Need signed applet to read a file in the jar?

i have an applet and i need to read a file (just a picture .jpg) within the jar. but i got a security exception when i try to make the File object for this jpg
thanks and sorry for my english

Image image = Toolkit.getDefaultToolkit().getImage(getClass().getResorce("FileName.jpg"));i need to make something like this
File file = new File("picture.jpg");
the idea is verify that picture.jpg is really the picture that i put and not other with the same name... and if it is a file objet i can see the last modification date, to make a validation...
another way is to read some pixels and verify that its colors dont change... but i dont know how to do this neither.
but thanks anyway!

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I want to read the file inside the jar file, use following method:
File file = new File("filename");
It works if not in JAR file, but it doesn't work if it's in a JAR file.
I found someone had the same problem, but no reply.
http://forum.java.sun.com/thread.jsp?forum=22&thread=180618
Can you help me ? I have tried this for all night !
Thanks in advance
Leo

If you want to read a file from the JAR file that the
application is packaged in (rather than a separate
external JAR file) you do it like this ...
InputStream is =
ClassLoader.getSystemResourceAsStream("filename");Better to use
this.getClass().getClassLoader().getResourceAsStream();
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I have an applet that runs with JWS. The user can input some information and then I need to show this information in a web page. As the application can be run offline, I cannnot use JSP�s to generate the web page. The information is saved in a xml file, so I use a xsl parser to generate the html code. The problem is that I have to include some javascript files (.js). I put these files inside the jar, but, how can I read these files, or how can I reference these files from inside the html page ?
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You can use getClass().getResource(classpath)
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Hi All,
I want to save some preferences in a file called "preferences". I kept the preferences file under my java package.
If i am running the code inside the NetBeans 6.9 IDE it's working file. But once i have created a JAR and try to run the application, it couldn't find the path.
Please help me that how to resolve this issue. I don't want to save this preferences file outside of my JAR (i.e) within my java package.
Here is the code,
package mypackage;
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
public class ReadFile
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        try
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            PrintWriter writer = new PrintWriter(out);
            writer.println("Hello Java!");
            writer.close();
            out.close();
        catch (Exception ex)
            System.out.println(ex.getMessage());
    private void readFile()
        try
            FileInputStream fi = new FileInputStream(getClass().getClassLoader().getResource("mypackage/preferences").getPath().replace("%20", " "));
            BufferedReader br = new BufferedReader(new InputStreamReader(fi));
            System.out.println(br.readLine().trim());
            br.close();
            fi.close();
        catch (Exception ex)
            System.out.println(ex.getMessage());
    public static void main(String[] args)
        ReadFile read = new ReadFile();
        read.writeFile();
        read.readFile();
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{color:#ff0000}*file:\my jar path\jarname.jar!\mypackage\preferences (The filename, directoryname, or volume label syntax is incorrect)*{color}

Thanks sabre150,
sabre150 wrote:
You cannot update a running jar file. I am sorry. I didn't know about it. Thanks to point out.
There are two ways I approach this depending on my exact requirements -
1) use the java.util.prefs.Preferences APII will try this one
>
2) if not already present I copy the preferences file from the jar to a known place. I use a directory in the user's home directory and normally make the directory name the program with a '.' prefix.
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XML file in JAR:
SQLMaps/admin/sample.xml [folder structure inside the jar file]
my application has a path like SQLMaps/admin/sample.xml
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Regards
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but i need the application to read the xml file in the jar file
to be more clear.
the jar file has xml in a specified folder.

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Thank You

Hello,
I was able to solve my problem by thinking & my code goes as follows.I am trying to read a video file in my program.
public Vector getFileMediaContent(RandomAccessFile fileObj){
Runtime runtime = Runtime.getRuntime();
System.out.println ("Free memory : inside Boolean Type Panel" + runtime.freeMemory() );
dataContent.removeAllElements();
System.out.println("dataContent :"+dataContent.size());
try{
int size=(int)fileObj.length();
if(size<2000000){
byte[] data = new byte[size];
fileObj.read(data);
dataContent.addElement(data);
data=null;
System.gc();
else{
int fixedsize=2000000;
int startindex=0;
int read=0;
int remaining=0;
while(read!=-1){
byte[] data=new byte[fixedsize];
read=fileObj.read(data,0,data.length);
dataContent.addElement(data);
startindex=startindex+data.length;
remaining=size-startindex;
fileObj.seek(startindex);
data=null;
System.gc();
if(remaining>0 && remaining<2000000){
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read=fileObj.read(data1,0,data1.length);
dataContent.addElement(data1);
data1=null;
System.gc();
System.out.println("outside while");
System.out.println("dataContent 1 :"+dataContent.size());
System.out.println ("Free memory : inside Boolean Type Panel" + runtime.freeMemory() );
fileObj = null;
System.gc();
}catch(Exception e){
e.printStackTrace();
return dataContent;
Now I am not facing the problem of IndexOut of Bounds Exception But I am getting Out of Memory Error.
Can You suggest me to come out of this,.
As I know I have two solutions.
1.Make the objects Null which is using more space & call System.gc();
2.Increase the Virtual Memory of my System.
Any solutions other than this?
And How to Increase the Virtual Memory?Please do reply.
ThankYou

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Signed applet sounds cool - I guess Microsoft's ActiveX technology would be the mirror of this.
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Hello!
I have my j2me application in a .jar file , and my application needs to read a .txt file which is outside my .jar but in the same directory.
I tried to do :
InputStream input = getClass().getResourceAsStream("/myfile.txt");
as well as
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but nothing is working...
Could you help me, please??? I'm getting crazy with this :(
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Thanks sabre150,
sabre150 wrote:
You cannot update a running jar file. I am sorry. I didn't know about it. Thanks to point out.
There are two ways I approach this depending on my exact requirements -
1) use the java.util.prefs.Preferences APII will try this one
>
2) if not already present I copy the preferences file from the jar to a known place. I use a directory in the user's home directory and normally make the directory name the program with a '.' prefix.
One cannot access files in a jar file using the File API. One needs to use the getResource() or getResourceAsStream() methods on Class or ClassLoader.

