Problems creating partition

While creating a partition for Windows on my MacBook, a message popped up saying I had to restart my computer. This was before the partition was finished being created. After restarting, there was much less space available on my hard drive, but no other evidence of a partition. I started up Boot Camp Assistant again, and started over from the beginning as if I hadn't created the partition. What happened and how can I fix it?

Hello,
Just this past weekend I installed boot camp on my Leopard OS. My computer also kept shutting down on me, or it would give me a "verification failed: use disk utility to repair the disk and solve this problem." After some time of dealing with apple care, I was able to get some help "repairing my disk." These are the steps that they had me take: Number one - make sure that you have some free space on your hard drive - ie - they had me take off my itunes while creating the partition because they said that the less space available, the harder it is for the program to find, say, 10 gb of free space all in one spot. The next thing you may want to try is going to disk utility and selecting "verify disk permissions". Once that is done go back to disk utility and select "repair disk permissions". Once that is done - if you still can't create the partition, go back to disk utility and select merely "verify disk" and then again "repair disk permissions". If this still doesn't work, insert your mac os x installation disk 1 and use the top menu bar to go back to disk utility and select "repair disk." You probably won't be able to select repair disk without using your install cd. After doing that, I was still unable to create a partition, in which case they had me go into a sort of dos mode and force a repair on the hard disk - which is basically to say that despite asking (via disk utility) for the hard disk to be repaired, some things were being left out, and you have to command the computer to search for and repair any imperfections in the system. I say, if you get to that point and you have to go into the dos mode - call support and tell them that is what you want to do. Once they had me force the repair a few times it eventually came up with a message similar to "there is nothing left to repair on this disk, the volume is OK." After that, I was able to partition and install windows. I hope this helps!

Similar Messages

Problem : Creating partition is really slow

I have a problem creating partitions between two applications, using Essbase 9.3.1
PartA is on [server]:1423 and contains data
PartB is on [server]:2423 and is empty
They both have the same outline (PartB is a "save as" of PartA)
When I try to create the partition, I got no error but the process is really long (I started it 30 minutes ago and still not finished...)
If I do it on two applications within the same port number (my first test was on 1423), it works fine and takes about 10 seconds to create.
I don't know what's the problem. Any ideas ?
Thanks

Download an EtreCheck report:
http://www.etresoft.com/etrecheck
That will provide some basic information about your MBP and is a good place to start finding your problem.
Ciao.

Error while creating partition table

Hi frnds i am getting error while i am trying to create a partition table using range
getting error ORA-00906: missing left parenthesis.I used the following statement to create partition table
CREATE TABLE SAMPLE_ORDERS
(ORDER_NUMBER NUMBER,
ORDER_DATE DATE,
CUST_NUM NUMBER,
TOTAL_PRICE NUMBER,
TOTAL_TAX NUMBER,
TOTAL_SHIPPING NUMBER)
PARTITION BY RANGE(ORDER_DATE)
PARTITION SO99Q1 VALUES LESS THAN TO_DATE(‘01-APR-1999’, ‘DD-MON-YYYY’),
PARTITION SO99Q2 VALUES LESS THAN TO_DATE(‘01-JUL-1999’, ‘DD-MON-YYYY’),
PARTITION SO99Q3 VALUES LESS THAN TO_DATE(‘01-OCT-1999’, ‘DD-MON-YYYY’),
PARTITION SO99Q4 VALUES LESS THAN TO_DATE(‘01-JAN-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q1 VALUES LESS THAN TO_DATE(‘01-APR-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q2 VALUES LESS THAN TO_DATE(‘01-JUL-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q3 VALUES LESS THAN TO_DATE(‘01-OCT-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q4 VALUES LESS THAN TO_DATE(‘01-JAN-2001’, ‘DD-MON-YYYY’)
;

