Need query for..

Question

Table A               
ID     Name     Date     Paid
1     A     5-Sep-11     10
1     A     6-Sep-11     12
1     A     7-Sep-11     15
2     B     6-Sep-11     13
2     B     7-Sep-11     16
2     B     8-Sep-11     5
3     C     8-Sep-11     12
3     C     9-Sep-11     11
Output Req               
When passed ID and Name as filter conditions then output Latest Paid
e.g
for 1,A--->15
for 2,B--->5
for 3,C--->11
I blv this can be done using rank but I m looking for a way to do it without using a subquery.
Thanks in advance.

Answer 1

Try this
"afiedt.buf" 17 lines, 699 characters
  1  with t
  2  as
  3  (
  4  select 1 id, 'A' name, to_date('05-Sep-11','dd-mon-rr') dt, 10 paid from dual union all
  5  select 1, 'A', to_date('06-Sep-11','dd-mon-rr'), 12 from dual union all
  6  select 1, 'A', to_date('07-Sep-11','dd-mon-rr'), 15 from dual union all
  7  select 2, 'B', to_date('06-Sep-11','dd-mon-rr'), 13 from dual union all
  8  select 2, 'B', to_date('07-Sep-11','dd-mon-rr'), 16 from dual union all
  9  select 2, 'B', to_date('08-Sep-11','dd-mon-rr'), 05  from dual union all
10  select 3, 'C', to_date('08-Sep-11','dd-mon-rr'), 12 from dual union all
11  select 3, 'C', to_date('09-Sep-11','dd-mon-rr'), 11 from dual
12  )
13  select id, name, max(paid) keep(dense_rank last order by dt) paid
14    from t
15   group
16*     by id, name
SQL> /
        ID N       PAID
         1 A         15
         2 B          5
         3 C         11