Obtain count of values, including the values that are not in the table

Question

I have values: 1,2,3,7,8,9
and my table contain value 3,7,8,3
I need get result of select
-value- -count-
-1-     -0-
-2-     -0-
-3-     -2-
-7-     -1-
-8-     -1-
-9-     -0-
I tried
select value, count(value) from table where value in ('1','2','3','7','8','9') group by value
but I get only
-value- -count-
-3-     -2-
-7-     -1-
-8-     -1-
Thank you for help

Answer 1

Thank you for help but this is not functional if values are text (varchar).Have you mentioned that ? In your example post you have mentioned only numeric values. Why don't you try yourself, When you have an working (? Oops, there is no version mentioned by OP, So may not be working) example ?
SQL> SELECT * FROM v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - Prod
PL/SQL Release 10.2.0.3.0 - Production
CORE    10.2.0.3.0      Production
TNS for 32-bit Windows: Version 10.2.0.3.0 - Production
NLSRTL Version 10.2.0.3.0 - Production
SQL> SELECT job,COUNT(job)
  2  FROM emp
  3  GROUP BY job;
JOB       COUNT(JOB)
CLERK              4
SALESMAN           4
PRESIDENT          1
MANAGER            3
ANALYST            2
SQL> SELECT column_value,COUNT(job)
  2  FROM emp e, TABLE(sys.odciVARCHAR2list('CLERK','PROGRAMMER','SALESMAN'
  3                                        ,'SALESMAN','DBA','PRESIDENT','MANAGER'
  4                                        ,'Architect','ANALYST')) t
  5  WHERE e.job(+)=t.column_value
  6  GROUP BY column_value
  7  ORDER BY 1;
COLUMN_VALUE
COUNT(JOB)
ANALYST
         2
Architect
         0
CLERK
         4
COLUMN_VALUE
COUNT(JOB)
DBA
         0
MANAGER
         3
PRESIDENT
         1
COLUMN_VALUE
COUNT(JOB)
PROGRAMMER
         0
SALESMAN
         8