Please help with PL/SQL compiler message
Hi
When I compile a procedure, I get the message
"Expected Symbol Name is missing"
"Procedure created"
The procedure actually got created in the database and runs.
Can someone please let me know the meaning of "Expected Symbol Name is missing" and any side-effects of this message?
Thanks in advance.
Suresh,
I'm getting the message when I start the file that has the code for the stored procedure (like @X.sql). The first line of the code is CREATE OR REPLACE PROCEDURE .....
Thanks
Similar Messages
-
Please help with an sql to show more than one records into single row for each student
From the following data I would like to create an sql to get the information as the following layout
studentid, firstTerm, EnglishMark1,ScienceMark1,MathsMark1, Secondterm,EnglishMark2,ScienceMark2,MathsMark2,
ThirdTerm,EnglishMark3,ScienceMark3,MathsMark3 // As single rows for each student
Example
1 First, 30,40,20,Sec,30,40,20, simillarly next row for next row for another sudent. Please help to generate the sql for the same.
Please help it would be very appreciate.
With Thanks
Pol
polachancreate table yourdata (studentid int, term varchar(10), section varchar(50), Mark int)
insert into yourdata values
(1,'First','Math',20),(1,'First','English',30),(1,'First','Science',40),
(2,'First','Math',20),(2,'First','English',30),(2,'First','Science',40),
(3,'First','Math',20),(3,'First','English',30),(3,'First','Science',40),
(1,'Sec','Math',20),(1,'Sec','English',30),(1,'Sec','Science',40),
(2,'Sec','Math',20),(2,'Sec','English',30),(2,'Sec','Science',40),
(3,'Sec','Math',20),(3,'Sec','English',30),(3,'Sec','Science',40)
Select studentid
,max(case when term='First' and section='English' Then Mark End) as EnglishMark1
,max(case when term='First' and section='Science' Then Mark End) as ScienceMark1
,max(case when term='First' and section='Math' Then Mark End) as MathMark1
,max(case when term='Sec' and section='English' Then Mark End) as EnglishMark2
,max(case when term='Sec' and section='Science' Then Mark End) as ScienceMark2
,max(case when term='Sec' and section='Math' Then Mark End) as MathMark2
,max(case when term='Third' and section='English' Then Mark End) as EnglishMark3
,max(case when term='Third' and section='Science' Then Mark End) as ScienceMark3
,max(case when term='Third' and section='Math' Then Mark End) as MathMark3
From yourdata
Group by studentid
drop table yourdata -
Hi All,
This is driving me nuts but I can't see what I am doing wrong....
I have a simple PL/SQL with :
DECLARE
xxx NUMBER;
BEGIN
FOR z in 1..htmldb_application.g_f02.count loop
xxx:=htmldb_application.g_f02(z);
select task_id into present_task from dm_process_steps where process_id=:P34_ID AND task_id = xxx;
htp.p(xxx);
IF htmldb_application.g_f02(z) = present_task THEN
htp.p('PRESENT');
ELSE
htp.p('NOT PRESENT');
END IF;
END;
The above fails with:
ORA-01403: no data found
However if I replace the marked xxx with the number then the code works fine.
I do not understand the reason for this since I know that xxx has in fact a value and the select should be valid!
Kindly asking for any help on this!
Pawel.Scott,
This will probably be a quite extended but I'll try to make it as clear as possible. I took a different approach to find the element which is causing the problem.
I have 2 TABLES defined as:
DM_PROCESS_STEPS
ID Number
PROCESS_ID Number
TASK_ID Number
TASK_ORDER Number
DM_TASKS
TASK_ID Number
TASK_TITLE Varchar2
...and some more columns ...
