Provider Key!

When i try to create a new provider (samples examples) i've got the error;
Error: An error occurred when attempting to call the providers register function. (WWC-43134)
An unexpected error occurred: ORA-29532: Java call terminated by uncaught Java exception: java.io.EOFException: Premature EOF encountered (WWC-43000)
An unexpected error occurred: java.io.EOFException: Premature EOF encountered
at HTTPClient.StreamDemultiplexor.read(StreamDemultiplexor.java:246)
at HTTPClient.RespInputStream.read(RespInputStream.java:138)
at HTTPClient.RespInputStream.read(RespInputStream.java:95)
at HTTPClient.Response.readResponseHeaders(Response.java:914)
at HTTPClient.Response.getHeaders(Response.java:627)
at HTTPClient.Response.getStatusCode(Response.java:232)
at HTTPClient.RetryModule.responsePhase1Handler(RetryModule.java:80)
at HTTPClient.HTTPResponse.handleResponse(HTTPResponse.java:623)
at HTTPClient.HTTPResponse.getStatusCode(HTTPResponse.java:179)
at oracle.webdb.provider.web.HttpProviderDispatcher.dispatch(HttpProviderDispatcher.java:762)
at oracle.webdb.provider.web.HttpProviderDispatcher.registerProvider(HttpProviderDispatcher.java:251)
(WWC-43000)"
The problem is "Provider Key" parameter (i supose); what value do i have to write to create a new provider
thank's
null

Please provide additional information to solve problem in registering new provider.
1) Check correctness of provider.xml , by typing http://myserver.mydomain.com:port/servlets/<provider_name>(replace this with your URL) in web browser
This should display Test Page with provider_name.
2) give details of urlservices.jar version you are using ?
3) can you give jserv.log and provider.xml
Sample are available at http://portalstudio.oracle.com/pls/ops/docs/FOLDER/COMMUNITY/PDK/URLSERVICES/URL.SUBSCRIBER.README.HTML
null

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Edited by: Eric Brunelle on Feb 8, 2010 7:53 AM

> I am installing ecc6.0 on windows 2003 platfrom with 10g oracle database. I have problem providing solution manager key during installtion in the window.
>
> my db hostname is : deleted
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2.

Exception "algorithm ARC4 is not available from Provider Cryptix "

