Parseing a Float from a string.

Does anyone know how to parse a float from a string variable? The documentation says there is a method for it, it doesn't say what it is(?).
I.e. the equavilent of int this_num.parseint(this_string) only for a float.
Thanks.

Thanks, that helped...now for another apparently stupid question....
How do you add two floats??
I have:
fInvAmount = fInvAmount + Float.parseFloat(rsSmartStreamInvoice.getString("invoice_amt"))
and it tells me that 'operator + cannot be applied to java.lang.Float,float'

Similar Messages

How can i parse the number from the string each time automatic ?

I have this two lines:
last_file = fi[fi.Length - 1].FullName;
string lastFileNumber = last_file.Substring(86, 6);
In last_file i have: C:\\Users\\chocolade1972\\AppData\\Local\\mws\\My Weather Station\\radar_temp_directory\\radar000142.gif
So i counted and found that the number in this case 000124 is starting from index 86 and length 6
But for example on my brother pc the directory is shorter the name is not chocolade1972 so the index is incorrect.
It's not 86.
How can i use the Substring to find the correct index every time on any pc that have a differenet directory length ?
In this case it's working fine on my pc for any image i can get the number no problems. But i want it to work also on other pc's.

You can use Regex to match the filename you want.
Like Giovhan suggested you can first get the filename like:
string result;
result = Path.GetFileName(fileName);// in your example result = radar000142// in my regex I assume that a file can have a number of digits between 5 to 7 digits.Regex filenameRegex = new Regex("\d{5,7}");string number = filenameRegex.Match(result).Value;// by that way you can retrieve all numbers between 5 to 7 digits regardless of filename whether contains all 6 digits// or file that may contain 5 or 7 digits // You can play with the Regex code to decrease or increase number of digits by changing the numbers

Urgent pl. I want to extract float from string (%f %s) or (%s %f) separate

I want to extract float from string (%f %s) or (%s %f) separated by tab, whitespace etc., Since I am using jdk1.3.1 I can't use regular expression can anybody suggest a simple (one or two or few line code - compact) to get the float in (sign+/-)#.#### format ignoring other characters ?
I tried:
e.g.,
String d="4.000 [tab]4";
source string resulted from "SUBSTRING query of mySQL" can be of :
" -4.543 XYZ ",
" XYZ -4.546 ",
" xx-yy 6.58 3 ",
"6.0 xxx yyy zzz",
the expected results for float from the string should be:
-4.543
-4.546
6.580
6.000
If String containing data separated by comma:
e.g.,
"4.120     1     ,
AAXXFE     ,4.206     1     ,
     4.000     1,
     4.201     1,
     4.189     1,
     4.204     1,
S     DDERSF-RSA"
The result should be: "4.120,4.206,4.000,4.201,4.189,4.204,0.000"
The string is created by:
ResultSet rs1 = stmt.executeQuery(S1);
while (rs1.next()) {
String d = rs1.getString("SUBSTRING(FIELD1,LOCATE(\""+s2[i]+"\",FIELD1)+"+ k_st + ","+ length+")");
System.out.print(d+",");
May be I don't know how to use the following:
float f1 = Float.parseFloat(d);
===
String pattern = "###.###";
//float value = -2100.578f;
DecimalFormat myFormatter = new DecimalFormat(pattern);
String output = myFormatter.format(d);
System.out.println(d+" " + pattern + " " + output);
===

Hi
You made the best choice. JRegex is closer to java.util.regex.* and fine works with excellent performance in any JVM version so you can use examples/tutorials from both JRegex and Java.Sun.Com to learn more about regular expression.
About the regular expression in my last post, there are two capturing groups: the first for float numbers in IEEE format specification (also see Java Language Specification) and the second for any sequence of chars, groups using with any amount of blank spaces (spaces, tabs, etc :: see regular expression definition) as delimiter. The anchors "^" and "$" are being used to exactly match pattern in target string and you can relax this constraint as needed.
How to use JRegex? no secrets!
import jregex.*;
// a float number and string with any blank delimiter
String patternString ="^([+-]?(?:\\d+(?:\\.\\d*)?|\\.\\d+)(?:[eE][+-]?\\d+)?)\s+(.*)$";
Pattern pattern = new Pattern(patternString); // different from Sun regex package syntax
// below is identical in both packages
Matcher m = pattern.matcher(anyTargetString);
if (m.matches()) {
Double d = Double.parseDouble( m.group(1) );
String scratch = m.group(2);
// your stuff goes here
..Remember to put JRegex jarfile in classpath!
Regards and Success.