On the page I have a PL/SQL Region with:
DHTML_SHUTTLE (
pSQL_1=>'select "TASK_TITLE","TASK_ID" from "DM_TASKS"',
pSQL_2=>'select t.task_title, p.task_id from dm_tasks t,dm_process_steps p where t.task_id = p.task_id and process_id = :P34_ID order by p.task_order',
pID_1=>'1',
pID_2=>'2',
pSort1=>'N',
pSort2=>'Y',
pFixed1=>'Y',
pHeight=>'300',
pWidth=>'400',
pImagePrefix=>v('WORKSPACE_IMAGES')
NOTE: All above code comes from a working shuttle_sample code. The only things I modified were pSQL_1 and pSQL_2
- In this case I want to have "All available tasks in the first list"
- Since the syntax for pSQL_2 item must return two columns I wrote a joined queary so that I can see the Task_Title on the second list although this column doesn't directly come from DM_PROCESS_STEPS.
I also have a After Submit Process which is fired upon pressing an apply button:
DECLARE
BEGIN
-- Clean the Tasks from current Process --
delete from dump where process_id = :P34_ID;
-- Populate the Process with new list
FOR z in 1..htmldb_application.g_f02.count loop
INSERT INTO DUMP
(ID,TASK_ID,PROCESS_ID,TASK_ORDER)
VALUES (DM_PROCESS_STEPS_SEQ.nextval,htmldb_application.g_f02(z),:P34_ID,z);
END LOOP;
END;
Now, the problem is with htmldb_application.g_f02(z) element. If understand correctly (please verify this!) the value of this element is whatever the pSQL_2 returns in the second column. In this case, htmldb_application.g_f02(z) returns the Task_Id.
However, when I view the contents of the DM_PROCESS_STEPS table I can see that the first row (or rows) contain PROCESS_ID under TASK_ID column !!! This is were I am most confused as I cannot figure out were these htmldb_application.g_f02(z) come from !!!
For example:
1. I am trying to edit tasks for a process with process_id = 421:
2. In my select list I have 3 tasks (who's task_id are 746,782 and 785)
When executing the above update process I get the following results:
ID TASK_ID PROCESS_ID TASK_ORDER
1737 421 421 1
1738 421 421 2
1739 421 421 3
1740 746 421 4
1741 782 421 5
1742 785 421 6
If I am not mistaken the value of
htmldb_application.g_f02(1) - should be the Task_Id of the first element on my select list
htmldb_application.g_f02(2) - should be the Task_Id of the second element on my select list and so on....
Why does htmldb_application.g_f02(1-3) hold a different value is beyond me !
Questions which bother me:
- Is there any way to lookup to 'contents' of htmldb_application.g_f02(1) from a separate SQL session or does it has to be in run-time?
- Perhaps there is a way to flush or clean the htmldb_application.g_f02 ?
Your help would be greatelly appriciated !
Regards,
Pawel. -
Please Help with the sql below for hierarchies
Hi all.
I have a table named stg_org_hier whose data looks like this
i would like to build the hierarchy from BU,AREA,REGION,DISTRICT,TERR
There are data cyles in the data below
stg_org has this data
QTR_CD HIER_LVL_CD CURR_RDT_ID DISTRICT_RDT_ID
2007Q4 AREA E0F7B00000000 E0F7B00000000
2007Q4 BU E0F7B00000000 E0F7B00000000
2007Q4 AREA E0F7B40000088 E0F7B40000000
2007Q4 REGION N0F7B40400000 E0F7B40000000
2007Q4 REGION E0F7B40700000 E0F7B40000000
2007Q4 AREA E0F7B00000088 E0F7B00000000
2007Q4 AREA E0F7B40000000 E0F7B00000000
2007Q4 DISTRICT N0F6B40405C99 N0F7B40400000
2007Q4 REGION N0F7B40400088 N0F7B40400000
2007Q4 DISTRICT N0F7B40405M99 N0F7B40400000
2007Q4 TERR N0F1B40405201 N0F7B40405M99
they would like to see the output in the below in the below form