More than one of them. Try this instead:
CREATE TABLE SAMPLE_ORDERS
(ORDER_NUMBER NUMBER,
ORDER_DATE DATE,
CUST_NUM NUMBER,
TOTAL_PRICE NUMBER,
TOTAL_TAX NUMBER,
TOTAL_SHIPPING NUMBER)
PARTITION BY RANGE(ORDER_DATE) (
PARTITION SO99Q1 VALUES LESS THAN (TO_DATE('01-APR-1999', 'DD-MON-YYYY')),
PARTITION SO99Q2 VALUES LESS THAN (TO_DATE('01-JUL-1999', 'DD-MON-YYYY')),
PARTITION SO99Q3 VALUES LESS THAN (TO_DATE('01-OCT-1999', 'DD-MON-YYYY')),
PARTITION SO99Q4 VALUES LESS THAN (TO_DATE('01-JAN-2000', 'DD-MON-YYYY')),
PARTITION SO00Q1 VALUES LESS THAN (TO_DATE('01-APR-2000', 'DD-MON-YYYY')),
PARTITION SO00Q2 VALUES LESS THAN (TO_DATE('01-JUL-2000', 'DD-MON-YYYY')),
PARTITION SO00Q3 VALUES LESS THAN (TO_DATE('01-OCT-2000', 'DD-MON-YYYY')),
PARTITION SO00Q4 VALUES LESS THAN (TO_DATE('01-JAN-2001', 'DD-MON-YYYY')))In the future, if you are having problems, go to Morgan's Library at www.psoug.org.
Find a working demo, copy it, then modify it for your purposes.

Logical standby stopped when trying to create partitions on primary(Urgent

RDBMS Version: 10.2.0.3
Operating System and Version: Solaris 5.9
Error Number (if applicable): ORA-1119
Product (i.e. SQL*Loader, Import, etc.): Data Guard on RAC
Product Version: 10.2.0.3
logical standby stopped when trying to create partitions on primary(Urgent)
Primary is a 2node RAC ON ASM, we implemented partitions on primar.
Logical standby stopped appling logs.
Below is the alert.log for logical stdby:
Current log# 4 seq# 860 mem# 0: +RT06_DATA/rt06/onlinelog/group_4.477.635601281
Current log# 4 seq# 860 mem# 1: +RECO/rt06/onlinelog/group_4.280.635601287
Fri Oct 19 10:41:34 2007
create tablespace INVACC200740 logging datafile '+OT06_DATA' size 10M AUTOEXTEND ON NEXT 5M MAXSIZE 1000M EXTENT MANAGEMENT LOCAL
Fri Oct 19 10:41:34 2007
ORA-1119 signalled during: create tablespace INVACC200740 logging datafile '+OT06_DATA' size 10M AUTOEXTEND ON NEXT 5M MAXSIZE 1000M EXTENT MANAGEMENT LOCAL...
LOGSTDBY status: ORA-01119: error in creating database file '+OT06_DATA'
ORA-17502: ksfdcre:4 Failed to create file +OT06_DATA
ORA-15001: diskgroup "OT06_DATA" does not exist or is not mounted
ORA-15001: diskgroup "OT06_DATA" does not exist or is not mounted
LOGSTDBY Apply process P004 pid=49 OS id=16403 stopped
Fri Oct 19 10:41:34 2007
Errors in file /u01/app/oracle/admin/RT06/bdump/rt06_lsp0_16387.trc:
ORA-12801: error signaled in parallel query server P004
ORA-01119: error in creating database file '+OT06_DATA'
ORA-17502: ksfdcre:4 Failed to create file +OT06_DATA
ORA-15001: diskgroup "OT06_DATA" does not exist or is not mounted
ORA-15001: diskgroup "OT06_DATA" does not exist or
Here is the trace file info:
/u01/app/oracle/admin/RT06/bdump/rt06_lsp0_16387.trc
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64bit Production
With the Partitioning, OLAP and Data Mining options
ORACLE_HOME = /u01/app/oracle/product/10.2.0
System name: SunOS
Node name: iscsv341.newbreed.com
Release: 5.9
Version: Generic_118558-28
Machine: sun4u
Instance name: RT06
Redo thread mounted by this instance: 1
Oracle process number: 16
Unix process pid: 16387, image: [email protected] (LSP0)
*** 2007-10-19 10:41:34.804
*** SERVICE NAME:(SYS$BACKGROUND) 2007-10-19 10:41:34.802
*** SESSION ID:(1614.205) 2007-10-19 10:41:34.802
knahcapplymain: encountered error=12801
*** 2007-10-19 10:41:34.804
ksedmp: internal or fatal error
ORA-12801: error signaled in parallel query server P004
ORA-01119: error in creating database file '+OT06_DATA'
ORA-17502: ksfdcre:4 Failed to create file +OT06_DATA
ORA-15001: diskgroup "OT06_DATA" does not exist or is not mounted
ORA-15001: diskgroup "OT06_DATA" does not exist or
KNACDMP: *******************************************************
KNACDMP: Dumping apply coordinator's context at 7fffd9e8
KNACDMP: Apply Engine # 0
KNACDMP: Apply Engine name
KNACDMP: Coordinator's Watermarks ------------------------------
KNACDMP: Apply High Watermark = 0x0000.0132b0bc
Sorry our primary database file structure is different from stdby, we used db_file_name_convert in the init.ora, it look like this:
*.db_file_multiblock_read_count=16
*.db_file_name_convert='+OT06_DATA/OT06TSG001/','+RT06_DATA/RT06/','+RECO/OT06TSG001','+RECO/RT06'
*.db_files=2000
*.db_name='OT06'
*.db_recovery_file_dest='+RECO'
Is there any thing wrong in this parameter.
I tried this parameter before for cloning using rman backup. This din't work.
What exactly must be done? for db_file_name_convert to work.
Even in this case i think this is the problem its not converting the location and the logical halts.
help me out.....
let me know if you have any questions.
Thanks Regards
Raghavendra rao Yella.

