Method "jumping" return statement

(Sorry for my bad English)
Hi, i have a method that makes comparison between Strings, here it is :
 public String comparacion(String cc,String ci,int tlnm,int ndc){
 int te = ci.indexOf(' ');
 if( te != -1 ){
 String[] palabras = ci.split(" ");
 int index = palabras.length - 1;
 String nombre = "";
 int indice = 0;
 for( int k = 0; k <= index; k++ ){
 for( int lcc = cc.length() - 1,lci = palabras[k].length() - 1 ;
 lci >= 0 && lcc >= 0;
 lcc--,lci-- ){
 char ccc = cc.charAt(lcc);
 char cci = palabras[k].charAt(lci);
 if( ccc != cci ){
 break;
 if( "DE".equals(palabras[k]) || "DEL".equals(palabras[k]) ||
 "LA".equals(palabras[k]) || "LOS".equals(palabras[k]) ||
 "SAN".equals(palabras[k]) ){
 indice++;
 //System.out.println(index + " " + indice );
 break;
 if( ccc == cci ){
 if( lci == 0 ){
 nombre += palabras[k] + " ";
 indice++;
 //System.out.println("Afuera = " + index + " " + indice + " " + nombre);
 if( indice == index ){
 System.out.println(index + " " + indice);
 return null;
 if( tlnm - 1 == ndc ){
 //System.out.println(index + " " + indice );
 System.out.println("Posible nombre mal escrito en el catalogo : " + ci );
 if( te == -1 ){
 for( int lcc = cc.length() - 1,lci = ci.length() - 1; lci >= 0 && lcc >= 0; lcc--, lci-- ){
 char ccc = cc.charAt(lcc);
 char cci = ci.charAt(lci);
 if( ccc != cci ){
 //Son diferentes
 //System.out.println(cci + " es diferente de " + ccc);
 //return "Es doble supongo : " + cc ;
 break;
 if( ccc == cci ){
 //System.out.println(cci + " " + ccc);
 if( lci == 0 ){
 //System.out.println("Son iguales : " + ci + " " + cc);
 //return "Son iguales : " + ci + " y " + cc;
 return null;
 }The problem is in the if that evaluates if indice is equal as index if true and if my understanding of the return statement is right, then it should stop there and return to the
function where it was called from right? Unfortunately this is not happening, in fact i tested with the System.out.println and it enters when the condition is true but it seems
it skips the return and keeps going on the rest of the code. Any idea of what could be the issue ?
-Daniel

Hello Daniel,
IMHO your code has several issues wich make it hard to read and therefore hard to debug:
1. choose better variable names. Variable names should clearly express what they contain or what meaning they have. e.g.: int te = ci.indexOf(' '); // bad
int indexOfSpace = ci.indexOf(' '); // better
// but in your case it really should have been:
boolean isSingleWord = -1 == ci.indexOf(' ');2. you schould never return null unless null is a valid member of the result set (and not some kind of error indikator).
I understand that you plan to have it return something but my impression is that String meight not be the appropriate return type. The other option is that the name of this method is not appropriate.
3. what keep you from using StringTokenizer?
4. why do you iterate over the single characters yourself instead of relying on String.equals()?
5. the line if( te == -1 ) expresses the opposit of the first if, so you should turn it into else.
6. you should extract the bodies of <tt>if( te != -1 )</tt> and <tt>if( te == -1 )</tt> (after turning it to else) to their own methods.
7. the part if( "DE".equals(palabras[k]) || "DEL".equals(palabras[k])
 "LA".equals(palabras[k]) || "LOS".equals(palabras[k]) ||
 "SAN".equals(palabras[k]) )should better be written this way:private static final List<String> KEYWORD_LIST = Arrays.asList(new String[]{ "DE","DEL","LA", "LOS","SAN"]);
if(KEYWORD_LIST.contains(palabras[k]))8. The keyword check that does not depend on anything declared in the inner loop so it shuld be moved out of it.
9. the check of the input parameters tlnm and ndc do not depent on anything in both of the loops so it should be moved behind (or before) them.
10. if( ccc != cci ){
 break;
if( ccc == cci ){
} again this is the opposit so instead of breaking the loop you should have formed a better if.
hope this helps.
bye
TPD