QTR_CD HIER_LVL_CD CURR_RDT_ID DISTRICT_RDT_ID
2007Q4 BU E0F7B00000000 E0F7B00000000
2007Q4 AREA E0F7B00000000 E0F7B00000000
2007Q4 AREA E0F7B00000088 E0F7B00000000
2007Q4 AREA E0F7B40000000 E0F7B00000000
2007Q4 AREA E0F7B40000088 E0F7B40000000
2007Q4 REGION E0F7B40700000 E0F7B40000000
2007Q4 REGION N0F7B40400000 E0F7B40000000
2007Q4 DISTRICT N0F6B40405C99 N0F7B40400000
2007Q4 REGION N0F7B40400088 N0F7B40400000
2007Q4 DISTRICT N0F7B40405M99 N0F7B40400000
2007Q4 TERR N0F1B40405201 N0F7B40405M99
Here is the sql i have written :
select curr_terr_rdt_id,district_rdt_id,hier_lvl_cd,level from STG_ORG_QTR_SF_HCHY
connect by prior
curr_terr_rdt_id=district_rdt_idqtr_cd,hier_lvl_cd,curr_rdt_id, district_rdt_id
2007Q4,BU, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000088,E0F7B00000000
2007Q4,AREA, E0F7B40000000,E0F7B00000000
2007Q4,AREA, E0F7B40000088,E0F7B40000000
2007Q4,REGION, E0F7B40700000,E0F7B40000000
2007Q4,REGION, N0F7B40400000,E0F7B40000000
2007Q4,DISTRICT, N0F6B40405C99,N0F7B40400000
2007Q4,REGION, N0F7B40400088,N0F7B40400000
2007Q4,DISTRICT, N0F7B40405M99,N0F7B40400000
2007Q4,TERR, N0F1B40405201,N0F7B40405M99Not having a database at hand right now is helpful this time ;)
Indenting the data clearly shows that the hierarchy rules are being violated (cycles you are mentioning do not matter in this case):
Each node must have a unique predecessor except the root having none (in your case data on lines 3 and 4 both point to lines 1 and 2)
2007Q4,BU, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000088,E0F7B00000000
2007Q4,AREA, E0F7B40000000,E0F7B00000000
2007Q4,AREA, E0F7B40000088,E0F7B40000000
2007Q4,REGION, E0F7B40700000,E0F7B40000000
2007Q4,REGION, N0F7B40400000,E0F7B40000000
2007Q4,DISTRICT, N0F6B40405C99,N0F7B40400000
2007Q4,REGION, N0F7B40400088,N0F7B40400000
2007Q4,DISTRICT, N0F7B40405M99,N0F7B40400000
2007Q4,TERR, N0F1B40405201,N0F7B40405M99Removing the first data line or changing it's curr_rdt_id will make hierarhical queries work (lines 1 and 2 would better not point to themself)
Regards
Etbin
Message was edited by: Etbin
user596003 -
Please help with the sql logic
The below is going to be a record set from for a view from the FROM CLAUSE
1. Find component DOCUMENT where the document type = Square Metres (DOC.UOM_STD_ID = 'METR_MTR) If any components are found, retrieve the Document records for these components ONLY.
2. Otherwise, if no components exist with a Document type = Square Metres, look for components with a Document type of Acres (DOC.UOM_STD_ID = 'ACRE'). If found, retrieve the Space Lease records for these components ONLY.
3. Otherwise, if the Document does not have components with a type = Square Metres or Acres, look for components with the type of (DOC.UOM_STD_ID = 'PARK'). Then retrieve the departments associated with these parking components.
For Space Lease records above, retrieve the associated Org ID (SPACE.SPORG).
Return all departments where
the associated Org Type (ORG.ORGCLASS) = 'NON'
or the associated Org Type (ORG.ORGCLASS) = 'GD'
Thank youmaybe something like:
SQL> select emp.empno, emp.ename, emp.deptno
2 from emp,
3 (select case when (select 1 from emp where deptno = 10 and rownum = 1) = 1 then 1
4 when (select 2 from emp where deptno = 60 and rownum = 1) = 2 then 2
5 else 3
6 end case_col
7 from dual) d1
8 where deptno = decode(d1.case_col,1,10,
9 2,60,
10 3,70);
EMPNO ENAME DEPTNO
7839 KING 10
7782 CLARK 10
7934 MILLER 10
SQL> in you code it will be something like:
select ...
