Outer Join and Index Usage

I am simply trying to run the following query:
select /*+ index (serialnumber trans) */ distinct device,
device_path||device hierarchy,
sn.serialnumber
from z_xfmr_levels z
left join serialnumber sn
on z.device = sn.transformergrid(+);
I am using Oracle 9i
z_xfmr_levels has 75,000 distinct rows
serialnumber has 204,000 distinct rows
The explain plan shows a hash join and a full table scan on both tables.
How can I get the query to use the index on the transformergrid field of the serialnumber table?

user10441616 wrote:
I am simply trying to run the following query:
select /*+ index (serialnumber trans) */ distinct device,
device_path||device hierarchy,
sn.serialnumber
from z_xfmr_levels z
left join serialnumber sn
on z.device = sn.transformergrid(+);
I am using Oracle 9i
z_xfmr_levels has 75,000 distinct rows
serialnumber has 204,000 distinct rows
The explain plan shows a hash join and a full table scan on both tables.
How can I get the query to use the index on the transformergrid field of the serialnumber table?What makes you think an index access is more appropriate than the the two full scans and a hash join?
If you have some legitimate reason, please share ... if not, please read this http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:9422487749968

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    <PI>
    <PIqid>1</PIqid>
    <PIpid>450</PIpid>
    <PItext>CBB1015 - Router Firewall Settinngs Process</PItext>
    <PItype>Title</PItype>
    <PIto>2</PIto>
    <PO />
    </PI>
    <PI>
    <PIqid>2</PIqid>
    <PIpid>450</PIpid>
    <PItext>Is the customers PC Firewall turned off?</PItext>
    <PItype>Question</PItype>
    <PIfrom>1</PIfrom>
    <PIto>2.2,2.1</PIto>
    <PO>
    <POoid>1</POoid>
    <POqid>2</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>5</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>2</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>3</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>3</PIqid>
    <PIpid>450</PIpid>
    <PItext>Advise the customer to turn off the PC Firewall in order to continue. Has this been done?</PItext>
    <PItype>Question</PItype>
    <PIfrom>2.2</PIfrom>
    <PIto>3.2,3.1</PIto>
    <PIc>278</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>3</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>5</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>3</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>4</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>4</PIqid>
    <PIpid>450</PIpid>
    <PItext>Advise the customer the PC Firewall must be switched off before this process????</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>3.2</PIfrom>
    <PIe1>14</PIe1>
    <PO />
    </PI>
    <PI>
    <PIqid>5</PIqid>
    <PIpid>450</PIpid>
    <PItext>Is the customer able to access the internet now?</PItext>
    <PItype>Question</PItype>
    <PIfrom>3.1,2.1</PIfrom>
    <PIto>5.2,5.1</PIto>
    <PO>
    <POoid>1</POoid>
    <POqid>5</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>6</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>5</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>8</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>6</PIqid>
    <PIpid>450</PIpid>
    <PItext>Is the customer having a problem with a specific website?</PItext>
    <PItype>Question</PItype>
    <PIfrom>5.1</PIfrom>
    <PIto>6.2,6.1</PIto>
    <PO>
    <POoid>1</POoid>
    <POqid>6</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>7</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>6</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>8</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>7</PIqid>
    <PIpid>450</PIpid>
    <PItext>1536: CBB1008 - Browser Setup and Daignostics</PItext>
    <PItype>SubProcess</PItype>
    <PIfrom>6.1</PIfrom>
    <PIas>1536-1-0</PIas>
    <PO />
    </PI>
    <PI>
    <PIqid>8</PIqid>
    <PIpid>450</PIpid>
    <PItext>What is the security level on the CPE Management page?</PItext>
    <PItype>Question</PItype>
    <PIfrom>6.2,5.2</PIfrom>
    <PIto>8.4,8.3,8.2,8.1</PIto>
    <PIc>279</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
    <POtext>Block All</POtext>
    <POto>9</POto>
    </PO>
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    <POoid>2</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
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    <POto>11</POto>
    </PO>
    <PO>
    <POoid>3</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
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    <POto>12</POto>
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    <PO>
    <POoid>4</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
    <POtext>User Defined</POtext>
    <POto>12</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>9</PIqid>
    <PIpid>450</PIpid>
    <PItext>Change the security level to Standard. Does this resolve the customers issue?</PItext>
    <PItype>Question</PItype>
    <PIfrom>8.1</PIfrom>
    <PIto>9.2,9.1</PIto>
    <PIc>280</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>9</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>10</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>9</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>11</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>10</PIqid>
    <PIpid>450</PIpid>
    <PItext>Issue Resolved</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>9.1</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>122</PIe3>
    <PO />
    </PI>
    <PI>
    <PIqid>11</PIqid>
    <PIpid>450</PIpid>
    <PItext>Change the security level to Disabled. Is the customer able to browse the internet?</PItext>
    <PItype>Question</PItype>
    <PIfrom>9.2,8.2</PIfrom>
    <PIto>11.2,11.1</PIto>
    <PIc>281</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>11</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>12</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>11</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>14</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>12</PIqid>
    <PIpid>450</PIpid>
    <PItext>Change the security level to Standard. Is the customer able to browse the internet now?</PItext>
    <PItype>Question</PItype>
    <PIfrom>11.1,8.3,8.4</PIfrom>
    <PIto>12.2,12.1</PIto>
    <PIc>283</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>12</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>13</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>12</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>14</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>13</PIqid>
    <PIpid>450</PIpid>
    <PItext>Issue Resolved</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>12.1</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>123</PIe3>
    <PO />
    </PI>
    <PI>
    <PIqid>14</PIqid>
    <PIpid>450</PIpid>
    <PItext>Ask the customer to perform a master reset. Does this resolve their issue?</PItext>
    <PItype>Question</PItype>
    <PIfrom>12.2,11.2</PIfrom>
    <PIto>14.2,14.1</PIto>
    <PIc>282</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>14</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>16</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>14</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>15</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>15</PIqid>
    <PIpid>450</PIpid>
    <PItext>Faulty CPE</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>14.2</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>124</PIe3>
    <PO />
    </PI>
    <PI>
    <PIqid>16</PIqid>
    <PIpid>450</PIpid>
    <PItext>Issue Resolved</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>14.1</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>123</PIe3>
    <PO />
    </PI>
    </P>
    Thanks in advance
    Edited by: user512743 on Nov 18, 2008 4:46 AM

