PHP image upload to SERVER
Hi, I had create a upload picture into the server.It is able
to work on the WAMP server and upload successfully. However, I
faced some error when I upload into the server.
Warning: copy(): open_basedir restriction in effect.
File(/images/uploaded/1221651842.jpg) is not within the allowed
path(s):
(/var/www/vhosts/sppa.org.sg/subdomains/istaff/httpdocs:/tmp) in
/var/www/vhosts/sppa.org.sg/subdomains/istaff/httpdocs/editImage.php
on line 138
Warning: copy(/images/uploaded/1221651842.jpg): failed to
open stream: Operation not permitted in
/var/www/vhosts/sppa.org.sg/subdomains/istaff/httpdocs/editImage.php
on line 138
Can anybody please help?
Thanks a million!
Hi, I had create a upload picture into the server.It is able
to work on the WAMP server and upload successfully. However, I
faced some error when I upload into the server.
Warning: copy(): open_basedir restriction in effect.
File(/images/uploaded/1221651842.jpg) is not within the allowed
path(s):
(/var/www/vhosts/sppa.org.sg/subdomains/istaff/httpdocs:/tmp) in
/var/www/vhosts/sppa.org.sg/subdomains/istaff/httpdocs/editImage.php
on line 138
Warning: copy(/images/uploaded/1221651842.jpg): failed to
open stream: Operation not permitted in
/var/www/vhosts/sppa.org.sg/subdomains/istaff/httpdocs/editImage.php
on line 138
Can anybody please help?
Thanks a million!
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Ok, i found a php image upload script that im using for a cms
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How do I combine the 2 form into one? Please help. It is
driving me to dispair.
Attach Code
<form enctype="multipart/form-data" action="uploader.php"
method="POST">
<input type="hidden" name="MAX_FILE_SIZE" value="500000"
/>
Choose a file to upload: <input name="uploadedfile"
type="file" />
<br />
<input type="submit" value="Upload File" />
</form>
<form action="<?php echo $editFormAction; ?>"
method="post" name="form2" id="form2">
<table align="center">
<tr valign="baseline">
<td nowrap="nowrap" align="right">Image One</td>
<td><input type="text" name="kingsImage1"
value="<?php echo
htmlentities($row_rskingscentre['kingsImage1'], ENT_COMPAT,
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<td><input type="text" name="kingsImage2"
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</tr>
<tr valign="baseline">
<td nowrap="nowrap" align="right">Image
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htmlentities($row_rskingscentre['kingsImage3'], ENT_COMPAT,
'UTF-8'); ?>" size="32" /></td>
</tr>
<tr valign="baseline">
<td nowrap="nowrap"
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<td><input type="submit" value="Update record"
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<p> </p>
<p>
<input type="hidden" name="MM_update" value="form2" />
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echo $row_rskingscentre['kingsHeader']; ?>" />
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</form>jeffoirecoupe1234 wrote:
> Ok, i found a php image upload script that im using for
a cms image gallery on
> my site. But for it to work the way i need to i have to
have certain
> information submited into a mysql table at the same
time. I could just make it
> so the user types the name of the image in a second
form, but i would rather
> not have to as it seems a clumsy way to do things and
opens things up to typos
> etc.
>
> So, i can upload the image ok, and i can upload data to
the table, but i dont
> know what I have to do so that the name of the uploaded
file is automaticly
> inserted into the mysql table.
>
> The first bit of code below is the form I am using to
upload the file to the
> server. The second bit of code is what I am using to
tell the server what the
> file name is.
>
> How do I combine the 2 form into one? Please help. It is
driving me to dispair.
>
> Attach Code
>
> <form enctype="multipart/form-data"
action="uploader.php" method="POST">
> <input type="hidden" name="MAX_FILE_SIZE"
value="500000" />
> Choose a file to upload: <input name="uploadedfile"
type="file" />
> <br />
> <input type="submit" value="Upload File" />
> </form>
>
> <form action="<?php echo $editFormAction; ?>"
method="post" name="form2"
> id="form2">
> <table align="center">
> <tr valign="baseline">
> <td nowrap="nowrap" align="right">Image
One</td>
> <td><input type="text" name="kingsImage1"
value="<?php echo
> htmlentities($row_rskingscentre['kingsImage1'],
ENT_COMPAT, 'UTF-8'); ?>"
> size="32" /></td>
> </tr>
> <tr valign="baseline">
> <td nowrap="nowrap" align="right">Image
Two</td>
> <td><input type="text" name="kingsImage2"
value="<?php echo
> htmlentities($row_rskingscentre['kingsImage2'],
ENT_COMPAT, 'UTF-8'); ?>"
> size="32" /></td>
> </tr>
> <tr valign="baseline">
> <td nowrap="nowrap" align="right">Image
Three</td>
> <td><input type="text" name="kingsImage3"
value="<?php echo
> htmlentities($row_rskingscentre['kingsImage3'],
ENT_COMPAT, 'UTF-8'); ?>"
> size="32" /></td>
> </tr>
> <tr valign="baseline">
> <td nowrap="nowrap"
align="right"> </td>
> <td><input type="submit" value="Update record"
/></td>
> </tr>
> </table>
> <p> </p>
> <p>
> <input type="hidden" name="MM_update" value="form2"
/>
> <input type="hidden" name="kingsHeader"
value="<?php echo
> $row_rskingscentre['kingsHeader']; ?>" />
> </p>
> </form>
>
>
>
Hi Jeff:
Though this does not show you how to solve this issue via a
code
snippett, there are a couple of extensions at WebAssist.com
that enable
you to do this, they are Data Assist and Digital File Pro.