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T.B.M wrote:
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Missing return statement question

I got a missing return statement error when i compile in this code but however i dont get any missing return statement errors in the second code that i pasted here.. What is the difference i didn't get it ? Thank you.
public class primechecker {
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public class positiveornegative {
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In your first snippet, the compiler has no guarantee that the for loop will be executed at all. That leaves only one return inside an if condition which again it has no guarantee that it will ever be reached(the if test may fail). This leads the compiler to the conclusion that your method may never return anything at all. Yet it's definition says that it must return a value.

Missing return statement error

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}It says i am missing the return statement,but i do have set return something,whats the error? thx for helping

For example, what happens if the SQL query doesn't
return any rows, and rs.next() is never true?The while() loop will be skipped and the if statement
will execute, which has two branches, one of which is
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Missing Return Statement - Please Help

I get the "missing return statement" in line 47 in the getNumber method when I try to compile. Any suggestions?
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import java.util.Random; //imports class Random
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 int answer;
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 public void play()
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 while (userGuess != 0);
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 int answer = 1 + randomNumbers.nextInt( 1000 );
 } //ERROR IS DISPLAYED HERE
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 public void checkUserGuess()
 if ( userGuess >= answer)
 System.out.println("Your guess is too high, try again");
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 System.out.println("Your guess is too low, try again");
 else
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}

The error message says it all.
You declared your getNumber method as returning integer.
However you didnt return any number.
add the reutrn statement to the method
return answerJust to add, you have declared answer as global
variable and agian answer as local variable.
You are messing up a little there.
Message was edited by:
lupansansei

Missing return statement? News to me!

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the code....
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 int lineCount=0;
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 Entry[] array=new Entry[entryCount];
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 fileScanner.close();
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Entry temp;
for (start = 0; start < array.length - 1; start++)
indexSmallest = start;
for (curPos = start + 1; curPos < array.length; curPos++)
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indexSmallest = curPos;
} // end for
temp = array[start];
array[start] = array[indexSmallest];
array[indexSmallest] = temp;
 return array;
Any help would be most appreciated.

The code you posted has mismatched braces: it needs another } at the end.
Linked with this is how - or rather when - you return array from the populateEntry()
method. You have a couple of nested for-loops and you return array inside (at the
end of) the outer loop.
The compiler is really fussy about making sure that an Entry[] is returned from this
method. If you outer for-loop never gets executed for some reason, then the return
statement will never be reached. The compiler won't accept this.
Either
(1) move the return statement outside both loops so it is always executed. This
appears to be the most logical thing - but I haven't read your code that closely. It's
just that having return at the end of a for-loop (with no "continue" in sight), doesn't
make a lot of sense.
or
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I caught it in the catch block and at last I am having one finally?
as per normal order try block next catch block and at last finally will execute.
I execute the above code by putting a return statement inside catch block.I got the same order of execution irrespective of return statement inside catch?
What is the significance of return inside catch?
Case 2:
Lets take the scenario.
class MyException
     public static void main(String[] args)
          int i=1,j=0;
          try
               try
               System.out.println("the value is: "+(i/j));
               System.out.println("Inside try block");
               catch(ArithmeticException e)
               System.out.println("hi in ame");
               //return;
          finally
          System.out.println("inner finally");
                                        System.out.println("outer try");
          catch(Exception e)
                         e.printStackTrace();
               System.out.println("in exception");
          finally
               System.out.println("plz wait");
If return statement is there inside the inner try and catch the code out of inside outer try not getting executed Why So?
Any clarifications?
Thanking you,
Murthy.

