Ping authorization via e-mail doesn't work. I have an iTunes account but must seek authorization for Ping. I don't know why this is but I never get an e-mail message with the link. Why?

Question

Hi. I use iTunes for podcasts and to burn MP3s from audible.com. It works great except PING. I need to confirm my identity to the PING server. It purports to sen me an e-mail but I never get it. Why is this?

Answer 1

Hello Ulrich,
thank you for your answer. Concerning the dataflow I agree and it is what I usually do. Actually I follow the dataflow paradigm whenever there is no problem (the 'false case' in the screenshot):
“FW102x Initialize.vi” -> “FW102x Get Position.vi” -> “FW102x Set Position.vi”.
Whenever there is a mistake, this just doesn't work with these drivers. The sequence
“FW102x Initialize.vi” -> “FW102x Get Position.vi”  -> ///error/// -> “FW102x Close.vi”, “FW102x Reset.vi”  ;; “FW102x Initialize.vi”
will give me errors for “FW102x Close.vi”, “FW102x Reset.vi”  and “FW102x Initialize.vi” reporting "session handle not valid". However, if I "bypass" the instrument handles directly from the first "Initialize" to "Close" and "Reset", they will report the same error, but the second "Initialize" will work again. I can even merge the first two frames and execute "Close" and "Reset" at the same time to do so. But whenever I try something else, e.g. do the 'correct' wiring, I am unable to close, reset or reinitialize. I have to restart LabView completely, to make the vi work again. So I guess the session is still hanging around somewhere in memory, but I can't access it anymore.
Surprisingly, wherever I put Probes on the data handle wires they show the correct "ASRL5::INSTR" (with or without correct wiring). But only the "Bypass" wire makes the vi work. Since you couldn't find the drivers in the driver network, I guess they might just run into problems, if an error occurs.
But thanks for your comment anyway. The problem is fixed for the moment. It's just that I prefer to actually know what I am doing here instead of producing some code I'd rather not show anyone.
Carsten