Hi reega,
Thanks for your reply, our logical stdby has '+RT06_DATA/RT06'
and primary has '+OT06_DATA/OT06TSG001'
so we are using db_file_name_convert init parameter but it doesn't work.
Is there any thing particular steps hiding to use this parameter? as i tried this parameter for rman cloning it din't work, as a workaround i used rman set new name command for clonning.
Let me know if you have any questions.
Thanks in advance.

Problem defining partition for storing value 0 with new data

Hi forumers,
I've a problem with partitioning and need some advices.
I've a table that will be partitioned by column Process_N which have values from 0 to 50000:
Process_N between 1 and 29999 represents old data;
Process_N >= 30000 represents new data;
Process_N = 0 means the row is not processed yet and so these value represents new data too.
Can I have a partition for old values (from 1 to 29999) and another partition to store new values (0 + values >= 30000) ? Hou can I define that ?
Thank you in advance.
Best Regards,
Helena

Helena,
What's your oracle version? I think it will be better to create 3 partitions usign RANGE partitions (< 1, 2-29999, >=30000 <=50000). Is there a specific reason you want to include 0 and values greater than 29000 in one partition? What the significant difference between 0 and 30000 specially as both represent new data?
CREATE TABLE my_part_table (
   process_n NUMBER NULL,
   my_data VARCHAR2 (1 BYTE) NULL,
   my_other_data VARCHAR2 (30 BYTE) NULL,
   data_state NUMBER NULL
TABLESPACE test_data
PARTITION BY RANGE (process_n)
   (PARTITION partition_0
       VALUES LESS THAN (1)
       TABLESPACE test_data,
   PARTITION partition_2_29999
      VALUES LESS THAN (30000)
      TABLESPACE test_data,
   PARTITION partition_30000
      VALUES LESS THAN (50001)
      TABLESPACE test_data);Regards

Storage clause of create partition based on last storage value

Hello,
could you give some advice how could i resolve this problem ?
I have procedure which is executed by job every day, once a day, and what it does, it automaticly add new partitions on one table.
I am now strugling with how to construct statement that will place every new partition in new tablespaces.
I created 8 tablespaces named data1..data8 and for this purpose, so now i am trying to understand how can i perform check in what tablespace was last partition placed and based on that, add new partition in first next tablespace. For example, last was created in data8 tablespace, so next must be created in data1 tablespace.
How can i check that ? Anyone have some suggestions ?
I am currently going with this logic :
select tablespace_name from
(select * from user_tab_partitions where table_name='partitioned_table' order by partition_name desc)
where rownum < 2 )And with this i get the name of the last used tablespace for the last created partition, but i currently don't know how to use this info further.
Deos someone have some other idea about this ?
Edited by: user11141123 on May 7, 2009 4:01 AM
Edited by: user11141123 on May 7, 2009 4:16 AM