hi all
i am developing the application in which i am using two encryption/decryption algorithms one is "RC4" and second is "AES(256 bit key)".
1.first i am taking the credit card number from database which is in
the encrypted format using 'RC4".
2.After taking the Credit card number from database i am decrypting them using RC4.
3. After decrypting them i am encrypting them using "AES(256 bit key") and putting the paymentid and encrypted credit card number in HashMap.
For that i have written following classes
RC4EncMemory.java ( which is taking encrypted credit card number from database ,decrypting them using "RC4" and then encrypting them using "AES")
import java.security.GeneralSecurityException;
import java.security.Security;
import java.sql.*;
import java.util.*;
import java.util.HashMap;
import javax.crypto.SecretKey;
import cryptix.jce.provider.key.RawSecretKey;
import cryptix.provider.Cryptix;
public class RC4EncMemory
     DbAccess db=null;
     RC4EncMemory crypt=null;
     PreparedStatement pstmt=null;
     ResultSet rs=null;
     EncryptionPerformance per=null;
     AESEccryption aes=null;
     private String originalCCnumber=null;
     private int paymantid;
     private byte[] b;
     private byte[] aesencrypted;
     public RC4EncMemory()
     {db=new DbAccess();}
     public void selectAllCCNumber()
          HashMap allccnumber=new HashMap(1000);
          String qry =DbAccess.getPropertyValue("cedera.ccnumber.selectccnumberFromPayment");
          System.out.println(qry);
          try
          {rs=db.getResultSet(qry);
          if(rs!=null)
          {     crypt=getInstance();
               while(rs.next())
                    System.out.println("In while");
                    paymantid=rs.getInt("paymentid");
                    b=rs.getBytes("ccnumber");
                    System.out.println("paymantid >>> " + paymantid);
                    originalCCnumber=DecryptCCNumber(b);
                    Security.removeProvider("RC4");
                    System.out.println("decrypted original >>> " + originalCCnumber);
                    aesencrypted=getAESEncryption(originalCCnumber);
                    //allccnumber.put(new Integer(paymantid),new String(originalCCnumber));
               Set key=allccnumber.keySet();
               Iterator i=key.iterator();
               while(i.hasNext())
               {System.out.println(" Payment id from HashMap " +(Integer)i.next());
               System.out.println("Size of the HashMap: >>" + allccnumber.size());
          else
               System.out.println("empty");
          allccnumber.clear();
          }catch(SQLException exp)
                         System.out.println("Exception in SQL" + exp);
                    finally
                         try{          rs.close();
                                   pstmt.close();
                                   db.conn.close();
                         }catch(Exception er){}
     public String DecryptCCNumber(byte[] encryptedCCNumber)
          {     String decrypted=null;
               if(encryptedCCNumber!=null)
               {decrypted = decrypt(encryptedCCNumber);
               return decrypted;
     public String decrypt(byte data[])
          if(data == null || data.length == 0)
          return null;
          try
               xjava.security.Cipher cipher = xjava.security.Cipher.getInstance("RC4", "Cryptix");
               cipher.initDecrypt(rsaKey);
               byte out[] = cipher.crypt(data);
               return new String(out);
          catch(GeneralSecurityException se)
          { System.out.println("SecurityException in decrypt method: " + se);
          return null;
     public static synchronized RC4EncMemory getInstance()
          if(_rc4decryption == null)
               Security.addProvider(new Cryptix());
               _rc4decryption = new RC4EncMemory();
               makeRC4Key();
          return _rc4decryption;
private static void makeRC4Key()
{          String seed = "CvMjSpVrGsTnAj";
          rsaKey = new RawSecretKey("RC4", seed.getBytes());
public byte[] getAESEncryption(String originalCCNumber)
{     aes=AESEccryption.getInstance();
     return aes.encrypt(originalCCNumber);
public static void main(String args[])
     RC4EncMemory mem1=new RC4EncMemory();
     mem1.selectAllCCNumber();
     private static SecretKey rsaKey = null;
     private static RC4EncMemory _rc4decryption = null;
In the above programs i am getting the output as follows
output:-
in while
paymantid >>> 3338157
decrypted original >>> 5856373015065936
inside encrypt method
Original Data----->5856373015065936
Encrypted Data----->[B@3cc0bc
after encryption of data
In while
paymantid >>> 3338169
SecurityException in decrypt method: java.security.NoSuchAlgorithmException: algorithm ARC4 is not available from provider Cryptix
decrypted original >>> null
In while
paymantid >>> 3338290
SecurityException in decrypt method: java.security.NoSuchAlgorithmException: algorithm ARC4 is not available from provider Cryptix
decrypted original >>> null
my program is able to decrypt the only first credit card numbers using RC4 and then encrypt it using AES(as shown in bold above) but it is not able decrypt the rest of the credit card number from the database using "RC4" and it is throwing above exception regarding the "RC4" algorithm .
can anybody tell me what is reason behind this exception? my guess is the we cann't use the two providers simultaneously.
please anybody help me
AESEccryption.java(which helps to encrypt the credit card number in AES using encrypt method )
import java.security.GeneralSecurityException;
import java.security.Security;
import java.sql.*;
import javax.crypto.spec.SecretKeySpec;
import org.bouncycastle.jce.provider.BouncyCastleProvider;
import cryptix.provider.Cryptix;
public class AESEccryption
     AESEccryption cryptAES=null;
     AESEccryption cryptAES1=null;
     public AESEccryption(){}
     public static synchronized AESEccryption getInstance()
          {     if(_aesEncryption == null)
                    Security.insertProviderAt(new BouncyCastleProvider(),3);
                    //Security.addProvider(new BouncyCastleProvider());
                    //Security.addProvider(new Cryptix());
                    _aesEncryption = new AESEccryption();
                    makeAESKey();
               return _aesEncryption;
     private static void makeAESKey()
               String seed = "FFF3454D1E9CCDE00101010101010101";
               int length=seed.length();
               if(length!=32)
               {     System.out.println("Key size must be 32 characters only");
                    System.exit(0);
               skeySpec = new SecretKeySpec(seed.getBytes(),0,32,"AES");
public byte[] encrypt(String data)
     {     if(data == null)
          return null;
          try
          {     System.out.println("inside encrypt method");
               javax.crypto.Cipher cipher = javax.crypto.Cipher.getInstance("AES");
               cipher.init(javax.crypto.Cipher.ENCRYPT_MODE,skeySpec);
               byte out[] = cipher.doFinal(data.getBytes());
               return out;
          catch(GeneralSecurityException se)
               System.out.println("SecurityException: " + se);
          return null;
     public static void main(String args[])throws Exception
     {     AESEccryption aesenc=new AESEccryption();
          aesenc.selectAllCCNumber();
          if(flag)
               System.out.println("Flag " + flag);
     private static SecretKeySpec skeySpec = null;
     private static AESEccryption _aesEncryption = null;
Regards
Pandurang
Message was edited by:
andylimp12
Message was edited by:
andylimp12
Message was edited by:
andylimp12

