Parsing an xml string into id-value pair format

Hi,
I am new in oracle BPEL.
My requirement is that I need to parse an xml string containing tag name and coressponding value into an 'id -value' pair.
For example-
The input xml format is -
<employee>
<empid>12345</empid>
<name>xyz</name>
<city>London</city>
</employee>
The required xml format is-
<employee>
<item id="empid" value="12345"/>
<item id="name" value="xyz"/>
<item id="city" value="London"/>
</employee>
Please let me know if there is a work-around for this.
Thanks

Something like this (have not tested):
<xsl:for-each select="//employee">
<employee>
<xsl:for-each select="./*">
<item>
<xsl:attribute name="id">
<xsl:value-of select="name()"/>
</xsl:attribute>
<xsl:attribute name="value">
<xsl:value-of select="text()"/>
</xsl:attribute>
</item>
</xsl:for-each>
</employee>
</xsl:for-each>

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Parsing input stream into named value pairs

Hi everyone. I figured I would post this scenario, and hope to get some 'expert' opinions on what the best way to handle this would be.
I have an input stream being returned to me and I need to separate them into name/value pairs. I receive this as two lines of strings. The first line is the variable names, and the second line is the values. This is the format:
"Variable1","Variable2","Variable3","Variable4"
"Value1","Value2","Value3","Value4"
I need to separate this out into:
Variable1 = "Value1"
Variable2 = "Value2"
What I was thinking of doing is to create a hashtable, read the first line in and assign those as the keys, then read the second line in and assign those as the values. I'm not quite sure if this is even possible as of yet, but thats my original game plan. My primary goals are:
1. Seperate each variable name and match it with its appropriate value
2. Be able to retrieve each value by calling the appropriate variable name.
Any advice/opinion on this is greatly appreciated!!! Thanks!

You could choose to feed the String through an InputStream and use a StreamTokenizer, which is substantially more powerful than StringTokenizer. I would personally, however, choose to parse it myself, as antequated as that might seem. ;)
Presume that s1 is equal to
"Var1", "Var2", "MoreVars", "EvenMoreVars" , "LastVar"
And that s2 is equal to
"Hello","9900", ":)", "He said \"hi\".", "Hi, there."
These would make good sample data, but aren't necessarily the case.
String s1 = ...;
String s2 = ...;
HashMap map = null;
String[] keys = parseQuotedByCommas(s1);
String[] values = parseQuotedByCommas(s2);
if (keys.length==values.length)
    map = new HashMap();
    for (int i=0;i<keys.length;i++)
        map.put(keys, values[i]);
} else
// Error!
// throws IllegalArgumentException for improperly formatted strings
public static String[] parseQuotedByCommas(String s)
     ArrayList acc = new ArrayList();
     char[] ch = s.toCharArray();
     int i = 0;
     try
          while (i < ch.length)
               while (ch[i] == ' ') i++;
               if (i < ch.length)
                    if (ch[i] != '"')
                         throw new IllegalArgumentException(
                         "Expected '\"', receieved '" + ch[i] + "'");
                    i++;
                    StringBuffer sb = new StringBuffer();
                    boolean stop = false;
                    while (!stop)
                         switch (ch[i])
                              case '"':
                                   if (ch[i - 1] == '\\')
                                        sb.append('"');
                                   else
                                        stop = true;
                                   break;
                              case '\\':
                                   int j = i;
                                   boolean write = true;
                                   while ((j >= 0) && (ch[j] == '\\'))
                                        write = !write;
                                        j--;
                                   if (write) sb.append('\\');
                                   break;
                              default:
                                   sb.append(ch[i]);
                         i++;
                    acc.add(sb.toString());
               if (i < ch.length)
                    while (ch[i] == ' ') i++;
                    if (i < ch.length)
                         if ((ch[i] != ',') && (ch[i] != '"'))
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                         i++;
     } catch (IndexOutOfBoundsException oob)
          throw new IllegalArgumentException("Unexpected end of string.");
     return (String[]) (acc.toArray(new String[0]));
That should work for anything formatted as
<String> ::= [<WhiteSpace>] <Stmt> [ [<WhiteSpace>] , [<WhiteSpace>] <Stmt> ] *
<Stmt> ::= " <Characters> "
<Characters> ::= \" | \\ | <AnyCharacterExceptQuoteOrBackslash>
<WhiteSpace> ::= <Space>*
Any questions?
Oh, BTW, that was all blue 'cause the code tag doesn't take well to '"'.

How to get an xml string into a Document w/o escaping mark-up characters?

