Problem in Runtime.getRuntime().exec

Question

Hi,
I am trying to start the tomcat server through a java application.Before starting the server,i need to run a batch file for setting up some classpaths.I am able to run the batch file and start the server,but its opening the 2 windows.How do i suppress it?
One more problem is how do i stop the server?
Code is:
import java.io.*;
public class Test
public static void main(String args[]) {
try {
     Process p = Runtime.getRuntime().exec("cmd /c start C:\\soap.bat");     
     p.destroy();
     Process p1 = Runtime.getRuntime().exec("cmd /c start C:\\jakarta-tomcat-3.2.1\\bin\\startup");
     //p.waitFor();     
     Thread.sleep(10000);
     p1.destroy();     
BufferedReader br = new BufferedReader(new InputStreamReader(p.getInputStream()));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(p.getOutputStream()));
bw.write("1");
bw.flush();
String line;
while ((line = br.readLine()) != null) {
System.out.println(line);
br.close();
bw.close();
System.out.println(p.exitValue());
catch(Exception e) {
System.out.println(e);
I need the help as early as possible.
pls cc reply to:[email protected]
Thanks
Anitha

Answer 1

Soln. to your first prob:
1) To have the other DOS window closed, click on the extreme left-top corner of that window. In the menu that drops down ,select properties.In the properties window make sure the 'close on Exit' check Box is checked. Apply the changes.
2) To stop the server u need to call the shutdown.bat file in the tomcat\bin dir. If u want to do this thru java then call the shutdown.bat file from your Runtime.exec() method. Same as u did for the startup file
Hope this helps.