from document t1,
(select case when (select 1 from document doc where DOC.UOM_STD_ID = 'METR_MTR' and rownum = 1) = 1 then 1
when (select 1 from document doc where DOC.UOM_STD_ID = 'ACRE' and rownum = 1) = 2 then 2
else 3
end case_col
from dual) d1
where t1.uom_std_id = decode(d1.case_col,1,'METR_MTR',
2,'ACRE',
3,'PARK',
null);note: untested -
Please help with better sql plan - full test case
Hello,
here is my test case:
SQL> create table ib_auth_devices(dv_id number(12) primary key , dv_cl_id number(12));
Table created.
SQL> create table ib_clients (cl_id number(12) primary key);
Table created.
SQL> alter table ib_auth_devices add constraint fk1 foreign key(dv_cl_id) references ib_clients(cl_id);
Table altered.
SQL> create table ib_tokens (to_dv_id number(12) primary key);
Table created.
SQL> alter table ib_tokens add constraint to_dv_id foreign key(to_dv_id) references ib_auth_devices(dv_id);
Table altered.
SQL> create table ib_auth_cards(au_dv_id number(12) primary key);
Table created.
SQL> alter table ib_auth_cards add constraint au_dv_id foreign key(au_dv_id) references ib_auth_devices(dv_id);
Table altered.
SQL> insert into ib_clients values(1);
1 row created.
SQL> insert into ib_clients values(2);
1 row created.
SQL> insert into ib_clients values(3);
1 row created.
SQL> insert into ib_clients values(4);
1 row created.
SQL> insert into ib_clients values(5);
1 row created.
SQL> commit;
Commit complete.
SQL> insert into ib_auth_devices values(1 , 1);
1 row created.
SQL> insert into ib_auth_devices values(2 , 2);
1 row created.
SQL> insert into ib_auth_devices values(3,3);
1 row created.
SQL> insert into ib_auth_devices values(4,4);
1 row created.
SQL> commit;
Commit complete.
SQL> insert into ib_tokens values(1);
1 row created.
SQL> insert into ib_tokens values(2);
1 row created.
SQL> insert into ib_tokens values(3);
1 row created.
SQL> insert into ib_auth_cards values(1);
1 row created.
SQL> insert into ib_auth_cards values(2);
1 row created.
SQL> commit;
Commit complete.
SQL> select cl_id from ib_clients;
CL_ID
1
2
3
4
5
SQL> select cl_id from ib_clients cli , ib_auth_devices ad
2 where
3 cli.cl_id = ad.dv_cl_id;
CL_ID
1
2
3
4
SQL> select * from ib_tokens;
TO_DV_ID
1
2
3
SQL> select * from ib_auth_cards;
AU_DV_ID
1
2
SQL> select * from ib_clients;
CL_ID
1
2
3
4
5
SQL> select * from ib_auth_devices;
DV_ID DV_CL_ID
1 1
2 2
3 3
4 4
SQL> exec dbms_stats.gather_table_stats(user , 'IB_AUTH_DEVICES' , cascade => true);
PL/SQL procedure successfully completed.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_TOKENS' , cascade => true);
PL/SQL procedure successfully completed.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_CLIENTS' , cascade => true);
PL/SQL procedure successfully completed.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_AUTH_CARDS' , cascade => true);
PL/SQL procedure successfully completed.