  • Oute Join and Inner Join

    Hi,
    I need to join three tables, based on some conditions (EKPO, EKBE and EKKN Note: All PO line items from EKPO will have a movement associated in the EKBE Table. Capture all PO line items where no matches found in the EKPO-EKBE join)
    for the above requirement shall I write my query like this?
    SELECT ekpo~ebeln
             ekpo~ebelp
             ekpo~loekz
             ekpo~txz01
             ekpo~matnr
             ekpo~bukrs
             ekpo~werks
             ekpo~menge
             ekpo~meins
             ekpo~knttp
             ekbe~vgabe
             ekbe~bwart
             ekbe~menge
             ekbe~dmbtr
             ekbe~shkzg
             ekkn~sakto
             ekkn~kostl
             ekkn~ps_psp_pnr
    INTO CORRESPONDING FIELDS OF TABLE i_podata
             FROM ekpo LEFT OUTER JOIN ekbe ON ekbeebeln = ekpoebeln AND
                                               ekbeebelp = ekpoebelp
                            INNER JOIN ekkn ON ekknebeln = ekpoebeln AND
                                               ekknebelp = ekpoebelp
                                         WHERE ekpo~werks IN s_werks AND
                                               ekpo~ebeln IN s_ebeln.
    Shall I use both Outer Join and Inner join in one Query?
    Please correcte me.
    Thanks
    Frank Rex

    Hi,
    You can use both inner join and outer join in the same select statement.
    Ensure first all the inner joins between tables are declared and put the left outer join at the end.
    Some sample code for your reference:
      SELECT
              AVBELN AKUNNR ABSTNK ABSTDK AVKORG AVTWEG AAUART AKNUMV
              BPOSNR BMATNR BWERKS BSPART BLGORT BKZWI1
              SUM( BKWMENG ) AS KWMENG DBZIRK D~VKGRP
              EDISPO EPRCTR
    FROM VBAK AS A INNER JOIN VBAP AS B ON AVBELN EQ BVBELN
                   INNER JOIN VBPA AS C ON CVBELN EQ BVBELN
                   INNER JOIN KNVV AS D ON DKUNNR EQ AKUNNR
                AND DVKORG EQ AVKORG AND DVTWEG EQ AVTWEG
                   LEFT OUTER JOIN MARC AS E ON E~MATNR EQ
                             BMATNR AND EWERKS EQ B~WERKS
              INTO CORRESPONDING FIELDS OF TABLE IT_ORDERS
              WHERE A~VKORG IN SO_VKORG
              AND A~VTWEG IN SO_VTWEG
              AND A~KUNNR IN SO_KUNNR
              AND A~ERDAT IN SO_ERDAT
              AND A~AUART IN ('ZFOR','ZROR','ZEOR','ZDXR','ZXOR','ZRM1','ZGOR','ZSOR')
              AND B~MATNR IN SO_MATNR
              AND B~WERKS IN SO_WERKS
              AND B~SPART IN SO_SPART
              AND B~ABGRU EQ SPACE
              AND A~LIFSK EQ SPACE
              AND A~FAKSK EQ SPACE
              AND B~VSTEL IN SO_VSTEL
              AND B~LGORT IN SO_LGORT
              AND C~KUNNR IN SO_SHIP
              AND C~PARVW EQ 'WE'
              AND D~VKGRP IN SO_VKGRP
              AND D~BZIRK IN SO_BZIRK
              AND B~LGORT NE '0950'
              GROUP BY AVBELN AKUNNR ABSTNK ABSTDK 
              AVKORG AVTWEG AAUART AKNUMV B~POSNR
              BMATNR BWERKS BSPART BKZWI1 D~BZIRK
              DVKGRP BLGORT EDISPO EPRCTR E~MATGR.
    Lakshminarayanan.
    P.S.Mark all helpful answers for points.

  • Script to find out table and index candidates to keep in the buffer pool

    I am looking for a script to find out tables and indexes to keep in the buffer pool.
    Could you help me on this ?
    thanks...
    Markus

    this is more of a open question. As you know ur data well. We do not know whats ur data. cachin tables in buffer pool is okay, but it might age out after not being used...instead you can use the KEEP POOL...to cache small tables/popular tables into the keep pool...as keep pool guarantees full caching .....
    here are some links on keep pool cacheing
    http://download.oracle.com/docs/cd/B19306_01/server.102/b14211/memory.htm#sthref410
    http://www.dba-oracle.com/oracle_tips_cache_small_fts.htm
    http://www.dba-oracle.com/t_script_automate_keep_pool_tables_indexes.htm
    http://www.dba-oracle.com/oracle_news/news_caching_keep_pool_large_objects_clob_blob.htm
    Edited by: user630084 on Apr 8, 2009 5:48 AM

  • How to find out CPU and memory usage for an instance?

    Hi DBA Gurus,
    How to find out CPU usage and memory usage for an instance?
    Any information is appreciated!
    Thank you!
    Robert

    you can calculate cpu usage by adding fallowing three factors which you can get from v$sysstat
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    2. Recursive CPU time : Sometimes, to execute a SQL statement issued by a user, the Oracle Server must issue additional statements. Such statements are called recursive calls or recursive SQL statements. For example, if you insert a row into a table that does not have enough space to hold that row, the Oracle Server makes recursive calls to allocate the space dynamically if dictionary managed tablespaces are being used.
    Recursive calls are also generated due to the inavailability of dictionary info in the dictionary cache, firing of database triggers, execution of DDL, execution of SQL within PL/SQL blocks, functions or stored procedures and enforcement of referential integrity constraints
    3. Other CPU time : This represents the percentage of time spent looking for buffers, fetching rows or index keys, etc. Generally, \"Other\" CPU should represent the highest percentage of CPU time out of the total CPU time used.
    total memory used you can calculate adding
    total_agrigate_area+sga
    memory usage on os level you can know by fallowing commands
    vmstat 5 20 depending upon os

  • Problem with outer joins and the class indicator/discriminator

    Hello,
    I am having a problem defining a query in toplink (10.1.3.3).
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    The query then comes down to (as I have it now):
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    ....t1.ovr_id = t2.id(+) AND t2.discriminator = 'OVR' AND ...
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    ... LEFT JOIN values t2 ON (t1.ovr_id = t2.id AND t2.discriminator = 'OVR') ...
    This leads to the behaviour that the query returns ONLY the objects that have override and default values.
    An overview of the queries (simplified)
    Toplink, at the moment, returns only results if both override and default values exists:
    SELECT t1.id
    t1.def_id,
    t1.ovr_id
    FROM values t2,
    parameter t1,
    values t0
    WHERE nvl(t2.value, t0.value) = 15 AND
    t1.ovr_id = t2.id(+) AND t2.discriminator = 'OVR' AND
    t1.def_id = t0.id AND t0.discriminator = 'DEF'
    Situation Wanted:
    SELECT t1.id
    t1.def_id,
    t1.ovr_id
    FROM parameter t1
    LEFT JOIN values t2 ON (t1.ovr_id = t2.id AND t2.discriminator = 'OVR')
    JOIN values t0 ON (t1.def_id = t0.id AND t0.discriminator = 'DEF')
    WHERE nvl(t2.value, t0.value) = 15
    Anyone know if there is some statement I am missing to allow an actual outer join on descriptors containing class indicators/discriminators? A possible rewrite?
    Thanks in advance,
    Rudy

    This is a bug in TopLink's outer join support for Oracle. Currently the outer join is put in the where clause, instead of the from clause, as we do on other platforms. You might be able to fix it by changing your OraclePlatform to return false for shouldPrintOuterJoinInWhereClause().
    Please log this bug on EclipseLink, or through Oracle technial support.
    There is a workaround using,
    descriptor.getInhertiancePolicy().setAlwaysUseOuterJoinForClassType(true);
    James : http://www.eclipselink.org