How to parse a BigDecimal from a localized number String

I want to be able to build a BigDecimal instance from a localized String.
i.e.: From a string like "2.123,45123" I want to get when I get by doing: new BigDecimal("2123.45123");
The NumberFormat parse(String) method answers doubles, so I lose presition. When I do nf.parse(2,0000000000000000001) y get a Double representing 2. I can't make a BigDecimal from such a string afaik.
The problem is the localized version on the number (in the string) otherwise it works fine (with the US locale).

>>
So you only can't convert a string to a BigDoublethat
uses the ',' for the decimal place and the '.' forthe
real number separators? If that's the case, whycan't
you use a String buffer then to strip out all the
periods and replace the comma with a period so it
looks like a US decimal string then use that?Thank you very much for your answer. That would have
been a workaround. I found a BigDecimal parser that's
absolutely perfect for the task.
http://users.belgacombusiness.net/arci/math/
Gives to BigDecimals what java standard gives to all
the other Number subclasses. Good! Frankly, I'm usually just lazy enough to hack a solution.... because I like to say that I hack. evil laugh

How to extract an integer or a float value from a String of characters

Hi i have a problem getting to a float value within a string of characters..
for instance the string is
"numberItem xxxxxxxxx 700.0" (each x is a space..the forum wouldnt let me put normal spaces for some reason)
how do i store 700.0 in a float variable
remember the string is obtained from an inputfile
so far i got the program to store the inputfile data line by line in a String array..i tried tokenizing the string to get to the the float value but since i have mulitple spaces within my string, the token method only gets "numberItem" from the above String
This is all i have so far:
String c;
String Array[] =new String[g]; (i used a while loop to obtain g(the nubmer of lines in the file))
while((c=(cr.readLine()))!=null)
Array[coun]=c;
it would be reallllllllllllllllllllllllllllllllllllllly easy if there was a predefined method to extract numeric values from a string in java..
Edited by: badmash on Feb 18, 2009 5:50 PM
Edited by: badmash on Feb 18, 2009 5:50 PM
Edited by: badmash on Feb 18, 2009 5:55 PM

badmash wrote:
Hi i have a problem getting to a float value within a string of characters..
for instance the string is
"numberItem xxxxxxxxx 700.0" (each x is a space..the forum wouldnt let me put normal spaces for some reason)
with the space included
how do i store 700.0 in a float variable
remember the string is obtained from an inputfile
so far i got the program to store the inputfile data line by line in a String array..i tried tokenizing the string to get to the the float value but since i have mulitple spaces within my string, the token method only gets "numberItem" from the above StringHuh?
Not true.
Anyway why not use string split, split on spaces and grab the last element (which by the format you posted would be your 700.0)
Then there is the Float.parseFloat method.
It is easy.
And another thing why not use a List of Strings if you want to store each line? (And why did you post that code which doesn't really have anything to do with your problem?) Also in future please use the code formatting tags when posting code. Select the code you are posting in the message box and click the CODE button.

Parsing XML from a String

I have a servlet, this recieves an XML file from the client as a file input type from a html form. This XML is wrapped up in http headers and stuff. I parse the input stream from the client's http request to get a string containing the xml. This is fine.
How do I now build an XML document from this string? The DocumentBuilder will take in files and InputStreams but I can't find anything that helps me?
The only solution I've come up with is to write out the string to a temp file and then parse it back into a Document.
Any ideas anyone?????

Document doc = documentBuilder.parse(new InputSource(new StringReader(yourXMLString)));
voila!

How to parse out curly quotes from a string

Hi,
I am writing a web application, where people will be copying from a Word Document into a text area. Then I get a String from the parameter passed.
How can I parse out curly quotes and mdashes from this String? Are there specific character codes that I can parse out to replace them with regular quote characters or html quote characters?
Thanks,
Gabe

Interesting problem and one that we had to deal with a couple of years ago. I think you might be talking about smart quotes and these are actually control characters used by MS products. They show up as squares in HTML unless properly dealt with. Try downloading some UNICODE charts to find out the values of these characters. I think they are something like 0044 and 0042 but I cannot remember off hand.