SQL> l
1 select cli.cl_id from ib_clients cli , ib_auth_devices ad,
2 (select dv_cl_id as cl_id
3 from ib_auth_cards, ib_auth_devices
4 where
5 au_dv_id = dv_id
6 ) cards,
7 ( select dv_cl_id as cl_id
8 from ib_tokens, ib_auth_devices
9 where
10 to_dv_id = dv_id
11 ) tokens
12 where
13 cli.cl_id = ad.dv_cl_id
14 and cards.cl_id(+)= cli.cl_id
15 and cards.cl_id is null
16 and tokens.cl_id(+)= cli.cl_id
17* and tokens.cl_id is null
SQL> r
1 select cli.cl_id from ib_clients cli , ib_auth_devices ad,
2 (select dv_cl_id as cl_id
3 from ib_auth_cards, ib_auth_devices
4 where
5 au_dv_id = dv_id
6 ) cards,
7 ( select dv_cl_id as cl_id
8 from ib_tokens, ib_auth_devices
9 where
10 to_dv_id = dv_id
11 ) tokens
12 where
13 cli.cl_id = ad.dv_cl_id
14 and cards.cl_id(+)= cli.cl_id
15 and cards.cl_id is null
16 and tokens.cl_id(+)= cli.cl_id
17* and tokens.cl_id is null
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=4 Bytes=128)
1 0 FILTER
2 1 HASH JOIN (OUTER)
3 2 FILTER
4 3 HASH JOIN (OUTER)
5 4 NESTED LOOPS (Cost=1 Card=4 Bytes=24)
6 5 TABLE ACCESS (FULL) OF 'IB_AUTH_DEVICES' (Cost=1
Card=4 Bytes=12)
7 5 INDEX (UNIQUE SCAN) OF 'SYS_C008299' (UNIQUE)
8 4 VIEW (Cost=1 Card=2 Bytes=26)
9 8 NESTED LOOPS (Cost=1 Card=2 Bytes=18)
10 9 TABLE ACCESS (FULL) OF 'IB_AUTH_DEVICES' (Cost
=1 Card=4 Bytes=24)
11 9 INDEX (UNIQUE SCAN) OF 'SYS_C008303' (UNIQUE)
12 2 VIEW (Cost=1 Card=3 Bytes=39)
13 12 NESTED LOOPS (Cost=1 Card=3 Bytes=27)
14 13 TABLE ACCESS (FULL) OF 'IB_AUTH_DEVICES' (Cost=1 C
ard=4 Bytes=24)
15 13 INDEX (UNIQUE SCAN) OF 'SYS_C008301' (UNIQUE)
Statistics
0 recursive calls
12 db block gets
9 consistent gets
0 physical reads
0 redo size
364 bytes sent via SQL*Net to client
431 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
8 sorts (memory)
0 sorts (disk)
1 rows processedAny ideas about rewriting this query to achive better performance ?
Oracle version 8.1.7
Best Regards.
GrzegorzThe answer to this question totally depends on the real volumes you have in your tables. Your test case is probably not showing us these volumes.
However, I see some needless table accesses, so it's probably safe to conclude that this rewrite will speed something up:
SQL> create table ib_auth_devices(dv_id number(12) primary key , dv_cl_id number(12));
Tabel is aangemaakt.
SQL> create table ib_clients (cl_id number(12) primary key);
Tabel is aangemaakt.
SQL> alter table ib_auth_devices add constraint fk1 foreign key(dv_cl_id) references ib_clients(cl_id);
Tabel is gewijzigd.
SQL> create table ib_tokens (to_dv_id number(12) primary key);
Tabel is aangemaakt.
SQL> alter table ib_tokens add constraint to_dv_id foreign key(to_dv_id) references ib_auth_devices(dv_id);
Tabel is gewijzigd.
SQL> create table ib_auth_cards(au_dv_id number(12) primary key);
Tabel is aangemaakt.
SQL> alter table ib_auth_cards add constraint au_dv_id foreign key(au_dv_id) references ib_auth_devices(dv_id);
Tabel is gewijzigd.
SQL> insert into ib_clients values(1);
1 rij is aangemaakt.
SQL> insert into ib_clients values(2);
1 rij is aangemaakt.
SQL> insert into ib_clients values(3);
1 rij is aangemaakt.
SQL> insert into ib_clients values(4);
1 rij is aangemaakt.
SQL> insert into ib_clients values(5);
1 rij is aangemaakt.
SQL> insert into ib_auth_devices values(1 , 1);
1 rij is aangemaakt.
SQL> insert into ib_auth_devices values(2 , 2);
1 rij is aangemaakt.
SQL> insert into ib_auth_devices values(3,3);
1 rij is aangemaakt.