  • Rewrite the query with out joins and group by

    Hi,
    This was an interview question.
    Table Names: bookshelf_checkout
    bookshelf
    And the join condition between these two tables is title
    We need to rewrite below query without using join condition and group by clause ?
    SELECT b.title,max(bc.returned_date - bc.checkout_date) "Most Days Out"
               FROM bookshelf_checkout bc,bookshelf b
               WHERE bc.title(+)=b.title
               GROUP BY b.title;When I was in college, I read that most of the SELECT statements can be replaced by basic SQL operations (SET OPERATORS). Now I am trying to rewrite the query with SET operators but not able to get the exact result.
    Kindly help me on this.
    Thanks,
    Suri

    Something like this?
      1  WITH books AS (
      2  SELECT 'title 1' title FROM dual UNION ALL
      3  SELECT 'title 2' FROM dual UNION ALL
      4  SELECT 'title 3' FROM dual ),
      5  bookshelf AS (
      6  SELECT 'title 1' title, DATE '2012-05-01' checkout_date, DATE '2012-05-15' returned_date FROM dual UNION ALL
      7  SELECT 'title 1' title, DATE '2012-05-16' checkout_date, DATE '2012-05-20' returned_date FROM dual UNION ALL
      8  SELECT 'title 2' title, DATE '2012-04-01' checkout_date, DATE '2012-05-15' returned_date FROM dual )
      9  SELECT bs.title, MAX(bs.returned_date - bs.checkout_date) OVER (PARTITION BY title) FROM bookshelf bs
    10  UNION
    11  (SELECT b.title, NULL FROM books b
    12  MINUS
    13* SELECT bs.title, NULL FROM bookshelf bs)
    SQL> /
    TITLE   MAX(BS.RETURNED_DATE-BS.CHECKOUT_DATE)OVER(PARTITIONBYTITLE)
    title 1                                                           14
    title 2                                                           44
    title 3Lukasz

  • LIKE, LIKEC and Index usage

    I've table that contains about 20 million rows, and I've created index for varchar2(100) column. It works well if I do
    SELECT * FROM MY_TABLE WHERE MY_COL LIKE 'FOO%';
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    SELECT * FROM MY_TABLE WHERE MY_COL LIKEC 'FOO%';
    I always get full table scan in explain plan.
    I tried to use NVARCHAR, or index created by TO_NCHAR but I always end up hitting full table scan.
    Should I create index some special way or do something else before I get index working?

    Just a gut feeling : is the database using character semantics or byte semantics?
    My gut feeling, after looking up the documentation, is it should be character semantics.
    BTW: Not posting version info decreases the chance you get an adequate reply.
    Sybrand Bakker
    Senior Oracle DBA

  • Left outer join usage in obiee BMM layer

    Hi All,
    We lately started using left outer join in our bmm layer , to meet the requirement expectation .
    problem : We have two tables  Fact A , Dim B . There is an join int_id column to join them . Problem is... in table Dim B , we have 3 millions rows of Int_id and in fact table it is loaded for only data available(1 million rows).
    Due to this we are dropping rows  in the report ..as it is only getting data where fact.int_id = dim.int_id. So we used left outer join to solve to one particular report .(we know we can do ETl to load dummy int_id and make it null , but it is huge effort ..so we did left outer join)
    These days , same kind of reports are in requirement . if i keep on doing same left outer join to meet the requirement in BMM layer ? is there any disadvantages due to this ? any performance degrade due to this ? please throw few lines on left outer join and its usage ?
    Thanks,
    Sri

    Remodel your tables that might be a partition or any other way and follow in BI as per your new model.
    Simply: Go for ETL kind of solution

  • Performance Tunning - Connect By and Outer Join Used - Urgent

    Hi,
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    All the tables having 2 lakhs record but the final result set is 20 thousand rows.
    The query is taking 5 minutes to complete the execution. How could i improve the performance.
    The query is
    SELECT
    'ABC' hrchy_id,
    SUBSTR(c.abc_cd,1,1) ,
    a.org_no bu_node_id,
    SUBSTR(d.abc_cd,1,1) ,
    a.prnt_org ,
    level hrchy_lvl_nb,
    a.eff_from_dt,
    a.eff_to_dt,
    FROM ((parent a INNER JOIN f_org b ON (a.org_no = b.org_no))
         left join org c on ( (a.org_no = (c.abc_cd)))
    ) left join org d on ( (a.prnt_org = d.abc_cd)))
    WHERE a.co_cd ='000'
    START with a.prnt_org = '0'
    CONNECT BY a.prnt_org = PRIOR a.org_no
    ORDER SIBLINGS BY a.org_no;
    Please suggest any idea or commands to improve the performance.
    Thanks in advance.

    Can you provide the structure of tree based SQL.
    Thanks in advance.But you have it already :-)
    SELECT
    'ABC' hrchy_id,
    a.org_no bu_node_id,
    a.prnt_org ,
    level hrchy_lvl_nb,
    a.eff_from_dt,
    a.eff_to_dt,
    FROM parent a WHERE a.co_cd ='000'
    START with a.prnt_org = '0'
    CONNECT BY a.prnt_org = PRIOR a.org_no
    ORDER SIBLINGS BY a.org_no;Regards
    Dmytro

  • Sample code and senarios to use outer join?

    We know the ABAP4 syntax for inner join, but never tried outer join and we even don't know if there is any outer join syntax in ABAP4 or not.  Would be very appreciated if some ABAP expert here let us know if there is any outer join and list the difference between inner join and outer join with detailed senarios or when we would use outer join or when to use inner join?  Also give a sample code on the outer join if there is any in ABAP?
    Thanks and we will give you reward points!

    Hye..
    Left outer join between table 1 and table 2 where column D in both tables set the join condition:
    Table 1                      Table 2
    A
    B
    C
    D
    D
    E
    F
    G
    H
    a1
    b1
    c1
    1
    1
    e1
    f1
    g1
    h1
    a2
    b2
    c2
    1
    3
    e2
    f2
    g2
    h2
    a3
    b3
    c3
    2
    4
    e3
    f3
    g3
    h3
    a4
    b4
    c4
    3
    |--|||--|
        Left Outer Join
        |--||||||||--|
        | A  | B  | C  | D  | D  | E  | F  | G  | H  |
        |--||||||||--|
        | a1 | b1 | c1 | 1  | 1  | e1 | f1 | g1 | h1 |
        | a2 | b2 | c2 | 1  | 1  | e1 | f1 | g1 | h1 |
        | a3 | b3 | c3 | 2  |NULL|NULL|NULL|NULL|NULL|
        | a4 | b4 | c4 | 3  | 3  | e2 | f2 | g2 | h2 |
        |--||||||||--|
    Example
    Output a list of all custimers with their bookings for October 15th, 2001:
    DATA: CUSTOMER TYPE SCUSTOM,
          BOOKING  TYPE SBOOK.
    SELECT SCUSTOMNAME SCUSTOMPOSTCODE SCUSTOM~CITY
           SBOOKFLDATE SBOOKCARRID SBOOKCONNID SBOOKBOOKID
           INTO (CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
                 BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
                 BOOKING-BOOKID)
           FROM SCUSTOM LEFT OUTER JOIN SBOOK
             ON SCUSTOMID = SBOOKCUSTOMID AND
                SBOOK~FLDATE = '20011015'
           ORDER BY SCUSTOMNAME SBOOKFLDATE.
      WRITE: / CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
               BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
               BOOKING-BOOKID.
    ENDSELECT.
    Reward if helpful.
    Thanks.
    Imran.

