Need Help writing program

Question

very new to java, i conceptually know what i want to do, but it is hard to apply that to writing the program. this is very introductory so i'd appreciate all and any help.
i am trying to write a program such that if I select an integer, n, as in input, the program can convert that integer into it's binary representation. for example, if the integer is 4, then the program would output 001 as the binary representation of 4.
that is the first part, the second part is to have the binary representation go from most significan bit to least significant bit, so for the integer 4 it will come out as 100 (or 000100 or 00100).
ok basically i know i want the program to divide the chosen integer by 2 and take the remainder (n%2), which will be 1 or 0. i then want the program to take the value (n/2) and have that be the new n value, then repeat the steps over and over till my n just becomes 0. i am trying to do this with a while loop, but if there is an easier way to do this, please let me know. so far wha ti have is below, kinda stuck on how to write this program, please help. the output just keeps giving me 0 and doesn't end.
import java.util.*;
class Q3a{
static Scanner console = new Scanner (System.in);
     public static void main(String args[]){
          int n;
          n = console.nextInt();
          System.out.print("Choose an integer value :");
          while (true) {
          System.out.println("Remainder on dividing " + n + " by 2 is " + n%2);
          n = n/2;}
          System.out.println("New value of n is n/2 which is " + n);
          System.out.println("Remainder on dividing " + n + " by 2 is " + n%2);
          n = n/2;
          System.out.println("New value of n is n/2 which is " + n);
          System.out.println("Remainder on dividing " + n + " by 2 is " + n%2);
          n = n/2;
          System.out.println("New value of n is n/2 which is " + n);Message was edited by:
kribraider414

Answer 1

consider
while (n != 0){
  System.out.println(n%2);
  n = n/2;
}put the reverse of the stoping condition in the parens for the loop
This loop will run while n is NOT zero. It wil stop when n is zero. Try it for a few numbers and see what it does.
Pay particular attention to what it does if the number you supplied is zero (which is the one binary number that does not have a single one in it.)
Also take a look at what it does for negative numbers and decide what you want to do in that case.