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Hi all,
One of my classes inside jar needs to read XML file that resides in the same location where the jar sits. I use MyClass.getClass().getResource("MyXMLFile.xml") but it keeps returning null.
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Any help would be greatly appreciated.
Setya

Thanks for the dukes.
My JDBC post on this forum discusses the issues of
using Class-Path in your jar file. It works, but it
may vary from system to system.
Thanks also from my side: I have read recently your discussion about reading files in the jar's directory, since I had the same problem. So I was really glad to see your solution. However, I had one more problem, namely that I'm running my application sometimes from the jar, sometimes from the classes directly (debugging). In order to have always the correct path (although a different one) I have added some more lines to deal with that case. I hope that will be useful for you as well!
Dieter Profos
import java.awt.*;
import java.awt.event.WindowAdapter;
import java.awt.event.WindowEvent;
import java.awt.event.WindowListener;
import java.net.URL;
* @author pkwooster
* @author Dieter Profos
* @version 1.01 04/03/26
public class ReadOutside extends Frame {
private TextArea textArea;
public static void main(String[] args) {
// Create application frame.
ReadOutside tc = new ReadOutside();
tc.addWindowListener(new WindowAdapter() {
public void windowClosing(WindowEvent we) {
System.exit(0);
// Show frame
tc.setSize(600,250);
tc.setVisible(true);
public ReadOutside() {
textArea = new TextArea(20,80);
add(textArea);
readOutside(this);
public void readOutside(Object o) {
System.out.println(getCodeBasePath(o));
/** Gets the absolute path of the directory where the JAR or CLASS file is
* located. If the application is run from a jar file, the directory of the
* jar file is returned; if it is run from a class file, the method will
* return the directory path of the class file.
* @param o The main class of the application.
* @return The absolute directory path, or null if neither the class nor a
* jar file could be found.
public String getCodeBasePath(Object o) {
Class c = o.getClass();
URL url;
// get the class name
String className = c.getName();
textArea.append("class name = " + className + "\n");
// replace package periods by file separators
className = className.replace('.','/');
ClassLoader cl = c.getClassLoader();
if (cl == null)
cl = ClassLoader.getSystemClassLoader();
url = cl.getResource(className + ".class");
String xPath = url.toExternalForm();
textArea.append("url = " + url + "\n");
textArea.append("extPath = " + xPath + "\n");
// make sure that the path starts with jar:file:
if (xPath.startsWith("jar:file:")) {
// remove jar:file: + the subsequent file separator
xPath = xPath.substring("jar:file:".length()+1);
int n = xPath.indexOf("!");
if (n < 0)
n = xPath.length();
String jarPath = xPath.substring(0, n);
textArea.append("jar file path = " + jarPath + "\n");
n = jarPath.lastIndexOf("/");
String jarDir = jarPath.substring(0, n+1);
textArea.append("jar dir = " + jarDir + "\n");
return jarDir;
else { // if program is run from its class file (development phase!)
if (xPath.startsWith("file:")) {
// remove file: + the subsequent file separator
xPath = xPath.substring("file:".length()+1);
textArea.append("class file path = " + xPath + "\n");
int n = xPath.lastIndexOf("/");
String classDir = xPath.substring(0, n+1);
textArea.append("class dir = " + classDir + "\n");
return classDir;
return null;

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With the Partitioning, Real Application Clusters, OLAP, Data Mining
and Real Application Testing options
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5                                                          where rownum = 1
6                                                     )
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D
X
SQL>
SQL> select * from dual;
D
X
{code}
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Edited by: Yasu on Nov 12, 2012 10:14 AM

I tried manual method and yes i am able to find WAIT lines in trace file.
Connected to:
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
With the Partitioning, Real Application Clusters, OLAP, Data Mining
and Real Application Testing options
SQL> select value ||'/'||(select instance_name from v$instance) ||'_ora_'||
           (select spid||case when traceid is not null then '_'||traceid else null end
2    3                   from v$process where addr = (select paddr from v$session
4                                               where sid = (select sid from v$mystat
5                                                          where rownum = 1
6                                                     )
7                                          )
8             ) || '.trc' tracefile
9      from v$parameter where name = 'user_dump_dest'
10     /
TRACEFILE
/n01/oraadmin1/diag/rdbms/proddba/proddba1/trace/proddba1_ora_23021.trc
SQL> alter session set events '10046 trace name context forever, level 8';
Session altered.
SQL> select * from dual;
D
X
SQL> alter session set events '10046 trace name context off';
Session altered.
SQL> !ls -lrt /n01/oraadmin1/diag/rdbms/proddba/proddba1/trace/proddba1_ora_23021.trc
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SQL> !grep "WAIT" /n01/oraadmin1/diag/rdbms/proddba/proddba1/trace/proddba1_ora_23021.trc
WAIT #1: nam='SQL*Net message to client' ela= 6 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1352704368368424
WAIT #1: nam='SQL*Net message from client' ela= 4057810 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1352704372428142
WAIT #1: nam='SQL*Net message to client' ela= 6 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1352704372428492
WAIT #1: nam='SQL*Net message from client' ela= 195 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1352704372428892
WAIT #1: nam='SQL*Net message to client' ela= 3 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1352704372428939
WAIT #1: nam='SQL*Net message from client' ela= 46319788 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1352704418748740Not sure why using mknod fails in my case.
Edited by: Yasu on Nov 12, 2012 12:48 PM

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