  • Inner join and outer  join in infosets

    hi everyone,
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    Thanks in advance.
    Bye.

    Hello,
    Inner join:
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    Outer Join:
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    Hope, it clarifies your doubt. Let me know if any questions.
    Thanks
    Viswa

  • Nested outer join

    I need to select records, one for each index having a list of column pairs indicating column name and id.
    An index may have one or more columns (obviously).
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    Example output:
    table_name, index_name, column_name, column_id, column_name, column_id ...
    I wrote what looked like the correct syntax (unfortunately, Oracle's meta data is not normalized):
    select i.table_name, i.index_name,
    c1.column_name, c1.column_id,
    c2.column_name, c2.column_id,
    c3.column_name, c3.column_id
    from used_indexes i,
    user_ind_columns ic1, user_tab_columns c1,
    user_ind_columns ic2, user_tab_columns c2,
    user_ind_columns ic3, user_tab_columns c3
    where i.uniqueness='UNIQUE'
    and i.table_name = 'CUST'
    and i.table_name = ic1.table_name
    and i.index_name = ic1.index_name
    and ic1.table_name = c1.table_name
    and ic1.column_name = c1.column_name
    and ic1.column_position = 1
    and i.table_name = ic2.table_name(+)
    and i.index_name = ic2.index_name(+)
    and ic2.column_name = c2.column_name
    and ic2.table_name = c2.table_name
    and ic2.column_position = 2
    and i.table_name = ic3.table_name(+)
    and i.index_name = ic3.index_name(+)
    and ic3.column_name = c3.column_name
    and ic3.table_name = c3.table_name
    and ic3.column_position = 3
    This query seems to 'hang' in SQL*Plus not returning any results or errors... EVER! Any ideas as to what the problem might be? Any suggestions as to how to create this query in a more suportable way? I will have to extend this to include up to 10 index fields for each index.
    Thanks,
    Jim

    I am not sure if this does what you want, but it is syntactically correct and runs.
    select i.table_name, i.index_name,c1.column_name, c1.column_id,c2.column_name, c2.column_id
    from user_indexes i
      left outer join user_ind_columns ic2
        on i.table_name = ic2.table_name
        and i.index_name = ic2.index_name
      inner join user_tab_columns c2
        on ic2.table_name = c2.table_name
        and ic2.column_name = c2.column_name
      left outer join user_ind_columns ic1
        on i.table_name = ic1.table_name
        and i.index_name = ic1.index_name
      inner join user_tab_columns c1
        on ic1.table_name = c1.table_name
       and ic1.column_name = c1.column_name
    where i.uniqueness='UNIQUE'
    and ic1.column_position = 1
    and ic2.column_position = 2
    order by 1,2However I don't think you are approaching this the right way. How can you be sure you aren't going to miss an index column? You have to add 2 tables an inner and outer join and a where predicate for each column you want to capture. That could get silly. There is at least one index on 5 columns in the Oacle dictionary and I have encountered larger indexes.
    This query captures everything. You just need to do a bit of procedural work to turn it into create index statements or whatever you are after.
    select i.table_name, i.index_name,c2.column_name, c2.column_id, ic2.column_position
    from user_indexes i
      inner join user_ind_columns ic2
        on i.table_name = ic2.table_name
        and i.index_name = ic2.index_name
      inner join user_tab_columns c2
        on ic2.table_name = c2.table_name
        and ic2.column_name = c2.column_name
    where i.uniqueness='UNIQUE'
    order by i.table_name, i.index_name,ic2.column_position
    </pre]                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                               

