Query String parameter with # in its value
Hi,
When I send a parameter in a query string with value that has the hash symbol (i.e #) that parameter when fetched returns null. Why so?
Eg :
Page 1 :
String strTest = "1#2";
<a href="test.jsp?test=<%=strTest%>">Page 2: test.jsp
String strTest=request.getParameter("test");
System.out.println("strTest : "+strTest); // Prints null
Thanks</a>
Hi,
When I send a parameter in a query string with value
that has the hash symbol (i.e #) that parameter when
fetched returns null. Why so?
Its a special character and the url has to be 'rewritten properly.
>
Page 1 :
String strTest = "1#2";
<a href="test.jsp?test=<%=strTest%>">>
</a>
try this
<%
String strTest = java.net.URLEncoder.encode("1#2");
%>
<a href = "test.jsp?test=<%=strTest%>">test</a>and check the output in your next jsp :)
ram.
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Hi,
I use JDeveloper 11.1.1.2.0. and have the following table:
CREATE SEQUENCE COUNTRY_SEQ;
CREATE TABLE COUNTRY (
COUNTRY_ID NUMBER NOT NULL,
COUNTRY_NAME VARCHAR2(40),
COUNTRY_CODE CHAR(2) NOT NULL,
CONSTRAINT COUNTRY_ID_PK PRIMARY KEY (COUNTRY_ID)
INSERT INTO COUNTRY VALUES (COUNTRY_SEQ.NEXTVAL, 'Belgium', 'B');
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COMMIT;
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@NamedQuery(name = "Country.findAll", query = "select o from Country o"),
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If I change 'B' to 'BE' both in the DB and the code, it works. If I change to 'b', it doesn't. So it seems that the problem comes with 1 char long Strings.
Is it an EclipseLink bug?
I use Oracle Database 11g Enterprise Edition Release 11.1.0.7.0. But
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Thx, DonatHi,
That's true, it uses value bindings while the values are hard coded. I use the default EclipseLink embedded into JDeveloper 11.1.1.2, with the default settings. The JPA bean runs in the default embedded WebLogic of JDeveloper. This might be a default setting of EclipseLink to use bindings for hard coded values.
Here is a fragment of Country.java:
@Entity
@NamedQueries({
//@NamedQuery(name = "Country.findAll", query = "select o from Country o")
@NamedQuery(name = "Country.findAll", query = "select o from Country o where o.countryCode ='B' or o.countryCode ='NL'")
public class Country implements Serializable {
@Id
@Column(name="COUNTRY_ID", nullable = false)
private Long countryId;
@Column(name="COUNTRY_CODE", nullable = false)
private String countryCode;
@Column(name="COUNTRY_NAME", length = 40)
private String countryName;
And I have a JavaServiceFacade.java:
public class JavaServiceFacade {
private EntityManagerFactory emf = Persistence.createEntityManagerFactory("EjbModel-1-Outside");
public JavaServiceFacade() {
public static void main(String [] args) {
final JavaServiceFacade javaServiceFacade = new JavaServiceFacade();
List<Country> countries;
countries = javaServiceFacade.getCountryFindAll();
for (Country country : countries) {
System.out.println(country.getCountryCode());
private EntityManager getEntityManager() {
return emf.createEntityManager();
/** <code>select o from Country o</code> */
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BR, Donat -
JPA named query String parameter with length of 1
Hi,
I use JDeveloper 11.1.1.2.0. and have the following table:
CREATE SEQUENCE COUNTRY_SEQ;
CREATE TABLE COUNTRY (
COUNTRY_ID NUMBER NOT NULL,
COUNTRY_NAME VARCHAR2(40),
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INSERT INTO COUNTRY VALUES (COUNTRY_SEQ.NEXTVAL, 'Belgium', 'B');
INSERT INTO COUNTRY VALUES (COUNTRY_SEQ.NEXTVAL, 'Netherlands', 'NL');
COMMIT;
I made a JPA Entity with two queries:
@NamedQueries({
@NamedQuery(name = "Country.findAll", query = "select o from Country o"),
@NamedQuery(name = "Country.findByCountryCode", query = "select o from Country o where o.countryCode = 'B' or o.countryCode ='NL'")
The first works fine, gives back both B and NL. But the second gives back only NL. I have no clue why.
If I change 'B' to 'BE' both in the DB and the code, it works. If I change to 'b', it doesn't. So it seems that the problem comes with 1 char long Strings.
Is it an EclipseLink bug?
I use Oracle Database 11g Enterprise Edition Release 11.1.0.7.0. But
SELECT COUNTRY_ID, COUNTRY_NAME, COUNTRY_CODE FROM COUNTRY WHERE COUNTRY_CODE = 'B' OR COUNTRY_CODE = 'NL';
works in SQL*Plus.
Thx, DonatI moved this question to: Forum Home » Java Enterprise & Remote Computing » Enterprise JavaBeans
Donat -
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refer link
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Hi!
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pamLaura Rogers Blog
In case anyone stumbles upon this looking for an answer. Laura Rogers has the answer found in the comments section of her blog above. It’s not the best but it
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I cann't get query string parameter after recording
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http://blogs.msdn.com/b/slumley/archive/2007/04/17/enhanced-web-test-support-in-fiddler.aspx
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https://msdn.microsoft.com/en-us/library/ms182552.aspx
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https://msdn.microsoft.com/en-us/library/vstudio/ee317494%28v=vs.110%29.aspx
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Jason Guo
TechNet Community Support -
What I am trying to do is to check whether does that variable exist in the querystring, if it does change the value to another value.
How am I suppose to do abt doing that?Well, it's not too complex to do it with java... here is a simple example:
public class QueryStringChanger
public static String changeParameter(String query, String key, String value)
String[] keyValuePairs = query.split("&");
StringBuffer newQuery = new StringBuffer();
for (int k = 0; k < keyValuePairs.length; k++)
if (keyValuePairs[k].indexOf(key) != -1)
String[] thePair = keyValuePairs[k].split("=");
keyValuePairs[k] = thePair[0] + "=" + value;
if (k != 0) newQuery.append("&");
newQuery.append(keyValuePairs[k]);
return newQuery.toString();
public static void main(String[] args)
if (args.length != 3)
System.out.println("Syntax: java QueryStringChanger 'the query string' theKey theValue\n"+
"Example: java QueryStringChanger page=1&area=3&title=Not+So+Good title Pretty+Darn+Good");
System.exit(1);
System.out.println(changeParameter(args[0], args[1], args[2]));
System.exit(0);
}Not so sure what you would gain from a HashTable though...
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