Hi Nith,
Previously I have changed the document dispostal time out to 1 year but the error still occurs.
Now I change the document inline size from 64 KB to 27 MB (estimated max document size) and see how the LCES behaves.
I suspect if document size is larger than document inline size then LCES will write to some temp file. After that, user does not process the task for a long time, e.g. 3 days. And during the 3 days, the unix system/ websphere auto clear the temp file. After 3 days when user accesses the task again, LCES will complain "document is not in sending server side any more" ....
I refer to : http://blogs.adobe.com/livecycle/2008/10/livecycle_tuning_knob_default.html
For the Document sweep interval, I think, it relates Watch Folder, not this error so I don't change it.
Regards,
Anh

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Title: Excuse the interruption, but...
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<serial number here>
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Does composite primary key in BMP really work?

Here's a issue. I have a bean called CalendarEvent which uses name, startTime and endTime in composite fashion for primary key. I have a primary key class defined as well. Now I have a ejbFindByUser method which takes in a name and creates a collection of primary key class objects. THis happens properly. But when the client invokes findByUser it gets a collection of SIMILAR items. Its like only the last primary key object that was added into the collection by ejbFindByUser was translated by the server and the corresponding entity bean returned to the client.
Please help, this thing is killing me!!!

Thanks a ton for your response. However I am afraid I didn't fully understand what you were trying to say.
1) Don't use persisted data for your primary key (and
certainly not composite keys). This is an old skool
thing to do, and will end up hurting you later.I don't understand this comment. My database table needs a composite key for uniqueness. So I created my own PK class with those fields as members. The hash code returned by the PK class uses all these member variables to determine the hash code and I believe it will is unique. Also the equals method compares all these member variables. I didn't understand your line about using persisted data for primary key.
>
2) Ok, either your ejbFindByXXX() method is not
returning distinct primary key objects, or your
ejbLoad() method isn't working. If you can properly
retrieve an entity via the findByPrimaryKey method,
then I'd say you should re-examine what your
ejbFindByXX method is returning to the container.This is my understanding. When the client invokes findByPrimaryKey, the container invokes ejbFindByPrimaryKey with the provided key on ALL the ejb objects of that class. Only one of these EJB objects must be returning the same PK it took as an argument for ejbFindByPrimaryKey. The container must then return that EJB object back to the client. This is what happens in my code as per the logging statements i have in my ejbFindByPrimaryKey method. The argument is a PK object say pk1. I return an object pk2 and i ascertain that pk1 and pk2 have the same hash code and pk1.equals(pk2) returns true. well i guess it wld be easier to just return the argument but i didn't see a problem with this. Now the logging statements in ejbFindByPrimaryKey don't show any problem, they return the same primary key they get.
But this is what bothers me. I have two records inthe database. The container seems to call my ejbFindByPrimaryKey only once. Shouldn't it be checking twice on each of the ejbs corresponding to each of the records? And ultimately, it returns the wrong ejb back to the client.
I have no idea about this and would DEEPLY appreciate your help.
Thanks in anticipation,
Balan
>

Primary key generation

How do use primary keys generated by database within entity bean?

DBMS primary key generation uses a set of deployment descriptors that
are specified at compile time to generate container code which is used
in conjunction with a supported database to provide key generation
support. Specify the name of the supported DBMS and the generator name,
if required by the database. Generated primary key support for Oracle
databases use Oracle's SEQUENCE. Once the SEQUENCE already exists in the
database, you specify automatic key generation in the XML deployment
descriptors. In the weblogic-cmp-rdbms-jar.xml file
<automatic-key-generation>
<generator-type>ORACLE</generator-type>
<generator_name>test_sequence</generator-name>
<key-cache-size>10</key-cache-size>
</automatic-key-generator>
You need to specify the name of the ORACLE SEQUENCE to be used in the
generator-name element. If the ORACLE SEQUENCE was created with an
INCREMENT value, then you must specify a key-cache-size. This value must
match the Oracle SEQUENCE INCREMENT value.
Owen wrote:
How do use primary keys generated by database within entity bean?

