Need to display days for every "X" weeks

I have start and end dates, along with specific days of the week that I'm outputting.
However, I need to display them every "X" week but I'm not sure how to do that.
For example: show Monday, Wednesday, and Friday for every 2 weeks (or every 3, 4,5 weeks).
Can someone shed some light?
TIA

Another option, depending on what you are really trying to do.
Loop from day A to day B.
If current itteration of the day is a designated day of the week [dayOfWeek(currentDay)] do one thing, else do another.
If current itteration of the day is the end of the week [I.E. dayOfWeek(currentDay) is 7] then break the display to a new week.
There are probably other ways to do this as well. The date time functions could probably give you some ideas.
http://livedocs.adobe.com/coldfusion/8/htmldocs/functions-pt0_05.html#1098968

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How can I display summary for every 15 minutes using DATE datatype

This is probably an easy question, but the answer eludes me...
I am trying to write a SQL report that displays aggregate totals for every 15 minute period. I know you can do something like this to get every minute:
select to_char(import_date,'MM-DD-YYYY HH24:MI'),
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FROM       got_i_d_15
GROUP BY i_d_15
ORDER BY i_d_15;

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I wanted to pull the results from two date fields and calculate the lapsed time. Both dates in the calculation are from the same field, so I used the command feature in Crystal to differentiate the two
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once I had the above I used this:
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Now to what I need to do; if I provided too much info I am sorry, I just was hoping to give enough.
I need the results for a full work week; the catch is I donu2019t need it for the previous week but for two weeks back; i.e. if I ran the report on Monday the 19th I want to pull records from the 5th to the 9th
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to CurrentDate - DayofWeek(CurrentDate) u2013 1
will pull the prior full business week (m-f); i.e. ran on Monday the 19th- pulls records for the 12th to 16th, no good for me.
Furthermore, if the field is populated late Friday afternoon and field is not populated until the next week I need to capture that on the following weeks report- eventhough the first part was populated the prior week.
So, report runs Mon. the 19th captures 5th to 9th, but is populated the 9th and the is not populated til the 12th, 13th, or 14th then that cant show on report for week of 5th to 9th, but on the report for 12th to 16th.
Iu2019d greatly appreciate any assistance and apologize if I made little to no sense when describing my issue.

Try:
SELECT max(case when a.attribute_name = 'InstallerContact'
                    then "A"."CREATED_DATE" else null end) as installerContactCreatedDate,
             max(case when a.attribute_name = 'dateScheduled'
                    then "A"."CREATED_DATE" else null end) as dateScheduledCreatedDate,
     TO_NUMBER("A"."OBJECT_KEY")
FROM "OMS"."AUDITS" "A"
WHERE
("A"."ATTRIBUTE_NAME" = 'installerContact'
   AND "A"."CREATED_DATE" > SYSDATE - 45)
OR
("A"."ATTRIBUTE_NAME" = 'dateScheduled'
   AND "A"."CREATED_DATE" between SYSDATE, - datepart("dw", sysdate) - 13
                                             and SYSDATE - datepart("dw", sysdate) - 7 )
group by "A"."OBJECT_KEY"
having max(case when a.attribute_name = 'dateScheduled'
                    then "A"."CREATED_DATE" else null end) is not null
(where datepart("DW", <date>) returns the day of week. It's not clear what DB you are using.)
This assumes that the installer date is within 32 days or so of the scheduled date. Increase the 45 (or remove the date condition altogether - but that would be very slow on a big table) if that's not the case.
sysdate - datepart() returns the prior Saturday,
subtracting 7 days is the end of your week period (Saturday) two weeks ago,
subtracting 13 is the Sunday of your week period two weeks ago.
The case statement within the max() database aggregate functions will be null, and therefore not effect the results, if the attribute name is not the one we are interested in at the moment.
The having clause will restrict the returned records to those objects scheduled within the week of interest. (Since the WHERE clause is using an OR, there may be records with installerContact date > 45 days ago, but the dateScheduled is not within our week of interest. In that case, the max() in the HAVING clause will be null.)
And it's all done with one database query!
HTH,
Carl

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Dear Gurus,
I want to find the Last day of a given week number.
Can anyone help me out.
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Here I dont want to pass date,
If I give Week Number, Can I get that Week Numbers
Last date and First Date.
test@ORA10G>
test@ORA10G> -- this query fetches the start and end dates for a specified week in the current year
test@ORA10G>
test@ORA10G> select
2    wk as week,
3    min(dt) as start_date,
4    max(dt) as end_date
5 from (
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11 )
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test@ORA10G>
test@ORA10G> /
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WE START_DAT END_DATE
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test@ORA10G>
test@ORA10G> /
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WE START_DAT END_DATE
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test@ORA10G>
test@ORA10G> /
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test@ORA10G>
test@ORA10G>pratz
can be shortened further:
test@ORA10G>
test@ORA10G> select
2    to_char(trunc(sysdate,'yyyy')+level-1,'ww') as wk,
3    min(trunc(sysdate,'yyyy')+level-1) as start_dt,
4    max(trunc(sysdate,'yyyy')+level-1) as end_dt
5 from dual
6 where to_number(to_char(trunc(sysdate,'yyyy')+level-1,'ww')) = &week_number
7 connect by level <= trunc(add_months(sysdate,12),'yyyy') - trunc(sysdate,'yyyy')
8 group by to_char(trunc(sysdate,'yyyy')+level-1,'ww')
9 /
Enter value for week_number: 1
WK START_DT END_DT
01 01-JAN-08 07-JAN-08
test@ORA10G>
test@ORA10G> /
Enter value for week_number: 53
WK START_DT END_DT
53 30-DEC-08 31-DEC-08
test@ORA10G>
test@ORA10G> /
Enter value for week_number: 23
WK START_DT END_DT
23 03-JUN-08 09-JUN-08
test@ORA10G>
test@ORA10G> /
Enter value for week_number: 14
WK START_DT END_DT
14 01-APR-08 07-APR-08
test@ORA10G>
test@ORA10G>Message was edited by:
pratz

Start day for global agenda week view

Does anyone know if there is a way to change the first day of the week for the global agenda week view? For example, instead of having the week start on Monday, it starts on Sunday.

Hi Christopher,
The WEEKDAY function allows specifying either Sunday or Monday as the first day of the week:
WEEKDAY
The WEEKDAY function returns a number that is the day of the week for a given date. WEEKDAY(date, first-day)
Â date: The date the function should use. date is a date/time value. The time portion is ignored by this function.
Â first-day: An optional value that specifies how days are numbered.
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Need to display days for every "X" weeks

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