0].insertChildAfter(myXML.subAssembly.(@label == "Sub1")[0].part[myXML.subAssembly.(@label == "Sub1").part.length() - 1], <part label="Part1_5"/>);
trace(myXML);
This traces:
<product>
<subAssembly label="Sub1">
    <part label="Part1_1"/>
    <part label="Part1_2"/>
    <part label="Part1_3"/>
    <part label="Part1_4"/>
    <part label="Part1_5"/>
</subAssembly>
<subAssembly label="Sub2">
    <part label="Part2_1">
      <feature label="Feature2_1_1"/>
      <feature label="Feature2_1_2"/>
    </part>
    <part label="Part2_2">
      <feature label="Feature2_2_1"/>
      <feature label="Feature2_2_2"/>
    </part>
</subAssembly>
<subAssembly label="Sub3">
    <part label="Part3_1">
      <feature label="Feature3_1_1"/>
      <feature label="Feature3_1_2"/>
    </part>
</subAssembly>
</product>

Generating a XML file from a JSP request Page

Hi,
I am very new to JAVA with XML. My need is i want to capture some data in in a JSP page then after submitting ,it will generate a XML file. How can i do that??? Any help will be highly appriciated. If anybody can give me a good example....
Thx

<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Steven Muench ([email protected]):
Are you using our XML SQL Utility that comes with the Oracle XDK for Java? Is the correct result produced, but you are having trouble writing it to a file?<HR></BLOCKQUOTE>
hi steven,
yes i am using xml sql utility and have solved the problem..... as i was working from a remote system i didnot give the correct path that is the c:\.....etc of the machine i was giving http:// thats why i did not write to a file... now its working

Location of XML files

I am looking into using the XML SQL utility to generate XML documents. Is it possible for the XML documents to be output to any location?

Using the oracle.xml.parser.v2.XMLDocument.print() method is a good place to start. From here you can output the file to any file on your network (with permissions set correctly):
doc.print(new java.io.FileOutputStream(new File("H:/testing.xml")));

XML Output from Concurrent Request DBMS_XMLGEN

I am trying to create xml output for a concurrent request, using the DBMS_XMLGEN package to generate my XML?
I have gotten so far as to be able to run my procedure and see the output in TOAD using dbms_output.put_line, but I can't seem to quite get the right link to convert this to Oracle Apps output.
I have a concurrent request setup to output XML.
This calls my procedure to return to the output file.
So far, when I run from APPS, all that shows in the Output file is 'XML document must have a top level element.'
Here is the relevant code...
ctx DBMS_XMLGEN.ctxHandle; -- vars to convert SQL output to xml
xml clob;
xmlc varchar2(4000);
off integer := 1;
len integer := 4000;
i number := 0;
rc_data sys_refcursor;
begin
-- this calls simple open cursor for sql statement, returns rows
rc_data := fa10022_data(P_BOOK_TYPE_CODE
, P_STATE
, v_BEG_DATE_EFFECTIVE
, v_END_DATE_EFFECTIVE
, P_BEG_ASSET_ACCT
, P_END_ASSET_ACCT
, v_depr_per_ctr);
ctx := dbms_xmlgen.newContext(rc_data);
dbms_xmlgen.setRowsetTag(ctx, 'XXFA10022');
dbms_xmlgen.setRowTag(ctx, 'G_DATA');
xml := dbms_xmlgen.getXml(Ctx);
i := dbms_xmlgen.getNumRowsProcessed(ctx);
dbms_xmlgen.closeContext(Ctx);
apps.fnd_file.put_line(apps.fnd_file.output, xml);
I was also following this link...
http://www.appsassociates.com/products/Generation_XML_PLSQL.pdf
any suggestions?
Thanks!!
Janel

That was painful, but it helped!
Most of it is workflow code...POXMLGEN contains the pertinent coding.
I think my problem now lies with some of my data. Depending on what is returned, I sometimes receive a warning with no output. I know there are special characters in the data (ex eacute), but I can't tell if that is what is causing the issue. I do have the statement dbms_xmlgen.setConvertSpecialChars(ctx, TRUE); in my code, so not sure what else to do.
This is what is being returned in OPP log...
Caused by: oracle.xdo.parser.v2.XMLParseException: Start of root element expected.

How can i send xml file with a http servlet request

Hi
Please tell me how can I send a xml file into http servlet request.
I have a servlet(action) java file.From this servlet I have generate a xml file. Now I need to send that xml file to another servlet with http servlet request object.
Dave.