When you have
time, take a look at these Solution Recipes (tutorials) that
show how
DataAssist is used and then now Digital File Pro is used in
conjunction
with DataAssist:
http://www.webassist.com/professional/products/solutionrecipe/Media_139.asp
http://www.webassist.com/professional/products/solutionrecipe/Media_112.asp
DataAssist can be used to save time when you need to build
database
search and management applications quickly, and Digital File
Pro can be
used to include file upload functionality to your form fields
while
enabling you to insert your server file name into the
database, all on
the same page.
enthusiastically,
mark haynes -
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Hello,
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http://tompeez.wordpress.com/2011/11/26/jdev11-1-2-1-0-handling-imagesfiles-in-adf-part-1/
http://tompeez.wordpress.com/2011/11/26/jdev11-1-2-1-0-handling-imagesfiles-in-adf-part-2/
http://tompeez.wordpress.com/2011/12/16/jdev11-1-2-1-0-handling-imagesfiles-in-adf-part-3/
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So for sure it's not a simple issue as the max filesize
Are you sure ? Did you check the current "max_upload_filesize" setting ? As long you don´t check it, you can´t know :-)
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I have an image upload script that upload the image, but does not allow the name of the image to be inserted into the database.
Here is the code
if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "signup3")) {
$updateSQL = sprintf("UPDATE player SET photo=%s WHERE player_id=%s",
GetSQLValueString($_FILES['ufile']['name'], "text"),
GetSQLValueString($_POST['user'], "int"));
mysql_select_db($database_db, $db);
$Result1 = mysql_query($updateSQL, $db) or die(mysql_error());
$updateGoTo = "team-control.php";
if (isset($_SERVER['QUERY_STRING'])) {
$updateGoTo .= (strpos($updateGoTo, '?')) ? "&" : "?";
$updateGoTo .= $_SERVER['QUERY_STRING'];
header(sprintf("Location: %s", $updateGoTo));
//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","50000");
//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
//This variable is used as a flag. The value is initialized with 0 (meaning no error found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
$errors=0;
//checks if the form has been submitted
if(isset($_POST['Submit']))
//reads the name of the file the user submitted for uploading
$image=$_FILES['ufile']['name'];
//if it is not empty
if ($image)
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES['ufile']['name']);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
//if it is not a known extension, we will suppose it is an error and will not upload the file,
//otherwise we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
//print error message
echo '<h1>Unknown extension!</h1>';
$errors=1;
else
//get the size of the image in bytes
//$_FILES['image']['tmp_name'] is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES['ufile']['tmp_name']);
//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
echo '<h1>You have exceeded the size limit!</h1>';
$errors=1;
//we will give an unique name, for example the time in unix time format
//$image_name=time().'.'.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname=$image;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES['ufile']['tmp_name'], $newname);
if (!$copied)
echo '<h1>Copy unsuccessfull!</h1>';
$errors=1;
//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors)
echo "<h1>File Uploaded Successfully!</h1>";
I dont know why its not working...I've used this same script in the same way in another website and it works fine.Check with your host for permission settings. If it works locally, and on other servers, then the code works, it just may not work in the particular
environment your host has set up.
Lawrence Carmer - *Adobe Community Professional*
http://www.Cartweaver.com
Complete Shopping Cart Application for
Dreamweaver, available in PHP and ColdFusion
Stay updated - http://blog.cartweaver.com -
Restrict image pixel size in multiple image upload
Re: Multiple Image Upload behaviour.
One of the only issues I have with this extension is if users try to upload an image within the limits I set (of 250Kb) but with a high pixel count.
For example, a jpg of 800 x 600 at 200Kb causes no problem, but a one of 2000 pixels at 150Kb probably will.
