ORA-01878: specified field not found in datetime or interval

Question

I have TIME_SOLD field which is a date data type. WHen I run a simple query against this table with the where clause below, I get ORA-01878: specified field not found in datetime or interval. Please help?
and to_char(from_tz(cast(time_sold as timestamp), 'Australia/Sydney') at time zone 'US/Pacific', 'yyyymmdd') >= '20091001'
and to_char(from_tz(cast(time_sold as timestamp), 'Australia/Sydney') at time zone 'US/Pacific', 'yyyymmdd') < '20091101'

Answer 1

just to give an exampe I've created a table called your_table with a date field (time_sold).
I've inserted 100 random values plus this one: 20090329 02:30:00 (read it using the format yyyymmdd hh24:mi:ss).
It's a non valid time in Rome because on March 29 we went to the DST so time skipped from 02.00 to 03.00.
Here's my script's result:
SQL> declare
  2    x varchar2(100);
  3    cursor c is
  4      select time_sold from your_table;
  5  begin
  6    for r in c loop
  7      begin
  8       x:= to_char(from_tz(cast(r.time_sold as timestamp), 'Europe/Rome') at time zone 'US/Pacific', 'yyyym
mdd');
  9      exception
10        when others then
11           DBMS_OUTPUT.PUT_LINE(SQLCODE||' '||to_char(r.time_sold,'yyyymmdd hh24:mi:ss'));
12      end;
13    end loop;
14  end;
15  /
-1878 20090329 02:30:00Max