EFS with key protected by TPM

I would like to encrypt directory used for system backup and EFS private must be protected by TPM.
I have a valid certificate (template derived from "EFS Basic" + "Microsoft Platform Crypto Provider" RSA/2048)
D:\>whoami
nt authority\system
D:\>certutil -store my
my "Personal"
================ Certificate 0 ================
Serial Number: 1e***************
Issuer: CN=Enterprise TEST CA, O=GOV C=BO
NotBefore: 2015-04-02 09:42
NotAfter: 2017-04-02 09:52
Subject: CN=TPM1SRV.gov.bo
Non-root Certificate
Template: EFSTPM, EFS TPM
Cert Hash(sha1): a6 d5 a9 06 66 22 72 a4 58 a8 24 e6 24 c9 xx xx yy yy zz zz
Key Container = le-EFSTPM-19a2278c-c708-****-b3b0-***************
Unique container name: C:\ProgramData\Microsoft\Crypto\PCPKSP\**\**.PCPKEY
Provider = Microsoft Platform Crypto Provider
2.5.29.37: Flags = 0, Length = e
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Private key is NOT exportable
Encryption test passed
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EFS certificate thumbprint for computer TPM1SRV:
A6D5 A906 6622 72A4 58A8 24E6 24C9 xxxx yyyy zzzz
How ever when I'm trying to encrypt Directory on Windows 2012 R2, the error is
D:\>cipher /E EncryptedByTPM
Encrypting files in D:\
EncryptedByTPM      [ERR]
EncryptedByTPM: The specified certificate is self signed.
0 file(s) [or directorie(s)] within 1 directorie(s) were encrypted.
But this is not true, EFS is signed by Enterprise CA W2K12 R2.
What I'm doing wrong ?

@Amy thank you for the hint
** I did tests:
New Template derived from “EFS Basic”
Template->Cryptography->Provider -> Key Storage Provider
(CNG)
   I need to use CNG to have access to "Microsoft Platform Crypto Provider"
Test #1
Template->Cryptography->Provider ->Algorithm :
RSA
Template->Cryptography->Provider ->Microsoft Key Storage Provider (without TPM)
Result: EFS encryption failed
Test #1
   Template->Cryptography->Provider ->Algorithm : ECDH_256
   Template->Cryptography->Provider ->Microsoft Key Storage Provider (without TPM)
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** I found the info: “EFS supports KSPs only for Elliptic Curve Diffie-Hellman (ECDH) keys.”
<-
Kurt L Hudson MSFT
http://blogs.technet.com/b/pki/archive/2012/01/23/efs-certificates-may-be-recovered-as-cng-certificates-when-capi-csp-is-required.aspx
** What algo are supported by Platform Crypto Provider?
certutil –cspinfo
Provider Name: Microsoft Platform Crypto Provider
      Name: Microsoft Platform Crypto Provider
Asymmetric Encryption Algorithms:
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    BCRYPT_ASYMMETRIC_ENCRYPTION_INTERFACE -- 3
   no ECDH :(
Game Over: By design TPM can’t be used to protect EFS key
s
Do you know what are the plans for W10 – maybe EFS will able to use KSP for RSA keys ?

CA Cryptographic service provider?

