PHP/MySQL Record Insert question

Question

I am working with which PHP 4.4.2, MySQL Server 5.0 running
on Apache 2.0.55, and I am developing my web-site with Dreamweaver
8. All of which is running locally on my machine.
I am working on a real-estate website that allows landlords
around my local area to login to the web-site and add their
apartment or housing rental units into a database that students
that go to my small university can browse and search through. The
landlords register through a form that loads into a 'landlords'
table in the database and MySQL auto-increments an ID into a
'landlord_id' column which obviously assigns them their
'landlord_ID'.
My question is: When the landlord is filling out the form to
add one of their rental units ( which loads into a separate table I
called 'sites'), how can I make their 'landlord_id' (which resides
in the 'landlords' table) be entered into the 'landlord_id' column
in the 'sites' table for each site that they enter into the
database?
I'm trying to do this because when the landlord first logs
in, I'm going to have a dynamic table that displays all of the
sites they already have entered in the database, and only displays
their sites that they have already entered in by only displaying
the sites that have their 'landlord_id' in the site record.
Thanks so much for your help, and if I'm being confusing at
all, please reply or email me so I can clarify.

Answer 1

Cade06 wrote:
> Thanks alot for your reply, but I am completely new to
MySQL, and I am not
> quite sure how the syntax works. When you say " WHERE
landlord_username =
> 'whatever' "I'm not sure what needs to go in the
'whatever' portion of the
> code. Do I need to insert static text here or something
else? I am totally out
> of my element here, sorry :-/
It's probably not so much MySQL syntax that's the problem for
you, but a
lack of understanding how to work with Dreamweaver
recordsets, server
behaviors, and sessions. Building database-driven sites with
Dreamweaver
isn't difficult, but there are a lot of things involved.
The Log In User server behavior automatically creates a
session variable
called $_SESSION['MM_Username']. You can use this as a
parameter to pass
to the SQL query in the Advanced Recordset dialog box. In the
SQL area
you would type (I'm guessing the name of your table and the
username
column):
SELECT landlord_id FROM landlords
WHERE landlord_username = 'col1'
Then click the plus button above the Variables area, and
create a
Parameter with the following values:
Name: col1
Default value: 1
Runtime value: $_SESSION['MM_Username']
You can then extract the result of the recordset, and assign
it to a
session variable like this:
$_SESSION['landlord_id'] = $row_recordsetName['landlord_id'];
> Also, I understand that I need to do this on the login
page, but do I need to
> define the recordset again on the add_site page as well?
I guess I'm still not
> quite clear on how I specify the session variable as the
value that needs to be
> entered in the sites table as the landlord_ID.
As long as the session is still valid (which it would be if
you use
Restrict Access to Page), you will always have access to that
landlord's
id through $_SESSION['landlord_id'].
David Powers
Author, "Foundation PHP for Dreamweaver 8" (friends of ED)
Author, "Foundation PHP 5 for Flash" (friends of ED)
http://foundationphp.com/