Need help in writing SQL query

Hi,
I have a rquirement where I need to convert columns into records.
Table1:
(note: I have around 150 columns i.e period1 to period150)
unit startdate Period1 period2 period3 period4 period5
A 1/1/2011 100 200 300 400 500
Now I need data in below format
UNIT startdate period
A 1/1/2011 100
A 1/1/2011 200
A 1/1/2011 300
A 1/1/2011 500
Please suggest me...
Thanks.

With UNPIVOT you can "name" each of your rows using as.
One trick is to "name" the rows to a number - then you can add that number of weeks to your start date - like this:
with t as (
   select 'A' unit, DATE '2011-01-01' startdate, 100 period1, 200 period2 ,300 period3, 400 period4 ,500 period5 from dual
select
unit,
startdate + numtodsinterval(week*7,'day') startdate,
qty
from t
unpivot(
   qty for week in (
      period1 as 0,
      period2 as 1,
      period3 as 2,
      period4 as 3,
      period5 as 4
;Theoretically the above should work - but somehow I get a NULL date on my 11.1 instance? And I don't have another version to test with, alas.
But try it and see if it works on your instance ;-)

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    Srikanth wrote:
    ... but the number of records returned by above query are lot more than number of records in the table.
    Why did the number go up?
    It's something only you can find out
    Maybe some Emp have several Supervisor(s) like
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    select '100009','EG0001' from dual union all
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            select supervisor,null
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    SUPERVISOR
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    TU0001
    EG0001
    TU0001
    ___EG0001
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    EG0001
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    100009
    _________GE0064
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    GE0064
    ____________GE0002
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    EG0001
    ______EG0009
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  • Need help on oracle sql query

    Hi team,
    Please help me on below query,
    I have table like given below
    Tran_Id  tran_date   amount. Actorid
       1.         10-apr-15.   100.         1
       2.         11-apr-15.   100.         1
       3.         11-apr-15.   900.         1
       4.         12-apr-15.   100.         1
       5.         13-apr-15.   350.         1
       6.         14-apr-15.   400.         1
    Now please find the query,
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    >1500 and the  date when the tran amount
    Has breached
    Ex:
    Actor-id.  Breached-date.    Total
      1.              13-apr-15.            1900
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    Regards,
    Rajendra

    Your solution (same as Saubhik's) is incorrect. Look at source data - multiple transactions can occur same day. Therefore, your qury will return wrong results if breached amount is 1000:
    with trans as (
    select  1  tran_Id, to_date('10-apr-15', 'dd-mon-yy') tran_date,  100 amount, 1 actorid from dual union all
    select  2,  to_date('11-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
    select  3,  to_date('11-apr-15', 'dd-mon-yy'), 900, 1 from dual union all
    select  4,  to_date('12-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
    select  5,  to_date('13-apr-15', 'dd-mon-yy'), 350, 1 from dual union all
    select  6,  to_date('14-apr-15', 'dd-mon-yy'), 400, 1 from dual union all
    select  7,  to_date('12-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
    select  8,  to_date('13-apr-15', 'dd-mon-yy'), 1200, 2 from dual union all
    select  9,  to_date('14-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
    select  10,  to_date('15-apr-15', 'dd-mon-yy'), 300, 2 from dual
    trans_running_tot as (
    select tran_id, tran_date,
      sum(amount) over (partition by actorid order by tran_date) tot_amt, actorid
    from trans
    trans_ranked as (
    select actorid,tran_id, tran_date,
      rank() over (partition by actorid order by tot_amt) rk
    from trans_running_tot
    where tot_amt > 1000
    select * from trans_ranked where rk=1
       ACTORID    TRAN_ID TRAN_DATE         RK
             1          2 11-APR-15          1 -- here total amount was only 200
             1          3 11-APR-15          1
             2          8 13-APR-15          1
    SQL>
    As you can see, 2 rows were returned for actor 1. Why? Default for analytic ORDER BY is RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW. Therefore, all rows with same transation_date will fall into same window:
    SQL>  with trans as (
      2   select  1  tran_Id, to_date('10-apr-15', 'dd-mon-yy') tran_date,  100 amount, 1 actorid from dual union all
      3   select  2,  to_date('11-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
      4   select  3,  to_date('11-apr-15', 'dd-mon-yy'), 900, 1 from dual union all
      5   select  4,  to_date('12-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
      6   select  5,  to_date('13-apr-15', 'dd-mon-yy'), 350, 1 from dual union all
      7   select  6,  to_date('14-apr-15', 'dd-mon-yy'), 400, 1 from dual union all
      8   select  7,  to_date('12-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
      9   select  8,  to_date('13-apr-15', 'dd-mon-yy'), 1200, 2 from dual union all
    10   select  9,  to_date('14-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
    11   select  10,  to_date('15-apr-15', 'dd-mon-yy'), 300, 2 from dual
    12   )
    13  select tran_id, tran_date,
    14    sum(amount) over (partition by actorid order by tran_date) tot_amt, actorid
    15  from trans
    16  /
       TRAN_ID TRAN_DATE    TOT_AMT    ACTORID
             1 10-APR-15        100          1
             2 11-APR-15       1100          1
             3 11-APR-15       1100          1
             4 12-APR-15       1200          1
             5 13-APR-15       1550          1
             6 14-APR-15       1950          1
             7 12-APR-15        300          2
             8 13-APR-15       1500          2
             9 14-APR-15       1800          2
            10 15-APR-15       2100          2
    10 rows selected.
    SQL>
    So correct solution is to ORDER BY transation id. Also, just in case if amount can be 0, we should add tranaction id when ordering by sum:
    with trans as (
    select  1  tran_Id, to_date('10-apr-15', 'dd-mon-yy') tran_date,  100 amount, 1 actorid from dual union all
    select  2,  to_date('11-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
    select  3,  to_date('11-apr-15', 'dd-mon-yy'), 900, 1 from dual union all
    select  4,  to_date('12-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
    select  5,  to_date('13-apr-15', 'dd-mon-yy'), 350, 1 from dual union all
    select  6,  to_date('14-apr-15', 'dd-mon-yy'), 400, 1 from dual union all
    select  7,  to_date('12-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
    select  8,  to_date('13-apr-15', 'dd-mon-yy'), 1200, 2 from dual union all
    select  9,  to_date('14-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
    select  10,  to_date('15-apr-15', 'dd-mon-yy'), 300, 2 from dual
    trans_running_tot as (
    select tran_id, tran_date,
      sum(amount) over (partition by actorid order by tran_id) tot_amt, actorid
    from trans
    trans_ranked as (
    select actorid,tran_id, tran_date,
      rank() over (partition by actorid order by tot_amt,tran_id) rk
    from trans_running_tot
    where tot_amt > 1000
    select * from trans_ranked where rk=1
       ACTORID    TRAN_ID TRAN_DATE         RK
             1          3 11-APR-15          1
             2          8 13-APR-15          1
    SQL>
    SY.

