Problem with my socket!!!!!

Question

Hi!!!!!!.
I need to print a "Hello Server" in the server. my code is this:
The server:
public static void main(String ar[])
ServerSocket s=null;
try
s=new ServerSocket(5432);
Socket s2=new Socket("localhost",5432);
while(true)
Socket s1=s.accept();
BufferedReader br=new BufferedReader(new InputStreamReader(s2.getInputStream()));
System.out.println(br.readLine());
br.close();
s1.close();
}catch(Exception e)
e.printStackTrace();
the client:
public static void main(String ar[])
try
Socket s1=new Socket("localhost",5432);
BufferedWriter bw=new BufferedWriter(new OutputStreamWriter(s1.getOutputStream()));
bw.write("Hello socket");
s1.close();
}catch(Exception e)
e.printStackTrace();
but only print the null value in the server. What happened with that?.
Thanks an sorry for my little english.
Greeting for Venezuela!!!!!!!!!!!!!.

Answer 1

Sorry!!!!!.
The real code is this:
public static void main(String ar[])
ServerSocket s=null;
try
s=new ServerSocket(5432);
while(true)
Socket s1=s.accept();
BufferedReader br=new BufferedReader(new InputStreamReader(s1.getInputStream()));
System.out.println(br.readLine());
br.close();
s1.close();
}catch(Exception e)
e.printStackTrace();
the client:
public static void main(String ar[])
try
Socket s1=new Socket("localhost",5432);
BufferedWriter bw=new BufferedWriter(new OutputStreamWriter(s1.getOutputStream()));
bw.write("Hello socket");
s1.close();
}catch(Exception e)
e.printStackTrace();
Thats code is wrong, what is the problem?.
Thanks!!!!