When you say you have generated an XML file what do you mean?
Is it a file stored on disk? Then pass the file path as a string to the servlet.
Is it stored in memory as an object? The pass a reference to the object to the servlet.
Or are you asking how to communicate between servlets?
Look in the JavaDocs for the RequestDispatcher class. You can use this class to forward the request to another servlet. Data can be passes using the RequestDispatcher by storing it as attributes using the request getAttribute and setAttribute methods. Also described in the JavaDOcs.
http://java.sun.com/j2ee/1.4/docs/api/javax/servlet/RequestDispatcher.html

Javascript request on non well-formed xml file in Safari

Hi,
I make an AJAX request to get a non well-formed xml file. On Internet Explorer (domNode is empty) and Firefox (domNode is not empty but a tag "parsererror" is present), I can know if the document is non well-formed but on Safari the request seems to be ok, I get a part of the non well-formed file (until the error).
I would like to say if I can make the difference between a well-formed xml file and a non well-formed xml file (with an AJAX request) on Safari.
Thanks
Julien

I have built a desktop application that can use these
calls to check if the xml contained in the document
called "file" is well formed.
Ok. So, the application works fine then?
DocumentBuilderFactory domFactory =
DocumentBuilderFactory.newInstance();
DocumentBuilder domBuilder =
lder domBuilder = domFactory.newDocumentBuilder();
domBuilder.parse(file);
They are part of the javax.xml.parsers.*; package.
Problem is that to serve this I need to put it in an
applet but since I have to write the xml string to a
file local to the server the applet is not working.
Huh? You lost me there. Are you getting security exceptions from the applet? If yes, you need to sign the applet. Otherwise, what is not 'working' in the applet compared to the application? Also, why do you need to first write it to a file?
My question is if anyone knows of some classes in the
API that will allow me to check if a String of XML is
well formed or not.
If the document is not well-formed, the parse() call will throw an exception. Catch this and process as needed.
I basically need to get a string from a field in a
data base in XML format and be able to test it
without first writing it to a document so I can get
the applet to work.
If you want to access an external database from an applet, you will need to sign the applet. You should not need to first write it to a file before parsing. Rather, simply use a stream (either InputStream or Reader) and wrap it in a StreamSource object.
If anyone knows something on this or has an
alternative suggestion please do tell.
Thanks.- Saish

StringWrite to Parse an XML File

I am creating a Servlet which recieves a XML FIle as a post request. Then I want to parse it, I am facing java.net.MalformedURLException. My code is as follows:
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
BufferedReader inReader = request.getReader();
char[] buffer = new char[4096]; // Create an input buffer
int bytes_read;
int count = 0;
StringWriter fileIn = new StringWriter(); // Create a buffer to gather the output
while((bytes_read = inReader.read(buffer)) != -1) { // Keep reading until the end
fileIn.write(buffer, 0, bytes_read); // Copy the bytes into the buffer
count += bytes_read;
inReader.close(); // Close the reader
try {
factor = DocumentBuilderFactory.newInstance();
builder = factory.newDocumentBuilder();
factory = builder.parse(fileIn.toString()); --- Here I got the Exception.
Can someone help me out.
Thanks
Raheel

factory = builder.parse(fileIn.toString()); --- Here I got the Exception.Yes, that is because you are not passing a URI that refers to the location of the XML, you are passing the XML itself. Looking in the API documentation for other versions of the parse() method:factory = builder.parse(new InputSource(new StringReader(fileIn.toString())));(I keep having to look at the code to find out what "fileIn" refers to, because "fileIn" is a really, really bad name for a StringWriter.)

Purge Concurrent Request and/or Manager Data program:

Hi Friends,
I am purging all my test report output logs using the above program, but the table
FND_CONC_PP_ACTIONS is not being deleted;
SQL> select count (*) from FND_CONC_PP_ACTIONS;
COUNT(*)
9470
FND_CONC_PP_ACTIONS
Stores the post request processing actions(e.g., print, notify) for each
submitted request. There's a concurrent_request_id here for each request_id
in the FND_CONCURRENT_REQUESTS.
How can i forced delete the tables? since im still on the testing phase its OK if i zero out
all of it.
Thanks a lot

or I want it zero (0) to delete all You cannot set it to zero (0). The Age parameter should be between (1) and (9999999).
Did I mess it up? when I manually deleted the contents of
I thought I can delete this logs manually because they are on filesystem.
I thought only the database tables are needed to be cared for. Even though you should not bother yourself and delete the files manually under $APPLOG and $APPLOUT directories since the concurrent request will do the job for you, it is safe to delete it manually. The only impact you would have here is, you would not be able to access the log/out files of the concurrent requests (if the requests still presented in the tables and you can see it from the application).
Did you try to use the "Count" parameter instead of the "Age"? The "Count" parameter indicates the number of (most recent) records for which you want to save concurrent request history, log file, and report output files.

Where is the glossary .xml file found

Hi I was trying to locate the .xml file that populates the Glossary widget so that I could copy it and create my own editable .xml file to import.
Can anyone tell me where I would find it?
Thanks
Mark

Wow! I just tried a quick few edits and I got the same thing. Now I did stretch the glossary down and here is a screen shot of how mine turned out.
Try doing that and see how it works for you.
At least it allows the student to scroll down to very bottom.
It almost seems like there are daily changes.....

Location of XMl file of a Concurrent Request

Similar Messages

Maybe you are looking for