Query AD cause Exception calling "FindAll" with "0" argument(s)

Hi all,
When I query an entry property of AD with PowerShell, i got some problems. Here is the script, what's wrong ? Any idea? Thanks!
Cause error at last line code. (Exception calling "FindAll" with "0" argument(s): "There is no such object on the server)
$MailboxServer = Get-MailboxServer -Identity $Env:COMPUTERNAME -ErrorAction SilentlyContinue
$dc = [System.DirectoryServices.ActiveDirectory.Domain]::GetCurrentDomain()
$exchOAB = New-Object System.DirectoryServices.DirectoryEntry("LDAP://" + $dc.Name + "/cn=Offline Address Lists,cn=Address Lists Container, " + $MailboxServer.DistinguishedName)
$objSearcher = New-Object System.DirectoryServices.DirectorySearcher
$objSearcher.SearchRoot = $exchOAB
$objSearcher.PageSize = 1000
$objSearcher.SearchScope = "OneLevel"
$objSearcher.Filter = "(objectClass=msExchOAB)"
$powershellOAB = $objSearcher.FindAll()

This is one of, now, four duplicate posts.
¯\_(ツ)_/¯

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        public static void main(String[] args) {
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         f.f1(1);
         f.f1(2);
         f.f1(1);
    }Here is the result:
    f1(1)
    generate exception
    result = 2
    generate exception
    caught an Exception: PException
    f1(2)
    result = 2
    result = 1
    f1(1)
    generate exception
    result = 2
    generate exception
    caught an Exception: PException

    The concern here is that when the
    try {
    finally {
    }pattern is used, without the catch block, purelly for flow control purpose, a return statement in the finally block could be problematic. If a finally block ends with a return statement, any exception that might be thrown in the try block would be ignored. The unhandled exception will not propergate, it simply lost in the midst. Because any code could throw unchecked exception, if the exception cannot afford to be lost, then one should be careful not to use return in the finally block. See the following test code:
    class Finally {
        void test() {
         int result;
         System.out.println("test()");
         try {
             result = f1();
             System.out.println("result = " + result);
         } catch(Exception e) {
             System.out.println("Caught an Exception: " + e);
         try {
             result = f2();
             System.out.println("result = " + result);
         } catch(Exception e) {
             System.out.println("Caught an Exception: " + e);
         try {
             f3();
         } catch(Exception e) {
             System.out.println("Caught an Exception: " + e);
         try {
             f4();
         } catch(Exception e) {
             System.out.println("Caught an Exception: " + e);
        int f1() {
         System.out.println("f1()");
         int a = 0;
         int b = 0;
         try {
             a = 1/0;  // this generate an unchecked exception
             b = 1;
         } finally {
             return b; // this return clobber the unchecked exception
        int f2() {
         System.out.println("f2()");
         int a = 0;
         int b = 0;
         a = 1/0; // this generate an unchecked exception
         b = 1;
         return b;
        void f3() {
         System.out.println("f3()");
         int a = 0;
         int b = 0;
         try {
             a = 1/0;  // this generate an unchecked exception
             b = 1;
         } finally {
             return;   // this return clobber the unchecked exception
        void f4() {
         System.out.println("f4()");
         int a = 0;
         int b = 0;
         try {
             a = 1/0;  // this generate an unchecked exception
             b = 1;
         } finally {
        public static void main(String[] args) {
         Finally f = new Finally();
         f.test();
    /code]
    Here are the results:test()
    f1()
    result = 0
    f2()
    Caught an Exception: java.lang.ArithmeticException: / by zero
    f3()
    f4()
    Caught an Exception: java.lang.ArithmeticException: / by zero
    We see that the devide by zero exception throw by f1() simply vanished, the unintended result 0, instead of the intended result 1, is returned. The test() method did not detect any abnormality in f1(), which is scary. To drive the point home, we try f3() and f4(), which has void return type. A simple return statement in f3() causes exception be lost. The stack frame seems intact, for otherwise, the test() method would exit abruptly before f2() even get a chance to be called.

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