Hi,
I am using one of the latest xerces using Java. I am pretty sure I am using xerces-2.
I have an existing Document and I am trying to add more content to it. The new content itself is xml string. I am trying to insert this xml string into the document using document.createTextNode. I am able to insert, but somewhere it is escaping the mark-up characters (<,>,etc). When I convert the document into String, I can see, for example, <userData> instead of <userData>.
There is an alternative option to accomplish this by creating a new document with this xml string, get the root element, import this element into my document. Execution time for this procedure is very high - means, this is very bad in terms of time-wise performance.
Can any help on how to accomplish this (bringing an xml string into a document without escaping mark-up characters) in time-efficient way.

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Convert XML string into DOM

Hi all,
I have a question here regarding converting XML string into a DOM document.
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The Document.Parse() methods do not have one that takes in String as its parameter.
I'm not sure what is the best way to do this in Java.
Any help is greatly appreciated.
Thank you in advance.
regards,
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Convert XML String to Document with StringReader.
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DocumentBuilderFactory factory =
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REG: WRITE XML STRING INTO XML FILE

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                  InputSource inStream = new InputSource();
                  inStream.setCharacterStream(new StringReader(xmlString));
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                  Transformer xformer = TransformerFactory.newInstance().newTransformer();
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org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed.
at org.apache.xerces.parsers.DOMParser.parse(Unknown Source)
at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(Unknown Source)
Is that my XML string is not well formed. Is it so then please let me how to convert my xml string into well formed XML data.
Please help me out.
Thanking You.

There are many reasons why xmlString could be not well formed. There is no magic recipe for making it well formed: just look at it and see why it is not parseable.
Note that this line:
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How would I get the Oracle XML Parser to parse an XML string?
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file -- I would like to do something of the form...
parser.parse("<test>testing</test>");
On a related note, whilst the PL/SQL utilities are helpful, I
would like to see more in the way of documentation and examples
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perhaps a complete worked example (including a DTD).
Keep up the good work!
Many thanks,
Ian Brettell,
Indus International.
null

Ian Brettell (guest) wrote:
: How would I get the Oracle XML Parser to parse an XML string?
: The example ("DOMSample") only demonstrates how to parse an XML
: file -- I would like to do something of the form...
: parser.parse("<test>testing</test>");
With the latest version, 1.0.0.1, now available, you can use the
InputStream and InputSource methods. Please see the doc for
details.
: On a related note, whilst the PL/SQL utilities are helpful, I
: would like to see more in the way of documentation and examples
: for the Parser itself, showing more examples of DOM API calls
and
: perhaps a complete worked example (including a DTD).
: Keep up the good work!
: Many thanks,
: Ian Brettell,
: Indus International.
Thanks for the input. I will pass it onto the documentation team.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
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I am using Xerces2 Java Parser 2.4.0,
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parse(InputSource source)
parse(java.lang.String systemId)
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hi
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String myRecords =
"<data>"+
" <employee>"+
" <name>John</name>"+
" <Designation>Manager</Designation>"+
" </employee>"+
" <employee>"+
" <name>Sara</name>"+
" <Designation>Clerk</Designation>"+
" </employee>"+
"<data>"+

I tried it in a servlet, it and it worked. The entire code is long. But here it is most of it:
assuming that x is a string and has the xml of
<?xml version="1.0" ?>
- <company>
- <employee>
<firstname>Tom</firstname>
<lastname>Cat</lastname>
</employee>
- <employee>
<firstname>Paul</firstname>
<lastname>Enderson</lastname>
</employee>
- <employee>
<firstname>George</firstname>
<lastname>Jungle</lastname>
</employee>
</company>
=========================
try {
DocumentBuilderFactory factory =
DocumentBuilderFactory.newInstance();
DocumentBuilder db = factory.newDocumentBuilder();
InputSource inStream = new InputSource();
inStream.setCharacterStream(new StringReader(*x*));
Document doc = db.parse(inStream);
doc.getDocumentElement().normalize();
out.println("Root element " + doc.getDocumentElement().getNodeName() + "<BR>");
NodeList nodeLst = doc.getElementsByTagName("employee");
out.println("Information of all employees<BR>");
for (int s = 0; s < nodeLst.getLength(); s++) {
Node fstNode = nodeLst.item(s);
if (fstNode.getNodeType() == Node.ELEMENT_NODE) {
Element fstElmnt = (Element) fstNode;
NodeList fstNmElmntLst = fstElmnt.getElementsByTagName("firstname");
Element fstNmElmnt = (Element) fstNmElmntLst.item(0);
NodeList fstNm = fstNmElmnt.getChildNodes();
out.println("First Name : " + ((Node) fstNm.item(0)).getNodeValue() + "<BR>");
NodeList lstNmElmntLst = fstElmnt.getElementsByTagName("lastname");
Element lstNmElmnt = (Element) lstNmElmntLst.item(0);
NodeList lstNm = lstNmElmnt.getChildNodes();
out.println("Last Name : " + ((Node) lstNm.item(0)).getNodeValue() + "<BR>");
} catch (Exception e) {
System.out.println(e);
out.close();
==============
The output is
Root element company
Information of all employees
First Name : Tom
Last Name : Cat
First Name : Paul
Last Name : Enderson
First Name : George
Last Name : Jungle