SQL> insert into ib_auth_devices values(4,4);
1 rij is aangemaakt.
SQL> insert into ib_tokens values(1);
1 rij is aangemaakt.
SQL> insert into ib_tokens values(2);
1 rij is aangemaakt.
SQL> insert into ib_tokens values(3);
1 rij is aangemaakt.
SQL> insert into ib_auth_cards values(1);
1 rij is aangemaakt.
SQL> insert into ib_auth_cards values(2);
1 rij is aangemaakt.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_AUTH_DEVICES' , cascade => true);
PL/SQL-procedure is geslaagd.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_TOKENS' , cascade => true);
PL/SQL-procedure is geslaagd.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_CLIENTS' , cascade => true);
PL/SQL-procedure is geslaagd.
SQL> exec dbms_stats.gather_table_stats(user , 'IB_AUTH_CARDS' , cascade => true);
PL/SQL-procedure is geslaagd.
SQL> set autotrace on explain
SQL> select cli.cl_id
2 from ib_clients cli
3 , ib_auth_devices ad
4 , ( select dv_cl_id as cl_id
5 from ib_auth_cards
6 , ib_auth_devices
7 where au_dv_id = dv_id
8 ) cards
9 , ( select dv_cl_id as cl_id
10 from ib_tokens
11 , ib_auth_devices
12 where to_dv_id = dv_id
13 ) tokens
14 where cli.cl_id = ad.dv_cl_id
15 and cards.cl_id(+)= cli.cl_id
16 and cards.cl_id is null
17 and tokens.cl_id(+)= cli.cl_id
18 and tokens.cl_id is null
19 /
CL_ID
4
1 rij is geselecteerd.
Uitvoeringspan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=10 Card=4 Bytes=128)
1 0 FILTER
2 1 HASH JOIN (OUTER)
3 2 FILTER
4 3 HASH JOIN (OUTER)
5 4 NESTED LOOPS (Cost=4 Card=4 Bytes=24)
6 5 TABLE ACCESS (FULL) OF 'IB_AUTH_DEVICES' (Cost=3 Card=4 Bytes=12)
7 5 INDEX (UNIQUE SCAN) OF 'SYS_C001354381' (UNIQUE) (Cost=1 Card=1 Bytes=3)
8 4 VIEW (Cost=3 Card=2 Bytes=26)
9 8 NESTED LOOPS (Cost=3 Card=2 Bytes=18)
10 9 INDEX (FULL SCAN) OF 'SYS_C001354385' (UNIQUE) (Cost=2 Card=2 Bytes=6)
11 9 TABLE ACCESS (BY INDEX ROWID) OF 'IB_AUTH_DEVICES' (Cost=2 Card=1 Bytes=6)
12 11 INDEX (UNIQUE SCAN) OF 'SYS_C001354380' (UNIQUE) (Cost=1 Card=1)
13 2 VIEW (Cost=3 Card=3 Bytes=39)
14 13 NESTED LOOPS (Cost=3 Card=3 Bytes=27)
15 14 INDEX (FULL SCAN) OF 'SYS_C001354383' (UNIQUE) (Cost=2 Card=3 Bytes=9)
16 14 TABLE ACCESS (BY INDEX ROWID) OF 'IB_AUTH_DEVICES' (Cost=2 Card=1 Bytes=6)
17 16 INDEX (UNIQUE SCAN) OF 'SYS_C001354380' (UNIQUE) (Cost=1 Card=1)
SQL> select cli.cl_id
2 from ib_clients cli
3 , ib_auth_devices ad
4 where cli.cl_id = ad.dv_cl_id
5 and not exists
6 ( select 'dummy'
7 from ib_auth_cards
8 where au_dv_id = ad.dv_id
9 )
10 and not exists
11 ( select 'dummy'
12 from ib_tokens
13 where to_dv_id = ad.dv_id
14 )
15 /
CL_ID
4
1 rij is geselecteerd.