  • Outer Join Performance Issue

    Dear All,
    Please help me in tuning the below query as it is including the outer join and is going for full table scans.
    Query :
    SELECT
    T27.CONFLICT_ID,
    T27.LAST_UPD,
    T27.CREATED,
    T27.LAST_UPD_BY,
    T27.CREATED_BY,
    T27.MODIFICATION_NUM,
    T27.ROW_ID,
    T24.ATTRIB_39,
    T27.REMIT_ADDR_ORG_ID,
    T27.REMIT_ORG_EXT_ID,
    T16.NAME,
    T25.ACCNT_TYPE_CD,
    T27.RECAL_TAX_SRV_FLG,
    T27.PROJ_ID,
    T8.PROJ_NUM,
    T8.BU_ID,
    T5.NAME,
    T8.INTEGRATION_ID,
    T12.CURCY_CD,
    T25.PR_BL_ADDR_ID,
    T25.URL,
    T27.TTL_INVC_AMT,
    T27.INVC_TYPE_CD,
    T27.TTL_PD_AMT,
    T3.CG_ASSSET_ID,
    T17.ASSET_NUM,
    T27.VENDR_INVOICE_NUM,
    T4.TOT_QTY_SHIP,
    T4.TOT_EXTND_PRICE,
    T27.ACCNT_ID,
    T25.INTEGRATION_ID,
    T25.NAME,
    T25.BU_ID,
    T25.AVAIL_CREDIT_AMT,
    T10.NAME,
    T27.AGREEMENT_ID,
    T4.TOT_EXTND_TAX,
    T27.STMT_SOURCE_CD,
    T4.SRC_INVLOC_ID,
    T27.STATUS_CD,
    T4.TOT_QTY_BONUS,
    T27.X_DEPOSIT_AMT,
    T27.COMMENTS,
    T27.INVC_FULLY_PAID_DT,
    T26.SEQ_NUM,
    T27.ELEMENT_ID,
    T26.INSCLM_ID,
    T14.INSCLAIM_NUM,
    T27.BL_PER_ID,
    T27.INS_CLAIM_ID,
    T27.FN_ACCNT_ID,
    T27.CUSTOMER_REF_NUM,
    T27.TTL_NONREC_AMT,
    T25.OU_NUM,
    T24.ATTRIB_39,
    T27.AMT_CURCY_CD,
    T2.CCNUM_ENCRPKEY_REF,
    T18.PR_DEPOSIT_ID,
    T19.DISCNT_RULE_CD,
    T27.ORDER_ID,
    T4.STATUS_CHG_FLG,
    T25.MAIN_PH_NUM,
    T25.MAIN_FAX_PH_NUM,
    T27.DELINQUENT_FLG,
    T15.LOGIN,
    T25.PR_POSTN_ID,
    T4.ORDER_NUM,
    T22.ADDR,
    T22.ZIPCODE,
    T27.INVC_NUM,
    T27.INVC_DT,
    T22.COUNTRY,
    T22.CITY,
    T27.BL_ADDR_ID,
    T23.NAME,
    T27.POSTED_DT,
    T20.NAME,
    T27.BL_PERIOD_ID,
    T27.GOODS_DLVRD_TS,
    T23.NET_DAYS,
    T27.PAYMENT_TERM_ID,
    T23.DUE_DT,
    T27.DUE_DT,
    T27.VOID_REASON_TEXT,
    T27.DEPT_CD,
    T24.ATTRIB_60,
    T24.ATTRIB_28,
    T21.AMT,
    T1.STATE,
    T1.ADDR,
    T1.ADDR_LINE_2,
    T1.COUNTRY,
    T1.CITY,
    T1.ZIPCODE,
    T11.LOGIN,
    T21.ROW_ID,
    T9.ROW_ID,
    T1.ROW_ID,
    T13.ROW_ID,
    T7.ROW_ID
    FROM
    SIEBEL.S_ADDR_PER T1,
    SIEBEL.S_PTY_PAY_PRFL T2,
    SIEBEL.S_INVLOC T3,
    SIEBEL.S_ORDER T4,
    SIEBEL.S_ORG_EXT T5,
    SIEBEL.S_POSTN T6,
    SIEBEL.S_PARTY T7,
    SIEBEL.S_PROJ T8,
    SIEBEL.S_CON_ADDR T9,
    SIEBEL.S_ORG_EXT T10,
    SIEBEL.S_USER T11,
    SIEBEL.S_DOC_QUOTE T12,
    SIEBEL.S_ACCNT_POSTN T13,
    SIEBEL.S_INS_CLAIM T14,
    SIEBEL.S_USER T15,
    SIEBEL.S_ORG_EXT T16,
    SIEBEL.S_ASSET T17,
    SIEBEL.S_ORDER_TNTX T18,
    SIEBEL.S_ORG_EXT_TNTX T19,
    SIEBEL.S_PERIOD T20,
    SIEBEL.S_DEPOSIT_TNT T21,
    SIEBEL.S_ADDR_PER T22,
    SIEBEL.S_PAYMENT_TERM T23,
    SIEBEL.S_ORG_EXT_X T24,
    SIEBEL.S_ORG_EXT T25,
    SIEBEL.S_INSCLM_ELMNT T26,
    SIEBEL.S_INVOICE T27
    WHERE
    T25.BU_ID = T10.PAR_ROW_ID (+) AND
    T26.INSCLM_ID = T14.ROW_ID (+) AND
    T27.ELEMENT_ID = T26.ROW_ID (+) AND
    T27.LAST_UPD_BY = T15.PAR_ROW_ID (+) AND
    T4.QUOTE_ID = T12.ROW_ID (+) AND
    T3.CG_ASSSET_ID = T17.ROW_ID (+) AND
    T27.BL_ADDR_ID = T22.ROW_ID (+) AND
    T8.BU_ID = T5.PAR_ROW_ID (+) AND
    T27.PER_PAY_PRFL_ID = T2.ROW_ID (+) AND
    T27.REMIT_ORG_EXT_ID = T16.PAR_ROW_ID (+) AND
    T27.PROJ_ID = T8.ROW_ID (+) AND
    T27.BL_PERIOD_ID = T20.ROW_ID (+) AND
    T27.PAYMENT_TERM_ID = T23.ROW_ID (+) AND
    T12.BU_ID = T19.PAR_ROW_ID (+) AND
    T27.ACCNT_ID = T25.PAR_ROW_ID (+) AND
    T27.ORDER_ID = T18.ROW_ID (+) AND
    T4.SRC_INVLOC_ID = T3.ROW_ID (+) AND
    T27.ORDER_ID = T4.ROW_ID (+) AND
    T27.ACCNT_ID = T24.PAR_ROW_ID (+) AND
    T18.PR_DEPOSIT_ID = T21.ROW_ID (+) AND
    T27.BL_ADDR_ID = T9.ADDR_PER_ID (+) AND
    T27.ACCNT_ID = T9.ACCNT_ID (+) AND
    T27.BL_ADDR_ID = T1.ROW_ID (+) AND
    T25.PR_POSTN_ID = T13.POSITION_ID (+) AND
    T25.ROW_ID = T13.OU_EXT_ID (+) AND
    T13.POSITION_ID = T7.ROW_ID (+) AND
    T13.POSITION_ID = T6.PAR_ROW_ID (+) AND
    T6.PR_EMP_ID = T11.PAR_ROW_ID (+) AND
    (T27.INVC_TYPE_CD = :1) AND
    (T27.DEPT_CD = :2);
    Explan Plan Output :
    PLAN_TABLE_OUTPUT
    Plan hash value: 3132260827
    | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
    | 0 | SELECT STATEMENT | | 1 | 1958 | 1896K (11)| 00:50:46 |
    | 1 | NESTED LOOPS OUTER | | 1 | 1958 | 1896K (11)| 00:50:46 |
    | 2 | NESTED LOOPS OUTER | | 1 | 1922 | 1896K (11)| 00:50:46 |
    | 3 | NESTED LOOPS OUTER | | 1 | 1885 | 1896K (11)| 00:50:46 |
    | 4 | NESTED LOOPS OUTER | | 1 | 1861 | 1896K (11)| 00:50:46 |
    | 5 | NESTED LOOPS OUTER | | 1 | 1849 | 1896K (11)| 00:50:46 |
    | 6 | NESTED LOOPS OUTER | | 1 | 1817 | 1896K (11)| 00:50:46 |
    | 7 | NESTED LOOPS OUTER | | 1 | 1792 | 1896K (11)| 00:50:46 |
    | 8 | NESTED LOOPS OUTER | | 1 | 1771 | 1896K (11)| 00:50:46 |
    | 9 | NESTED LOOPS OUTER | | 1 | 1739 | 1896K (11)| 00:50:46 |
    | 10 | NESTED LOOPS OUTER | | 1 | 1483 | 1896K (11)| 00:50:46 |
    | 11 | NESTED LOOPS OUTER | | 1 | 1451 | 1896K (11)| 00:50:46 |
    | 12 | NESTED LOOPS OUTER | | 1 | 1419 | 1896K (11)| 00:50:46 |
    | 13 | NESTED LOOPS OUTER | | 1 | 1361 | 1896K (11)| 00:50:46 |
    | 14 | NESTED LOOPS OUTER | | 1 | 1276 | 1896K (11)| 00:50:46 |
    | 15 | NESTED LOOPS OUTER | | 1 | 1202 | 1896K (11)| 00:50:46 |
    | 16 | NESTED LOOPS OUTER | | 1 | 1108 | 1896K (11)| 00:50:46 |
    | 17 | NESTED LOOPS OUTER | | 1 | 1087 | 1896K (11)| 00:50:46 |
    | 18 | NESTED LOOPS OUTER | | 1 | 1040 | 1896K (11)| 00:50:46 |
    | 19 | NESTED LOOPS OUTER | | 1 | 939 | 1896K (11)| 00:50:46 |
    | 20 | NESTED LOOPS OUTER | | 1 | 894 | 1896K (11)| 00:50:46 |
    | 21 | NESTED LOOPS OUTER | | 1 | 868 | 1896K (11)| 00:50:46 |
    | 22 | NESTED LOOPS OUTER | | 1 | 843 | 1896K (11)| 00:50:46 |
    | 23 | NESTED LOOPS OUTER | | 1 | 824 | 1896K (11)| 00:50:46 |
    | 24 | NESTED LOOPS OUTER | | 1 | 690 | 1896K (11)| 00:50:46 |