Yes Sean,
i would like this to do bacuse of the tablespace that are created for that purpose, for that partitioned table.
For some reason, they must be used, and by the current logic where that procedure adds new partiotions with default storage option, they can't be used
and all partitions are created in one other tablespace named data.
This is situation on production, and i created similiar test environment.
data tablespace in production will in few days propably be full and intention is to start create new partitions in this way , in those new 8 tablespaces and in some time tottaly leave current and only used tablespace and that is data tablespace.
So i would like to somehow implement storage clause on already fully functional
alter table add partition
statement inside that procedure.
Is there some way for that ? That i use that qury i wrote above , and by using that value add on existing statement for create partition storage clause with next in line tablespace ?

Problems with partition tables

Hi all,
I've got some problems with partition tables. The script at the bottom run but when I wanna insert some values it returns me an error
(ORA-06550: line 1, column 30: PL/SQL: ORA-06552: PL/SQL: Compilation unit analysis terminated
ORA-06553: PLS-320: the declaration of the type of this expression is incomplete or malformed
ORA-06550: line 1, column 7: PL/SQL: SQL Statement ignored)
and I can't understand why!
There's something incorrect in the script or not?
Please help me
Thanks in advance
Steve
CREATE TABLE TW_E_CUSTOMER_UNIFIED
ID_CUSTOMER_UNIFIED VARCHAR2 (27) NOT NULL ,
START_VALIDITY_DATE DATE NOT NULL ,
END_VALIDITY_DATE DATE ,
CUSTOMER_STATUS VARCHAR2 (255)
PARTITION BY RANGE (START_VALIDITY_DATE)
SUBPARTITION BY LIST (END_VALIDITY_DATE)
PARTITION M200909 VALUES LESS THAN (TO_DATE('20091001','YYYYMMDD'))
(SUBPARTITION M200909_N VALUES (NULL), SUBPARTITION M200909_NN VALUES (DEFAULT)),
PARTITION M200910 VALUES LESS THAN (TO_DATE('20091101','YYYYMMDD'))
(SUBPARTITION M200910_N VALUES (NULL), SUBPARTITION M200910_NN VALUES (DEFAULT)),
PARTITION M200911 VALUES LESS THAN (TO_DATE('20091201','YYYYMMDD'))
(SUBPARTITION M200911_N VALUES (NULL), SUBPARTITION M200911_NN VALUES (DEFAULT)),
PARTITION M200912 VALUES LESS THAN (TO_DATE('20100101','YYYYMMDD'))
(SUBPARTITION M200912_N VALUES (NULL), SUBPARTITION M200912_NN VALUES (DEFAULT)),
PARTITION M201001 VALUES LESS THAN (TO_DATE('20100201','YYYYMMDD'))
(SUBPARTITION M201001_N VALUES (NULL), SUBPARTITION M201001_NN VALUES (DEFAULT)),
PARTITION M201002 VALUES LESS THAN (TO_DATE('20100301','YYYYMMDD'))
(SUBPARTITION M201002_N VALUES (NULL), SUBPARTITION M201002_NN VALUES (DEFAULT)),
PARTITION M210001 VALUES LESS THAN (MAXVALUE))
(SUBPARTITION M210001_N VALUES (NULL), SUBPARTITION M210001_NN VALUES (DEFAULT))
;

