Position function query in XSLT

Question

I have a query regarding XSLT mapping
I have two E1EDK03 segments for the same qualifier. But I want the values based on posiotion
Example:
<E1EDK03 SEGMENT="1">
         <IDDAT>012</IDDAT>
         <DATUM>20110720</DATUM>
      </E1EDK03>
     <E1EDK03 SEGMENT="1">
         <IDDAT>012</IDDAT>
         <DATUM>20110905</DATUM>
      </E1EDK03>
If position = 1, I need the 1st set of E1EDK03
<E1EDK03 SEGMENT="1">
         <IDDAT>012</IDDAT>
         <DATUM>20110720</DATUM>
      </E1EDK03>
If position = 2, I need the 2nd set of E1EDK03
<E1EDK03 SEGMENT="1">
         <IDDAT>012</IDDAT>
         <DATUM>20110905</DATUM>
      </E1EDK03>
How to achieve that using XSLT
Thanks

Answer 1

Hi,
Since we have E1EDK03 with same qualifier 012, I don't have any other identifier to distinguish them, because at one instance I need 1st occurrence of E1EKD03 structure and another instance I need the 2nd occurrence of E1EDK03.
If you observe, only DATUM will have different values. I was trying to do that using position function
I have defined a variable to copy the segments and later trying to get the each segment based on position
<!--copying all the E1EDK03 qualifier 012 segments -->
        <xsl:variable name="e1edk03_qual_012">
               <xsl:for-each select="//IDOC/*">
                    <xsl:if test="starts-with(name(), 'E1EDK03') and IDDAT = '012'">
                         <xsl:copy-of select="."></xsl:copy-of>
                    </xsl:if>
               </xsl:for-each>
        </xsl:variable>          
Now the above code has
<E1EDK03 SEGMENT="1">
         <IDDAT>012</IDDAT>
         <DATUM>20110720</DATUM>
      </E1EDK03>
     <E1EDK03 SEGMENT="1">
         <IDDAT>012</IDDAT>
         <DATUM>20110905</DATUM>
      </E1EDK03>
I want to split these into two E1EDK03 segments and use further in the XSLT mapping and populate in the target
Thanks