Mysql query (search multiple tables in database)

I have 12 tables in a database - january through to december.
I need to search all 12 tables for 'keyworrd' phrases submitted by the user through a search form.
Must be a more streamlined way of doing it than below using 'UNION'. I have incorporated 2 tables in the below query but I need a more 'condensed' query for all 12 tables?
$sql = ('SELECT * FROM january WHERE tourTitle = "'.$keyword.'" UNION SELECT * FROM february WHERE tourTitle = "'.$keyword.'"');
Cheers
Os

bregent wrote:
>That's what I did last year but thought I'd break it down this year into 12 easier to work with tables.
No, Ben is correct. Using 1 table for each month is absolutely the wrong way. It violates basic rules of normalization and causes all sorts of problems.
>Breaking it down appeals to be more so I can keep all the relevant months
>together instead of potentially becoming scattered throught-out one table.
That's what you use the Order By clause for.
>If by any chance the client says they want to update x, y or z I can go
>straight to the month in question without the necessity to flip through
>dozens of pages in phpMyAdmin as there is no real CMS management in place for this process.
Not sure what you are saying. Performing inserts, updates and queries is much simpler using a single table.
Whenever someone asks for a way to search through multiple tables, it tells me that the data structure is not designed well.
When I did this job last year there was about 60 pages created in phpMyAdmin. The records for January could be anywhere on those 60 pages as I may have to add additional records much later on in the process.
My thinking behind this was to keep all the month entries together so I could view them easily in phpMyAdmin.
Now due to my lack of knowlege about phpMyAdmin it could be possible to create a query to show only the january entries, I suspect it can do this.
I agree it is a lot simpler using 1 table to select and search through BUT I need if the ocassion arises to be able to view all the january or february entries etc one after the other, not 10 on page 2 and 3 on page 7 and 5 more on page 47 of phpMyAdmin.
So i quess what I really need is to write a select query in phpMyAdmin which only shows the selected entries for the month requested. I have not done much investigation into what phpMyAdmin can do........so I suppose I need to.
EDITED:
Arrgh you see IT WAS SO SIMPLE:
SELECT * FROM `tours` WHERE month = "March"
It's because I'm frightened of the bloody thing in case I mess something up!

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Message was edited by:
aerostra

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You don't need PL/SQL for this job, so don't use PL/SQL if you don't have to. (I realize this question was out of context, so you may have good reasons for doing this in PL/SQL.)
Do all filtering as early as possible. Don't waste effort computing things that won't be used .
A particular example of this is: Never use a HAVING clause when you can use a WHERE clause. What's the difference between a WHERE clause and a HAVING clause? The WHERE clause is applied before aggregate functions are computed, and the HAVING clause is applied after; there's no other difference. Therefore, if the HAVING clause isn't referencing an aggregate function, it could be done in a WHERE clause instead.

SQL query involving multiple tables

I have a scenario in SQL where For each post there are associated tags. A user is one who makes post and he belongs to a particular location. The location corresponds to a particular country.
I create tables as
CREATE TABLE post_table
post_id VARCHAR(20),
user_id VARCHAR(20),
PRIMARY KEY(post_id)
CREATE TABLE tags_table
   post_id VARCHAR(20),
   tags VARCHAR(20),
   PRIMARY KEY(tags, post_id),
   FOREIGN KEY(post_id) REFERENCES post_table(post_id) ON DELETE CASCADE
CREATE TABLE location
location_id VARCHAR(20),
country VARCHAR(20),
PRIMARY KEY (location_id)
CREATE TABLE user_info
user_id VARCHAR(20),
location_id VARCHAR(30),
PRIMARY KEY (user_id),
FOREIGN KEY(location_id) REFERENCES location(location_id) ON DELETE CASCADE
);Now, I insert values in these tables as
INSERT INTO post_table VALUES( 'p1', 'u1' );
INSERT INTO post_table VALUES( 'p2', 'u1' );
INSERT INTO post_table VALUES( 'p3', 'u2' );
INSERT INTO post_table VALUES( 'p4', 'u3' );
INSERT INTO post_table VALUES( 'p5', 'u2' );
INSERT INTO tags_table VALUES( 'p1', 'US Open' );
INSERT INTO tags_table VALUES( 'p1', 'Real good' );
INSERT INTO tags_table VALUES( 'p1', 'Madrid' );
INSERT INTO tags_table VALUES( 'p2', 'Madrid' );
INSERT INTO tags_table VALUES( 'p3', 'Rossoneri' );
INSERT INTO tags_table VALUES( 'p4', 'Milan' );
INSERT INTO tags_table VALUES( 'p4', 'Los Angeles' );
INSERT INTO tags_table VALUES( 'p5', 'Rossoneri' );
INSERT INTO location VALUES( 'loc1', 'Spain');
INSERT INTO location VALUES( 'loc2', 'England');
INSERT INTO user_info VALUES( 'u1', 'loc1' );
INSERT INTO user_info VALUES( 'u2', 'loc2' );
INSERT INTO user_info VALUES( 'u3', 'loc1' );Now I have to fire a query For each country, display the most seen tag(s)
So for this data the result should be like
Country              MostTags
Spain                Madrid
England              RossoneriPlease help me write this query guys.

Hi,
Something like this
select      country
     , tags from
             select      l.country
               , t.tags
               , dense_rank() over (     partition by l.country
                              order by count(*) desc) drn
          from      location l
               , user_info u
               , post_table p
               , tags_table t
          where      l.location_id = u.location_id
               and p.user_id=u.user_id
               and p.post_id=t.post_id
          group by l.country
               , t.tags
where drn <=1   -- rank depends on like 1,2 or 3 popular tags for each countryRegards
Anurag

Mysql query (search multiple tables in database)

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