Is there an easy way to convert from a String with a comma, ie. 1,000.00 to

Is there an easy way to convert from a String with a comma, ie. 1,000.00 to a float or a double?
thanks,
dosteov

Like DrClap said: DecimalFormat. However, make sure you understand the Locale things, as explained at http://java.sun.com/j2se/1.3/docs/api/java/text/DecimalFormat.html (which refers to NumberFormat as well) and use them explicitly. Like
public class FormatTest
public static void main(String args[])
    try
      // see NumberFormat.getInstance()
      DecimalFormat fmt = new DecimalFormat();
      Number num = fmt.parse("1,000.01");
      System.out.println(num.doubleValue());
    catch(ParseException pe)
      System.out.println(pe);
}most likely seems OK on your system, but may print "1.0" (or even fail) on some non-English platforms!
When performing calculations, also see http://developer.java.sun.com/developer/JDCTechTips/2001/tt0807.html
a.

Getting char values from a string problem

Hi,
Here's an example of what I'm trying to do:
boolean loopSwitch = true;
while (loopSwitch)
     String orderDecider = JOptionPane.showInputDialog (null, "Would you like your numbers to be ordered in   ascending or descending order(A/D)",      "Order decision", JOptionPane.QUESTION_MESSAGE);
     if (orderDecider == A)
     loopSwitch = false;
     }I basically want the user to input either a/A/d/D and to get the char values from the string so I can use them in an if statement.
Basically, I wanna parse the string into a char.
Is this possible?
Thanks.
Edited by: xcd on Oct 16, 2009 8:38 AM

Why not just use the String.equals() method to compare a String to a String?
But if you must, you can use the String.charAt() method to return a char at a particular location in the String.
Note: char literals need to be surrounded by single quotes ('A') and String literals need to be surrounded by double quotes ("A").

How to create an XML document from a String.

Can anyone help,
     In the Microsoft XML Document DOM there is a load function load(string) which will create an XML document, but now we are switching to Java and I do not know how to create and XML document from a string, this string �xml document� is passed to my program from a webservice and I need to read several xml elements form it in a web server.
This string is a well formatted XML document:
<?xml version="1.0" encoding="UTF-8"?>
<Countries NumberOfRecords="1" LanguageID="en-us">
     <Country>
          <CountryCode>AU</CountryCode>
          <CountryName>AUSTRALIA</CountryName>
     </Country>
</Countries>

Thanks PC!
I made it work using:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
factory.setIgnoringComments(true); // We want to ignore comments
// Now use the factory to create a DOM parser
DocumentBuilder parser = factory.newDocumentBuilder();
//TransformThisStringBuffer is a string buffer wich contain the 'XML document (String)'
InputStream in = new ByteArrayInputStream(TransformThisStringBuffer.toString().getBytes());
// Parse the InputStream and build the document
Document document = parser.parse(in);
But which one is faster InputSource or InputStream, were would you put the "new InputSource(new StringReader(yourString))" in the above code?

InputStream from a String?

Hi all,
does anybody know how you would go about getting a java.io.InputStream from a string object? I know you can create a StringReader from a string, but the StringBufferInputStream is depreciated. I want to parse an xml String with the DocumentBuilder class, but it only takes an InputStream object, not a Reader object.
any suggestions?
thanks,
J

Adding to Mr. Sampieri's explanation:
The encoding is specified in the initial processing instruction of the XML. If absent, the default encoding is UTF-8. (The default encoding of Java depends on the locale, so it's better to specify the correct encoding when writing your program.)
Check if the names of the XML encodings are different from the names of the Java encodings (charsets).
<?xml version="1.0" encoding="ISO8859-1" ?>

How to create a Document object from a string.

If I use the following code, the input String cannot contain "\n", otherwise, it generates errors.
in the following code, inputXMLString is a String object that has xml content.
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new InputSource(new StringReader(inputXMLString))); How can I create a Document object from a string with "\n" in the string?
Thanks.

If I use the following code, the input String cannot
contain "\n", otherwise, it generates errors.That's going to be a huge surprise to thousands of people who process XML containing newline characters every day without errors.
Perhaps your newline characters are in the middle of element names, or something else that causes your XML to be not well-formed. I'm just guessing here, though, because you didn't say what errors you were getting.

