Need some advice in this code

Question

probabily this is a easy stuff..but right now i cant..
I have :
A JSP interface : where user could select option "A" or option "B" or option "C". and a text field to enter some data.
in the Action class, i check by the request.getParamter() to see what the user has selected from the drop down and then apply the following logic in the Action class.
if user selets option "A"
          // put data into session
          show page1.jsp
if user selets option "B"
          // put data into session
          show page2.jsp
if user selets option "C"
          // put data into session
          show page3.jsp
This is what i want to do in the Action class.
Problem :
========
As you see, i have one form bean . but i have to show 3 view depending upon user selection.
How many Action class do i need ?(though i have one only....but could not figure out how do i go about this)
please tell me the flow.
regards

Answer 1

<forward name="success" path="/page1.jsp"/>
/>
          <forward name="failure" path="/index.jsp"/>
</action>
see, the mapping has only page1.jsp.....but i have to
keep page2.jsp and also page3.jsp because user could
select option "B" or option "C" so he could get
those pages as well,
<forward name="successA" path="/page1.jsp"/>
<forward name="successB" path="/page2.jsp"/>
<forward name="successC" path="/page3.jsp"/>
<forward name="failure" path="/index.jsp"/> 
Inside your Action class: String userOption = ...; // A, B or C that use chose
findForward("success" + userOption);
There's nothing magical about "success" and "failure." They just happen to be the most common two ways to leave a page.