First, please format your code as per http://forum.java.sun.com/features.jsp#Formatting
I'm not sure what part you don't understand.
.    public static void main(String[] args) {
.        try {
.            try {
.                throw new ArithmeticException();
.                System.out.println("Inside try block"); // #1
.            catch(ArithmeticException e) {
.                System.out.println("hi in ame"); // #2
.                return;
.            finally {
.                System.out.println("inner finally"); // #3
.            System.out.println("outer try"); // #4
.        catch(Exception e) {
.            System.out.println("in exception"); // #5
.        finally {
.            System.out.println("plz wait"); // #6
.    }#1 -- You won't get here because you throw AME.
#2 -- You will get here because you caught the AME you just threw.
#3 -- You will get here because it's a finally
#4 -- You won't get here. I think that this is what you're asking about: Why don't we get here? Because we've already done 'return' and this line is NOT inside a finally. The only things that can get executed after a return are finally blocks.
#5 -- You won't get here because you already caught the AME and didn't rethrow it or any other exception.
#6 -- You will get here because it's a finally.
Once you do a return, the only code you can execute before exiting the method are finally blocks. First the one corresponding to the try/cathc block where your return is, then the finally for the try/catch that encloses that one, and so on outward. The code between one finally and the next (#4 here) is NOT executed.
If you still have a question, please try to clarify exactly what behavior you don't understand.
Don't return from inside t/c/f.

Return statement in catch block !

Hello Java Gurus,
The code is not compiling when i remove return from the catch block
i dont really understand the essence of return statement in catch block
any help is greatly appreciated !
Thanks in advance !
import java.io.*;
public class fileinputstream {
   public static void main(String arg[]) {
        FileInputStream fin ;
        FileOutputStream fout;
       try {
             fin =new     FileInputStream("input_file.txt");
             int bytes_av = fin.available();
             System.out.println("bytes available the input file "+bytes_av);
       catch(FileNotFoundException e)
           System.out.println("The input file is not present");
           return;
       catch(IOException e)
           System.out.println("error while giving bytes available the input file");
           return;
       try
                 fout =new FileOutputStream("output_file.txt");
       catch(FileNotFoundException e)
           System.out.println("The output file cannot be created");
           return;
       int data=0;
       try {
           data =(int)fin.read();
       catch(IOException e) {
           System.out.println("Exception while reading from file");
        while(-1!=data)      {
                   try
                   fout.write(data);
                   catch(IOException e)
                       System.out.println("Error while writing to file");
                   try
                       data =(int)fin.read();
                   catch(IOException e)
                       System.out.println("Exception while reading from file");
        try {
               fin.close();
               fout.close();
        catch(IOException e) {
           System.out.println("Error while closing files");
}

You do understand what "return" means, don't you? It
exits the method, main() in this case.
So the return statements in the catch blocks end the
program. If you remove the return statements, the
program will continue with the code after the catch
blocks. It needs the variables "fout" and "fin"
there, and these must be initialised.
If there are no return statements in the catch
blocks, the variables "fin" and "fout" will be not
initialized when you get to the code that uses them,
and that's an error. The java compiler is telling you
that you must always initialise the variables (you
can set them to "null", for example).Great explanation !!!
Thanks !

Switch statesment in return statement

Hello, how do i effectively use a switch statement in a method that returns a string, below is my understanding but this implementation will not compile
public String toString(int format){
     return switch(format){
                         case 0: System.out.print(year+" "+month+" "+day);
                                   break;
                         case 1: System.out.print(month+" "+day+" "+year);
                                   break;
                         case 3: System.out.print(day+" "+month+" "+year);
               default: System.out.print("that is not a valid format");

If you are new to Java I suggest using the New to Java forum in future.
The problem also appears to be that you haven't used any of the constructs correctly.
BTW: Why is there no format #2
public String toString(int format){
    switch(format) {
          case 0: return year+" "+month+" "+day;
          case 1: return month+" "+day+" "+year;
          case 3: return day+" "+month+" "+year;
          default: throw new IllegalArgumentException("that is not a valid format");
}There are allot of ways you could do this better but it requirements more advanced programming.

Method "jumping" return statement

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