Hi Hoek,
the DB version is 10.2 (italian version, then SET is correct).
...there's something strange: now I can INSERT rows but I can't update them!
I'm using this command string:
UPDATE TW_E_CUSTOMER_UNIFIED SET END_VALIDITY_DATE = TO_DATE('09-SET-09', 'DD-MON-RR') WHERE
id_customer_unified = '123' and start_validity_date = TO_DATE('09-SET-09', 'DD-MON-RR');
And this is the error:
Error SQL: ORA-14402: updating partition key column would cause a partition change
14402. 00000 - "updating partition key column would cause a partition change"
*Cause: An UPDATE statement attempted to change the value of a partition
key column causing migration of the row to another partition
*Action: Do not attempt to update a partition key column or make sure that
the new partition key is within the range containing the old
partition key.
I think that is impossible to use a PARTITION/SUBPARTITION like that: in fact the update of "END_VALIDITY_DATE" cause a partition change.
Do u agree or it's possible an update on a field that implies a partition change?
Regards Steve

Problems with Partition pruning using LIST option in 9i

I am declaring the following partitions on a fact table and when
I do an explain plan on the following SELECT statements it is
doing a full table scan on the fact table. However if I use
the "PARTITION" statement in the FROM clause it picks up the
correct partition and runs great. I have used the analyze
command and dbms_utility.analyze_schema command on all tables
and indexes. I had simaliar problems when partitioning with the
RANGE options too. I have looked through all of the INIT file
parameters and don't see anything obvious. Is there something I
am missing?
Any help would be appreciated!
Thanks,
Bryan
Facttable create statement....
CREATE TABLE FactTable (
ProductGID INTEGER NULL,
CustomerGID INTEGER NULL,
OrganizationGID INTEGER NULL,
TimeGID INTEGER NULL,
FactValue NUMBER NOT NULL,
ModDate DATE NULL,
CombinedGID INTEGER NOT NULL)
PARTITION BY LIST (CombinedGID)
(PARTITION sales1 VALUES(9999101),
PARTITION sales2 VALUES(9999102),
PARTITION sales3 VALUES(9999103),
PARTITION model1 VALUES(9999204),
PARTITION model2 VALUES(9999205),
PARTITION model3 VALUES(9999206));
Select statement....that is causing a full table scan.....the
*tc tables are the equivelent to dimension tables in a star
schema.
SELECT tco.parentgid, tcc.parentgid, tcp.parentgid, sum
(factvalue)
FROM facttable f, custtc tcc, timetc tct, prodtc tcp, orgtc tco
WHERE
tco.childgid = f.organizationgid
AND tco.parentgid = 18262
AND tcc.childgid = f.customergid
AND tcc.parentmembertypegid = 16
AND tcp.childgid = f.productgid
AND tcp.parentmembertypegid = 7
AND tct.childgid = f.timegid
AND tct.parentgid = 1009
GROUP BY tco.parentgid, tcc.parentgid, tcp.parentgid;
Select statement that works great....
SELECT tco.parentgid, tcc.parentgid, tcp.parentgid, sum
(factvalue)
FROM facttable partition(sales1) f, custtc tcc, timetc tct,
prodtc tcp, orgtc tco
WHERE
tco.childgid = f.organizationgid
AND tco.parentgid = 18262
AND tcc.childgid = f.customergid
AND tcc.parentmembertypegid = 16
AND tcp.childgid = f.productgid
AND tcp.parentmembertypegid = 7
AND tct.childgid = f.timegid
AND tct.parentgid = 1009
GROUP BY tco.parentgid, tcc.parentgid, tcp.parentgid;

Hi Hoek,
the DB version is 10.2 (italian version, then SET is correct).
...there's something strange: now I can INSERT rows but I can't update them!
I'm using this command string:
UPDATE TW_E_CUSTOMER_UNIFIED SET END_VALIDITY_DATE = TO_DATE('09-SET-09', 'DD-MON-RR') WHERE
id_customer_unified = '123' and start_validity_date = TO_DATE('09-SET-09', 'DD-MON-RR');
And this is the error:
Error SQL: ORA-14402: updating partition key column would cause a partition change
14402. 00000 - "updating partition key column would cause a partition change"
*Cause: An UPDATE statement attempted to change the value of a partition
key column causing migration of the row to another partition
*Action: Do not attempt to update a partition key column or make sure that
the new partition key is within the range containing the old
partition key.
I think that is impossible to use a PARTITION/SUBPARTITION like that: in fact the update of "END_VALIDITY_DATE" cause a partition change.
Do u agree or it's possible an update on a field that implies a partition change?
Regards Steve

