Oracle group by query

Question

create a matrix query to display a job, the salary for that job based on department number, and the total salary for that job, for departments 20,50,80,90 giving each column an appropriate heading. this is the excise query available in oracle in ebook. I have solved it by using inline view.. given below.. Is ther any other way to solve the same quey.. Please help..
SELECT job_id,
CASE
WHEN department_id=20
THEN salary
ELSE NULL
END AS dept20,
CASE WHEN department_id=50 THEN salary ELSE NULL
END AS dept50,
CASE WHEN department_id=80 THEN salary ELSE NULL
END AS dept80,
CASE WHEN department_id=90 THEN salary ELSE NULL
END AS dept90,
salary
FROM
(SELECT job_id,
SUM(salary) salary,
department_id
FROM employees
WHERE department_id IN (20,50,80,90)
GROUP BY job_id,
department_id
) order by job_id;

Answer 1

Hi,
you can try something like this:
*not tested
select distinct job_id,
(select nvl(sum(salary), 0) from employees where job_id = e.job_id and department_id = 20) sum_sal_20,
(select nvl(sum(salary), 0) from employees where job_id = e.job_id and department_id = 50) sum_sal_50,
(select nvl(sum(salary), 0) from employees where job_id = e.job_id and department_id = 80) sum_sal_80,
(select nvl(sum(salary), 0) from employees where job_id = e.job_id and department_id = 90) sum_sal_90
from employees e
where department_id IN (20,50,80,90)
group by job_id, department_idRegards
Imran