Need sql query to get OIM request pending approval details for one user
HI OIM Guru,
It would be great help if someone can provide me sql query by which i can find out how many requests are pending for approval for one user ?
1. Below query will give you status of all the request.
SELECT REQ.REQUEST_ID , REQ.REQUEST_STATUS FROM REQUEST REQ
2. You can have following status
Obtaining Operation Approval
Obtaining Template Approval
Operation Approval Approved
Operation Approval Rejected
Post Operation Processing Initiated
Request Approval Rejected
Request Closed
Request Completed
Request Created
Request Failed
Request Withdrawn
Template Approval Rejected
3. Now prepare the query from above sapmle, the requset status string should not contains foloowing values.
Rejected
Failed
Closed
Withdrawn
Completed
The builded query will give you the desired result for 11g
for 10 G
Get the OST_STATUS from Req table, and do you logic above stated
-Kuldeep
Edited by: Kuldeep on May 22, 2012 1:04 AM
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Then who can i check this number for one user in my date base ?
Cheers
Fayçal.Enable the audit by setting
alter system set audit_trail=true scope=spfile;.
Setting this parameter bounce of database
Enable the following audit option
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Anand -
Need SQL query to get the result.
Region
Month
Trx Type
Resolution Summary
AMERICAS
May-13
Adjustments
Correct
EMEA
May-13
Adjustments
Incorrect
AMERICAS
May-13
Credit Memo
Incorrect
EMEA
May-13
Invoice
Correct
AMERICAS
May-13
Credit Memo
Correct
OFD
May-13
Adjustments
Correct
AMERICAS
May-13
Invoice
Incorrect
LAD
May-13
Adjustments
Correct
LAD
May-13
Adjustments
Correct
OFD
May-13
Adjustments
Correct
Above is my Table and find below the required result.Similarly for other regions as well. Can anyone help me with the SQL Query?
Region
Resolution Summary
Adjustment
Credit Memo
Invoice
Grand Total
AMERICAS
Correct
1
1
2
Incorrect
0
1
1
2Like this?
SQL> select * from transaction_audit;
REGION MTH TRX_TYPE RESOLUTIO
AMERICAS may-13 ADJUSTMENTS CORRECT
EMEA may-13 ADJUSTMENTS INCORRECT
AMERICAS may-13 CREDIT MEMO INCORRECT
EMEA may-13 INVOICE CORRECT
AMERICAS may-13 CREDIT MEMO CORRECT
OFD may-13 ADJUSTMENTS CORRECT
AMERICAS may-13 INVOICE INCORRECT
LAD may-13 ADJUSTMENTS CORRECT
LAD may-13 ADJUSTMENTS CORRECT
OFD may-13 ADJUSTMENTS CORRECT
10 rows selected.
SQL> select region
2 , resolution_summary
3 , count(decode(trx_type, 'ADJUSTMENTS', trx_type)) adjustments
4 , count(decode(trx_type, 'CREDIT MEMO', trx_type)) credit_memo
5 , count(decode(trx_type, 'INVOICE' , trx_type)) invoice
6 from transaction_audit
7 group
8 by region
9 , resolution_summary
10 order
11 by region
12 , resolution_summary
13 /
REGION RESOLUTIO ADJUSTMENTS CREDIT_MEMO INVOICE
AMERICAS CORRECT 1 1 0
AMERICAS INCORRECT 0 1 1
EMEA CORRECT 0 0 1
EMEA INCORRECT 1 0 0
LAD CORRECT 2 0 0
OFD CORRECT 2 0 0
6 rows selected.
SQL> -
Need sql query to get sales channel code
Hi Experts,
As per my requirement i need to get the sales channel code by passing invoice number or transaction number ,or concurrent request id, with out any join condition . Please help me on this.
Regards
Deb1. Below query will give you status of all the request.
SELECT REQ.REQUEST_ID , REQ.REQUEST_STATUS FROM REQUEST REQ
2. You can have following status
Obtaining Operation Approval
Obtaining Template Approval
Operation Approval Approved
Operation Approval Rejected
Post Operation Processing Initiated
Request Approval Rejected
Request Closed
Request Completed
Request Created
Request Failed
Request Withdrawn
Template Approval Rejected
3. Now prepare the query from above sapmle, the requset status string should not contains foloowing values.
Rejected
Failed
Closed
Withdrawn
Completed
The builded query will give you the desired result for 11g
for 10 G
Get the OST_STATUS from Req table, and do you logic above stated
-Kuldeep
Edited by: Kuldeep on May 22, 2012 1:04 AM -
Need a sql query to get multiple dates in rows
Hi All,
i need a query to get dates for last 7 days and each dates should be in one row...
but select sysdate from dual..gives one row...
Expexcted Output
Dates:
01-oct-2013
30-sep-2013
29-sep-2013
28-sep-2013
27-sep-2013
26-sep-2013Hi,
Do you mean that you want all 7 dates together on 1 row?