Hello,
I am planning to install Single tier Enterprise CA on a dedicated Windows 2008 R2 Server.
We still have Windows XP SP3 workstations and I have some questions about the "cryptography" options on the Certificate Authority installation wizard.
The "Select a cryptographic service provider (CSP)" -selection defaults to "rsa#microsoft software key storage provider". I'am not sure can I select it, or any of the "Cryptography Next Generation (CNG)"
providers (marked with #).
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I believe Windows 2003 CA Defaults to "Microsoft Strong Cryptographic Provider" so thinking of selecting that to guarantee compatibility with Windows XP.
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You should use the strongest provider (which provides additional features) that is supported by the operating system that runs CA service. In your case it is Microsoft Key Storage Provider. Do not use any legacy provider (strong or enhanced CSP). With Microsoft
KSP you have several options: xxx#Microsoft Key Storage Provider, where xxx -- is public key algorithm supported by the provider. Here you must select the algorithm that is supported by all certificates clients. Currently RSA is Internet PKI standard algorithm
which is supported by almost all certificate clients.
In other words, the most "safe" configuration is RSA#Microsoft Key Storage Provider, signature algorithm = "SHA1" and key length 2048. The following variations are possible without affecting many clients: change key length to 4096 (I don't see a big deal
here) and change to SHA256 signature algorithm. However, legacy clients (Windows XP and Windows Server 2003) may not work with this algorithm (they require updates to support SHA2 algorithms).
My weblog: http://en-us.sysadmins.lv
PowerShell PKI Module: http://pspki.codeplex.com
Check out new:
PowerShell FCIV tool.
Thanks Vadims for the solution and others for confirming.
Installing ca with:
CSP: Microsoft software key storage provider
Key length:2048
Hash algorithm for signing certificate: SHA1
CNG public key algorithm: RSA
Thanks
lakend

Strange Key Commands Issue - Please Help

I understand how to make/delete and export key commands.
I made a key command preference that I like that doesn't involve the screen set key commands ... herein lies the issue.
I delete the commands (1,2,3,4,5,6,7,8,9) that are assigned to screen sets because I want to use them for other things. I save the preset. If I keep logic open everything is hunky dory, but if I close logic and re-open it the screen set key commands are suddenly part of my preset again.
I'm running Logic 8 btw.
I thought Logic might automatically be initializing it's key commands from their provided key commands list, but after removing them I found that was not the case.
I also tried deleting my com.apple.logic.pro.plist file but still the screen set key commands keep showing up.
Does anyone know a way to keep Logic from adding them back into the key commands everytime I start it up?
-Stephan

swunderboy wrote:
WAIT!!!
I found a way around it:
instead of using "learn by key label" I used "learn by key position" and then the numbers on the number pad can be whatever I want!
YESSSSSS.
thanks again for your help!
LOL, OK, you never mentioned the keypad... I just assumed you were after the top row number keys... but those on the numpad are indeed available (or set in limestone). Good persistance! And thanks for reporting your solution.
regards, Erik.

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I began using Openbox in my laptop a while ago, and I was amazed by the speed, customization and simplicity it provides. After I started customizing my desktop I noticed that some of the special keys (TouchpadToggle, Volume, PrintScreen, etc) didn't worked at all. There are some applications for the Volume keys to work, but not for keys like touchpad-toggle and print-screen. Of course, there's a workaround for each case using simple scripts, but I wanted something a little more fancy, so I made:
Sleutel Bind
It's made in C and provides key events handling for:
XF86TouchpadToggle
Print (prtsc key)
It makes use of libnotify to display states ( touchpad enabled/disabled, screenshot taken, etc) and imlib2 (a very popular library, probably already installed in your system) to grab the screenshots. Almost all other keys are covered already by another application, but if needed, more key events will be added in the future.
Feel free to post your thoughts about Sleutel Bind, it's my first contribution to the community.
How to use
Once installed just run the command as a normal user.
If using openbox, place the following command in the "~/.config/openbox/autostart" file:
sleutelb &
Links
AUR
github
Last edited by DanielRS (2013-03-01 21:58:35)

mgmillani wrote:
I believe it must have been a bug and it was fixed, since print screen now works as expected. I'm using xmonad version 0.11-9, with ghc version 7.8.3.
davama wrote:
Note: for my print key to be recognized by xev i had to hold the ctrl key. that way it was not registered by xmonad. Also for xev command i use
xev | grep -A2 --line-buffered '^KeyRelease' | sed -n '/keycode /s/^.*keycode $[0-9]*$.* (.*, $.*$).*$/\1 \2/p'
Nice, that seems to be useful. Thanks!
@LQYMGT
Do you still have issues with the latest version? Otherwise I will mark this thread as solved.
well, still do not work... But I do not want to try it any more...So you can mark.

Where should i enter the keys to Extesnion Builder 2.1

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Hi
1. Make a Report manually.
2. In the data model view. Make your query.
3. Now in the group made for the query, add a placeholder column.
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