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                  3 George address3 SOLD_TO
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    SQL>Or alternative...
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    Wrote file afiedt.buf
      1  with t as (
      2    select 1 as customer_number, 'Fred' as customer_name, 'address1' as customer_address1, 'BILL_TO' as site_use_code from dual union all
      3    select 1 as customer_number, 'Fred' as customer_name, 'address1' as customer_address1, 'SHIP_TO' as site_use_code from dual union all
      4    select 2 as customer_number, 'Bob' as customer_name, 'address2' as customer_address1, 'BILL_TO' as site_use_code from dual union all
      5    select 3 as customer_number, 'George' as customer_name, 'address3' as customer_address1, 'BILL_TO' as site_use_code from dual union all
      6    select 3 as customer_number, 'George' as customer_name, 'address3' as customer_address1, 'SHIP_TO' as site_use_code from dual union all
      7    select 3 as customer_number, 'George' as customer_name, 'address3' as customer_address1, 'SOLD_TO' as site_use_code from dual union all
      8    select 4 as customer_number, 'Tim' as customer_name, 'address4' as customer_address1, 'BILL_TO' as site_use_code from dual union all
      9    select 5 as customer_number, 'Sam' as customer_name, 'address5' as customer_address1, 'BILL_TO' as site_use_code from dual
    10  )
    11  --
    12  -- END OF TEST DATA
    13  --
    14  select distinct
    15         customer_number
    16        ,customer_name
    17        ,customer_address1
    18        ,first_value(site_use_code) over (partition by customer_number order by decode(Site_use_code,'BILL_TO',1,'SHIP_TO',2,3) desc) as site_use_code
    19  FROM t
    20  WHERE Site_use_code IN ('BILL_TO','SHIP_TO','SOLD_TO')
    21* order by customer_number
    SQL> /
    CUSTOMER_NUMBER CUSTOM CUSTOMER SITE_US
                  1 Fred   address1 SHIP_TO
                  2 Bob    address2 BILL_TO
                  3 George address3 SOLD_TO
                  4 Tim    address4 BILL_TO
                  5 Sam    address5 BILL_TO

  • Need help in the sql query

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    Hi,
    781649 wrote:
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    insert into order values('g',2);Thanks for posting the CREATE TABLE and INSERT statements; it's very helpful.
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                                   ORDER BY          name_a
                           )         AS r_num
         FROM     order_table                    -- ORDER is not a good table name
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