Uitvoeringspan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=8 Card=1 Bytes=9)
1 0 FILTER
2 1 NESTED LOOPS (Cost=4 Card=1 Bytes=9)
3 2 TABLE ACCESS (FULL) OF 'IB_AUTH_DEVICES' (Cost=3 Card=1 Bytes=6)
4 2 INDEX (UNIQUE SCAN) OF 'SYS_C001354381' (UNIQUE) (Cost=1 Card=1 Bytes=3)
5 1 INDEX (UNIQUE SCAN) OF 'SYS_C001354385' (UNIQUE) (Cost=1 Card=1 Bytes=3)
6 1 INDEX (UNIQUE SCAN) OF 'SYS_C001354383' (UNIQUE) (Cost=1 Card=1 Bytes=3)Regards,
Rob. -
Hi ALL,
Test_dpnt is a table.from this i want to find the total no.of applications
(ssc,ssa,ssb,ssd,map,maq,oet,oet)---total 8.
parent - 2(since oet is indepentdent)
children---4
independent-2
source_app is the parent applications
dpnt_app---child application of parent
source_app dpnt_app
ssc ssa
ssc ssb
ssc ssd
mad map
mad maq
oet oet
I want the output likethis
total parent child independent
8 2 4 2
How to write the sql for thisstill unclear to me on how you will be able to get the output as
total parent child independent
8 2 4 2based on the sample data you have posted below:
app_srce app_dpnt app_dpnt-typ-c
43 190 R
43 191 R
150 200 R
150 201 R
300 300 Rdo you mean by the output should look something like this:
srce count dpnt count
2 1
1
2 1
1
1 1or that it needs to count all the rows for each of the 3 columns -
I switched over from an iPhone to a Samsung Galaxy S3 & I haven't been able to receive any text messages from iPhones. I have no problem sending the text messages but I'm not receivng any from iPhones at all. It has been about a week now that I'm having this problem. I've already tried fixing it myself and I also went into the sprint store, they tried everything as well. My last option was to contact Apple directly. Please help with turning my iMessage completely off so that I can receive my texts.
If you registered your iPhone with Apple using a support profile, try going to https://supportprofile.apple.com/MySupportProfile.do and unregistering it. Also, try changing the password associated with the Apple ID that you were using for iMessage.
-
How can I sync my iPhone on a different computer without erasing my applications? My iPhone was earlier synced with a PC which I don't use anymore.
On the new computer, I am getting a message that my all purchases would be deleted if I sync it with new iTunes library.
Please help with proper steps, if any.Also see... these 2 Links...
Recovering your iTunes library from your iPod or iOS device
https://discussions.apple.com/docs/DOC-3991
Syncing to a New Computer...
https://discussions.apple.com/docs/DOC-3141 -
Please help with the message I am receving on startup ""You can't open the application NovamediaDiskSupressor because PowerPC applications are no longer supported."
I have read some of the replies in the Apple Support Communities, but as I am no techie, I would have no idea how I would implement that solution.
Please help with what I need to type, how, where, etc.
Many thanks
AppleSueIn HunterCreekI am afraid there is no solution.
PowerPC refers to the processing chip used by Apple before they transferred to Intel chips. They are very different, and applications written only for PPC Macs cannot work on a Mac running Lion.
You could contact the developers to see if they have an updated version in the pipeline. -
Please help with slideshow problems!
Am using Photoshop Elements 8 and trying to make a slideshow. Have tried 4 times now and keep ending up with same problem, cannot reopen project to continue edititing. Won't show up in orginizer and when I find on harddrive and try to open get message " wmv file cannot be opened". How can I save a
slideshow inprogress and be able to reopen and continue to edit and make slideshow? I want to thank anyone who can help me with this in advance as I
have gotten so frustrated that I want to just scream.
ThanksThanks for the help, thought I had done so but maybe not. Anyway will have another go at it, now may I ask another
question? I am trying to add audio to slideshow. I have some music I purchased thru amazon as mp3 files but I get
message no codec and when I try to add wmv I get same message. What type of file do I need and how can I add
multiple songs to one slideshow. I have one little wmv file that will go in, but it just replicates itself multiple times until
it fills slide show.
