Need advise on how to model this rule

Hi,
I got stuck in modelling some rule. I will try to paint the picture using some example:
Assume the following entities (and relations)
the child (the children)
the toy (the childs toys)
the cupboard (the cupboards)
I would like to construct a boolean saying that all children can store their most favorite toy in the best cupboard
What I have tried so far:
I have inferred a relation for the best cupboard.
I also inferred a relation for the most favorite toy of a child.
Now I get stuck. What should be the way to do this? Is it possible? I have the feeling I am missing something. It might be versy simple, but I am relative new to OPA.
Any help is very much appreciated.
Cheers,
Han Joosten

Hi Han,
When I first had a go at this, I had several inferred relationships and it got complicated, so I tried to simplify it down to minimal inferred relationships. Here's what I did...
Entities and Relationships
Containment Relationships
Global --> one-to-many --> the child (relationship text: the children)
the child --> one-to-many --> the child's toy (relationship text: the child's toys; reverse text: the toy of the child)
Global --> one-to-many --> the cupboard (relationship text: the cupboards)
Inferred Relationships
the cupboard --> many-to-many --> the child's toy (relationship text: the cupboard's toys)
Note: Before you can write rules associating two different entities, you need to set up a relationship between them in the Properties file.
Rules
Determine the best cupboard...
I made up a number attribute 'the cupboard's priority'. The best cupboard is the one with the lowest priority number, i.e. the cupboard with priority 1 beats the cupboard with priority 2.
the cupboard is the best cupboard if
the cupboard's priority = the priority number of the top cupboard
the priority number of the top cupboard = InstanceMinimum(the cupboards, the cupboard's priority)
If you wanted to reverse the priority logic so that the highest number is the 'best', use InstanceMaximum instead.
Determine the favourite toy...
Similar approach with the toys:
the child's toy is the favourite toy if
the child's toy's priority = the priority number of the child's top toy
the priority number of the child's top toy = InstanceMinimum(the child's toys, the child's toy's priority)
Put the favourite toy of each child in the best cupboard...
Write a membership rule to associate the child's toys and the cupboards:
the child's toy is a member of the cupboard's toys if
the cupboard is the best cupboard and
ForScope(the toy of the child)
the child's toy is the favourite toy
Procedural rules to tie it all together...
The rules above do all the tricky logic work. If you want a Global level rule which ties it all together, you could add procedural rules, e.g.
the appropriate cupboard has been determined for all the favourite toys if
ForAll(the children, the child's favourite toy has been determined) and
ForAll(the cupboards, it is known whether or not the cupboard is the best cupboard)
the child's favourite toy has been determined if
ForAll(the child's toys, it is known whether or not the child's toy is the favourite toy)
Test case
I tried the following test scenario, which worked as expected.
Inputs
Child: Bart
Toys: Krusty Doll (priority 1), Television (priority 2)
Child: Lisa
Toys: Saxophone (priority 1), Malibu Stacy (priority 2)
Cupboard: Cupboard A (priority 1)
Cupboard: Cupboard B (priority 2)
Results
Cupboard A is the best cupboard
Instances of 'the child's toy' associated with Cupboard A: Krusty Doll, Saxophone
Cupboard B is not the best cupboard
No instances of 'the child's toy' associated with Cupboard B.
Further comments
If each child can have multiple 'favourite' toys (all of which can go in the best cupboard), then make 'the child's toy is the favourite toy' a base level attribute. Any toy where 'the child's toy is the favourite toy'=true will be associated with the best cupboard, i.e. Cupboard A in the scenario above.
Depending on what else you need to do, it may be worth creating an inferred relationship for 'the child's favourite toys', e.g.
the child's toy is a member of the child's favourite toys if
IsMemberOf(the child's toy, the child's toys) and
the child's toy is the favourite toy
Cheers,
Jasmine

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trojnfn
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