How to create partition in c drive in window7

hi,
I have HP pavilion dv6-Windows 7 home basic 64-bit , ofter recovery we have create partition in C drive but can't farmate. there is shown the facility avail in selected disks.
What, i do?
Mohan Singh

Hi,
Please use "Disk Management" to check first. Depending how many partitions are there, it is not recommenced to have more than 4 partitions on a physical disk.
Please use this tutorial to perform other tasks if you wish:
http://pcsupport.about.com/od/windows7/ht/disk-management-windows-7.htm
Regards.
BH
**Click the KUDOS thumb up on the left to say 'Thanks'**
Make it easier for other people to find solutions by marking a Reply 'Accept as Solution' if it solves your problem.

XMLA Create Partition Limit

Hello,
I'am trying to make SSIS package that will dynamically create cube partitions. First, I create XMLA Create script with SQL query and then I give this XMLA script to "Analysis Services Execute DDL Task".
Problem:
If I have more than 5 partition in XMLA script I got error after execution "Analysis Services Execute DDL Task".
Do someone know any limitations when creating more than 5 partition in one XMLA batch?
How can I solve this problem?
I'am using SSDT 2010.
Thx!

Hi,
I create XMLA script with sql procedure. When I execute that scrpit in SSMS Analysis Services XMLA query everything works just fine. There is no limit home much I can create cube partition in XMLA batch script. But when I give this script to "Analysis
Services Execute DDL Task" in SSIS I got error if the is more then 5 "create partition" script within one XMLA batch.
I do not know why this is happening? I can process 10 or more partition but I can create only 5 in one batch.
I don't won't use AMO to create partitions. The simplest solution is to create XMLA script in SP and execute that script in "Analysis
Services Execute DDL Task".
Where is the problem, how can I solve this?
Can you post whats exact error message you get?
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

Unable to Create Partitioned Table

Hi All,
I was trying to create a partitioned table using following
Create table customers (custcode number(5),
Name varchar2(20),
Addr varchar2(10),
City varchar2(20),
Bal number(10,2))
Partition by list (city),
Partition north_India values (‘DELHI’,’CHANDIGARH’),
Partition east_India values (‘KOLKOTA’,’PATNA’),
Partition south_India values (‘HYDERABAD’,’BANGALORE’,’CHENNAI’),
Partition west India values (‘BOMBAY’,’GOA’);
It is throwing me an error
ORA-00922: missing or invalid option
Will you please tell me what is wrong with this query? Is it possible to create partitioned table using select statement (create table as select... Partition by...)?
Regards
~Pravin

Pravin
Will you please tell me what is wrong with this query?I see 4 errors in the syntax. Therefore, I strongly suggest you to have a lock to this:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/statements_7002.htm#i2146309
In addition, have a look to the error message. If I run your script in SQL*Plus it clearly shows where the problem is. E.g.:
SQL> Create table customers (custcode number(5),
2 Name varchar2(20),
3 Addr varchar2(10),
4 City varchar2(20),
5 Bal number(10,2))
6 Partition by list (city),
7 Partition north_India values (‘DELHI’,’CHANDIGARH’),
8 Partition east_India values (‘KOLKOTA’,’PATNA’),
9 Partition south_India values (‘HYDERABAD’,’BANGALORE’,’CHENNAI’),
10 Partition west India values (‘BOMBAY’,’GOA’);
Partition by list (city),
ERROR at line 6:
ORA-00922: missing or invalid option
Is it possible to create partitioned table using select statement?Yes. With the usual syntax.
HTH
Chris Antognini
Author of Troubleshooting Oracle Performance, Apress 2008 (http://top.antognini.ch)

Stuck on Creating Partition Map

I was using the Install disk....the disk utility.....to erase my hard drive and now it is stuck on "Creating Partition Map". What do it do?
I am giving this i-Mac away so I want to make sure the disk is erased. Was it?

