Oracle standard example doesn't work

Question

Hi All,
I am surprsied to see that following standard example from Oracle doesn't work as expected. http://www.oracle.com/technology/products/integration/esb/files/stringtoxml.zip
Did any one face same error with it?
Regards,
Vigni

Answer 1

Hi,
The xml string is not valid, you need to place the following part at the beginning of the string:
<?xml version="1.0" encoding="UTF-8"?>
So the first line needs to read:
String in = "&lt;?xml version=\"1.0\" encoding=\"UTF-8\"?&gt;\n<parameters xmlns=\"http://www.tcs.com/WSIF/insurance/IdentifyPolicy/1.0\">\n" +
You also must change the indexOf parts to >=0 instead of >0. the parseString method should be:
public static NodeList parseString1(String inputXML) throws XMLParseException,
SAXException,
IOException {
System.out.println(inputXML);
StringBuffer s4= new StringBuffer(inputXML);
int index = 0;
while(s4.indexOf("&gt;") > 0 || s4.indexOf("&lt;") >= 0){
index = s4.indexOf("&gt;");
if (index>=0)
s4.replace(index,index+4,">");
index = s4.indexOf("&lt;");
if (index >=0)
s4.replace(index,index+4,"<");
System.out.println(s4.toString());
DOMParser parser1 = new DOMParser();
ByteArrayInputStream Bis1 = new ByteArrayInputStream(s4.toString().getBytes());
parser1.parse(Bis1);
XMLDocument xd1= parser1.getDocument();
return (xd1.getChildNodes());
Regards,
Andre