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</servlet>
<servlet-mapping>
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<url-pattern>/Login</url-pattern>
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e-mail : [email protected]

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XMLSerializer serializer = new XMLSerializer( printwriter, format );
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Hi,
Does anyone know of a method or a function module in ABAP which converts XML string into an abap format date and time.
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<ns2:EventDateTime>2009-07-02T10:13:45+10:00</ns2:EventDateTime>
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Edited by: eunice ocson on Jul 13, 2009 1:49 AM
Edited by: eunice ocson on Jul 13, 2009 1:50 AM
Edited by: eunice ocson on Jul 13, 2009 1:51 AM
Edited by: eunice ocson on Jul 13, 2009 1:51 AM

Hi Eunice
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Help: How to parse XML string into Node Context

Hi Experts,
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com.sap.engine.lib.xml.parser.NestedSAXParserException: Fatal Error: com.sap.engine.lib.xml.parser.ParserException: Name expected: 0x20(:main:, row:158, col:59)(:main:, row=158, col=59) -> com.sap.engine.lib.xml.parser.ParserException: Name expected: 0x20(:main:, row:158, col:59)
do anyone of you had a similar experience and were able to resolve it, please post it here. it will be highly appreciated. thanks in advance.

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DocumentBuilder db = dbf.newDocumentBuilder();
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hello everybody,
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<root>
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    </element>
    <element>
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in java whole data should be transfered as
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Han.

This code is to convert xml document to a string.
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Insert XML String into XML file at a certain position

Hello,
I have this xml string:
<jdbc-driver-params>
<url>jdbc:oracle:thin:@localhost:1521:mydb</url>
<driver-name>oracle.jdbc.OracleDriver</driver-name>
<properties>
<property>
<name>user</name>
<value>myuser</value>
</property>
</properties>
<password-encrypted>myuser</password-encrypted>
</jdbc-driver-params>and i need to insert it into an xml file at a certain position (as child for a node)
The xml file looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<jdbc-data-source xmlns="http://www.bea.com/ns/weblogic/90"
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    <name>myDB</name>
    <jdbc-data-source-params>
        <global-transactions-protocol>OnePhaseCommit</global-transactions-protocol>
    </jdbc-data-source-params>
</jdbc-data-source>And this is how I would like to get it in the end:
<?xml version='1.0' encoding='UTF-8'?>
<jdbc-data-source xmlns="http://www.bea.com/ns/weblogic/90" xmlns:sec="http://www.bea.com/ns/weblogic/90/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:wls="http://www.bea.com/ns/weblogic/90/security/wls" xsi:schemaLocation="http://www.bea.com/ns/weblogic/920 http://www.bea.com/ns/weblogic/920.xsd">
<name>mydb</name>
<jdbc-driver-params>
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    <driver-name>oracle.jdbc.OracleDriver</driver-name>
    <properties>
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      </property>
    </properties>
    <password-encrypted>myuser</password-encrypted>
</jdbc-driver-params>
<jdbc-connection-pool-params>
    <test-table-name>SQL SELECT 1 FROM DUAL</test-table-name>
</jdbc-connection-pool-params>
<jdbc-data-source-params>
    <global-transactions-protocol>OnePhaseCommit</global-transactions-protocol>
</jdbc-data-source-params>
</jdbc-data-source>So, I obtain the node for the given xml string, the jdbc-data-source node from the xml file and i attempt the appendChild. The problem is that nothing really gets inserted into the xml file.
Someone, any idea?
My code:
try
               DOMParser parser = new DOMParser();
               parser.parse(xmlFileName);
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               DocumentBuilder db = factory.newDocumentBuilder();
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               root.appendChild(doc.importNode(rootXMLString, true));
               return true;
          catch (Exception e)
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johnny
Edited by: smeag0l on Aug 6, 2008 5:08 PM
Edited by: smeag0l on Aug 6, 2008 5:43 PM

Well, you helped me again :-) Thank you very much!
Here is how the code should look:
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               DocumentBuilder db4XMLString = factory.newDocumentBuilder();
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               Node root4XMLString = doc4XMLString.getElementsByTagName(xmlStringNodeName).item(0);
               root4XMLFile.appendChild(doc4XMLFile.importNode(root4XMLString, true));
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               Source source = new DOMSource(doc4XMLFile);
               Transformer xformer = TransformerFactory.newInstance().newTransformer();
                  xformer.transform(source, result);

Parsing an xml string into id-value pair format

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