Thanks again, sorry to be a bother, but this thing is driving this old man crazy.
Date: Sun, 26 Dec 2010 20:34:32 -0700
From: [email protected]
To: [email protected]
Subject: Please help with slideshow problems!
You need to save the slideshow project in order to be able to go back later and make changes or additions to an existing slideshow . The wmv file is a final output format.
Now you are most probably using only the Output command: that is what makes the wmv file.
You should also do the Save Project command. (and I make it a practice to do the Save Project command before I do the Output command).
If you look at the Elements Organizer 8 Help, there is a topic on "Create a slide show".
-- Very close to the beginning of that topic is a screen shot of the Sldie Show Editor screen,
-- The bar below the usual menu bar is labeled with a "B" and called the Shortcuts bar.
-- The 1st entry on that Shortcuts bar is "Save Project"
It is the Save Project command that saves the information about which photos, audio, etc you placed in that specific slide show so that you can come back again to do subsequent editing. Save each Project with a unique name.
After completing the Save Project command, you shoud see an "icon" in the Organizer for that slide show.
Note: you must also keep the photo files and audio files which you have used in this slide show: you can't delete them because the project file does NOT contain a copy of the photos, it only has the identification and folder location of the photo and audio files.
> -
My "fn" button is stuck on only revealing mission control in Lion. With this problem none of my "f" keys will work nor can I hold "fn" and delete to delete text in opposite direction. Can someone please help with this?
Following the fix here worked for me:
https://discussions.apple.com/message/15680566#15680566
except my plist file was in ~/Library instead of /Library.
-Scott -
Hi, please help with the installation of Lightroom 4, I bought a new Mac (Apple) and I want to install a software that I have on the album cd. My new computer does not have the drives. Can I download software from Adobe? Is my license number just to be able to download the srtony adobe.
Adobe - Lightroom : For Macintosh
Hal -
[ETL]Could you please help with a problem accessing UML stereotype attributes ?
Hi all,
Could you please help with a problem accessing UML stereotype attributes and their values ?
Here is the description :
-I created a UML model with Papyrus tool and I applied MARTE profile to this UML model.
-Then, I applied <<PaStep>> stereotype to an AcceptEventAction ( which is one of the element that I created in this model ), and set the extOpDemand property of the stereotype to 2.7 with Papyrus.
-Now In the ETL file, I can find the stereotype property of extOpDemand as follows :
s.attribute.selectOne(a|a.name="extOpDemand") , where s is a variable of type Stereotype.
-However I can't access the value 2.7 of the extOpDemand attribute of the <<PaStep>> Stereotype. How do I do that ?
Please help
Thank youHi Dimitris,
Thank you , a minimal example is provided now.
Version of the Epsilon that I am using is : ( Epsilon Core 1.2.0.201408251031 org.eclipse.epsilon.core.feature.feature.group Eclipse.org)
Instructions for reproducing the problem :
1-Run the uml2etl.etl transformation with the supplied launch configuration.
2-Open lqn.model.
There are two folders inside MinimalExample folder, the one which is called MinimalExample has 4 files, model.uml , lqn.model, uml2lqn.etl and MinimalExampleTransformation.launch.
The other folder which is LQN has four files. (.project),LQN.emf,LQN.ecore and untitled.model which is an example model conforming to the LQN metamodel to see how the model looks like.
Thank you
Mana -
Want a complete migration guide to upgrade 11.1.0.7 to 11.2.0.3 database using DBUA..We are implementing R12.1.3 version and then have to migrate the default 11gR1 database to 11.2.0.3 version. Please help with some step by step docs
Upgrade to 11.2.0.3 -- Interoperability Notes Oracle EBS R12 with Oracle Database 11gR2 (11.2.0.3) (Doc ID 1585578.1)
Upgrade to 11.2.0.4 (latest 11gR2 patchset certified with R12) -- Interoperability Notes EBS 12.0 and 12.1 with Database 11gR2 (Doc ID 1058763.1)
Thanks,
Hussein
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