    | 25 | NESTED LOOPS OUTER | | 1 | 613 | 1896K (11)| 00:50:46 |
    | 26 | NESTED LOOPS OUTER | | 1 | 457 | 1896K (11)| 00:50:46 |
    |* 27 | TABLE ACCESS FULL | S_INVOICE | 1 | 269 | 1896K (11)| 00:50:46 |
    | 28 | TABLE ACCESS BY INDEX ROWID| S_PROJ | 1 | 188 | 1 (0)| 00:00:01 |
    |* 29 | INDEX UNIQUE SCAN | S_PROJ_P1 | 1 | | 1 (0)| 00:00:01 |
    | 30 | TABLE ACCESS BY INDEX ROWID | S_PAYMENT_TERM | 1 | 156 | 1 (0)| 00:00:01 |
    |* 31 | INDEX UNIQUE SCAN | S_PAYMENT_TERM_P1 | 1 | | 1 (0)| 00:00:01 |
    | 32 | TABLE ACCESS BY INDEX ROWID | S_INSCLM_ELMNT | 1 | 77 | 1 (0)| 00:00:01 |
    |* 33 | INDEX UNIQUE SCAN | S_INSCLM_ELMNT_P1 | 1 | | 1 (0)| 00:00:01 |
    | 34 | TABLE ACCESS BY INDEX ROWID | S_INS_CLAIM | 1 | 134 | 1 (0)| 00:00:01 |
    |* 35 | INDEX UNIQUE SCAN | S_INS_CLAIM_P1 | 1 | | 1 (0)| 00:00:01 |
    | 36 | TABLE ACCESS BY INDEX ROWID | S_PERIOD | 1 | 19 | 1 (0)| 00:00:01 |
    |* 37 | INDEX UNIQUE SCAN | S_PERIOD_P1 | 1 | | 1 (0)| 00:00:01 |
    | 38 | TABLE ACCESS BY INDEX ROWID | S_USER | 1 | 25 | 2 (0)| 00:00:01 |
    |* 39 | INDEX UNIQUE SCAN | S_USER_U2 | 1 | | 1 (0)| 00:00:01 |
    | 40 | TABLE ACCESS BY INDEX ROWID | S_ORDER_TNTX | 1 | 26 | 2 (0)| 00:00:01 |
    |* 41 | INDEX UNIQUE SCAN | S_ORDER_TNTX_P1 | 1 | | 1 (0)| 00:00:01 |
    | 42 | TABLE ACCESS BY INDEX ROWID | S_DEPOSIT_TNT | 1 | 45 | 1 (0)| 00:00:01 |
    |* 43 | INDEX UNIQUE SCAN | S_DEPOSIT_TNT_P1 | 1 | | 1 (0)| 00:00:01 |
    | 44 | TABLE ACCESS BY INDEX ROWID | S_ORDER | 1 | 101 | 2 (0)| 00:00:01 |
    |* 45 | INDEX UNIQUE SCAN | S_ORDER_P1 | 1 | | 1 (0)| 00:00:01 |
    | 46 | TABLE ACCESS BY INDEX ROWID | S_INVLOC | 1 | 47 | 1 (0)| 00:00:01 |
    |* 47 | INDEX UNIQUE SCAN | S_INVLOC_P1 | 1 | | 1 (0)| 00:00:01 |
    | 48 | TABLE ACCESS BY INDEX ROWID | S_DOC_QUOTE | 1 | 21 | 1 (0)| 00:00:01 |
    |* 49 | INDEX UNIQUE SCAN | S_DOC_QUOTE_P1 | 1 | | 1 (0)| 00:00:01 |
    | 50 | TABLE ACCESS BY INDEX ROWID | S_ORG_EXT_TNTX | 1 | 94 | 1 (0)| 00:00:01 |
    |* 51 | INDEX RANGE SCAN | S_ORG_EXT_TNTX_U1 | 1 | | 1 (0)| 00:00:01 |
    | 52 | TABLE ACCESS BY INDEX ROWID | S_PTY_PAY_PRFL | 1 | 74 | 1 (0)| 00:00:01 |
    |* 53 | INDEX UNIQUE SCAN | S_PTY_PAY_PRFL_P1 | 1 | | 1 (0)| 00:00:01 |
    | 54 | TABLE ACCESS BY INDEX ROWID | S_ADDR_PER | 1 | 85 | 2 (0)| 00:00:01 |
    |* 55 | INDEX UNIQUE SCAN | S_ADDR_PER_P1 | 1 | | 1 (0)| 00:00:01 |
    | 56 | TABLE ACCESS BY INDEX ROWID | S_ADDR_PER | 1 | 58 | 1 (0)| 00:00:01 |
    |* 57 | INDEX UNIQUE SCAN | S_ADDR_PER_P1 | 1 | | 1 (0)| 00:00:01 |
    | 58 | TABLE ACCESS BY INDEX ROWID | S_ORG_EXT | 1 | 32 | 1 (0)| 00:00:01 |
    |* 59 | INDEX UNIQUE SCAN | S_ORG_EXT_U3 | 1 | | 1 (0)| 00:00:01 |
    | 60 | TABLE ACCESS BY INDEX ROWID | S_ORG_EXT | 1 | 32 | 1 (0)| 00:00:01 |
    |* 61 | INDEX UNIQUE SCAN | S_ORG_EXT_U3 | 1 | | 1 (0)| 00:00:01 |
    | 62 | TABLE ACCESS BY INDEX ROWID | S_ORG_EXT | 1 | 256 | 2 (0)| 00:00:01 |
    |* 63 | INDEX UNIQUE SCAN | S_ORG_EXT_U3 | 1 | | 1 (0)| 00:00:01 |
    | 64 | TABLE ACCESS BY INDEX ROWID | S_ACCNT_POSTN | 1 | 32 | 3 (0)| 00:00:01 |
    |* 65 | INDEX RANGE SCAN | S_ACCNT_POSTN_U1 | 1 | | 2 (0)| 00:00:01 |
    | 66 | TABLE ACCESS BY INDEX ROWID | S_POSTN | 1 | 21 | 1 (0)| 00:00:01 |
    |* 67 | INDEX UNIQUE SCAN | S_POSTN_U2 | 1 | | 1 (0)| 00:00:01 |
    | 68 | TABLE ACCESS BY INDEX ROWID | S_USER | 1 | 25 | 2 (0)| 00:00:01 |
    |* 69 | INDEX UNIQUE SCAN | S_USER_U2 | 1 | | 1 (0)| 00:00:01 |
    | 70 | TABLE ACCESS BY INDEX ROWID | S_ORG_EXT | 1 | 32 | 2 (0)| 00:00:01 |
    |* 71 | INDEX UNIQUE SCAN | S_ORG_EXT_U3 | 1 | | 1 (0)| 00:00:01 |
    |* 72 | INDEX UNIQUE SCAN | S_PARTY_P1 | 1 | 12 | 1 (0)| 00:00:01 |
    | 73 | TABLE ACCESS BY INDEX ROWID | S_ASSET | 1 | 24 | 2 (0)| 00:00:01 |
    |* 74 | INDEX UNIQUE SCAN | S_ASSET_P1 | 1 | | 2 (0)| 00:00:01 |
    | 75 | TABLE ACCESS BY INDEX ROWID | S_ORG_EXT_X | 1 | 37 | 2 (0)| 00:00:01 |
    |* 76 | INDEX RANGE SCAN | S_ORG_EXT_X_U1 | 1 | | 2 (0)| 00:00:01 |
    | 77 | TABLE ACCESS BY INDEX ROWID | S_CON_ADDR | 1 | 36 | 3 (0)| 00:00:01 |
    |* 78 | INDEX RANGE SCAN | S_CON_ADDR_U1 | 1 | | 2 (0)| 00:00:01 |
    Predicate Information (identified by operation id):
    27 - filter("T27"."DEPT_CD"=:2 AND "T27"."INVC_TYPE_CD"=:1)
    29 - access("T27"."PROJ_ID"="T8"."ROW_ID"(+))
    31 - access("T27"."PAYMENT_TERM_ID"="T23"."ROW_ID"(+))
    33 - access("T27"."ELEMENT_ID"="T26"."ROW_ID"(+))
    35 - access("T26"."INSCLM_ID"="T14"."ROW_ID"(+))
    37 - access("T27"."BL_PERIOD_ID"="T20"."ROW_ID"(+))
    39 - access("T27"."LAST_UPD_BY"="T15"."PAR_ROW_ID"(+))
    41 - access("T27"."ORDER_ID"="T18"."ROW_ID"(+))
    43 - access("T18"."PR_DEPOSIT_ID"="T21"."ROW_ID"(+))
    45 - access("T27"."ORDER_ID"="T4"."ROW_ID"(+))
    47 - access("T4"."SRC_INVLOC_ID"="T3"."ROW_ID"(+))
    49 - access("T4"."QUOTE_ID"="T12"."ROW_ID"(+))
    51 - access("T12"."BU_ID"="T19"."PAR_ROW_ID"(+))
    53 - access("T27"."PER_PAY_PRFL_ID"="T2"."ROW_ID"(+))
    55 - access("T27"."BL_ADDR_ID"="T1"."ROW_ID"(+))
    57 - access("T27"."BL_ADDR_ID"="T22"."ROW_ID"(+))
    59 - access("T8"."BU_ID"="T5"."PAR_ROW_ID"(+))
    61 - access("T27"."REMIT_ORG_EXT_ID"="T16"."PAR_ROW_ID"(+))
    63 - access("T27"."ACCNT_ID"="T25"."PAR_ROW_ID"(+))
    65 - access("T25"."ROW_ID"="T13"."OU_EXT_ID"(+) AND "T25"."PR_POSTN_ID"="T13"."POSITION_ID"(+))
    67 - access("T13"."POSITION_ID"="T6"."PAR_ROW_ID"(+))
    69 - access("T6"."PR_EMP_ID"="T11"."PAR_ROW_ID"(+))
    71 - access("T25"."BU_ID"="T10"."PAR_ROW_ID"(+))
    72 - access("T13"."POSITION_ID"="T7"."ROW_ID"(+))
    74 - access("T3"."CG_ASSSET_ID"="T17"."ROW_ID"(+))
    76 - access("T27"."ACCNT_ID"="T24"."PAR_ROW_ID"(+))
    78 - access("T27"."BL_ADDR_ID"="T9"."ADDR_PER_ID"(+) AND "T27"."ACCNT_ID"="T9"."ACCNT_ID"(+))
    filter("T27"."ACCNT_ID"="T9"."ACCNT_ID"(+))
    117 rows selected.
    We are using 10.2.0.3 oracle version.