Here's one way:
SELECT LISTAGG ( TO_CHAR ( SYSDATE + 1 - LEVEL
, 'DD-Mon-YYYY'
) WITHIN GROUP (ORDER BY LEVEL) AS txt
FROM dual
CONNECT BY LEVEL <= 7
This is an example of String Aggregation, that is, taking a column on multiple rows, and concatenating all the values (however many htere happen to be) into 1 big string column 1 row.
Like everything else, exactly how to do it depends on your Oracle version.
For more on String Aggregation, including differetn techniques for different versions, see http://www.oracle-base.com/articles/10g/StringAggregationTechniques.php
Message was edited by: FrankKulash
Sorry, I mis-read the question. -
SQL query to get the list of approvals
Hi,
Could someone let me know the SQL query to get the list of all the pending approvals for a user in OIM 11g R2.
ThanksThere are a few ways to do this:
- The easiest would be to use a Relationship Query from the CMC. To do this, go to the Universes section on the CMC, right click on the relevant universe, select tools >> Check Relationships.
- Use Query Builder. You will need more than one query to pull the information you need. You could try something like the below (for Webi)
SELECT SI_NAME, SI_WEBI, SI_DATACONNECTION FROM CI_APPOBJECTS
WHERE SI_KIND = 'universe' and SI_NAME = 'Universe Name'
This will give you a list of Webi Reports by SI_ID.
You'll need another query to list Webi report names:
SELECT SI_NAME FROM CI_INFOOBJECTS WHERE SI_ID IN (SI_ID from query above)
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SQL query to get a list of relations between workitems
How can I create a SQL query to get a list of all problems with related changes? And all problems with related incidents?
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The query below will get all of the related work items from the Change Request class. The way the joins work is ChangeRequestDimvw gets the list of change requests. Then inner joins WorkItemDimvw to get the WorkItemDimKey for each CR. Then inner joins WorkItemRelatesToWorkItemFactvw
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Now the tricky part is it appears that these relationship are set based on which item that created the relationship. So you need to union a second query that reverse the relationship on the WorkItemRelatesToWorkItemFactvw.
This query should give you a good start on getting the related work items. You can filter it down from here if you only want to include problems.
SELECT C.ID, WIWI.ID
FROM dbo.ChangeRequestDimvw C
INNER JOIN dbo.WorkItemDimvw WI ON
WI.EntityDimKey = C.EntityDimKey
INNER JOIN dbo.WorkItemRelatesToWorkItemFactvw AS WIRWI ON
WIRWI.WorkItemDimKey = WI.WorkItemDimKey
INNER JOIN dbo.WorkItemDimvw AS WIWI ON
WIWI.WorkItemDimKey = WIRWI.WorkItemRelatesToWorkItem_WorkItemDimKey
union
SELECT C.ID, WIWI.ID
FROM dbo.ChangeRequestDimvw C
INNER JOIN dbo.WorkItemDimvw WI ON
WI.EntityDimKey = C.EntityDimKey
INNER JOIN dbo.WorkItemRelatesToWorkItemFactvw AS WIRWI ON
WIRWI.WorkItemRelatesToWorkItem_WorkItemDimKey = WI.WorkItemDimKey
INNER JOIN dbo.WorkItemDimvw AS WIWI ON
WIWI.WorkItemDimKey = WIRWI.WorkItemDimKey
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Sql query to get union of matching rows
I want to write a sql query that shows union f all the [Type] for each [Key] if [Key] has atleast one [Type] in common and for non matched [Key]s it will return the row as it is.
For example In the sql table below [Key] '1' and '2' has [Type] 'B' in common and [Key] '1' and '4' has [Type] 'A' in common. In this case [Key] '1', '2' and '4' are related so result will be union of [Type]s in [Key]s '1', '2' and '4' which are 'A', 'B', 'C'
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Input:
declare @categories table ([Key] int, [Type] Char(1))
insert into @categories ([Key], [Type]) values (1, 'A')
insert into @categories ([Key], [Type]) values (1, 'B')
insert into @categories ([Key], [Type]) values (2, 'B')
insert into @categories ([Key], [Type]) values (2, 'C')
insert into @categories ([Key], [Type]) values (3, 'D')
insert into @categories ([Key], [Type]) values (4, 'E')
insert into @categories ([Key], [Type]) values (4, 'A')
insert into @categories ([Key], [Type]) values (5, 'F')
insert into @categories ([Key], [Type]) values (5, 'G')
insert into @categories ([Key], [Type]) values (6, 'G')
insert into @categories ([Key], [Type]) values (6, 'H')
Desired output:
Key Type
1 A
1 B
1 C
1 E
2 A
2 B
2 C
3 D
4 A
4 B
4 E
5 F
5 G
5 H
6 F
6 G
6 H
The data element names are wrong. KEY is a reserved word; “Categories" and "type" are called attribute properties in ISO-11179 rules. Matthias Kläy is right; this is a graph problem in disguise, but you can do it with set theory to get what are called
equivalence classes.
