Problem with changing double to int!

Question

Hi guys. I've got a major headache trying to solve this problem, and I'm hoping maybe someone abit wiser than I could help me out.
I've added two lots of code, one where if I input 10 as the distance I get an answer of 423.529411..etc. However I want it to display this as just 423seconds. Then print on the next line 'to Travel 10 takes 0 hours, 7mins and 3 seconds. Instead it prints 0.1117etc hours and 7.0574738 minutes and 3.529etc seconds.
   public static double enterDistance()
         System.out.println("Type the travel distance: ");
         distance = UserInput.readDouble();
         if (distance < 0)
              System.out.println("Illegal Distance Value");
              distance = 0;
              enterRoadType();
              enterDistance();
         return distance;
    public static void calcTime()
         enterRoadType();
         time = enterDistance()/speed; // time in secs
         tottime = tottime + time; //total time in hours
         System.out.println("To travel " + distance + " takes " + (time*60*60) + " seconds");
          System.out.println("To travel " + distance +" takes " + time + " hours and " + (time*convert%convert) + " minutes and " + (time *convert*convert%convert) + " seconds");
          Totaltime = Totaltime + (time*convert*convert);
          Totaldistance = Totaldistance + distance;        
    }So to try and get it to do what I want, I change this line:
time = enterDistance()/speed; // time in secsto
time = (int)(enterDistance()/speed); // time in secsHowever then it prints that it takes 0 seconds, 0 hours, 0 mins.
Argh I'm so lost.
Any help is appreciated

Answer 1

I see you use (time*60*60) to display your seconds,
this means that time = enterDistance()/speed; // time in secs is actually wrong
So my guess is that you either or using wrong units for your speed or distance.
I think if you try time = (int)(60*60*enterDistance()/speed); you will not get 0 for your time but i would focus on why your seconds arent seconds first