    Hi
    according to the explain plan, > 99% of the cost of the query is coming from a single operation -- step 27, full scan of S_INVOICE table.
    This probably means that there are no usable indexes on DEPT_CD and/or INVC_TYPE_CD.
    So start by tuning SELECT * FROM S_INVOICE T27 WHERE ("T27"."DEPT_CD"=:2 AND "T27"."INVC_TYPE_CD"=:1)
    BTW the plan shows that 1 row is to be returned, while Oracle actually returns 117 -- this means that the optimizer estimates are not very reliable here.
    Best regards,
    Nikolay

  • Outer join vs. 'SELECT in SELECT'

    Hi All,
    I am generally curious about which method to use between a Outer join and 'SELECT in SELECT'. We can have same result with both methods.
    My question is, for real life complex queries, which method is more efficiant? less resource intensive? Any thories you guys have?
    I am on Oracle 10.2 on lunix.
    See my example below
    -- First table
    create table emp
    id   number,
    name varchar2(1000),
    constraint emp_pk primary key ( id )
    -- second table. There will be 1 record, for few of the records in EMP table, in this table
    create table leave
    id     number,
    emp_id number,
    leave_date date,
    constraint leave_pk primary key (id),
    constraint leave_fk foreign key ( emp_id ) references emp
    create index leave_idx_1 on leave ( emp_id ) ;
    -- Populate some sample data in there
    insert into emp (id, name)
    select object_id, object_name from dba_objects where rownum < 10001 ;
    declare
    cursor c1 is
       select id from emp where mod(id,2) = 0 ;
    v_id  number := 1 ;
    v_date DATE := '01-JAN-08';
    begin
      for c2 in c1
      loop
          insert into leave values ( v_id, c2.id, v_date );
          v_id := v_id + 1;
          v_date := v_date + 1;
      end loop;
    end;
    -- Set autotrace
    set autotrace traceonly explain
    -- =================================
    -- Outer join
    -- =================================
    select e.id, e.name, l.id, l.leave_date
    from   emp e, leave l
    where  e.id = l.emp_id (+) ;
    -- ===================================
    -- select in select to get same results as above outer join
    -- ===================================
    select e.id, e.name,
           (select l.id from leave l where l.emp_id = e.id ) leave_id,
           (select l.leave_date from leave l where l.emp_id = e.id ) leave_date
    from   emp e ;My hidden question, how these two methods internally work? in the plan we can only see something like 'hash join right outer' or something like that. But how exactly outer join is executed? how is the result formed?
    I have got following plans for the two methods
    SQL> select e.id, e.name, l.id, l.leave_date
      2  from   emp e, leave l
      3  where  e.id = l.emp_id (+) ;
    Elapsed: 00:00:00.03
    Execution Plan
    Plan hash value: 98076489
    | Id  | Operation             | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT      |       | 10000 |  5371K|    16   (7)| 00:00:01 |
    |*  1 |  HASH JOIN RIGHT OUTER|       | 10000 |  5371K|    16   (7)| 00:00:01 |
    |   2 |   TABLE ACCESS FULL   | LEAVE |  5012 |   171K|     6   (0)| 00:00:01 |
    |   3 |   TABLE ACCESS FULL   | EMP   | 10000 |  5029K|     9   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       1 - access("E"."ID"="L"."EMP_ID"(+))
    Note
       - dynamic sampling used for this statement
    SQL> select e.id, e.name,
      2         (select l.id from leave l where l.emp_id = e.id ) leave_id,
      3         (select l.leave_date from leave l where l.emp_id = e.id ) leave_date
      4  from   emp e ;
    Elapsed: 00:00:00.18
    Execution Plan
    Plan hash value: 2670217481
    | Id  | Operation                   | Name        | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT            |             | 10000 |  5029K|     9   (0)| 00:00:01 |
    |   1 |  TABLE ACCESS BY INDEX ROWID| LEAVE       |    50 |  1300 |     2   (0)| 00:00:01 |
    |*  2 |   INDEX RANGE SCAN          | LEAVE_IDX_1 |    20 |       |     1   (0)| 00:00:01 |
    |   3 |  TABLE ACCESS BY INDEX ROWID| LEAVE       |    50 |  1100 |     2   (0)| 00:00:01 |
    |*  4 |   INDEX RANGE SCAN          | LEAVE_IDX_1 |    20 |       |     1   (0)| 00:00:01 |
    |   5 |  TABLE ACCESS FULL          | EMP         | 10000 |  5029K|     9   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - access("L"."EMP_ID"=:B1)
       4 - access("L"."EMP_ID"=:B1)
    Note
       - dynamic sampling used for this statementPlease let me know your thoughts.
    Thanks in advance