An edge in a graph has two nodes. Some authors allow a single node to count as a edge, but a better way is to put the same node on both ends of the edge. Here is the graph in a table with all the needed constraints. This is why you should post DDL and not be
so rude.
DROP TABLE Graph;
CREATE TABLE Graph
(edge INTEGER NOT NULL,
node_1 CHAR(1) NOT NULL,
node_2 CHAR(1) NOT NULL,
CHECK (node_1 <= node_2),
PRIMARY KEY (node_1, node_2));
Here is your data in the correct format.
INSERT INTO Graph
VALUES
(1, 'A', 'B'),
(2, 'B', 'C'),
(3, 'D', 'D'), -- orphan node
(4, 'A', 'E'),
(5, 'F', 'G'),
(6, 'G', 'H');
Now Google Warshall's Algorithm. It uses three nested loops and an adjacency array. This is very clean and fast in a procedural language. Not so much in SQL. Let us do this in steps:
WITH X1 (edge, node1_1, node1_2, node2_1, node2_2 )
AS
(SELECT CASE WHEN G1.edge <> G2.edge
THEN G1.edge ELSE G2.edge END,
G1.node_1, G1.node_2,
G2.node_1, G2.node_2
FROM Graph AS G1, Graph AS G2
WHERE G1.node_1 IN (G2.node_1, G2.node_2)
AND G1.edge <> G2.edge),
X2 (edge, node_1, node_2)
AS
(SELECT edge,
CASE WHEN node1_1 IN (node2_1, node2_2) THEN node1_2 ELSE node1_1 END,
CASE WHEN node2_1 IN (node1_1, node1_2) THEN node2_2 ELSE node2_1 END
FROM X1)
SELECT DISTINCT edge,
CASE WHEN node_1 < node_2 THEN node_1 ELSE node_2 END,
CASE WHEN node_2 < node_1 THEN node_1 ELSE node_2 END
FROM X2;
The X1 subquery gets the paths of length two. The X2 subquery removes the middle node and creates a new sorted edge. Insert these new rows into Graphs, if they are not there. Repeat the process until no more rows are added.
DROP TABLE Graph;
CREATE TABLE Graph
(edge INTEGER NOT NULL,
node_1 CHAR(1) NOT NULL,
node_2 CHAR(1) NOT NULL,
CHECK (node_1 <= node_2),
PRIMARY KEY (node_1, node_2));
INSERT INTO Graph
VALUES
(1, 'A', 'B'),
(2, 'B', 'C'),
(3, 'D', 'D'), -- orphan node
(4, 'A', 'E'),
(5, 'F', 'G'),
(6, 'G', 'H');
Here is the monster rolled up into a single statement.
INSERT INTO Graph
SELECT DISTINCT edge,
CASE WHEN node_1 < node_2 THEN node_1 ELSE node_2 END,
CASE WHEN node_2 < node_1 THEN node_1 ELSE node_2 END
FROM (SELECT edge,
CASE WHEN node1_1 IN (node2_1, node2_2) THEN node1_2 ELSE node1_1 END,
CASE WHEN node2_1 IN (node1_1, node1_2) THEN node2_2 ELSE node2_1 END
FROM
(SELECT CASE WHEN G1.edge < G2.edge
THEN G1.edge ELSE G2.edge END,
G1.node_1, G1.node_2,
G2.node_1, G2.node_2
FROM Graph AS G1, Graph AS G2
WHERE G1.node_1 IN (G2.node_1, G2.node_2)
AND G1.edge <> G2.edge) AS X1(edge,node1_1, node1_2, node2_1, node2_2) )
AS X2(edge, node_1, node_2)
EXCEPT
SELECT * FROM Graph;
SELECT * FROM Graph ORDER BY edge, node_1, node_2;
1 A B
1 A C
1 B E
1 C E
2 B C
3 D D
4 A E
5 F G
5 F H
6 G H
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Hi
I use SQL Server Management Studio
can I have a sql query to get count as shown below against each month column and name column to get distinct count.
for example if there is two rows with the same date period and same name then the count should be one in first row and zero in the next row of the same data.
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AA
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AK
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10/1/2013 0:00
AK
1
10/1/2013 0:00
AK
0Hi,
Thanks for the query but this query gives the total count like shown below
if see the second row in the below table AK for 2012-12-1 gives total count as 2 but need the query to show the first row as 1 and there after 0
query result
Month name cnt
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2012-12-01 00:00:00.000 AK 2
2012-12-01 00:00:00.000 AK 2
2013-01-01 00:00:00.000 AB 1
2013-01-01 00:00:00.000 AK 2
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