No, it sounds like there's been a problem. Do the following:
Extended Hard Drive Preparation
1. Boot from your OS X Installer Disc. After the installer loads select your language and click on the Continue button. When the menu bar appears select Disk Utility from the Installer menu (Utilities menu for Tiger or Leopard.)
2. After DU loads select your hard drive (this is the entry with the mfgr.'s ID and size) from the left side list. Note the SMART status of the drive in DU's status area. If it does not say "Verified" then the drive is failing or has failed and will need replacing. SMART info will not be reported on external drives. Otherwise, click on the Partition tab in the DU main window.
3. Under the Volume Scheme heading set the number of partitions from the drop down menu to one. Set the format type to Mac OS Extended (Journaled.) Click on the Options button, set the partition scheme to GUID (for Intel Macs) or APM (for PPC Macs) then click on the OK button. Click on the Partition button and wait until the process has completed.
4. Select the volume you just created (this is the sub-entry under the drive entry) from the left side list. Click on the Erase tab in the DU main window.
5. Set the format type to Mac OS Extended (Journaled.) Click on the Options button, check the button for Zero Data and click on OK to return to the Erase window.
6. Click on the Erase button. The format process can take up to several hours depending upon the drive size.

Problem Creating Hyperlink to another workbook

I am having a problem creating a hyperlink to a worksheet in another workbook.
Here is what I have done:
Created the master and detail reports in 2 different workbooks.
Executed the master worksheet to display the data
Right clicked the field in the first row where I want to create the hyperlink, and chose Manage Links
Clicked the New Link button
Chose Worksheet for Where do you want to link to?
Clicked Browse by the Destination Worksheet
Clicked the detail report from the list of workbooks but the select button is grayed out
Does anyone have any idea why it won't let me select the detail report to link to?
I have OracleBI Discoverer Plus 10g
Any suggestions would be deeply appreciated.

Yes, I did add a parameter to the detail report so that I could get detail just for that one item. The part that is giving me trouble is specifying the Destination workbook/worksheet. I see the detail report when I browse but the Select button is grayed out so I haven't made it to the part where you identify what values to pass to the detail report yet.

I'm exhausted of trying to find a solution to a problem created by Apple. I have moved to iCloud, following your instructions and now I can not use my mobileme e-mail address. How can I contact directly with Apple, not just an automatic reply phone number

I'm exhausted of trying to find a solution to a problem created by Apple. I have moved to icloud following all your instructions and now I can not use my mobile me e-mail address. I can not activate icloud because when I put my e-mail address it answers that somebody is already using my address. I have my old e-mails, but I can not receive any e-mail or send them.
I have contacted Apple Technical Support in Spain and I was sent an e-mail saying that I have to call a phone number and when I call it is always an answering machine who answers that says that I have to pay 50€ for a consultation or wait for 10 minutes. When I have made the consultation it was never mentioned that I have to pay 50€ for a phone consultation. If I don't want to wait I have to pay for the Apple Tecnical Support which cost 250 €, this was not mentioned in the technical support page.
Can somebody let me know how can I contact Apple in another way in order to talk with a human being or chat directly? I was very happy just using my mobileme e-mails, I didn't need any clouds and I was force by Apple to registered if I want to continue using my mobileme e-mail address.

Sandra,
See this Apple support document for information on reporting an issue with your iTunes purchase.
http://support.apple.com/kb/HT1933
B-rock

I would like to create a playlist of some of my voicememos to hear on my iphone5. I have no problem creating the list and can listen on playlist on computer but not when i sync to my phone. How can I listen to voicememos in a playlist on my iPhone?

I would like to create a playlist of some of my voicememos to hear on my iphone5. I have no problem creating the list and can listen on playlist on computer but not when i sync to my phone. How can I listen to voicememos in a playlist on my iPhone?

Hi czigrand,
Thanks for visiting Apple Support Communities.
Currently, you can gift dollar amounts or individual items (EG. songs) on the iTunes Store. See this article for more information:
In the iTunes Store, you can gift a dollar amount or specific music, movies, TV shows, or apps from your iPhone, iPod touch, iPad, Mac, or PC. Follow these steps to send a gift from the iTunes Store.
iTunes: Sending iTunes Gifts
http://support.apple.com/kb/HT2736
Best Regards,
Jeremy

Problems creating partition

Similar Messages

Maybe you are looking for