    A better indicator of performance would be to look at the number of consistent gets that are required to execute the query.
    In my environment:
    SQL> SELECT * FROM V$VERSION;
    BANNER
    Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
    PL/SQL Release 10.2.0.4.0 - Production
    CORE    10.2.0.4.0      Production
    TNS for 64-bit Windows: Version 10.2.0.4.0 - Production
    NLSRTL Version 10.2.0.4.0 - Production
    SQL> SHOW PARAMETER OPT
    NAME                                 TYPE        VALUE
    filesystemio_options                 string
    object_cache_optimal_size            integer     102400
    optimizer_dynamic_sampling           integer     2
    optimizer_features_enable            string      10.2.0.4
    optimizer_index_caching              integer     0
    optimizer_index_cost_adj             integer     100
    optimizer_mode                       string      ALL_ROWS
    optimizer_secure_view_merging        boolean     TRUE
    plsql_optimize_level                 integer     2The OUTER JOIN produced the following results:
    SQL> select e.id, e.name, l.id, l.leave_date
      2  from   emp e, leave l
      3  where  e.id = l.emp_id (+) ;
    10000 rows selected.
    Execution Plan
    Plan hash value: 98076489
    | Id  | Operation             | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT      |       | 10000 |   380K|     9  (12)| 00:00:01 |
    |*  1 |  HASH JOIN RIGHT OUTER|       | 10000 |   380K|     9  (12)| 00:00:01 |
    |   2 |   TABLE ACCESS FULL   | LEAVE |  5017 | 80272 |     3   (0)| 00:00:01 |
    |   3 |   TABLE ACCESS FULL   | EMP   | 10000 |   224K|     5   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       1 - access("E"."ID"="L"."EMP_ID"(+))
    Statistics
              0  recursive calls
              0  db block gets
            723  consistent gets
              0  physical reads
              0  redo size
         364047  bytes sent via SQL*Net to client
           7672  bytes received via SQL*Net from client
            668  SQL*Net roundtrips to/from client
              0  sorts (memory)
              0  sorts (disk)
          10000  rows processedThe inline subquery produced these results:
    SQL> select e.id, e.name,
      2         (select l.id from leave l where l.emp_id = e.id ) leave_id,
      3         (select l.leave_date from leave l where l.emp_id = e.id ) leave_dat
      4  from   emp e ;
    10000 rows selected.
    Execution Plan
    Plan hash value: 1706216391
    | Id  | Operation         | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT  |       | 10000 |   224K|     5   (0)| 00:00:01 |
    |*  1 |  TABLE ACCESS FULL| LEAVE |     1 |     9 |     3   (0)| 00:00:01 |
    |*  2 |  TABLE ACCESS FULL| LEAVE |     1 |    13 |     3   (0)| 00:00:01 |
    |   3 |  TABLE ACCESS FULL| EMP   | 10000 |   224K|     5   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       1 - filter("L"."EMP_ID"=:B1)
       2 - filter("L"."EMP_ID"=:B1)
    Statistics
              0  recursive calls
              0  db block gets
         360705  consistent gets
              0  physical reads
              0  redo size
         364053  bytes sent via SQL*Net to client
           7672  bytes received via SQL*Net from client
            668  SQL*Net roundtrips to/from client
              0  sorts (memory)
              0  sorts (disk)
          10000  rows processedSee the 723 consistent gets versus 360705? That is a huge difference.
    The second method may be more viable if you create indexes on the columns in the leave table that you are joining to your EMP table.
    For example:
    SQL> CREATE INDEX LEAD_ID_IDX ON LEAVE(EMP_ID, ID, LEAVE_DATE);
    Index created.
    SQL> set autotrace traceonly
    SQL> select e.id, e.name,
      2         (select l.id from leave l where l.emp_id = e.id ) leave_id,
      3         (select l.leave_date from leave l where l.emp_id = e.id ) leave_date
      4  from   emp e ;
    10000 rows selected.
    Execution Plan
    Plan hash value: 1822800249
    | Id  | Operation         | Name        | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT  |             | 10000 |   224K|     5   (0)| 00:00:01 |
    |*  1 |  INDEX RANGE SCAN | LEAD_ID_IDX |     1 |     9 |     2   (0)| 00:00:01 |
    |*  2 |  INDEX RANGE SCAN | LEAD_ID_IDX |     1 |    13 |     2   (0)| 00:00:01 |
    |   3 |  TABLE ACCESS FULL| EMP         | 10000 |   224K|     5   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       1 - access("L"."EMP_ID"=:B1)
       2 - access("L"."EMP_ID"=:B1)
    Statistics
              1  recursive calls
              0  db block gets
          22111  consistent gets
             19  physical reads
              0  redo size
         364053  bytes sent via SQL*Net to client
           7672  bytes received via SQL*Net from client
            668  SQL*Net roundtrips to/from client
              0  sorts (memory)
              0  sorts (disk)
          10000  rows processedThe query improved by a more than a factor of 10 with the index but the consistent gets are still significantly higher then the OUTER JOIN query. Additionally I always try and take the approach when developing queries to minimize the number of table accesses possible. In your second place you have to access the LEAVE table twice, instead of once in the first query.

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