How to get separators from a string

I need to find the thousand separator, hundred separator and decimal separator from a string. I need to check which separator is available in a string ie., thousand or hundred separator. There may be a case where there is no separators.
Please suggest me. I would be greatful if you provide me a code snippet.
Thanks in advance...

Hi Ananth,
Try following:
//For decimal fraction
if (Count(Split(StrReverse(ToText ({OINV.DocTotal})), '.') ) > 1) then "With Decimal" else "Without Decimal"
//For Units
//Convert numbers to string valule
//Reverse the string so that you cold parse them accordingly in units, hundreds, thousands etc
//and finally split and parse each comma
if
    Length
        Split
                (Split(StrReverse(ToText ({OINV.DocTotal})), '.')[2]) , ','
            )[1]
    ) <= 2
) Then "Hundreds"
Else "Thousands"
You can continue on length of each subscript in array for hundreds, thousands, millions...
Cheers,
Kashif Ali

Key from a String

Hi to all,
i have a big problem.
I must set an RSA key value (Modulus and Exponent) from a String conteining the encrypted value
( for example :hVqLzLgUeZTxQ95UdJDTpIwbf6F7v.... ).
Is possible to do this ?
I didn't found classes and method to do this from the API.
Somebody can help me?
thank you!

ghstark wrote:
z4c4gn0 wrote:
Hi to all,
i have a big problem.
I must set an RSA key value (Modulus and Exponent) from a String conteining the encrypted value
( for example :hVqLzLgUeZTxQ95UdJDTpIwbf6F7v.... ). Is possible to do this ?
I didn't found classes and method to do this from the API.
Somebody can help me?
I cannot offer much help without more clarifying details, though perhaps others can deduce what you need. Just from the little you have written, I might guess that you have a base64 encoded (*not* encrypted) string or strings containing the RSA modulus and exponent. In that case, I know sabre150 has shown what to do, so search this forum for posts containing keywords "XML " and "RSA". Also, examine the class http://java.sun.com/javase/6/docs/api/java/security/spec/RSAPublicKeySpec.html as well as the base64 decoders from the jakarta commons codex classes.
I must get the keyinfo from an XML Signed file, and use this parameters for sign another one, so
i have my class that return the String value of RSA Module and Exponent parsed.
Now i need to sign using this parameters, and i tried the RSAPublicKeySpec that you said
in this way:
String mod="blablalba"; //the string module parsed
String exp ="blablalba"; //the string exponend parsed
byte [] modbyte=mod.getBytes();
byte [] expbyte=exp.getBytes();
BigInteger modulus = new BigInteger(modbyte);
BigInteger publicExponent =new BigInteger(expbyte);
System.out.println(exp+" = "+publicExponent);
System.exit(0);
RSAPublicKeySpec keySpec = new RSAPublicKeySpec(modulus, publicExponent);
KeyFactory keyFactory = KeyFactory.getInstance("RSA");
RSAPublicKey pk = (RSAPublicKey)keyFactory.generatePublic(keySpec);
that's work but don't return the right value of parameters, because Transform the strings in BigInteger.
What can i do?
thanks

Remove leading zeros from a string

Hi,
I have a string with some numeric value.
e.g.
String a = 54890001
I want to make it 10 digits long by padding zeros at the begining
Now a = 0054890001 ( this is for display purpose ) I know how to do it.
Now How can strip these leading zeros from this number to get back the actual number. The user sees this 10 digit number and he can change it to something like 0067490001. Now I want to strip these leading zeros.
and i shd get 67490001.
In other words, how to strip leading zeros from a string ?
Thanks for help
Vinod

I would try two things: First, just try a straightforward parsing of your String using the Integer.parseInt() method. This is only my first suggestion because the number could be interpreted as octals; only testing will really tell. Second, try a method like this:
public static String removeLeadingZeros(String str) {
    if (str == null) {
        return null;
    char[] chars = str.toCharArray();
    int index = 0;
    for (; index < str.length; index++) {
        if (chars[index] != '0') {
            break;
    return (index == 0) ? str : str.substring(index);
}Shaun

Parseing a Float from a string.

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