I understand that there is probably more server load to resize a large pixel image, so is there a way to check the pixel size of images to be uploaded as well as the file size and reject it if it is too large?But what you could do, is retrieving the php.ini´s "post_max_size" value and display a note to your site visitors:
<br />
<br />
<b>1.</b> put this into the doc´s head:
<br />
<br /><?php<br />$replace_max_size_MB = str_replace("M"," MB",ini_get('post_max_size'));<br />?>
<br />
<br />
<b>2.</b> the related message:
<br />
<br />Pics larger than <?php echo $replace_max_size_MB; ?> will be rejected by the server
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<br />Günter Schenk
<br />Adobe Community Expert, Dreamweaver -
This is my Jsp code for image upload in database:
This is my Jsp code for image upload in database:
-----------Upload.jsp----------------
<html>
<head>
</head>
<body bgproperties="fixed" bgcolor="#CCFFFF">
<form method="POST" action="UploadPicture.jsp" enctype="multiform/form-data">
<%! int update=0; %>
<%@ page import="java.util.*" %>
<%@ page import="java.sql.*" %>
<%@ page import="java.text.*" %>
<%@ page import="java.sql.Date" %>
<%@ page import="java.io.*"%>
<%@ page language = "java" %>
<%
try
String ct="3";
String path;
File image=new File(request.getParameter("upload"));
path=request.getParameter("upload");
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
Connection con = DriverManager.getConnection("jdbc:odbc:itPlusElectronics","","");
PreparedStatement pstmt=con.prepareStatement("insert into graphics values(?,?,?)");
pstmt.setString(2,path);
pstmt.setString(3,ct);
InputStream is=new FileInputStream(path);
pstmt.setBinaryStream(1, is, (int)(image.length()));
int s=pstmt.executeUpdate();
if(s>0)
out.println("Uploaded");
else
%>
unsucessfull
<%}
is.close();
pstmt.close();
catch(Exception e)
}%>
</p>
<p><br>
<img src="UploadedPicture.jsp">image</img>
<p></p>
</form>
</body>
</html>
My database name is itPlusElectronics and the table name is "graphics".
I have seen as a result of the above code that the image is stored in database as "Long binary data". and database table is look like as follows-------
picture path id
Long binary data D:\AMRIT\1-1-Picture.jpg 3
To retrive and display i use this JSP code as--
------------------------UploadedPicture.jsp------------------------------
<html>
<head>
</head>
<body bgproperties="fixed" bgcolor="#CCFFFF">
<%! int update=0; %>
<%@ page import="java.util.*" %>
<%@ page import="java.sql.*" %>
<%@ page import="java.text.*" %>
<%@ page import="java.io.*"%>
<%@ page language = "java" %>
<%@page import="javax.servlet.ServletOutputStream"%>
<%
try
String path;
path=request.getParameter("upload1");
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
Connection con = DriverManager.getConnection("jdbc:odbc:itPlusElectronics","","");
PreparedStatement pst = con.prepareStatement("SELECT * FROM graphics WHERE id ='3'");
// pst.setString(3, id);
ResultSet rs = pst.executeQuery();
path=rs.getString("path");
if(rs.next()) {
byte[] bytearray = new byte[4096];
int size=0;
InputStream sImage;
sImage = rs.getBinaryStream(1);
response.reset();
response.setContentType("image/jpeg");
response.addHeader("Content-Disposition","filename=path");
while((size=sImage.read(bytearray))!= -1 )
response.getOutputStream().write(bytearray,0,size) ;
response.flushBuffer();
sImage.close();
rs.close();
catch(Exception e)
%>
</body>
</html>
Now after browsing a jpg image file from client side and pressing submit button ;
I am unable display the image in the Upload.jsp file.Though I use
<img src="UploadedPicture.jsp">image</img> HTML code in Upload.jsp
file .
Now I am unable to find out the mistakes which is needed for displaying the picture in the Upload.jsp page..
If any one can help with the proper jsp code to retrive and display the image ,please please help me !!!!!!!!!!!!!!!!!!!!!!!!!!dketcham wrote:
cotton.m wrote:
>
2) I'm looking at how you called stuff, and you're trying to call the jsp file as an image? That jsp isn't the source of the image, just a page linking to an image. I think if you really want to do things that way you're going to need to just include that jsp within the jsp you're calling it from (or you can do it the easy way, and if you have the information to get the path of the image you want, you could simply call the image from the first jsp you posted)This is incorrect.
There are two JSPs. The second when called will (if it worked) return the source of an image as stored in the database.even when called with <img src=xx.jsp>??
Yes.
If any of what I say next seems obvious or otherwise negative I apologize, just trying to explain and I don't know what you know vs what you don't.
The link in the src is just a URL not a filetype. So just because it ends with JSP does not mean it has to return HTML. The content type is determined by the browser using the Content-Type header returned by the server in the HTTP response. In this case the header is set to be a jpeg so that's what the browser will attempt to interpret the content part of the response as.
So in fact one is not limited to just HTML or images but whatever content type you would like to return (that the browser can understand anyway). This could be HTML or it could be an image of some type or it could be a PDF or it could be an Excel spreadsheet. All you have to do in the JSP is set the header appropriately and then send content that is actually in that format.
This does not just apply to JSP by the way but all other web programming languages. You can do similar things to produce the same results in PHP, Perl, ASP etc.
The only JSP/Servlet complication is whether or not doing this in a JSP is a "good" idea but I am not an expert enough at that to make a definitive statement. Mostly though JDBC in a JSP is a no-no.
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When trying to access the shared iTunes library of my Macbook Pro on my iPad(iOS 5.1) the TV Shows are all mixed up. Some shows are not even displayed. The same library display normally via my Apple TV. It appears that iPad using iOS 5 has lost the a
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